Kuchengetedza simba remakanika panzvimbo dzakakombama - matambudziko nemhinduro
1. Kana kumhanya kwebhora panzvimbo A kuri 6 m/s, kumhanya kwebhora panzvimbo B kuri √92 m/s, uye kukurumidza nekuda kwegiravhiti kuri g = 10 m/s 2. Ndeipi kukwirira kwepoindi B (h)?
Zvinozivikanwa:
Kumhanya kwebhora panzvimbo A (v)A) = 6 m/s
Kumhanya kwebhora panzvimbo B (v B ) = √92 m/s
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Kureba kweA (h A ) = 5.6 metres
Kureba kweB (h B ) = h
Zvinodiwa: Kureba kwepoindi B (h)
Solution:
Simba rekutanga remakanika = simba regiravhiti
Papoindi A, kumhanya kwebhora = 0, saka simba rekufamba kwebhora = 0. KE = 1/2 mv 2 = 1/2 m (0) = 0.
Bhora rakareba mamita 5.6 saka rine simba rekukwevera pasi. Simba rekukwevera pasi : PE = mgh = m (10)(5.6) = 56 m
Simba rekutanga remakanika = simba regiravhiti + simba rekinetic = 56 m + 0 = 56 m
Simba rekupedzisira remakanika = simba regiravhiti + simba rekinetic
Papoindi B, kukwirira kwebhora i h. Simba rekukwevera pasi: PE = mgh = m (10) h = 10 mh
Simba rekufamba kwebhora: KE = 1/2 mv 2 = 1/2 m (√92) 2 = 1/2 m (92) = 46 m
Simba rekupedzisira remakanika = simba regiravhiti + simba rekinetic = 10 mh + 46 m = m (10 maawa + 46)
Nheyo yekuchengetedza simba remakanika:
Simba rekutanga remakanika = simba rekupedzisira remakanika
56 m = m (maawa gumi + 46)
56 = maawa gumi + 46
56 - 46 = maawa gumi
10 = maawa makumi maviri
h = 10/10
h = mamita 1
2.
Kana velocity yekutanga = 0, kuwedzera simba nekuda kwegiravhiti = 10 m/s 2 , saka chii chinonzi kumhanya pakukwirira kweB.
Zvinozivikanwa:
Kumhanya kwekutanga (v o ) = 0
Kureba kwekutanga (h o ) = 50 m – 10 m = 40 m
Kureba kwekupedzisira (h t ) = 0
Kukurumidza kunokonzerwa negiravhiti (g) = 10 ms -2
Kudiwa: Kumhanya kwekupedzisira (v t )
Solution:
Kuchinja kwesimba rekinetic:
ΔKE = 1/2 m (v t 2 – v o 2 ) = 1/2 m (v t 2 – 0) = 1/2 mv t 2
Kuchinja kwesimba ringangowanikwa:
ΔPE = mg (h t – ho ) = m (10)(0-40) = m (10)(-40) = – 400 m
Verenga kumhanya kwekupedzisira (v t ) uchishandisa equation yenheyo yekuchengetedza simba remakanika :
0 = ΔKE + ΔPE
0 = 1/2 mv t 2 - 400 m
1/2 mv t 2 = 400 m
1/2 v t 2 = 400
v t 2 = 2 (400)
v t = √(400)(2)
v t = 20√2 m/s
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