Equation yesimba rakajairika

Mibvunzo mitatu pamusoro peNormal force equation

1. Bhokisi rine huremu hwe5 kg. Kana g = 10 m/s ² , tsvaga:

a) huremu hwebhokisi

b) simba rakajairika kana bhokisi rakaiswa padenga rakati sandara

c) simba rakajairika kana bhokisi rakagara padenderedzwa rakanamira rinoumba kona ye30 ^o kusvika yakatwasuka

Anozivikanwa:

Huremu hwebhuroko (m) = 5 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: w, N mundege uye N mugomo

Solution:

a) Kurema kwedanda

w = mg = 5 (10) = 50 Newton

b) Simba rakajairika kana bhokisi riri mudenga rakati sandara

N = w = 50 Newton

c) Simba rakajairika kana bhokisi riri padivi rakanamira

N = w _y = w cos θ = 50 (cos 30) = 50 (½ √3) = 25√3 Newtons

2. Chirauro che 120 gram chinodzvanywa chakamira pabhodhi nesimba re 15 N. Chii chinoshanda pachirauro chacho?

Inozivikanwa:

Huremu (m) = magiramu 120 = 0.12 kg

Simba (F) = 15 Newton

Zvinodiwa: Simba rakajairika

Solution:

Simba rakajairika = kusundidzira = 15 Newtons

3. Mvura yekunwa iri mubhodhoro ichiri mubhokisi inodhonzwa nesimba reF = 200 N rinoumba kona ye37 ^o ine horizontal. Sin 37 ^o = 0.6. Huremu hwekadhibhodhi nezviri mukati maro huri 20 kg. Kana coefficient yestatic friction pasi iri 0.5 uye coefficient ye kinetic friction pasi iri 0.2, sarudza simba rakajairika rinoshanda pakadhibhodhi.

Anozivikanwa:

Simba rekudhonza (F) = 200 N

Chivi 37 = 0,6

Fy = F chivi 37 = (200) (0,6) = 120 N

Huremu hwekadhibhodhi (m) = 20 kg

Kurema kwekadhibhodhi (w) = mg = (20)(10) = 200 N

Zvinodiwa: Simba rakajairika pakadhibhodhi (N)

Solution:

Verenga simba rakajairika uchishandisa fomura yesimba rakajairika:

N = w – F _y = 200 – 120 = 80 Newtons