Ugesi oqinile - izinkinga nezixazululo

Ugesi oqinile - izinkinga nezixazululo

Amandla kagesi

1. Iphuzu A ensimini kagesi . Ubukhulu bensimu kagesi endaweni A = 0.5 NC -1 . Uma kufakwa ishaja engu-0.25-C endaweni A, pho iyini amandla kagesi asetshenziswa ekushajeni.

Kwaziwa:

Insimu kagesi endaweni A = 0.5 NC -1

Ukushaja kukagesi endaweni A = 0.25 C

Kufunwa: Amandla kagesi

Isixazululo:

F = q E

F = (0.25 C)(0.5 NC -1 )

F = 0.125N

2. Amashaja amabili angu-5 C no-4 C ahlukaniswe ngebanga lamamitha angu-3. Uma i-Coulomb constant ingu-9 × 109 Nm2 C-2, ubukhulu bamandla kagesi abhekana nokushaja okubili bungakanani?

Kwaziwa:

Ishaja 1 (q)1) = 5 C

Ishaja 2 (q)2) = 4 C

Ibanga phakathi kokushaja 1 nokushaja 2 (r) = amamitha angu-3

I-coulomb's constant (k) = 9 × 109 Nm2 C-2

Kufunwa: Ubukhulu bamandla kagesi (F)

Isixazululo:

Ugesi oqinile - izinkinga nezixazululo 1

3. Ishaja kagesi +q1 = 10 μC ; +q2 = 20 μC; kanye no-q3 zihlukanisiwe, njengoba kuboniswe esithombeni esingezansi. Amandla kagesi asebenza ekushajeni q2 = 0, pho-ke iyini inkokhelo ka-q3.

Ugesi oqinile - izinkinga nezixazululo 2

Kwaziwa:

Ishaja 1 (q 1 ) = 10 μC = 10 x 10 -6 C

Ishaja 2 (q 2 ) = 20 μC = 20 x 10 -6 C

Kufunwa: Iyini icala lika-q3

Isixazululo:

Kunezenzo ezimbili zamandla ku-+q2.

Amandla okuqala amandla axoshayo phakathi kokushaja +q1 futhi ukhokhise +q2 lokho kungu-F12, ngakwesokudla.

Amandla kagesi aphelele asebenza ku-q2 = 0 bese kuba u-q3 kumele kube negative.

Amandla esibili amandla akhangayo phakathi kokushaja +q2 kanye no-q3 lokho kungu-F23, ngakwesobunxele.

Womabili la mandla asebenza ku-q2, zinobukhulu obufanayo kodwa zinohlangothi oluphambene.

Ugesi oqinile - izinkinga nezixazululo 3

Amandla e-Net asebenza ku-+q2 = 0.

Ugesi oqinile - izinkinga nezixazululo 4

4. Izindleko ezintathu q1, q, kanye no-q2 zisemgqeni. Uma u-q = 5.0 μC kanye no-d = 30 cm, khona-ke ubukhulu kanye nesiqondiso samandla kagesi kusebenza kanjani ekushajeni u-q.

Ugesi oqinile - izinkinga nezixazululo 5

Kwaziwa:

Ishaja 1 (q)1) = 30 μC = 30 x 10-6 C

Ishaja 2 (q)2) = 60 μC = 60 x 10-6 C

Ishaja 3 (q) = 5 μC = 5 x 10-6 C

Ibanga eliphakathi kuka-q1 kanye no-q = d

Ibanga eliphakathi kuka-q2 futhi u-q = 2d

d = 30 cm = 0.3 amamitha

d 2 = (0.3) 2 = 0.09

I-coulomb's constant (k) = 9 x 109 N m2 C-2

Kufunwa: Ubukhulu kanye nesiqondiso samandla kagesi kusebenza ngokushaja kagesi

Isixazululo:

Kunamandla amabili asebenza ku-q okungu-F1 ngakwesokudla (u-q no-q1 banethemba ngakho-ke F1 kude no-q no-q1) kanye no-F2 ngakwesobunxele (u-q no-q2 banethemba ngakho-ke F2 kude no-q no-q2). Okokuqala kubalwe u-F1 noF2.

Ugesi oqinile - izinkinga nezixazululo 6Amandla aphelele angama-7.5 Newtons. Isiqondiso samandla aphelele = isiqondiso sika-F1, iphuzu elingakwesokudla ukuze ushaje u-q2.

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Inkambu kagesi

5. Akuvamile okuphakathi ukukhokha u-q usephuzwini lika-P ensimini kagesi Okhiqizwayo ngokushaja (+) ukuze ithole amandla angu-0.05 N maqondana nokushaja. Uma ubukhulu kagesi field at iphuzu P lingu-2 x 10-2 NC-1, khona-ke kuyini ubukhulu kanye nohlobo lweshaja olubangela electric inkambu.

Kwaziwa:

Amandla kagesi (F) = 0.05 N

Insimu kagesi (E) = 2 x 10 -2 NC -1 = 0.02 NC -1

Okufunayo: Ubukhulu kanye nohlobo lweshaja kagesi

Isixazululo:

Ishaja kagesi ibalwa kusetshenziswa ifomula eveza ubudlelwano phakathi kwamandla kagesi (F), insimu kagesi (E) kanye neshaja kagesi (q):

F = q E

q = F / E = 0.05 N / 0.02 NC –1 = 2.5 Ama-Coulomb

Ishaja u-q ibhekana namandla kagesi aqonde ekushajeni (+) okukhiqiza insimu kagesi, ngakho-ke ishaja u-q ayilungile.

6. Amashaja u-A no-B ahlukaniswe ngebanga lamamitha angu-4. Iphuzu C liphakathi kwamashaja womabili, imitha eli-1 ukusuka endaweni u-A. Uma u-QA = –300 μC, QB = 600 μC. 1/4 π ε0 = 9 × 109 N m2 C– 2, bese kuba ubukhulu bensimu kagesi endaweni C ekhiqizwa yizo zombili iziteshi.

Kwaziwa:

Ibanga phakathi kwezindleko A no-B (r)AB) = amamitha angu-4

Ibanga phakathi kwephuzu C kanye nokushaja u-A (r)AC) = 1 amamitha

Ibanga phakathi kwephuzu C kanye neshaja B (r)BC) = amamitha angu-3

Inkokhelo A (q)A) = –300 μC = -300 x 10-6 C = -3 x 10-4 I-Coulomb

Ishaja B (q)B) = 600 μC = 600 x 10-6 C = 6 x 10-4 I-Coulomb

Okungaguquki (k) = 9 × 109 N m2 C-2

Kufunwa: Insimu kagesi endaweni C

Isixazululo:

Insimu kagesi ekhiqizwa yishaja A endaweni C:

Ugesi oqinile - izinkinga nezixazululo 7

Shaja A ayilungile kangangokuthi isiqondiso sensimu kagesi sikhomba ekushajeni u-A futhi sibheke kude nokushaja u-B (ngakwesobunxele).

Insimu kagesi ekhiqizwa yishaja B endaweni C:

Ugesi oqinile - izinkinga nezixazululo 8

Ishaja B ilungile kangangokuthi indlela insimu kagesi eqondiswa ngayo ikude neshaja B futhi ikhomba ukushaja u-A (ngakwesobunxele).

Umphumela wensimu kagesi endaweni A:

E = E A + E B

E = (27 x 10 5 ) + (6 x 10 5 )

E = 33 x 10 5 N/C

Isiqondiso sensimu kagesi sikhomba ukushaja u-A futhi sibheke kude nokushaja u-B (kwesobunxele).

7. Uthuli oluyi-1 mg luntanta emoyeni. Uma ukushaja kothuli kungu-0.5 μC futhi ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s2, nquma ubukhulu bensimu kagesi esekela uthuli.

Kwaziwa:

Isisindo sothuli (m) = 1 mg = 1 x 10-6 kg

Ukushaja kothuli (q) = 0.5 μC = 0.5 x 10-6 C

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Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2

Kufunwa: Inkambu kagesi

Isixazululo:

w = mg

w = isisindo sothuli, m = isisindo sothuli, g = ukusheshisa ngenxa yamandla adonsela phansi

Amandla adonsela phansi asebenza othulini:

w = mg = (1 x 10 -6 kg)(10 m/s 2 ) = 10 x 10 -6 kg m/s 2 = 10 x 10 -6 AmaNewton

Isibalo sensimu kagesi:

E = F/q

E = insimu kagesi, F = amandla kagesi, q = ishaja kagesi

Faka u-F esilinganisweni sensimu kagesi bese u-w esilinganisweni sesisindo:

E = F/q = w/q

E = (10 x 10 -6 N) / (0.5 x 10 -6 C)

E = 10 N / 0,5 C

E = 20 N/C

8. Izindleko ezimbili q1 = 32 μC kanye no-q2 = -214 μC zihlukaniswe ngebanga lika-x, njengoba kuboniswe esithombeni esingezansi. Akukho nsimu kagesi endaweni ethi P etholakala ku-10 cm ukusuka ku-q2Thola u-x.

Ugesi oqinile - izinkinga nezixazululo 9

Kwaziwa:

Ishaja 1 (Q)1) = 32 μC

Ishaja 2 (Q)2) = -214 μC

Ibanga lephuzu P kusuka ku-q1 = x + 10 cm

Ibanga lephuzu P kusuka ku-q2 = 10cm

Okufunayo: x

Isixazululo:

Ugesi oqinile - izinkinga nezixazululo 10

E1 = insimu kagesi ekhiqizwa yi-charge Q1. Isiqondiso sensimu kagesi kude ne-Q1 ngoba u-Q1 kuyinto enhle. E2 = insimu kagesi ekhiqizwe yi-Q2. Isiqondiso sensimu kagesi sikhomba ku-Q2 ngoba u-Q2 kuyinto engemihle.

Akukho mandla aphelele endaweni ethi p etholakala ku-10 cm ukusuka ku-Q2

Ugesi oqinile - izinkinga nezixazululo 11

Sebenzisa ifomula ye-quadratic:

Ugesi oqinile - izinkinga nezixazululo 12

9. Iphuzu elishajiwe u-q lisephuzwini u-P ensimini kagesi Okhiqizwayo ngokushaja (+), ngaleyo ndlela kube namandla angu-0.05 N. Uma ishaja ingu-+5 × l0-6 Coulomb, ingabe ubukhulu bensimu kagesi endaweni C buyini.

Kwaziwa:

Amandla kagesi (F) = 0.05 amaNewton

Ishaja kagesi (Q) = +5 × l0-6 I-Coulomb = 0.000005

Kufunwa: Insimu kagesi endaweni P

Isixazululo:

E = F / Q

E = 0.05 Newton / 0.000005 Coulomb

E = 5 Newton / 0.0005 Coulomb

E = 10,000 Newton/Coulomb

E = 10 4 N/C

E = 10 4 NC -1

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