Dhibaatooyinka lagu xalliyay Fiisigiska Aasaasiga ah

9 Miisaanka heerkulka ee beddelaya (Miisaanka Celsius miisaanka Fahrenheit miisaanka Kelvin)

1. 50 ^o C = ….. ^o F ?

Solution

Cadaadiska jawiga caadiga ah , barta barafowga biyaha waa 0 ^o C cabbirka Celsius iyo 32 ^o F cabbirka Fahrenheit. Cadaadiska jawiga caadiga ah, barta karkaraya biyaha waa 100 ^o C cabbirka Celsius iyo 212 ^o F cabbirka Fahrenheit.

0 ^o C = 32 ^o F iyo 1 00 ^o C = 212 ^o F. Isbeddel 5 C ^o = isbeddel 9 F ^o.

Miisaanka Celsius, masaafada u dhaxaysa 0 ^o C iyo 100 ^o C waxaa loo qaybiyaa 100 isku-dhafan oo isku-dhafan. Miisaanka Fahrenheit, masaafada u dhaxaysa 0 ^o C iyo 100 ^o C waxaa loo qaybiyaa 180 isku-dhafan oo isku-dhafan.

To ^o F = (180/100) To ^o C + 32

To ^o F = (9/5) To ^o C + 32

To ^o F = (9/5) 50 + 32

To ^o F = (9) 10 + 32

T ^o F = 90 + 32

T ^o F = 122

50 ^o C = 122 ^o F

2. 86 ^o F = ….. ^o C ?

Solution

To ^o C = (100/180)(T ^o F – 32)

To ^o C = (5/9)(T ^o F – 32)

To ^o C = (5/9)(86 – 32)

To ^o C = (5/9)(54)

To ^o C = (5)(6)

To ^o C = 30

86 ^o F = 30 ^o C

3. 50 ^o C = ….. K ?

Solution

T = T ^o C + 273

T = 50 + 273

T = 323

50 ^o C = 323 K

4. 212 ^o F = ….. K ?

Solution

To ^o C = (100/180)(T ^o F – 32)

To ^o C = (5/9)(T ^o F – 32)

To ^o C = (5/9)(212 – 32)

To ^o C = (5/9)(180)

To ^o C = (5)(20)

To ^o C = 100

212 ^o F = 100 ^o C + 273

212 ^o F = 373 K

 

5. x ^o C = x ^o F

x = …..?

Solution

1: Beddelidda miisaanka Celsius una beddel cabbirka Fahrenheit

2: Beddelidda miisaanka Fahrenheit una beddel cabbirka Celsius

6. 122°F = ….. Celsius

Solution

Beddelka u dhexeeya labada miisaan ee heerkulka waxaa lagu qori karaa:

T _C = 5/9 (T _F – 32)

T _C = Heerkulka Celsius, T _F = heerkulka Fahrenheit

Heerkulka Celsius:

T _C = 5/9 (122 – 32) = T _C = 5/9 (90) = 5 (10)

T _C = 50 ^o C

7. Jaantuska hoose wuxuu muujinayaa cabbirka heerkulka dareeraha iyadoo la adeegsanayo heerkulbeegga cabbirka Fahrenheit! Haddii heerkulka dareeraha lagu cabbiro heerkulbeegga cabbirka Celsius, markaa waa maxay heerkulka dareeraha e.

La yaqaan:

Miisaanka Fahrenheit (T _F ) = 95 ^o F

La Raadinayo: Cabbirka Celsius

Xalka:

Cadaadiska 1 atm, barta barafowga biyaha waa 0 °C halka cabbirka Fahrenheit uu yahay 32 ^° F. Taas beddelkeeda, barta karkaraya biyaha ee cabbirka Celsius waa 100 ^° C halka cabbirka Fahrenheit uu yahay 212 ^° F.

Cabbirka Celsius, inta u dhaxaysa 0 °C iyo 100 °C waxaa jira 100 ° halka cabbirka Fahrenheit uu yahay 32 °F ilaa 212 °F waxaa jira 180 °.

T _C = 100/180 (T _F – 32)

T _C = 5/9 (T _F – 32)

T _C = 5/9 ( 95 – 32)

T _C = 5/9 ( 63 )

T _C = 315/9

T _C = 35 ^o C

8. Iyada oo ku saleysan sawirka hoose, go'aami heerkulka P ee heerkulbeegga Celsius.

Solution

T_C = 100/180 (T_F - 32)

T _C = 5/9 (T _F – 32)

T _C = 5/9 (104 – 32)

T _C = 5/9 (72)

T _C = 360/9

T _C = 40 ^o C

9. Haddii heerkulka cabbirka Celsius uu yahay sida ka muuqata sawirka hoose, go'aami heerkulka cabbirka Fahrenheit sida ka muuqata sawirka hoose.

Xalka:

T^oF = (180/100) T^oC+32

To ^o F = (9/5) To ^o C + 32

To ^o F = (9/5) 60 + 32

To ^o F = (9) 12 + 32

T ^o F = 108 + 32

T ^o F = 140

1. Beddelidda miisaanka heerkulka
2. Balaadhinta toosan
3. Ballaarinta aagga
4. Ballaarinta mugga
5. Heat
6. U dhigma farsamo ee kulaylka
7. Awood gaar ah oo kul iyo kulayl ah
8. Kulayl qarsoon, kulayl isku-dhafan, kulayl uumi-baxa
9. Ilaalinta tamarta ee wareejinta kulaylka

Akhri wax dheeraad ah

1. Shaxanka hoose waxaa lagu muujiyay jaantuska xoogga (F) iyo fidinta (x ). Soo hel joogtada guga!

Solution

Qaacidada sharciga Hooke :

k = F/x

F = xoog (Newton)

k = joogto ah guga (Newton/mitir)

x = isbeddelka dhererka (mitir)

Joogtada guga:

k = 10 / 0.02 = 20 / 0.04

k = 500 N/m

2. Go'aami joogtada guga.

Solution

Joogtada guga:

k = F/x

k = 5 / 0.01 = 10 / 0.02 = 15 / 0.03 = 20 / 0.04

k = 500 N/m

3. Guga A wuxuu leeyahay dhererkii asalka ahaa ee 60 cm halka guga B uu leeyahay dhererkii asalka ahaa ee 90 cm. Guga A wuxuu leeyahay joogto ah 100 N/m, guga B wuxuu leeyahay joogto ah 200 N/m. Saamiga isbeddelka dhererka guga A iyo isbeddelka dhererka gu'ga B waa…

La yaqaan:

Joogtada guga A (k _A ) = 100 N/m

Joogtada guga B (kB ₎ = 200 N/m

Xoogga guga A (F _A ) = F

Xoogga guga B (F _B ) = F

La rabay: Δl _A : Δl _B

Xalka:

Qaacidada sharciga Hooke:

Δl = F / k

Δl = isbeddelka dhererka, F = xoog, k = joogto ah

Isbeddelka dhererka gu'ga A:

Δl _A = F _A / k _A = F / 100

Isbeddelka dhererka guga B:

Δl _B = F _B / k _B = F / 200

Saamiga isbeddelka dhererka guga A iyo isbeddelka dhererka guga B:

Δl _A : Δl _B

F/100: F/200

1 / 100: 1 / 200

1 / 1: 1 / 2

2: 1

4. Xarig nayloon ah oo dhererkiisu yahay 20 cm, waxaa jiidaya xoog dhan 10 N. Isbeddelka dhererka xariggu waa 2 cm. Go'aami baaxadda xoogga haddii isbeddelka dhererku yahay 6 cm.

La yaqaan:

Xoogga (F) = 10 N

Isbeddelka dhererka ( Δl ) = 2 cm = 0.02 m

La rabo: baaxadda xoogga (F) haddii Δl = 0.06 m.

Xalka:

Joogto ah:

k = F / Δl

k = 10 / 0.02 = 500 N/m

Baaxadda xoogga (F) haddii Δl = 0.06 m:

F = kx

F = (500)(0.06)

F = 30N

[wpdm_package id='689′]

1. Sharciga Hooke
2. Cadaadis, cadaadis, Modulus-ka Young

Akhri wax dheeraad ah

Modulus-ka Dhibaatada Walbahaarka ee Dhalinyarada - Dhibaatooyinka iyo Xalalka

1. Xadhig nayloon ah wuxuu leeyahay dhexroor dhan 2 mm, oo uu jiido xoog dhan 100 N. Go'aami cadaadiska!

La yaqaan:

Xoogga (F) = 100 N

Dhexroorka (d) = 2 mm = 0.002 m

Gacanka (r) = 1 mm = 0.001 m

La Doonayo: Walbahaarka

Xalka:

Aagga:

A = π r ²

A = (3.14)(0.001 m) ² = 0.00000314 m ²

A = 3.14 x 10 ^-6 m ²

Walwalka:

2. Xadhig dhererkiisu yahay 100 cm ayaa xoog lagu jiidaa. Isbeddelka dhererka xadhiggu waa 2 mm. Go'aami culayska!

La yaqaan:

Dhererka asalka ah (l ₀ ) = 100 cm = 1 m

Isbeddelka dhererka (Δl) = 2 mm = 0.002 m

La Doonayo: Nooca

Xalka:

Tareenka :

3. Xadhig 4 mm dhexroor ah wuxuu leeyahay dherer asal ah 2 m. Xariga waxaa jiidaya xoog dhan 200 N. Haddii dhererka ugu dambeeya ee gu'gu uu yahay 2.02 m, go'aami: (a) cadaadis (b) cadaadis (c) Modulus-ka Young

La yaqaan:

Dhexroorka (d) = 4 mm = 0.004 m

Gacanka (r) = 2 mm = 0.002 m

Aagga (A) = π r ² = (3.14) (0.002 m) ²

Bedka (A) = 0.00001256 m ² = 12.56 x 10 ^-6 m ²

Xoogga (F) = 200 N

Dhererka asalka ah ee guga (l ₀ ) = 2 m

Isbeddelka dhererka (Δl) = 2.02 – 2 = 0.02 m

La Doonayo: (a) Cadaadiska (b) Cadaadiska c) Modulus-ka Young

Xalka:

(a) Walbahaarka

(b) Cadaadiska

(c) Qaab-dhismeedka Young

4. Xariggu wuxuu leeyahay dhexroor 1 cm ah dhererkiisuna waa 2 m. Xariggu wuxuu jiidayaa xoog dhan 200 N. Go'aami isbeddelka dhererka xarigga! Modulus-ka Young ee xarigga = 5 x 10 ⁹ N/m ²

La yaqaan:

Modulus-ka Young (E) = 5 x 10 ⁹ N/m ²

Dhererka asalka ah (l ₀ ) = 2 m

Xoogga (F) = 200 N

Dhexroorka (d) = 1 cm = 0.01 m

Gacanka (r) = 0.5 cm = 0.005 m = 5 x 10 ^-3 m

Bedka (A) = π r ² = (3.14)(5 x 10 ^-3 m) ² = (3.14)(25 x 10 ^-6 m ² )

Bedka (A) = 78.5 x 10 ^-6 m ² = 7.85 x 10 ^-5 m ²

La rabay : Isbeddelka dhererka (Δl)

Xalka:

Qaacidada moodulka Young:

Isbeddelka dhererka :

5. Sibidhku wuxuu leeyahay dherer dhan 5 mitir wuxuuna leeyahay bedka halbeegga ah 3 m ³ oo taageeraya cuf dhan 30,000 kg. Go'aami (a) Cadaadiska (b) Cadaadiska (c) Isbeddelka dhererka! Dardargelinta cufisjiidadka (g) = 10 m/s ^2. Modulus-ka Young ee sibidhka = 20 x 10 ⁹ N/m ²

La yaqaan:

Qaab-dhismeedka shubka ee Young = 20 x 10 ⁹ N/m ²

Dhererka bilowga ah (l ₀ ) = 5 mitir

Bedka cutubka (A) = 3 m ²

Miisaanka (w) = mg = (30,000)(10) = 300,000 N

La doonayo: (a) Cadaadiska (b) Cadaadiska (c) Isbeddelka dhererka!

Xalka:

(a) Walbahaarka

(b) Cadaadiska

(c) Isbeddelka dhererka

1. Sharciga Hooke
2. Cadaadis, cadaadis, Modulus-ka Young

Akhri wax dheeraad ah

1. Kubbad, oo ku xiran dhammaadka xarig jiif ah, ayaa lagu wareejinayaa goobaabin 20 cm ah. Kubbadu waxay ku wareegsan tahay 360 ^o ilbiriqsi kasta. Go'aami baaxadda dardargelinta bartamaha!

La yaqaan:

Xawaaraha xagasha (ω ) = 360 ^o / ilbiriqsi = 1 kacaan/ilbiriqsi = 6.28 radiyaan/ilbiriqsi

Gacanka (r) = 20 cm = 0.2 m

La Doonayo: Dardargelinta bartamaha (a _r )

Xalka:

a _r = v ² / r —> v = r ω

a _r = (r ω) ² / r = r ² ω ² / r

a _r = r ω ²

a _s = dardargelinta bartamaha, v = xawaaraha toosan, r = radius, ω = xawaaraha xagasha

Baaxadda xawaaraha dhexe ee centripetal-ka :

a _r = r ω ² a _r = (0,2 m)( 6.28 rad/s)

a _r = 1.256 m/s ²

2. Taayir 30 cm ah oo gacan ah ayaa wareegaya xawaare dhan 180 rpm. Go'aami xawaaraha dhexe ee barta ku taal geeska giraangiraha!

La yaqaan:

Gacanka (r) = 30 cm = 0.3 m

Xawaaraha xagasha ( ω ) = 180 wareeg / 60 ilbiriqsi = 3 wareeg / ilbiriqsi = (3)(6.28 gacan) / ilbiriqsi = 18.84 gacan/ilbiriqsi

La Rabay: dardargelinta bartamaha ( a _r ) ee r = 0.3 m

Xalka:

Baaxadda xawaaraha dhexe ee centripetal-ka:

a _r = r ω ²

a _r = (0.3 m)(18.84 rad/s)

a _r = 5.65 m/s ²

3. Gaariga tartanka wuxuu ku socdaa waddo wareeg ah oo 50 mitir ah. Haddii xawaaraha gaarigu yahay 72 km/saacaddii, go'aami baaxadda xawaaraha dhexe!

La yaqaan:

Gacanka (r) = 50 mitir

Xawaaraha (v) = 72 km/saacaddii = (72)(1000 mitir) / 3600 ilbiriqsi = 20 mitir/ilbiriqsi

La rabay : baaxadda xawaaraha dhexe (a _r )

Xalka:

a _r = v ² / r = 20 ² / 50 = 400 / 50 = 8 m/s ²

4. Gaadhigu wuxuu leeyahay xawaaraha ugu badan ee dhexe ee 10 m/s ² , sidaa darteed gaadhigu wuu leexan karaa isagoon ka bixin waddo qaloocan. Haddii gaadhigu uu ku socdo xawaare joogto ah 108 km/saacaddii, waa maxay gacanka qalooca aan bannayn?

La yaqaan:

Dardargelinta bartamaha (a _r ) = 10 m/s ²

Xawaaraha gaariga (v) = 108 km/ saacaddii = (108)(1000) / 3600 = 30 mitir s / sec c on d

La doonayo: gacan (r)

Xalka:

r = v ² / a _r

r = 30 ^2/10 = 900 / 10 = 90 mitir s

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[wpdm_package id='439′]

1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Taayir 3 0 cm ah oo gacan ah ayaa ku wareegaya 5 rad/s oo joogto ah ^2. Waa maxay baaxadda dardargelinta toosan ee barta ku taal (a) 10 cm oo ka fog bartamaha (b) 20 cm oo ka fog bartamaha (c) ee geeska giraangiraha?

La yaqaan:

Gacanka (r) = 30 cm = 0.3 m

Dardargelinta xagasha ( α ) = 5 rad/s ²

La doonayo: dardargelinta toosan (a) r = 0.1 m (b) r = 0.2 m (c) r = 0.3 m

Xalka:

Xiriirka ka dhexeeya dardargelinta toosan (a) iyo dardargelinta xagasha:

a = r α

(a) dardargelinta toosan, r = 0.1 m

a = (0.1 m)(5 rad/s ² ) = 0.5 m/s ²

(b) dardargelinta toosan, r = 0.2 m

a = (0.2 m)(5 rad/s ² ) = 1 m/s ²

(c) dardargelinta toosan, r = 0.3 m

a = (0.3 m)(5 rad/s ² ) = 1.5 m/s ²

2. Barkin 50 cm ah oo gacan ah. Haddii dardargelinta toosan ee barta ku taal geeska barkinta ay tahay 2 m/s ² , go'aami xawaaraha xagasha ee barkinta!

La yaqaan:

Gacanka (r) = 50 cm = 0,5 m

Dardargelinta toosan (a) = 2 m/s ²

La doonayay: dardargelinta xagasha

Xalka:

α = a / r = 2 / 0.5 = 4 rad/s ²

3. Daabyada ku jira blender 20 cm oo gacan ah, marka hore marka la nasto. 2 ilbiriqsi ka dib, daabyadu waxay wareegaan 10 rad/s. Go'aami baaxadda dardargelinta toosan (a) dhibic ku taal 10 cm bartamaha (b) dhibic ku taal geeska daabyada.

La yaqaan:

Gacanka (r) = 20 cm = 0.2 m

_{Xawaaraha xagasha bilowga ah} ( ωo ) = 0

Xawaaraha xagasha ugu dambeeya ( ω _{t )} = 10 radiyaan/ilbiriqsi

Muddada (t) = 2 ilbiriqsi

La Rabay: dardargelinta toosan ee barta ku taal (a) r = 0.1 m (b) r = 0.2 m

Xalka:

ω _t = ω _o + α t

10 = 0 + α (2)

10 = 2 α

α = 10/2

 α = 5 rad/s

(a) dardargelinta toosan ee r = 0.1 m

a = r α = (0.1 m) (5 rad/s ² ) = 0.5 m/s ²

(b) dardargelinta toosan ee r = 0.2 m

a = r α = (0.2 m) (5 rad/s ² ) = 1 m/s ²

4. Taayir 20 cm ah oo gacan ah ayaa la dedejinayaa 2 ilbiriqsi laga bilaabo 20 rad/s si loo nasto. Go'aami baaxadda dardargelinta toosan (a) dhibic ku taal 10 cm oo ka fog bartamaha (b) dhibic ku taal 10 cm oo ka fog bartamaha.

La yaqaan:

Gacanka (r) = 20 cm = 0.2 m

Xawaaraha xagasha bilowga ah ( ω _o ) = 20 rad/s

_{Xawaaraha xagasha ugu dambeeya} ( ωt ) = 0

Muddada (t) = 2 ilbiriqsi

La Rabay: Dardargelinta toosan (a) r = 0.1 m (b) r = 0.2 m

Xalka:

ω _t = ω _o + α t

0 = 20 + α (2)

-20 = 2 α

α = -20 / 2

 α = -10 rad/s

Calaamad taban macnaheedu waa xawaaraha xagasha ayaa hoos u dhacaya.

(a) dardargelinta toosan ee r = 0.1 m

a = r α = (0.1 m) (-10 rad/s ² ) = -1 m/s ²

(b) dardargelinta toosan ee r = 0.2 m

a = r α = (0.2 m) (-10 rad/s ² ) = -2 m/s ²

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[wpdm_package id='439′]

1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Kubbad dhammaadka xarig ah ayaa si isku mid ah ugu wareegaysa goob siman oo gacan ah 2 mitir xawaare xagal joogto ah 10 rad/s. Go'aami baaxadda xawaaraha toosan ee barta ku taal:

(a) 0.5 mitir u jirta bartamaha

(b) 1 mitir u jirta bartamaha

(c) 2 mitir u jirta bartamaha

La yaqaan:

Gacanka (r) = 0.5 mitir s, 1 mitir, 3 mitir

Xawaaraha xagasha = 10 radian s / se cond

La Doonayo: Xawaaraha toosan

Xalka:

v = r ω

v = xawaaraha toosan , r = gacanka , ω = xawaaraha xagasha

(a) Xawaaraha toosan (v) ee barta ku taal r = 0.5 mitir

v = r ω = (0.5 mitir s )(10 rad/s) = 5 mitir s / se xaalad

(b) Xawaaraha toosan (v) ee barta ku taal r = 1 mitir

v = r ω = (1 mitir)(10 rad/s) = 10 mitir s / se xaalad

(c) Xawaaraha toosan (v) ee barta ku taal r = 2 mitir s

v = r ω = (2 mitir s )(10 rad/s) = 20 mitir s / se xaalad

2. Daabyada ku jira blender-ka ayaa ku wareegaya xawaare dhan 5000 rpm. Go'aami baaxadda xawaaraha toosan:

(a) bar ku taal 5 cm bartamaha

(b) bar ku taal 10 cm oo u jirta bartamaha

La yaqaan:

Gacanka (r) = 5 cm iyo 10 cm

Xawaaraha xagasha (ω) = 5000 kacdoonada / 60 ilbiriqsidhamaado = 83.3 kacdoonada / sexaalad = (83.3)(6.28 radiyaan) / sexaalad = 523.3 radians / sexaalad

La Doonayo: Cabbirka xawaaraha toosan

Xalka:

(a) Cabbirka xawaaraha toosan ee barta ku taal 0.05 m bartamaha

v = r ω = (0.05 m)( 523.3 rad/s) = 26 m/s

(b) Cabbirka xawaaraha toosan ee dhibic ku taal 0,1 m bartamaha

v = r ω = (0.1 m)( 523.3 rad/s) = 52 m/s

3. Bar ku taal cidhifka giraangiraha 30 cm oo gacan ah, oo ku wareegsan goobaabin xawaare joogto ah 10 mitir/ilbiriqsi.

Waa maxay baaxadda xawaaraha xagasha?

La yaqaan:

Gacanka ( r) = 30 cm = 0.3 mitir s

Xawaaraha toosan (v) = 10 mitir s / se xaalad

La Doonayo: xawaaraha xagasha

Xalka:

ω = v / r = 10 / 0.3 = 33 raadiyaan s / se xaalad

4. Gaari leh taayiro dhexroorkoodu yahay 50 cm wuxuu socdaa 10 mitir 1 ilbiriqsi gudaheed . Waa maxay xawaaraha xagasha?

La yaqaan:

Gacanka (r) = 0.25 mitir

Xawaaraha toosan ee barta ku taal geeska taayirada (v) = 10 mitir s / se xaalad

La Doonayo: Xawaaraha xagasha

Xalka:

ω = v / r = 10 / 0.25 = 40 raadiyaan s / se xaalad

5. Xawaaraha xagasha ee giraangiraha 20 cm ee radians waa 120 rpm. Waa maxay masaafada haddii gaarigu socdo 10 ilbiriqsi gudahood.

La yaqaan:

Gacanka (r) = 20 cm = 0.2 mitir s

Xawaaraha xagasha = 120 rev / 60 sexaaladaha = 2 rev / sexaalad = (2)(6.28) raadiyaans / sexaalad = 12.56 radians / sexaalad

La Raadinayo : masaafada

Xalka:

Xawaaraha geeska giraangiraha:

v = r ω = (0.2 mitir s )(12.56 raadiyaan s / se cond ) = 2.5 mitir s / se cond

Mitirka 2.5s / second macnaheedu waa bar ku taal geeska safarka giraangiraha Mitirka 2.5s 1 ilbiriqsi kasta. Ka dib markii ay 10xaaladaha, barta ayaa safreysa Mitirka 25s.

Markaa masaafada waa 25 mitir ilbiriqsi.

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

Beddelidda cutubyada xagasha (heerka, radian, kacaanka)

1. ¼ dib u eegis = ….. ^o ( darajada )?

Solution

1 kacaan = 360 ^o

½ dib u eegis = 180 ^o

¼ dib u eegis = 90 ^o

2. ½ dib u eegis = …….. r xayeysiis?

Solution

1 rev = 2 π rad = 2 (3.14) rad = 6.28 rad

½ rev = pi rad = 3.14 rad

3. 180 ^o = ….. dib u eegis?

Solution

360 ^o = 1 kacaan

180 ^o = ½ dib

4. 90 ^o = ….. rad?

Solution

360 ^o = 2 π rad = 2 (3.14) rad = 6.28 ra d

180 ^o = π rad = 3.14 rad

90 ^o = ½ π rad = ½ (3.14) = 1.57

5. 60 rad = ….. dib u eegis?

Solution

6.28 rad = 1 dib u habayn

60 rad/6.28 = 9.55 dib u habayn

6. 40 rad= ….. ^o?

Solution

6.28 rad = 360 ^o

40 rad/6.28 = (6.37) (360 ^o ) = 2292.99 ^o

Barakaca xagasha iyo barokaca toosan

1. Taayir baaskiil oo dhexroorkiisu yahay 60 cm ayaa wareegaya 10 radian. Waa maxay kala-guurka toosan ee barta ku taal geeska taayiradda?

La yaqaan:

Gacanka (r) = 30 cm = 0.3 m

Xagasha (θ ) = 10 gacan

La Raadinayo: barokac toosan (l)

Xalka:

l = r θ

l = (0.3 m)(10 rad)

l = 3 mitir

2. Taayir 50 cm ah oo gacan ah ayaa wareegta 360 ^o . Waa maxay kala-guurka toosan ee barta ku taal geeska giraangiraha?

La yaqaan:

Gacanka (r) = 50 cm = 0.5 mitir

Xagasha ( θ ) = 360 ^o = 6.28 radiyaan

La Raadinayo: barokac toosan (l)

Xalka:

l = r θ

l = (0.5 m)(6.28 rad)

l = 3.14 mitir

3. Taayir 50 cm ah oo gacan ah ayaa wareegaya 2 wareeg. Waa maxay kala-guurka toosan ee barta ku taal geeska giraangiraha?

La yaqaan:

Gacanka (r) = 50 cm = 0,5 m

Xagasha ( θ ) = 2 wareeg = (2)(6.28 gacan) = 12.56 gacan

La rabay: barokac toosan (l)?

Xalka:

l = r θ

l = (0.5 m)(12.56 rad)

l = 6.28 m

4. Bar ku taal cidhifka giraangiraha 2 mitir oo gacan ah, waxay u socotaa 100 mitir. Go'aami meesha ay ka soo baxayso xagasha.

La yaqaan:

Gacanka (r) = ½ (dhexroor) = ½ (2 mitir) = 1 mitir

Barakaca toosan (l) = 100 mitir

Xalka:

(a) Barakaca xagasha (ee raadiyaanka)

θ = s / r = 100 / 1 = 100 radiyaan

(b) Barakaca xagasha (heerar)

1 raadiyaan = 360 ^o

100 raadiyaanka = 100(360 ^o ) = 36,000 raadiyaanka

(c) Barakac xagal ah (kacaankii)

6.28 raadiyaanka = 1 kacaan

36,000 / 6.28 = 5732,484 kacaan

5. Walax ayaa wareeg ku wareegsan 10 mitir waxayna wareegtaa 180 ^o . Waa maxay gacanka?

La yaqaan:

Barakaca toosan (l) = 10 mitir

Xagasha ( θ ) = 180 ^o = 3.14 radiyaan

La doonayo: gacan (r)

Xalka:

r = l / θ = 10 / 3.14 = 3.18 mitir

1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Taayir 1 mitir ah oo gacan ah ayaa si isku mid ah u dardargeliya 2 rad/s ^2. Go'aami xawaaraha xagasha iyo xawaaraha xagasha ee giraangiraha, 2 ilbiriqsi ka dib.

La yaqaan:

Gacanka (r) = 1 mitir

Dardargelinta xagasha (α ) = 2 rad/s ²

La rabay: dardargelinta xagasha iyo xawaaraha xagasha 2 ilbiriqsi ka dib.

Xalka:

(a) Dardargelinta xagasha 2 ilbiriqsi gudahood

Dardargelinta xagasha waa mid joogto ah, sidaas darteed 2 ilbiriqsi ka dib, dardargelinta xagasha ee giraangiraha waa 2 rad/s ².

(b) Xawaaraha xagasha 2 ilbiriqsi gudahood

Dardargelinta xagasha 2 rad/s ² macnaheedu waa xawaaraha xagasha wuxuu kordhiyaa 2 rad/s ilbiriqsi kasta 1 ilbiriqsi kasta. Ka dib 1 ilbiriqsi, xawaaraha xagasha = 2 rad/s. Ka dib 2 ilbiriqsi, xawaaraha xagasha = 4 rad/s ilbiriqsi.

2. Walax ayaa si isku mid ah u dardargelisa laga bilaabo nasashada ilaa 60 rpm 10 ilbiriqsi gudahood. Go'aami baaxadda dardargelinta xagasha!

La yaqaan:

Xawaaraha xagasha bilowga ah (ω _o ) = 0

Xawaaraha xagasha ugu dambeeya ( ω _t ) = 60 rpm = 60 wareeg / 60 ilbiriqsi = 1 kacaanka / ilbiriqsi = 6,28 radiyaan/ilbiriqsi

Muddada (t) = 10 ilbiriqsi

La Doonayo: Dardargelinta xagasha ( α )

Xalka:

ω _o = xawaaraha xagasha bilowga ah, ω _t = xawaaraha xagasha ugu dambeeya, α = dardargelinta xagasha, t = waqtiga u dhexeeya, θ = xagasha.

ω _t = ω _o + α t

6.28 = 0 + α (10)

6.28 = 10 α

α = 6.28 / 10

α = 0.628 rad/s ²

Baaxadda xawaaraha xagasha = 0.628 rad/s ²

3. Shay ayaa hoos u dhacaya laga bilaabo 20 rad/s ilaa 10 rad/s 4 ilbiriqsi gudahood. Go'aami baaxadda dardargelinta xagasha!

La yaqaan:

Muddada (t) = 4 ilbiriqsi

Xawaaraha xagasha bilowga ah ( ω _o ) = 20 rad/s

Xawaaraha xagasha ugu dambeeya ( ω _t ) = 10 rad/s

La rabay : baaxadda xawaaraha xagasha (α )

Xalka:

ω _t = ω _o + α t

10 = 20 + α (4)

10 – 20 = 4 α

-10 = 4 α

α = -10 / 4

α = – 2.5 rad/s ²

Baaxadda xawaaraha xagasha waa -2.5 rad/s ^2. Calaamad taban macnaheedu waa shaygu wuu yaraanayaa. Dardargelin = xawaaraha xagasha ayaa kordha, hoos u dhac = xawaaraha xagasha ayaa yaraada.

4. Shay ayaa la dedejinayaa 2 ilbiriqsi laga bilaabo 10 rad/s ilaa 2 rad/s ^2. Go'aami xagasha lagu wareegsan yahay shayga!

La yaqaan:

Xawaaraha xagasha bilowga ah ( ω _o ) = 10 rad/s

Dardargelinta xagasha (α ) = 2 rad/s ²

waqtiga u dhexeeya (t) = 2 ilbiriqsi

La rabay: xagal (θ)

Xalka:

θ = ω _o + ½ α t ²

θ = (10)(2) + ½ (2)(2 ² )

θ = 20 + (1)(4) = 20 + 4

θ = 24 raadiyaan

5. Taayirada gaadhigu waxay hoos uga dhacdaa 20 rad/s si ay u nasato ka dib wareega 20 radians. Go'aami baaxadda xawaaraha xagasha ee taayirada!

La yaqaan:

xawaaraha xagasha bilowga ah ( ω _o ) = 20 rad/s

_{xawaaraha xagasha ugu dambeeya} ( ωt ) = 0

Xagasha ( θ ) = 20 radiyaan

La rabay: baaxadda xawaaraha xagasha (α )

Xalka:

ω _t ² = ω _o ² + 2 α θ

0 = 20 ² + 2 α (20)

0 = 400 + 40 α

400 = – 40 α

α = – 400 / 40

α = – 10 rad/s ²

6. Ul PQ oo dhererkeedu yahay 60 cm ayaa ku wareegaysa barta Q sida dhidibka wareegga iyo PQ oo ah radiuska wareegga. Ul PQ ayaa ka soo kabanaya nasashada ilaa 0.3 rad/s ^2. Waa maxay xawaaraha toosan ee barta P ee t = 10 ilbiriqsi, haddii booska bilowga xagasha uu yahay 0.

La yaqaan:

Dhererka usha PQ = gacanka goobada (r) = 60 cm = 60/100 m = 0.60 m

Xawaaraha xagasha bilowga ah (ω _o ) = 0 rad/s

Dardargelinta xagasha (α) = 0.3 rad s ^-2

Booska xagasha bilowga ah (θ _o ) = 0

La Rabay: Xawaaraha toosan (v) ee dhibicda P at t = 10 ilbiriqsi

Xalka:

Xawaaraha xagasha ugu dambeeya 10 ilbiriqsi ka dib:

ω _t = ω _o + α t = 0 rad/s + (0.3 rad s ^-2 )(10 s) = 3 rad/s

Xawaaraha ugu dambeeya ee toosan 10 ilbiriqsi ka dib:

v = r ω = (0.6 m)(3 rad/s) = 1.8 m/s

7. Shay wuxuu ku wareegaa xawaaraha bilowga ah ee 4 rad/s, dardargelinta xagashana waa 0.5 rad/s ^2. Waa maxay xawaaraha shayga 4 ilbiriqsi ka dib.

La yaqaan:

Xawaaraha xagasha bilowga ah (ω _o ) = 4 rad/s

Dardargelinta xagasha (α) = 0.5 rad/s ²

Muddada (t) = 4 ilbiriqsi

La Doonayo: Xawaaraha shayga 4 ilbiriqsi ka dib (ω _t )

Xalka:

ω _t = ω _o + α t

ω _t = 4 + (0.5)(4)

ω _t = 4 + 2

ω _t = 6 rad/s

8. Saacad derbi ah oo dhexroorkeedu yahay 10 cm waxay leedahay saddex irbadood, mid walbana wuxuu muujinayaa saacadaha, daqiiqadaha iyo ilbiriqsiyada. Isbarbardhigga tirada wareegyada irbadda saacadda: irbadda daqiiqadda: irbadda labaad.

A. 1: 3: 180

B. 1: 12: 720

C. 4: 12: 180

D. 4: 12: 720

La yaqaan:

1 saac = 60 daqiiqo

12 saacadood = (12)(60 daqiiqo) = 720 daqiiqo

Xawaaraha xagasha ee irbadda saacadda = 1 kacaan / 12 saacadood = 1 kacaan / 720 daqiiqo

Xawaaraha xagal ee irbadda daqiiqadaha = 1 kacaan / 1 saac = 1 kacaan / 60 daqiiqo

Xawaaraha xagal ee irbadda labaad = 1 wareeg / 1 daqiiqo

La Doonayo: Isbarbardhigga tirada wareegyada irbadda saacadda: irbadda daqiiqadda: irbadda labaad

Xalka:

Isle'egta dhaqdhaqaaqa wareegga:

Xawaaraha xagasha = tirada wareegyada / waqtiga u dhexeeya

Tirada wareegyada = xawaaraha xagasha x waqtiga u dhexeeya

Isla waqtigaas, tusaale ahaan, 1 daqiiqo, inta wareeg ee irbadda saacadda ah, irbadda daqiiqadda ah, iyo irbadda labaad.

Tirada wareegyada irbadda saacadda = xawaaraha xagasha x waqtiga u dhexeeya = (1 kacaanka / 720 daqiiqo)(1 daqiiqo) = 1/720 wareeg

Tirada wareegyada irbadda daqiiqadda = xawaaraha xagasha x waqtiga u dhexeeya = (1 kacaanka / 60 daqiiqo)(1 daqiiqo) = 1/60 wareeg

Tirada wareegyada irbadda labaad = xawaaraha xagal x waqtiga u dhexeeya = (1 kacaanka / 1 daqiiqo)(1 daqiiqo) = 1/1 kacaanka

Isbarbardhigga tiro kacaanno ah:

Tirada wareegyada irbadda saacadda: tirada wareegyada irbadda daqiiqadda: tirada wareegyada irbadda labaad.

1/720: 1/60: 1/1

1/720: 12/720: 720/720

1: 12: 720

Jawaabta saxda ah waa B.

9. Kubad lagu xidhay xarig. Kubaddu waxay u wareegtaa si ay ugu dhaqaaqdo meel wareegsan oo barbar socota dusha sare ee dhulka. Dhaqdhaqaaqan, kubbaddu way degdegaysaa sababtoo ah…..

A. Isjiidjiid hawada

B. Miisaanka kubbadda

C. Xoogga xiisadda

D. Xoogga cufisjiidadka

Xalka:

Sharciga labaad ee dhaqdhaqaaqa Newton wuxuu sheegayaa in shay la dedejiyo haddii uu jiro xoog natiijo leh. Kubaddu waxay ku xiran tahay xarigga, marka xariggu wareego, kubbaddu sidoo kale way wareegtaa. Marka kubbaddu wareegto (kubaddu waxay ku dhaqaaqdaa goobaabin), kubbaddu waxay martaa dardargelinta dhexe. Dhammaan walxaha dhaqaaqaya waa dardargelinta dhexe ee wareegsan. Dardargelinta dhexe waxaa sababa xoogga dhexe . Xoogga dhexe ee kiiskan waa xoogga xiisadda.

Jawaabta saxda ah waa C.

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Shay ayaa ku wareegaya goobaabin iyadoo xawaaraha xagasha ee joogtada ah uu yahay 10 rad/s. Go'aami (a) Xawaaraha xagasha 10 ilbiriqsi ka dib (b) Barkaca xagasha 10 ilbiriqsi ka dib.

La yaqaan:

Xawaaraha xagasha (ω) = 10 rad/s

La doonayo:

(a) Xawaaraha xagasha (ω) 10 ilbiriqsi ka dib.

(b) Xagasha (θ) 10 ilbiriqsi ka dib

Xalka:

(a) Xawaaraha xagasha (ω) ka dib 10 ilbiriqsi

Shay dhaqdhaqaaq wareeg ah oo isku mid ah si xawaaraha xagalku uu u ahaado mid joogto ah, 10 rad/s.

(b) Barakaca xagasha (θ)

Xawaaraha xagasha joogtada ah 10 radian/ilbiriqsi macnaheedu waa shayga qiyaastii 10 radian ilbiriqsikiiba. 10 ilbiriqsi ka dib, shayga qiyaastii 10 x 10 radian = 100 radian.

2. Walax ayaa ku dhaqaaqda goobaabin xawaare joogto ah oo ah 10 m/s. Kala-goysyada goobada = 1 mitir. Go'aami (a) Xawaaraha Walxaha ka dib 5 ilbiriqsi (b) Kala-goysyada Walxaha ka dib 5 ilbiriqsi (c) Dardargelinta Bartamaha.

La yaqaan:

Gacanka goobada (r) = 1 mitir

Xawaaraha walxaha (v) = 10 m/s

Xalka:

(a) Xawaaraha walxaha 5 ilbiriqsi ka dib

Dhaqdhaqaaqa shaygu wuxuu ku jiraa dhaqdhaqaaq wareeg ah oo isku mid ah si xawaaruhu u noqdo mid joogto ah, 10 m/s.

(b) Bararka walxaha 5 ilbiriqsi ka dib

10 mitir/ilbiriqsi macnaheedu waa 1 ilbiriqsi kasta, barokaca walxaha = 10 mitir. 5 ilbiriqsi ka dib, barokaca walxaha = 5 x 10 mitir = 50 mitir.

(c) Dardargelinta bartamaha (a _r )

a _r = v ² / r = 10 ² / 1 = 100 / 1 = 100 m/s ²

3. Kubad ku xiran hal dhinac oo xarig ah, waxaa lagu wareejinayaa goobaabin leh gacan 2 mitir ah oo leh xawaare joogto ah oo ah 60 rpm. Go'aami (a) baaxadda xawaaraha xagasha ka dib 2 ilbiriqsi (b) barokaca xagasha ka dib 1 daqiiqo.

La yaqaan:

Gacanka goobada (r) = 2 mitir

Xawaaraha xagasha (ω) = 60 rpm = 60 wareeg / 1 daqiiqo

= 60 kacaan / 60 ilbiriqsi = 1 kacaan / ilbiriqsi = 2π radians / ilbiriqsi

= 2(3.14) raadiyaan / ilbiriqsi = 6.28 raadiyaan / ilbiriqsi

Xalka:

(a) Xawaaraha xagasha (ω) ka dib 2 ilbiriqsi

Xawaaraha xagasha waa mid joogto ah markaa 2 ilbiriqsi ka dib, xawaaraha xagasha (ω) = 6.28 radians / ilbiriqsi

(b) Barakaca xagasha (θ)

Xawaaraha xagasha = 1 kacaan/ilbiriqsi macnaheedu waa 1 ilbiriqsi kasta, kubaddu waxay la kulantaa 1 kacaan. 60 ilbiriqsi ka dib, kubbaddu waxay dhaqaaqdaa 60 kacaan.

Xawaaraha xagasha = 6.28 radians/ilbiriqsi macnaheedu waa 1 ilbiriqsi kasta, kubaddu waxay ku socotaa xagal dhan 6.28 radians. 60 ilbiriqsi ka dib, kubbaddu waxay dhaqaaqdaa 376.8 radians.

4. Taayir baaskiil wuxuu wareegaa 120 wareeg 60 ilbiriqsi gudahood. Waa maxay xawaaraha xagasha?

Xalka:

(a) wareegyada daqiiqaddii (rpm)

120 wareeg / 60 ilbiriqsi = 120 wareeg / 1 daqiiqo = 120 wareeg / daqiiqo = 120 wareeg

(b) darajo ilbiriqsikiiba ( ^o / s)

1 kacaan = 360 ^o , 120 kacaan = 43200 ^o

120 wareeg / 60 ilbiriqsi = (120)(360 ^o ) / 60 ilbiriqsi = 43200 ^o / 60 ilbiriqsi = 720 ^o / ilbiriqsi

(c) raadiyaan ilbiriqsikiiba (rad/s)

1 kacaan = 6.28 radiyaan

120 wareeg / 60 ilbiriqsi = (120)(6.28) raadiyaan / 60 ilbiriqsi = 753.6 raadiyaan / 60 ilbiriqsi = 12.56 raadiyaan/ilbiriqsi.

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1. Cutubyada xaglaha ee beddelka dhibaatooyinka muunada leh ee xalalka
2. Dhibaatooyinka muunadda iyo xalalka barakaca xagal iyo barokaca toosan
3. Dhibaatooyinka muunada xawaaraha xagasha iyo xawaaraha toosan ee xalalka
4. Muunadaha muunadaha dardargelinta xagasha iyo dardargelinta toosan ee xalalka
5. Dhibaatooyinka muunadaha ee xalalka ah ee dhaqdhaqaaqyada wareegsan ee isku midka ah
6. Muunadaha dhibaatooyinka dardargelinta dhexe ee xalalka
7. Dhaqdhaqaaqyo wareeg ah oo aan isku mid ahayn oo muunad ah oo ku saabsan xalalka

Akhri wax dheeraad ah

1. Kubbad 0. 1 -kg ah, oo ku xiran dhammaadka xarig jiif ah, ayaa lagu wareejinayaa goobaabin 50 cm ah iyo xawaaraha xagasha kubbadda i s 4 rad s ^-1 . Waa maxay baaxadda xoogga dhexe?

La yaqaan:

Cufnaanta (m) = 100 garaam = 100/1000 kg = 1/10 kg = 0.1 kg

Xawaaraha xagasha ( ω) = 4 radiyaan/se xaalad

Gacanka (r) = 50 cm = 50/100 m = 0.5 m

La Raadinayo: Xoogga dhexe

Xalka:

Xoogga dhexe waa xoog saafi ah oo soo saara dardargelinta dhexe :

∑ F = ma _r

∑ F = mv ² /r = m ω ² r

∑ F = xoog saafi ah = xoog dhexe , m = cuf , v = xawaare , ω = xawaare xagal , r = gacan

∑ F = m ω ² r = (0.1)(4) ² (0.5) = (0.1)(16)(0,5) = 0.8 Newtons

2. Kubbadu si siman ayay ugu wareegaysaa goobaabin jiif ah. Haddii xawaaruhu isu beddelo afar jibaar qiimaha bilowga ah, waa maxay baaxadda xoogga dhexe…..

La yaqaan:

Cufnaanta = m

Xawaaraha = v

Xawaaraha bilowga ah = v _o

Gacanka (r) = r

La Raadinayo: Cabbirka xoogga dhexe ee dhexe

Xalka:

3. Qalooc wareegsan oo radius R ah ayaa loo qaabeeyey si gaari ku socda xawaare 12 ms ^–1 uu si ammaan ah ugala gorgortami karo leexashada. Isku-darka is-jiidjiidka taagan ee u dhexeeya gaariga iyo wadada = 0.4. Waa maxay radius R. Dardargelinta cufisjiidadka awgeed ( g ) = 10 ms ^–2.

La yaqaan:

Xawaaraha (v) = 12 m/s

Isku-darka is-jiidjiid aan joogto ahayn ( μs ₎ = 0.4

Dardargelinta cufisjiidadka awgeed (g) = 10 m/s ²

La Raadinayo: Gacan (R)

Xalka:

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1. Cufka iyo miisaanka
2. xoog caadi ah
3. Sharciga labaad ee dhaqdhaqaaqa Newton
4. Xoogga is-qabqabsiga
5. Dhaqdhaqaaq dusha sare oo siman oo aan lahayn xoog is jiidjiid ah
6. Dhaqdhaqaaqa laba jidh oo leh xawaare isku mid ah oo ku yaal dusha sare ee toosan ee qallafsan oo leh xoogga is-jiidjiidka
7. Dhaqdhaqaaqa diyaaradda u janjeerta iyada oo aan lahayn xoog is jiidjiid ah
8. Dhaqdhaqaaqa diyaaradda qallafsan ee u janjeerta oo leh xoogga is jiidjiidka
9. Dhaqdhaqaaqa wiishka
10. Dhaqdhaqaaqa jirka waxaa isku xira fiilooyin iyo boolal
11. Laba jir oo leh xawaare isku mid ah
12. Wareegidda qalooc fidsan - dhaqdhaqaaqa dhaqdhaqaaqa wareegsan
13. Soo koobidda qalooca bangi - dhaqdhaqaaqa dhaqdhaqaaqa wareegsan
14. Dhaqdhaqaaq siman oo goobo jiif ah
15. Xoogga dhexe ee dhaqdhaqaaqa wareegsan ee isku midka ah

Akhri wax dheeraad ah