fisiks

Li-vector tsa yuniti - mathata le litharollo

1. Ntho e tsamaya ho Velocity ea v = (2i − 1.5j) m/s. Ke eng ho baleha ea ntho eo ka mor'a metsotsoana e 4?

Tse tsejoang:

Karolo e rapameng ea lebelo (v)_x) = 2 m/s

Karolo e otlolohileng ea lebelo (v)_y) = 1.5 m/s

Nako ea ho arohana (t) = metsotsoana e 4

Ho batloa: Ho tlosoa

Bala haholoanyane

Ho falla ha li-vector - mathata le litharollo

1. Motho o tsamaea ho tloha ntlheng ea A ho ea ntlheng ea B, limithara tse 600 ka leboea; ebe o ea ntlheng ea C, limithara tse 400 ka bophirima; ebe o ea ntlheng ea D, limithara tse 200 ka boroa; ebe o qetella ntlheng ea E, limithara tse 700 ka bochabela. Boholo ba sekepe ke bofe? ho baleha?

Tharollo:

Tse tsejoang:

AF = AB – BF = AB – CD = 600 – 200 = 400 m

EF = DE – DF = DE – BC = 700 – 400 = 300 m

Bala haholoanyane

Ho eketsa li-vector ho sebelisa likarolo - mathata le litharollo

1. Li-vector tse tharo joalo ka ha ho bontšitsoe setšoantšong se ka tlase.

V₁ = 30

V₂ = 30

V₃ = 40

Sephetho ke sefe likotsi.

Tse tsejoang:

V₁ = 30, sekhutlo pakeng tsa V₁ le mothapo oa x = 30^o

Bala haholoanyane

Litšoantšo tsa motsamao o otlolohileng - mathata le litharollo

1. Sebaka sa kerafo (se otlolohileng) khahlanong le nako (se otlolohileng) joalo ka ha ho bontšitsoe setšoantšong se ka tlase. Ntho e phomotseng e bontšitsoe ka nomoro…

Tharollo:

Nomoro ea 3, e bontšitsoeng ka mola o otlolohileng.

Bala haholoanyane

Lebelo le tloaelehileng - mathata le litharollo

1. Motho e mong o potoloha khutlonnetsepa e bolelele ba limithara tse 400 le bophara ba limithara tse 100, makhetlo a 12 ka hora e le 'ngoe. lebelo le tloaelehileng le lebelo le tloaelehileng?

Tse tsejoang:

Bolelele ba khutlonnetsepa = limithara tse 400

Bophara ba khutlonnetsepa = limithara tse 100

Selikalikoe sa khutlonnetsepa = (2 x 400 metres) + (2 x 100 metres) = 800 metres + 200 metres = 1000 metres

Sebaka = 12 x 1000 metres = 12,000 metres = 12 km

Bala haholoanyane

Molao-motheo oa batho ba batšo - mathata le litharollo

1. Metsi a digrama tse 200 mochesong wa 30°C a kopantswe le metsi a digrama tse 100 mochesong wa 90°C. mocheso o itseng ea metsi = 1 cal.gram^-1° C^-1Fumana mocheso oa ho qetela oa motsoako!

Tse tsejoang:

Boholo ea metsi 2 (m₁) = digrama tse 200

Mocheso oa metsi 1 (T)₁= 30^oC

Boima ba metsi 2 (m₂) = digrama tse 100

Bala haholoanyane

10 Dynamics Ntho e hokahaneng ka thapo hodima pulley Mochini wa Atwood – Mathata le Ditharollo

1. Boloko A e nang le boima ea 5 kg, e behiloe sebakeng se boreleli se bataletseng. Boloko B bo nang le boima ba 3 kg bo leketlileng pheletsong e 'ngoe ea thapo bo hokahantsoeng le boloko A holim'a pulley. Ho potlakisa ka baka la matla a khoheli ke 10 m/s². Ke eng ho potlaka ea liboloko ka bobeli?

Tse tsejoang:

Boima ba boloko A (m_A) = 5 kg

Boima ba boloko B (m_B) = 3 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Bala haholoanyane

Motsamao o chitja - mathata le litharollo

1. Ntho e boima ba 10 kg e tsamaya ka sedikadikwe ka lebelo le sa fetoheng la 4 m/s. Haeba radius ya sedikadikwe e le 0.5 metres, jwale:

1) Maqhubu a di-circle ke 4/π Hz

2) The ho potlaka ha bohareng ke 32 ms^-2

3) The matla a bohareng ke 320 N

4) Nako ke 4π s.

Ke lipolelo life tsa 'nete?

Bala haholoanyane

Motsamao oa ho oa o lokolohileng - mathata le litharollo

1. Lejoe le oela ka bolokolohi ho tloha bophahamong ba limithara tse 45. Haeba ho potlaka ka lebaka la matla a khoheli ke 10 ms^-2, lebelo la lejoe ke lefe ha le thula fatshe?

Tse tsejoang:

Bophahamo (h) = limithara tse 45

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: Lebelo la ho qetela la lejoe ha le otla fatše (v_t)

Bala haholoanyane