1. Cufka sanduuqa = 2 kg, dardargelinta cuf-isjiidadka awgeed = 9.8 m/s 2. Soo hel (a) xoogga saafiga ah ee dedejiya sanduuqa hoos u dhigista (b) baaxadda dardargelinta sanduuqa.

Solution

La yaqaan:
Cufnaanta (m) = 2 kg
Dardargelinta cufisjiidadka awgeed (g) = 9.8 m/s 2
Miisaanka (w) = mg = (2)(9.8) = 19.6 Newtons
w x = w sin 30 = (19.6)(0.5) = 9.8 Newtons
w y = w cos 30 = (19.6)(0.5√3) = 9.8√3 Newtons
Xalka:
(a) Shabaqa ce ee dardargeliya sanduuqa
Diyaaradda leexatay waa siman tahay, sidaa darteed ma jirto xoog is jiidjiid ah. Xoogga kaliya ee ku shaqeeya shayga waa w x.
∑ F = w x
∑ F = 9.8 Newton
(b) baaxadda dardargelinta
∑ F = ma
9.8 = (2) a
a = 9.8/2
a = 4.9 m/s 2
Baaxadda xawaaraha waa 4.9 m/s 2 , jihada xawaaraha ayaa hoos u socota.
2. Diyaaradda leexatay waa siman tahay sidaa darteed ma jirto xoog is jiidjiid ah . Cufnaanta shayga waa 3 kg, dardargelinta cufisjiidadka awgeed waa 9.8 m/s 2. Go'aami baaxadda xoogga F haddii (a) shaygu nasto (b) shaygu uu hoos u socdo iyadoo la adeegsanayo dardargelin joogto ah oo ah 2 m/s 2 (c) shaygu uu kor u socdo iyadoo la adeegsanayo dardargelin joogto ah oo ah 2 m/s 2.

Solution

La yaqaan:
Cufnaanta (m) = 3 kg
Dardargelinta cufisjiidadka awgeed (g) = 9.8 m/s 2
Miisaanka (w) = mg = (3)(9.8) = 29.4 Newtons
w x = w sin 30 = (29.4)(0.5) = 14.7 Newtons
w y = w cos 30 = (29.4)(0.5√3) = 14.7√3 Newtons
Xalka:
(a) Baaxadda xoogga F haddii shay uu nasto
Sharciga ugu horreeya ee dhaqdhaqaaqa Newton wuxuu dhigayaa in haddii shay uu nasto, xoogga saafiga ah uu ku dhaqmo shayga uu yahay eber.
∑ F = 0
F – w x = 0
F = w x
F = 14.7 Newton
(b) Baaxadda xoogga F haddii shay uu hoos ugu socdo si joogto ah 2 m/s 2
∑ F = ma
w x – F = ma
14.7 – F = (3)(2)
14.7 – F = 6
F = 14.7–6
F = 8.7 Newton
(c) Baaxadda xoogga F haddii shay uu kor ugu socdo si joogto ah 2 m/s 2
∑ F = ma
F – w x = ma
F – 14.7 = (3)(2)
F – 14.7 = 6
F = 14.7 + 6
F = 20.7 Newton
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- Cufka iyo miisaanka
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