Ugesi oqinile - izinkinga nezixazululo
Amandla kagesi
1. Iphuzu A ensimini kagesi . Ubukhulu bensimu kagesi endaweni A = 0.5 NC -1 . Uma kufakwa ishaja engu-0.25-C endaweni A, pho iyini amandla kagesi asetshenziswa ekushajeni.
Kwaziwa:
Insimu kagesi endaweni A = 0.5 NC -1
Ukushaja kukagesi endaweni A = 0.25 C
Kufunwa: Amandla kagesi
Isixazululo:
F = q E
F = (0.25 C)(0.5 NC -1 )
F = 0.125N
2. Amashaja amabili angu-5 C no-4 C ahlukaniswe ngebanga lamamitha angu-3. Uma i-Coulomb constant ingu-9 × 10 9 Nm 2 C –2 , ubukhulu bamandla kagesi abhekene namashaja amabili bungakanani?
Kwaziwa:
Ishaja 1 (q 1 ) = 5 C
Ishaja 2 (q 2 ) = 4 C
Ibanga phakathi kokushaja 1 nokushaja 2 (r) = amamitha angu-3
I-Coulomb's constant (k) = 9 × 10 9 Nm 2 C –2
Okufunwayo: Ubukhulu bamandla kagesi (F)
Isixazululo:
3. Ishaja kagesi +q 1 = 10 μC ; +q 2 = 20 μC ; kanye no-q 3 kuhlukanisiwe, njengoba kuboniswe esithombeni esingezansi. Amandla kagesi asetshenziswa ekushajeni q 2 = 0, khona-ke iyini ishaja ye-q 3.
Kwaziwa:
Ishaja 1 (q 1 ) = 10 μC = 10 x 10 -6 C
Ishaja 2 (q 2 ) = 20 μC = 20 x 10 -6 C
Okufunwayo: Iyini imali ye-q 3
Isixazululo:
Kunezenzo ezimbili zamandla ku-+ q2.
Amandla okuqala amandla axoshayo phakathi kokushaja +q 1 kanye nokushaja +q 2 okungu-F 12 , ngakwesokudla.
Amandla kagesi aphelele asebenza ku-q 2 = 0 bese kuthi u-q 3 ube negative.
Amandla esibili amandla akhangayo phakathi kokushaja +q 2 kanye no-q 3 okungu-F 23 , ngakwesobunxele.
Womabili la mandla asebenza ku-q 2 , anobukhulu obufanayo kodwa aphambene.
Amandla e-Net asebenza ku-+q 2 = 0.
4. Amashaja amathathu q 1 , q , kanye no q 2 asemugqeni. Uma q = 5.0 μC kanye no d = 30 cm, khona-ke ubukhulu kanye nesiqondiso samandla kagesi sisebenza kuphi kushaja q.
Kwaziwa:
Ishaja 1 (q 1 ) = 30 μC = 30 x 10 -6 C
Ishaja 2 (q 2 ) = 60 μC = 60 x 10 -6 C
Ishaja 3 (q) = 5 μC = 5 x 10 -6 C
Ibanga phakathi kuka-q 1 no-q = d
Ibanga phakathi kuka-q 2 no-q = 2d
d = 30 cm = 0.3 amamitha
d 2 = (0.3) 2 = 0.09
I-Coulomb's constant (k) = 9 x 10 9 N m 2 C -2
Okufunwayo: Ubukhulu kanye nesiqondiso samandla kagesi kusebenza ngokushaja kagesi
Isixazululo:
Kunamandla amabili asebenza ku-q angama-F 1 abheke kwesokudla (u-q no-q 1 bahle ngakho-ke u-F 1 ubheke kude no-q no-q 1 ) kanye no-F 2 ubheke ngakwesokunxele (u-q no-q 2 bahle ngakho-ke u-F 2 ubheke kude no-q no-q 2 ). Kubalwe kuqala u-F 1 no-F 2.
Amandla aphelele angama-7.5 Newtons. Isiqondiso samandla aphelele = isiqondiso sika-F1, iphuzu elingakwesokudla ukuze ushaje u-q2.
Inkambu kagesi
5. Ishaja yephoyinti u-q isendaweni engu-P ensimini kagesi ekhiqizwa yishaja (+) ukuze ibhekane namandla angu-0.05 N endleleni eya ekushajeni. Uma ubukhulu bensimu kagesi endaweni engu-P bungu-2 x 10 -2 NC -1 , khona-ke ubukhulu nohlobo lweshaja olubangela insimu kagesi.
Kwaziwa:
Amandla kagesi (F) = 0.05 N
Insimu kagesi (E) = 2 x 10 –2 NC –1 = 0.02 NC –1
Okufunwayo: Ubukhulu kanye nohlobo lweshaja kagesi
Isixazululo:
Ishaja kagesi ibalwa kusetshenziswa ifomula eveza ubudlelwano phakathi kwamandla kagesi (F), insimu kagesi (E) kanye neshaja kagesi (q):
F = q E
q = F / E = 0.05 N / 0.02 NC –1 = 2.5 Ama-Coulomb
Ishaja u-q ibhekana namandla kagesi aqonde ekushajeni (+) okukhiqiza insimu kagesi, ngakho-ke ishaja u-q ayilungile.
6. Amashaja u-A no-B ahlukaniswe ngebanga lamamitha angu-4. Iphuzu C liphakathi kwamashaja womabili, imitha eli-1 ukusuka endaweni A. Uma u-Q A = –300 μC, u-Q B = 600 μC. 1/4 π ε 0 = 9 × 10 9 N m 2 C– 2, khona-ke ubukhulu bensimu kagesi endaweni C ekhiqizwa yiwo womabili amashaja buyini.
Kwaziwa:
Ibanga phakathi kwezindleko A kanye no-B (r AB ) = amamitha angu-4
Ibanga phakathi kwephuzu C kanye nokushaja A (r AC ) = 1 imitha
Ibanga phakathi kwephuzu C kanye neshaja B (r BC ) = amamitha angu-3
Ishaja A (q A ) = –300 μC = -300 x 10 -6 C = -3 x 10 -4 I-Coulomb
Ishaja B (q B ) = 600 μC = 600 x 10 -6 C = 6 x 10 -4 Ama-Coulomb
Okungaguquki (k) = 9 × 10 9 N m 2 C –2
Kufunwa: Inkundla kagesi endaweni C
Isixazululo:
Insimu kagesi ekhiqizwa yishaja A endaweni C:
Ishaja A ayilungile kangangokuthi isiqondiso sensimu kagesi sikhomba kushaja A futhi siqhelelene neshaja B (ngakwesobunxele).
Insimu kagesi ekhiqizwa yishaja B endaweni C:
Ishaja B ilungile kangangokuthi indlela insimu kagesi eqondiswa ngayo ikude neshaja B futhi ikhomba ukushaja u-A (ngakwesobunxele).
Umphumela wensimu kagesi endaweni A:
E = E A + E B
E = (27 x 10 5 ) + (6 x 10 5 )
E = 33 x 10 5 N/C
Isiqondiso sensimu kagesi sikhomba ukushaja u-A futhi sibheke kude nokushaja u-B (kwesobunxele).
7. Uthuli oluyi-1 mg luntanta emoyeni. Uma ukushaja kothuli kungu-0.5 μC futhi ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s2, nquma ubukhulu bensimu kagesi esekela uthuli.
Kwaziwa:
Isisindo sothuli (m) = 1 mg = 1 x 10 -6 kg
Ukushaja kothuli (q) = 0.5 μC = 0.5 x 10 -6 C
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Kufunwa: Insimu kagesi
Isixazululo:
w = mg
w = isisindo sothuli, m = isisindo sothuli, g = ukusheshisa ngenxa yamandla adonsela phansi
Amandla adonsela phansi asebenza othulini:
w = mg = (1 x 10 -6 kg)(10 m/s 2 ) = 10 x 10 -6 kg m/s 2 = 10 x 10 -6 AmaNewton
Isibalo sensimu kagesi:
E = F/q
E = insimu kagesi, F = amandla kagesi, q = ishaja kagesi
Faka u-F esilinganisweni sensimu kagesi bese u-w esilinganisweni sesisindo:
E = F/q = w/q
E = (10 x 10 -6 N) / (0.5 x 10 -6 C)
E = 10 N / 0,5 C
E = 20 N/C
8. Amashaja amabili q 1 = 32 μC kanye q 2 = -214 μC ahlukaniswe yibanga lika-x, njengoba kuboniswe esithombeni esingezansi. Ayikho insimu kagesi endaweni P etholakala ku-10 cm ukusuka ku-q 2. Thola u-x.
Kwaziwa:
Ishaja 1 (Q 1 ) = 32 μC
Ishaja 2 (Q 2 ) = -214 μC
Ibanga lephuzu P kusukela ku-q 1 = x + 10 cm
Ibanga lephuzu P kusuka ku-q 2 = 10 cm
Kufunwa: x
Isixazululo:
E 1 = insimu kagesi ekhiqizwa ngokushaja Q 1. Isiqondiso sensimu kagesi sikude ne-Q 1 ngoba u-Q 1 ulungile. E 2 = insimu kagesi ekhiqizwa ngu-Q 2. Isiqondiso sensimu kagesi sikhomba ku-Q 2 ngoba u-Q 2 ulungile.
Akukho mandla aphelele endaweni ethi p etholakala ku-10 cm ukusuka ku-Q 2
Sebenzisa ifomula ye-quadratic:
9. Iphuzu elishajiwe u-q lisephuzwini u-P ensimini kagesi ekhiqizwa yishaja (+), ngaleyo ndlela linamandla angu-0.05 N. Uma ishaja ingu-+5 × l0 –6 Coulomb, khona-ke ubukhulu bensimu kagesi ephuzwini u-C buyini.
Kwaziwa:
Amandla kagesi (F) = 0.05 amaNewton
Ishaja kagesi (Q) = +5 × l0 –6 I-Coulomb = 0.000005
Kufunwa: Insimu kagesi endaweni P
Isixazululo:
E = F / Q
E = 0.05 Newton / 0.000005 Coulomb
E = 5 Newton / 0.0005 Coulomb
E = 10,000 Newton/Coulomb
E = 10 4 N/C
E = 10 4 NC -1
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