Equation yekukakavadzana kwetambo

Mibvunzo mitatu nezve equation yekumanikidzwa kwetambo

1. Mufananidzo uri pazasi unoratidza mabhuroko matatu, anoti A, B naC ari panzvimbo yakatsetseka yakatwasuka. Kana huremu A = 1 kg, huremu B = 2 kg uye huremu C = 2 kg uye F = 10 N, saka sarudza chiyero chekumanikidzwa mutambo pakati paA naB nekumanikidzwa mutambo pakati paB naC.

Anozivikanwa:

Huremu hweA (m)_A) = 1 kg

Huremu B (m)_B) = 2 kg

Huremu hweC (m_C) = 2 kg

Simba rekudhonza (F) = 10 N

Kuda: T_AB :T_BC

Solution:

Verenga kukurumidza kwehurongwa uchishandisa fomura yaNewton's Second Law:

ΣF = ma

F = (m_A +m_B +m_C) a

10 = (1 + 2 + 2) a

10 = 5 a

a = 10 / 5

a = 2 m/s²

Shandisa fomura yekukweshana kwetambo kuverenga T_AB

ΣF = ma

T_AB = m_A a = 1 (2) = 2 Newton

Shandisa fomura yekukweshana kwetambo kuverenga T_BC

ΣF = ma

T_BC = (m_A +m_B) a = (1 + 2) (2) = (3)(2) = 6 Newtons

2. Chinhu A chine huremu hwe6 kg uye chinhu B chine huremu hwe3 kg zvakabatanidzwa netambo sezvakaratidzwa. Kana coefficient of friction iri 0.3 uye g = 10 m/s², sarudza kukurumidza kwechinhu uye kusimba kwetambo dzebhuroko rega rega.

Inozivikanwa:

Huremu hwechinhu A (m)_A) = 6 kg

Huremu hwechinhu B (m)_B) = 3 kg

Kukweshana kwebhokisi A (µ)_k= = 0.3

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Huremu hwebhuroko A (w)_A) = m_A g = (6)(10) = 60 N

Simba rakajairika pabhuroko A (N)_A) = w_A = 60N

Huremu hwebhuroko B (w)_B) = m_B g = (3)(10) = 30 N

Kuda: Kukurumidza kwehurongwa (a) uye kushushikana kwetambo (T)

Solution:

Verenga simba rekukweshana rekinetic kureva simba rekukweshana kana bhuroko A richifamba:

F_k = µ_k N_A = (0,3)(60) = 18 Newton

Verenga kukurumidza kwesystem (a):

ΣF = ma

wB – F_k = (m_A +m_B) a

30 – 18 = (6 + 3) a

12 = 9 a

a = 12 / 9 = 1,3 m/s²

Verenga kusimba kwetambo iri pabhuroko A (T)_A):

ΣF = ma

T_A - F_k = (m_A) a

T_A – 18 = (6)(1,3)

T_A - 18 = 7,8

T_A = 7,8 + 18 = 25,8 Newtons

Verenga kumanikidzwa kwetambo padanda B (T)_B):

ΣF = ma

w_B - T_B = m_B (A)

30 - T_B = 3 (1,3)

30 - T_B = 3,9

T_B = 30 - 3,9

T_B = 26,1 Newton

3. Zvinhu zviviri A naB zvine huremu hwe5 kg ne3 kg zvakabatana nepulley isina kukweshana. Simba P rinoiswa papulley richikwira kumusoro. Kana mabhuroko ese ari maviri pakutanga akamira pasi, chii chinonzi kukurumidza kwebhuroko A, kana hukuru hweP huri 60 N?

Tarisawo kumanikidzwa kuri mutambo pamabhuroko A naB.

Inozivikanwa:

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Huremu hweA (m)_A) = 5 kg

Huremu hwebhuroko A (w)_A) = m_A g = (5)(10) = 50 Newton

Huremu B (m)_B) = 3 kg

Huremu hwebhuroko B (w)_B) = m_B g = (3)(10) = 30 Newton

Simba P = 60 N

Kuda: Kukurumidzisa kwehurongwa hwematanda A naB (a) uye kushushikana kwetambo padanda A (T)_A) uye danda B (T)_B)

Solution:

Verenga kukurumidza kwehurongwa uchishandisa fomura yeMutemo wechipiri waNewton.

ΣF = ma

w_A - w_B = (m_A +m_B) a

50 – 30 = (5 + 3) a

20 = 8 a

a = 20 / 8

a = 2,5 m/s²

Shandisa fomura yekumanikidza simba kuti uverenge kumanikidzwa kuri mutambo

Kushushikana kwetambo pabhuroko A:

ΣF = ma

w_A - T_A = m_A a

50 - T_A = 5 (2,5)

50 - T_A = 12,5

T_A = 50 – 12,5 = 37,5 Newton

Kumanikidzwa kwetambo pabhuroko B:

ΣF = ma

T_B - w_B = m_B a

T_B – 30 = 3 (2,5)

T_B - 30 = 7,5

T_B = 7,5 + 30 = 37,5 Newtons