Isikhathi samandla - izinkinga nezixazululo

Isikhathi samandla - izinkinga nezixazululo

1. Uma u-F R engamandla aphelele ka-F 1 , F 2 , no-F 3 , ubukhulu bamandla u-F 2 no-x buyini?

Kwaziwa:

Amandla aphelele (F)R) = 40 NIsikhathi samandla - izinkinga nezixazululo 1

Amandla 1 (F 1 ) = 10 N

Amandla (F 3 ) = 20 N

Okufunwayo: Ubukhulu bamandla F 2 kanye nebanga lika-x

Isixazululo:

Thola ubukhulu bamandla F 2 :

Phoqa amaphuzu aye phezulu, okusayinwe okungekuhle kanye nokuphoqa amaphuzu aye phansi, okusayinwe okungekuhle.

ΣF = 0

– F R + F 1 + F 2 – F 3 = 0

– 40 + 10 + F 2 – 20 = 0

– 30 + F 2 – 20 = 0

– 50 + F 2 = 0

F 2 = amaNewton angu-50.

Uphawu olune-plus lubonisa ukuthi isiqondiso samandla siphezulu.

Thola u-x.

Khetha u-A njenge-axis yokujikeleza.

τ 1 = F 1 l 1 = (10 N)(1 m) = 10 Nm

I-torque 1 ijikeleza umsebe ngokuphikisana newashi ngakho-ke sibeka uphawu oluhle ku-torque 3.

τ 2 = F 2 x = (50)(x) = 50x Nm

I-torque 1 ijikeleza umsebe ngokuphikisana newashi ngakho-ke sibeka uphawu oluhle ku-torque 3.

τ 3 = F 3 x = (20 N)(1.75 m) = -35 Nm

I-torque 2 ijikeleza ngomsebe ngokwewashi ngakho-ke sibeka uphawu olubi ku-torque 2.

Isikhathi samandla :

Στ = 0

10 + 50x – 35 = 0

50x - 25 = 0

50x 25

x = 25/50

x = 0.5 m

2. Amandla ka-F 1 , F 2 , F 3 , kanye no-F 4 asebenza endukwini ye-ABCD njengoba kuboniswe esithombeni. Uma isisindo senduku singanakwa, ubukhulu besikhathi samandla buyini, mayelana nephuzu A.

I-axis yokujikeleza = iphuzu A.

Kwaziwa:

Amandla F1 = 10 N, ingalo ye-lever l1 = 0 Isikhathi samandla - izinkinga nezixazululo 2

I-Force F 2 = 4 N, ingalo ye-lever l 2 = 2 amamitha

I-Force F 3 = 5 N, ingalo ye-lever l 3 = 3 amamitha

I-Force F 4 = 10 N, ingalo ye-lever l 4 = 6 amamitha

Kufunwa: isikhathi samandla mayelana nephuzu A

Isixazululo:

Isikhashana samandla 1 (τ 1 ) = F 1 l 1 = (10)(0) = 0

Isikhashana samandla 2 (τ 2 ) = F 2 l 2 = (4)(2) = -8 Nm

Isikhashana samandla 3 (τ 3 ) = F 3 l 3 = (5)(3) = 15 Nm

Isikhashana samandla 4 (τ 4 ) = F 4 l 4 = (10)(6) = -60 Nm

Uma i-torque ijikeleza induku ngokuphambene newashi khona-ke sibeka uphawu oluhle.

Uma i-torque ijikeleza induku ngokwewashi, khona-ke sibeka uphawu olubi.

Umphumela wesikhathi samandla:

τ = 0 – 8 Nm + 15 Nm – 60 Nm

τ = -68 Nm + 15 Nm

τ = -53 Nm

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

3. Amandla amathathu asebenza endukwini, F A = ​​​​F C = 10 N kanye F B = 20 N, njengoba kuboniswe esithombeni esingezansi. Uma ibanga lika-AB = BC = 20 cm, yisiphi isikhathi samandla mayelana nephuzu C.

Kwaziwa:

I-axis yokujikeleza endaweni C.Isikhathi samandla - izinkinga nezixazululo 3

Ibanga phakathi kwe-F A kanye ne-axis yokujikeleza (r AC ) = 40 cm = 0,4 amamitha

Ibanga phakathi kuka-F B kanye ne-axis yokujikeleza (r BC ) = 20 cm = 0.2 amamitha

Ibanga phakathi kwe-F C kanye ne-axis yokujikeleza (r CC ) = 0 cm

F A = ​​​​10 Newton

F B = 20 Newton

I-FC = amaNewton ayi-10

Okufunwayo: Umphumela wesikhathi samandla mayelana nephuzu C.

Isixazululo:

Isikhathi samandla A:

Στ A = (F A )(r AC isono 90 o ) = (10 N)(0,4 m)(1) = -4 Nm

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

Isikhathi samandla B:

Στ B = (F B )(r BC isono 90 o ) = (20 N)(0,2 m)(1) = 4 Nm

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.

Isikhathi samandla C:

Στ C = (F C )(r CC isono 90 o ) = (10 N)(0)(1) = 0

Umphumela wesikhathi samandla:

Στ = Στ 1 + Στ 2 + Στ 3

Στ = -4 + 4 + 0

Στ = 0 Nm

4. Ubude benduku bungama-50 cm. Amandla amathathu asebenza endukuni, njengoba kuboniswe esithombeni esingezansi. Uma i-axis yokujikeleza iyiphuzu C, iyini inetha lomzuzu wamandla.

Kwaziwa:

I-axis yokujikeleza endaweni C.Isikhathi samandla - izinkinga nezixazululo 4

Ibanga phakathi kuka-F 1 kanye ne-axis yokujikeleza lingu-(r 1 ) = 30 cm = 0,3 amamitha

Ibanga eliphakathi kuka-F 2 kanye ne-axis yokujikeleza (r 2 ) = 10 cm = 0,1 amamitha

Ibanga eliphakathi kuka-F 3 kanye ne-axis yokujikeleza (r 3 ) = 20 cm = 0,2 amamitha

F 1 = 10 Newton

F 2 = 10 Newton

F 3 = 10 Newton

Okufunwayo: Umphumela wesikhathi samandla mayelana nephuzu C.

Isixazululo:

Isikhathi samandla 1:

Στ 1 = (F 1 )(r 1 isono 90 o ) = (10 N)(0,3 m)(1) = -3 Nm

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

Isikhathi samandla 2:

Στ 2 = (F 2 )(r 2 isono 90 o ) = (10 N)(0,1 m)(1) = 1 Nm

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.

Isikhathi samandla 3:

Στ 3 = (F 3 )(r 3 isono 30 o ) = (10 N)(0,2 m)(0,5) = -1 Nm

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

Umphumela wesikhathi samandla:

Στ = Στ 1 + Στ 2 + Στ 3

Στ = -3 + 1 – 1

Στ = -3 Nm

Uphawu lokususa lubonisa ukuthi umphumela womzuzu wamandla ujikeleza induku ngokwewashi.

5. Amandla amathathu F 1 , F 2 , kanye no-F 3 asebenza endukwini njengoba kuboniswe esithombeni esingezansi. Ubude benduni bungamamitha angu-4. Iyini isikhathi samandla mayelana nephuzu C?

(isono 53 o = 0.8, cos 53 o = 0.6, AB = BC = CD = DE = imitha elingu-1)

Kwaziwa:

I-axis yokujikeleza endaweni C. Isikhathi samandla - izinkinga nezixazululo 5

Amandla 1 (F 1 ) = 5 Newton

Ibanga eliphakathi komugqa wesenzo se-F1 ne -axis yokujikeleza (r 1 ) = amamitha angu-2

Amandla 2 (F 2 ) = 0.4 Newton

Ibanga phakathi komugqa wesenzo sika-F 2 ne-axis yokujikeleza (r 2 ) = 1 imitha

Amandla 3 (F 3 ) = 4.8 Newton

Ibanga eliphakathi komugqa wesenzo se- F3 ne -axis yokujikeleza (r 3 ) = amamitha ama-2

Okufunwayo: Isikhathi samandla mayelana nephuzu C.

Isixazululo:

Isikhathi samandla 1:

τ 1 = F 1 r isono 53 o = (5 N) (2 imitha) (0,8) = (10) (0,8) N = 8 N

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.

Isikhathi samandla 2:

τ 2 = F 2 r isono 90 o = (0,4 N)(1 imitha)(1) = -0,4 N

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

Isikhathi samandla 3:

τ 3 = F 3 r isono 90 o = (4,8 N)(2 imitha)(1) = -9,6 N

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

Umphumela wesikhathi samandla:

Στ = τ 1 – τ 2 – τ 3 = 8 – 0,4 – 9,6 = 8 – 10 = 2 Nm

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.

6. Uyini umphumela wesikhathi samandla mayelana ne-axis yokujikeleza endaweni ethi O ngamandla enza entongeni, njengoba kuboniswe esithombeni esingezansi?

Kwaziwa:

I-axis yokujikeleza endaweni ethi O. Isikhathi samandla - izinkinga nezixazululo 6

Amandla 1 (F 1 ) = 6 Newton

Ibanga phakathi komugqa wesenzo sika-F 1 ne-axis yokujikeleza (r 1 ) = 1 imitha

Amandla 2 (F 2 ) = 6 Newton

Ibanga eliphakathi komugqa wesenzo se-F2 ne -axis yokujikeleza (r 2 ) = amamitha angu-2

Amandla 3 (F 3 ) = 4 Newton

Ibanga eliphakathi komugqa wesenzo se-F3 ne -axis yokujikeleza (r 3 ) = amamitha angu-2

Okufunwayo: Umphumela wesikhathi samandla mayelana nephuzu C

Isixazululo:

Isikhathi samandla 1:

τ 1 = F 1 l 1 = (6 N)(1 m) = 6 Nm

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.

Isikhathi samandla 2:

τ 2 = F 2 r 2 isono 30 o = (6 N)(2 m)(0,5)= 6 Nm

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.

Isikhathi samandla 3:

τ 3 = F 3 l 3 = (4 N)(2 m) = -8 Nm

Uphawu lokususa lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokwewashi.

Umphumela wesikhathi samandla:

Στ = τ 1 + τ 2 – τ 3 = 6 + 6 – 8 = 4 Nm

Uphawu lwe-Plus lubonisa ukuthi umzuzu wamandla ujikeleza induku ngokuphambene newashi.