1. Shay 1 kg ah oo xawaare ku socda 5 m/s 2. Qiyaas xoogga saafiga ah ee loo baahan yahay si loo dedejiyo shayga.
La yaqaan:
Cufnaanta (m) = 1 kg
Dardargelinta (a) = 5 m/s 2
La Doonayo : xoog saafi ah (∑F)
Xalka:
Waxaan isticmaalnaa sharciga labaad ee Newton si aan u helno xoogga saafiga ah.
∑ F = ma
∑ F = (1 kg)(5 m/s 2 ) = 5 kg m/s 2 = 5 Newtons
2. Cufka shay = 1 kg, xoogga saafiga ah ∑F = 2 Newtons. Go'aami baaxadda iyo jihada dardargelinta shayga….
La yaqaan:
Cufnaanta (m) = 1 kg
Xoogga saafiga ah (∑F) = 2 Newton
La Doonayo : Cabbirka iyo jihada dardargelinta (a)
Xalka:
a = ∑F / m
a = 2/1
a = 2 m/s 2
Jihada dardargelinta = jihada xoogga saafiga ah (∑F)
3. Cufka walaxda = 2 kg, F 1 = 5 Newtons, F 2 = 3 Newton. Cabbirka iyo jihada dardargelinta waa…
La yaqaan:
Cufnaanta (m) = 2 kg
F1 = 5 Newtons
F2 = 3 Newtons
La Doonayo: Cabbirka iyo jihada dardargelinta (a)
Xalka:
xoog saafi ah:
∑ F = F 1 – F 2 = 5 – 3 = 2 Newtons
Baaxadda dardargelinta:
a = ∑F / m
a = 2/2
a = 1 m/s 2
Jihada dardargelinta = jihada xoogga saafiga ah = jihada F 1
4. Cufka walaxda = 2 kg, F 1 = 10 Newtons, F 2 = 1 Newton. Cabbirka iyo jihada dardargelinta waa…
La yaqaan:
Cufnaanta (m) = 2 kg
F2 = 1 Newtons
F1 = 10 Newtons
F 1x = F 1 cos 60 o = (10)(0.5) = 5 Newtons
La Doonayo : Cabbirka iyo jihada dardargelinta (a)
Xalka:
Xoogga saafiga ah:
∑ F = F 1x – F 2 = 5 – 1 = 4 Newtons
Baaxadda dardargelinta:
a = ∑F / m
a = 4/2
a = 2 m/s 2
Jihada dardargelinta = jihada xoogga saafiga ah = jihada F 1x
5. F 1 = 10 Newtons, F 2 = 1 Newton, m 1 = 1 kg, m 2 = 2 kg. Cabbirka iyo jihada dardargelinta waa…
La yaqaan:
Cufnaanta 1 (m1 ) = 1 kg
Cufnaanta 2 (m2 ) = 2 kg
F1 = 10 Newtons
F2 = 1 Newtons
La Doonayo : Cabbirka iyo jihada dardargelinta (a)
Xalka:
Xoogga saafiga ah:
∑ F = F 1 – F 2 = 10 – 1 = 9 Newtons
Baaxadda dardargelinta:
a = ∑F / (m 1 + m 2 )
a = 9 / (1 + 2)
a = 9/3
a = 3 m/s 2
Jihada dardargelinta = jihada xoogga saafiga ah = jihada F 1
6.
Baloog 40-kg ah oo lagu dardar galiyay xoog dhan 200 N. Dardargelinta baloogga waa 3 m/ s 2. Go'aami baaxadda xoogga is-jiidjiid ee uu la kulmay baloogga.
A. 15 N
B. 40 N
C. 43 N
D. 80 N
La yaqaan:
Cufnaanta (m) = 40 kg
Xoogga (F) = 200 N
Dardargelinta (a) = 3 m/s 2
La Raadinayo: Xoogga is-qabsiga (F g )
Xalka:
Isle'egta sharciga labaad ee dhaqdhaqaaqa Newton
∑ F = ma
∑ F = xoog saafi ah, m = cuf, a = dardargelin
Jihada xoogga F ee dhanka midig, jihada xoogga is jiidjiidka ee dhanka bidix (jihada xoogga is jiidjiidka ayaa ka soo horjeeda jihada dhaqdhaqaaqa shayga).
Dooro dhanka midig sida togan iyo dhanka bidix iyo dhinaca taban.
∑ F = ma
F – F g = ma
200 – F g = (40)(3)
200 – F g = 120
F g = 200 – 120
F g = 80 Newton
Jawaabta saxda ah waa D.
7. Baloogga A oo leh cuf dhan 100 garaam oo dul saar baloogga B oo leh cuf dhan 300 garaam, ka dibna baloogga B waxaa lagu riixaa xoog dhan 5 N oo si toosan kor ugu socda. Go'aami xoogga caadiga ah ee baloogga B ku sameeyo baloogga A.
A. 1 N
B. 1.25 N
C. 2 N
D. 3 N
La yaqaan:
Xoogga (F) = 5 Newton
Cufka baloogga A (m A ) = 100 garaam = 0.1 kg
Cufka baloogga B (m B ) = 300 garaam = 0.3 kg
Dardargelinta cufisjiidadka (g) = 10 m/s 2
Miisaanka baloogga A (w A ) = (0.1 kg)(10 m/s 2 ) = 1 kg m/s 2 = 1 Newton
Miisaanka baloogga B (w B ) = (0.3 kg)(10 m/s 2 ) = 3 kg m/s 2 = 3 Newtons
La Doonayo: Xoog caadi ah oo ay sameeyaan baloogga B si ay u joojiyaan A
Xalka:
Waxaa jira dhowr awoodood oo ka shaqeeya labada baloog, sida ku cad sawirka.
F = xoog riixid (ku dhaqan baloogga B)
w A = miisaanka baloogga A (ku dhaqan baloogga A)
w B = miisaanka baloogga B (ku dhaqan baloogga B)
N A = xoog caadi ah oo uu ku sameeyo baloogga B baloogga A (Ku dhaqan baloogga A)
N A ' = xoog caadi ah oo ay sameeyaan baloogga A ee baloogga B (Ku dhaqan baloogga B)
Ku dabaq sharciga labaad ee dhaqdhaqaaqa Newton labada baloog:
∑ F = ma
F – w A – w B + N A – N A ' = (m A + m B ) a
N A iyo N A ' waa awoodo fal-celin ficil ah oo leh isla baaxad laakiin ka soo horjeeda jihada sidaas darteed waa laga saarayaa isla'egta.
F – w A – w B = (m A + m B ) a
5 – 1 – 3 = (0.1 + 0.3) a
5 – 4 = (0.4) a
1 = (0.4) a
a = 1/0.4
a = 2.5 m/s 2
Ku dabaq sharciga labaad ee mooshinka Newton baloogga A:
∑ F = ma
N A – w A = m A a
N A – 1 = (0.1)(2.5)
NA – 1 = 0.25
NA = 1 + 0.25
NA = 1.25 Newtons
Jawaabta saxda ah waa B.
8. Shay miisaankiisu yahay 4 N oo ay taageerayaan xadhig iyo jiid. Xoogga 2 N wuxuu ku shaqeeyaa baloogga iyo dhammaadka xadhigga oo ay jiidaan xoog 9 N ah. Go'aami ficillada xoogga saafiga ah ee shayga X.
A. 3 N kor
B. 4 N hoos
C. 9 N kor
D. 9 N hoos
La yaqaan:
Miisaanka X (w X ) = 4 Newton
Xoogga jiidista (F x ) = 2 Newton
Xoogga xiisadda (F T ) = 9 Newtons
La Raadinayo: Xoogga saafiga ah wuxuu ku dhaqmaa shayga
Xalka:
Awoodo kor u kacsan oo ku shaqeeya shayga
Xoogga xiisadda wuxuu leeyahay isla baaxadda dhammaan qaybaha xarigga. Markaa xoogga xiisaddu waa 9 N.
Awoodaha toosan ee hoos u socda ee ku shaqeeya shayga
Waxaa jira laba awoodood oo ku shaqeeya shayga X, labada awoodoodna waxay si toosan hoos ugu jiraan, qaybta jiifa ee miisaanka w x iyo qaybta jiifa ee xoogga F x.
Falka xoogga saafiga ah ee shayga
F T – w X – F x = 9 – 4 – 2 = 9 – 6 = 3
Xoogga saafiga ah ee ku shaqeeya shayga X waa 3 Newtons, oo si toosan kor ugu socda.
Jawaabta saxda ah waa A.
9. Shay marka hore ku nasanaya dusha siman ee siman. Xoogga 16 N wuxuu ku shaqeeyaa shayga si shaygu u dardargeliyo 2 m/s 2. Haddii shayga isku midka ah uu ku nasto dusha toosan ee qallafsan sidaas darteed xoogga is-jiidjiidku wuxuu ku shaqeeyaa shayga 2 N, markaa go'aami dardargelinta shayga haddii xoogga isku midka ah ee 16 N uu ku dhaqmo shayga.
A. 1.75 m/s 2
B. 1.50 m/s 2
Q. 1.00 m/s 2
D. 0.88 m/s 2
La yaqaan:
Xoogga (F) = 16 Newtons = 16 kg m/s 2
Dardargelinta (a) = 2 m/s 2
Xoogga is-jiidjiidashada (F fric ) = 2 Newtons = 2 kg m/s 2
La rabay: Dardargelinta Shayga?
Xalka:
Dusha siman ee siman (aan lahayn xoog is jiidjiid ah):
ΣF = ma
F = ma
16 = (m) 2
m = 16 / 2
m = 8 kg
Cufka shayga waa 8 kiilo.
Dusha sare ee toosan oo qallafsan (waxaa jira xoog is jiidjiid ah):
ΣF = ma
F – F fric = ma
16 – 2 = 8 a
14 = 8 a
a = 14/8
a = 1.75 m/s 2
Xawaaraha shayga waa 1.75 m/s 2.
Jawaabta saxda ah waa A.
10. Tom iyo Andrew waxay shay ku riixaan dabaqa siman. Tom wuxuu shayga ku riixayaa xoog dhan 5.70 N. Haddii cufka shaygu yahay 2.00 kg oo dardargelinta shaygu ay tahay 2.00 ms -2 , markaa go'aami baaxadda iyo jihada ficilka xoogga ee Tom.
A. 1.70 N iyo jihadeedu waa liddi ku ah xoogga uu sameeyay Andre.w
B. 1.70 N iyo jihadeedu waxay la mid tahay xoogga uu Andrew sameeyay
C. 2.30 N iyo jihadeedu waa liddi ku ah xoogga uu Andrew sameeyay.
D. 2.30 N iyo jihadeedu waxay la mid tahay xoogga uu Andrew sameeyay.
La yaqaan:
Xoogga riixitaanka oo uu sameeyay Andrew (F 1 ) = 5.70 Newton
Cufka shayga (m) = 2.00 kg
Dardargelinta (a) = 2.00 m/s 2
La rabay: Weynaanta iyo jihada xoogga uu sameeyay Tom (F 2 )?
Xalka:
Ku dhaqan sharciga labaad ee dhaqdhaqaaqa Newton:
∑ F = ma
F 1 + F 2 = ma
5.70 + F 2 = (2)(2)
5.70 + F 2 = 4
F 2 = 4 – 5.70
F 2 = – 1.7 Newton
Calaamadda laga jaray waxay muujisay in (F 2 ) ay ka soo horjeeddo ficilka riixitaanka ee Andrew (F 1 ).
Jawaabta saxda ah waa A.
11. Haddii cufka baloogga uu isku mid yahay, jaantuskee ayaa muujinaya dardargelinta ugu yar?
Solution
Xoogga saafiga ah A:
ΣF = 4 N + 2 N - 3 N = 6 N - 3 N = 3 Newton, bidix
Xoogga saafiga ah B:
ΣF = 2 N + 3 N - 4 N = 5 N - 4 N = 1 Newton, dhanka midig
Xoogga saafiga ah C:
ΣF = 4 N + 3 N - 2 N = 7 N - 2 N = 5 Newton, dhanka midig
Xoogga saafiga ah D:
ΣF = 3 N + 4 N + 2 N = 9 Newton, dhanka midig
Isle'egta sharciga labaad ee Newton:
ΣF = ma
a = ΣF / m
a = dardargelin, ΣF = xoog saafi ah, m = cuf
Iyada oo ku saleysan qaacidada kor ku xusan, dardargelinta (a) waxay si toos ah ugu dhigantaa xoogga saafiga ah (ΣF) waxayna si liddi ku ah u dhigantaa cufka (m). Haddii cufka shay uu isku mid yahay, xoogga ka dhasha ayaa sii kordhaya, dardargelinta ayaa sii badanaysa ama xoogga ka dhasha ayaa sii yaraanaya, dardargelintu way sii yaraanaysaa.
Iyada oo ku saleysan xisaabinta kor ku xusan, xoogga saafiga ugu yar waa 1 Newton sidaa darteed dardargelintu sidoo kale waa kan ugu yar.
Jawaabta saxda ah waa B.
12. Xoogag qaar ayaa ku dhaqma shay miisaankiisu yahay 20 kg, sida ka muuqata sawirka hoose.
Go'aami xawaaraha shayga.
La yaqaan:
Cufka shayga (m) = 20 kg
Xoogga saafiga ah (ΣF) = 25 N + 30 N - 15 N = 40 N
La Doonayo: Dardargelinta shay
Xalka:
Dardargelinta Shayga waxaa lagu xisaabiyay iyadoo la adeegsanayo isle'egta sharciga labaad ee Newton:
ΣF = ma
a = ΣF / m = 40 N / 20 kg = 2 N/kg = 2 m/s 2
13. Weedhkee hoos ku qoran ayaa qeexaysa sharciga saddexaad ee Newton?
(1) Rakaabkii ayaa hore u riixay markii basku si lama filaan ah u bareegay
(2) Buugaagta warqadda ku qoran ma dhacayaan marka warqadda si dhakhso ah loo jiido
(3) Marka la ciyaarayo skateboard-ka marka cagtu dhulka dib u riixdo, skateboard-ku wuu hore u simbiriirixan doonaa
(4) O ars gadaal loo riixay, doonyaha ayaa hore u socda
Xalka:
(1) Sharciga ugu horreeya ee Newton
(2) Sharciga ugu horreeya ee Newton
(3) Sharciga saddexaad ee Newton
(4) Sharciga saddexaad ee Newton
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- Cufka iyo miisaanka
- xoog caadi ah
- Sharciga labaad ee dhaqdhaqaaqa Newton
- Xoogga is-qabqabsiga
- Dhaqdhaqaaqa dusha sare ee jiifka ah iyada oo aan lahayn xoog is jiidjiid ah
- Dhaqdhaqaaqa laba jidh oo leh xawaare isku mid ah oo ku yaal dusha sare ee toosan ee qallafsan oo leh xoogga is-jiidjiidka
- Dhaqdhaqaaqa diyaaradda u janjeerta iyada oo aan lahayn xoog is jiidjiid ah
- Dhaqdhaqaaqa diyaaradda qallafsan ee u janjeerta oo leh xoogga is jiidjiidka
- Dhaqdhaqaaqa wiishka
- Dhaqdhaqaaqa jirka waxaa isku xira fiilooyin iyo boolal
- Laba jir oo leh xawaare isku mid ah
- Wareegidda qalooc fidsan - dhaqdhaqaaqa dhaqdhaqaaqa wareegsan
- Soo koobidda qalooca bangi - dhaqdhaqaaqa dhaqdhaqaaqa wareegsan
- Dhaqdhaqaaq siman oo goobo jiif ah
- Xoogga dhexe ee dhaqdhaqaaqa wareegsan ee isku midka ah
