Ballaarinta aagga - dhibaatooyinka iyo xalalka

1. Heerkulka 20 o C, dhererka xaashi bir ah waa 50 cm ballaciisuna waa 30 cm. Haddii isku-dhafka ballaarinta toosan ee birta uu yahay 10 -5 o C -1 , go'aami isbeddelka aagga iyo aagga ugu dambeeya ee 60 o C.

La yaqaan:

Heerkulka bilowga ah (T 1 ) = 20 o C

Heerkulka kama dambaysta ah (T2 ) = 60 o C

Isbeddelka heerkulka ( ΔT ) = 60 o C – 20 o C = 40 o C

Bedka bilowga ah (A 1 ) = dhererka x ballaca = 50 cm x 30 cm = 1500 cm 2

Isugeynta ballaarinta toosan ee birta ( α) = 10 -5 o C -1

Isugeynta ballaarinta aagga ee birta ( β) = 2α = 2 x 10 -5 o C -1

La Doonayo: Isbeddelka aagga ( ΔA )

Xalka:

Isbeddelka aagga ( ΔA ):

ΔA = β A 1 ΔT

ΔA = ( 2 x 10 -5 o C -1 )(1500 cm 2 )(40 o C)

ΔA = (80 x 10 -5 ) (1500 cm 2 )

ΔA = 1 20,000 x 10 -5 cm 2

ΔA = 1. 2 x 10 5 x 10 -5 cm 2

ΔA = 1.2 cm 2

Aagga ugu dambeeya ( A 2 ):

A 2 = A 1 + ΔA

A 2 = 1500 cm 2 + 1. 2 cm 2

A 2 = 1501. 2 cm 2

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2. Heerkulka 30 ° C, bedka xaashida aluminiumka waa 40 cm 2 , isku-dhafka ballaarinta toosanna waa 24 x 10 -6 / o C. Go'aami heerkulka kama dambaysta ah haddii aagga kama dambaysta ahi yahay 40.2 cm 2.

La yaqaan:

Heerkulka bilowga ah (T 1 ) = 30 o C

Isugeynta ballaarinta toosan ( α ) = 24 x 10 -6 o C -1

Isugeynta ballaarinta aagga ( β) = 2a = 2 x 24 x 10 -6 o C -1 = 48 x 10 -6 o C -1

Bedka bilowga ah (A 1 ) = 40 cm 2

Bedka ugu dambeeya (A 2 ) = 40.2 cm 2

Isbeddelka aagga ( ΔA) = 40.2 cm 2 – 40 cm 2 = 0.2 cm 2

La Rabay: Go'aami heerkulka kama dambaysta ah ( T2 )

Xalka:

Qaacidada isbeddelka aagga ( ΔA) :

ΔA = β A 1 Δ T

Heerkulka kama dambaysta ah (T2 ) :

ΔA = β A 1 (T 2 – T 1 )

0.2 cm2 = (48 x) 10-6 oC-1(40 cm)2)(T2 - 30oC)

0.2 = (1920 x 10 -6 ) (T 2 – 30 )

0.2 = (1.920 x 10 -3 ) (T 2 – 30)

0.2 = (2 x 10 -3 ) (T 2 – 30)

0.2 / (2 x 10 -3 ) = T 2 – 30

0.1 x 10 3 = T 2 – 30

1 x 10 2 = T 2 – 30

100 = T 2 – 30

100 + 30 = T 2

T 2 = 130

Heerkulka kama dambaysta ah = 130 o C

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3. Gacanka giraanta ee 20 o C waa 20 cm. Haddii gacanka ugu dambeeya ee 100 o C uu yahay 20.5 cm, go'aami isku-dhafka ballaarinta aagga iyo isku-dhafka ballaarinta toosan…

La yaqaan:

Heerkulka bilowga ah (T 1 ) = 30 o C

Heerkulka kama dambaysta ah (T2 ) = 100 o C

Isbeddelka heerkulka ( ΔT ) = 100 o C – 30 o C = 70 o C

Gacanka bilowga ah (r 1 ) = 20 cm

Gacanka ugu dambeeya (r 2 ) = 20.5 cm

La Doonayo: Isugeynta ballaarinta aagga ( β )

Xalka:

Bedka bilowga ah (A 1 ) = π r 1 2 = (3.14)(20 cm) 2 = (3.14)(400 cm 2 ) = 1256 cm 2

Bedka ugu dambeeya (A 2 ) = π r 2 2 = (3.14)(20.5 cm) 2 = (3.14)(420.25 cm 2 ) = 1319.585 cm 2

Isbeddelka aagga ( ΔA) = 1319.585 cm 2 – 1256 cm 2 = 63.585 cm 2

Qaacidada isbeddelka aagga ( ΔA) :

ΔA = β A 1 ΔT

Isugeynta ballaarinta aagga:

ΔA = β A 1 ΔT

63.585 cm 2 = b (1 256 cm 2 )(70 o C)

63.585 = b ( 87,920 o C)

β = 63.585 / 87,920 o C

β = 0.00072 / o C

β = 7.2 x 1 0 -4 / o C

β = 7.2 x 1 0 -4 o C -1

Isugeynta ballaarinta toosan ( α ):

β = 2 α

α = β/2

α = (7.2 x 1 0 -4 ) / 2

α = 3.6 x 1 0 -4 o C -1

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  1. Beddelidda miisaanka heerkulka
  2. Balaadhinta toosan
  3. Ballaarinta aagga
  4. Ballaarinta mugga
  5. Heat
  6. U dhigma farsamo ee kulaylka
  7. Awood gaar ah oo kul iyo kulayl ah
  8. Kulayl qarsoon, kulayl isku-dhafan, kulayl uumi-baxa
  9. Ilaalinta tamarta ee wareejinta kulaylka

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