Izibalo ze-Fluid - izinkinga nezixazululo
Umfutho woketshezi
1. Kuyini i-dukuqhathanisa phakathi kwengcindezi ye-hydrostatic yegazi phakathin ubuchopho kanye nengxenye yomzimbas of izinyawo zika umuntu okuphakama kwakhe kungu-165 cm (ake sithi Ubuningi kwegazi = 1.0 × 103 kg / m3, ukusheshisa ngenxa yamandla adonsela phansi = 10m/s2)
Kwaziwa:
Ukuphakama (h) = 165 cm = 165/100 m = 1.65 amamitha
Ubuningi begazi (ρ) = 1.0 × 103 kg / m3
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s2
Okufunayo: ukucindezela koketshezi
Isixazululo:
P = ρ gh
P = (1.0 × 103)(10)(1.65)
P = (1.0 × 104)(1.65)
P = 1.65 x 104 N / m2
Ipayipi Eliphezulu
2. Ipayipi le-AU liqala ligcwaliswe ngamanzi kunepayipi elilodwa eligcwele uwoyela, njengoba kuboniswe esithombeni esingezansi. Ubuningi bamanzi buyi-1000 kg/m23Uma ukuphakama kwamafutha kungu-8 cm kanti ukuphakama kwamanzi kungu-5 cm, kungakanani ukuminyana kwamafutha?
Kwaziwa:
Ubuningi bamanzi = 1000 kg.m-3
Ukuphakama kwamanzi (h2= 5cm
Ukuphakama kwamafutha (h1= 8cm
Kufunwa: ukuminyana amafutha
Isixazululo:
ρ1 i-gh1 =ρ2 i-gh2
ρ1 h1 =ρ2 h2
(1000)(5) = (ρ2)(8)
5000 = (ρ2)(8)
ρ2 = 625 kg.m-3
3. Ipayipi le-AU laqala lagcwaliswa ngophalafini labe selingezwa amanzi. Uma isisindo se uphethiloli ungamagremu angu-0.8/cm3 futhi ukuminyana kwamanzi ingu-1 gram/cm3 futhi indawo yesigaba esiphambeneyo ingu-1.25 cm2. Nquma ukuthi kungakanani amanzi kufanele engezwe ukuze umehluko wokuphakama kwe Ubuso be-kerosene buyi-15 cm
A. 9 ml
B. 12 ml
C. 15 ml
D. 18 ml
Kwaziwa:
Ubuningi be-parafini (ρ)1) = 0.8 amagremu/cm3
Ubuningi bamanzi (ρ)2) = 1 amagremu/cm3
Indawo yesigaba sepayipie = 1.25cm2
Umehluko wokuphakama kobuso be-parafini (h1= 15cm
Kufunwa: Umthamo wamanzi
Isixazululo:
Ukuphakama kwamanzi (h2):
ρ1 i-gh1 = ρ2 i-gh2
(0,8)(15)(1)(h)2)
h2 = 12cm
Umthamo wamanzi:
V = (Indawo yesigaba sepayipie)ukuphakama kwamanzi)
V = (1.25 cm)2)(12 cm)
V = 15 cm3
Ilitha eli-1 = 1 dm3 = 103 cm3
I-millilitha eli-1 = 10-3 ilithas = (10-3)(103cm)3 = 1cm3
Umthamo wamanzi ungama-15 cm3 = amamililitha ayi-15
Impendulo efanele ithi C.
4. Ipayipi U eligcwele amanzi anobukhulu obungu-1000 kg/m23Ikholomu eyodwa yepayipi U egcwele i-glycerin enobukhulu obungu-1200 kg/m23Uma ukuphakama kwe-glycerin kungu-4 cm, thola umehluko wokuphakama kwamakholomu womabili epayipi.
A. 0.8 cm
B. 4 cm
C. 8 cm
D. 12 cm
Kwaziwa:
Ubuningi bamanzi (ρ)1) = 1000 kg/m3
Ubuningi be-glycerin (ρ)2) = 1200 kg/m3
Ukuphakama kwe-glycerin (h2= 4cm
Okufunayo: Umehluko wokuphakama kwamakholomu womabili epayipi.
Isixazululo:
Ukuphakama kwekholomu yepayipi (h1):
ρ1 h1 = ρ2 h2
(1000)(amahora)1) = (1200)(4)
(1000)(amahora)1= = 4800
h1 = 4.8cm
Umehluko wokuphakama kwamakholomu womabili epayipi U = h1 - h2 = 4.8 cm - 4 cm = 0.8 cm
Impendulo eyiyo ngu-A.
5. Ipayipi Unayo izinhlangothi ezimbili zivulekile zigcwele amanzi nge isisindo of 1 g / cm3Indawo yesigaba eceleni kwepayipi iyafana, okungu-1 cm2Othile uyashaya on umkhawulo owodwa wonyawo lombhobho ukuze ubuso be amanzi ngakolunye unyawo aphakama ngamasentimitha ayi-10 ukusuka endaweni yawo yokuqala. Uma the ukusheshisa ngenxa yamandla adonsela phansi is 10 m/s2 bese inqume amandla wenza lokho umuntu.
A. 20 kilodynes
B. 10 kilodynes
C. 2 kilodynes
D. 1 kilodyne
Kwaziwa:
Shintsha wonke amayunithi abe uhlelo lwamazwe ngamazwe.
Ubuningi bamanzi (ρ)1) = 1 gr/cm3 = 10-3 kg / 10-6 m3 = 103 kg / m3
Indawo yesiphambano sepayipi (A) = 1 cm2 = 10-4 m2
Ushintsho lwekholomu yepayipi (h) = 10 cm = 1 dm = 10-1 m
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 ms-2 = 101 Nks.-2
Umthamo wamanzi ahambayo (V) = (A)(h) = (1 cm)2)(10 cm) = 10 cm3 = (101)(10-6 m3= = 10-5 m3
Kufunwa: Amandla (F) asetshenziswa ngumuntu.
Isixazululo:
Amandla asebenze yilowo muntu = isisindo samanzi anokuphakama okungu-10 cm
F = w
F = mg —–> Isibalo sobuningi: m = ρ V
F = ρ V g
F = (10)3)(10-5)(101)
F = (10)4)(10-5)
F=10-1 I-Newton —–> 1 uNewton = 105 mxolisi
F = (10)-1)(105 dyne)
F=104 mxolisi
F = amakhilodine ayi-10
Impendulo efanele ngu-B.
6. Ipayipi elinomumo ka-Y lifakwa libheke phansi ukuze unyawo lwesobunxele nonyawo lwesokudla kucwiliswe ezinhlotsheni ezimbili zoketshezi. Ngemva kokuba zombili izinyawo zicwiliswe oketshezini, khona-ke ingxenye ephezulu yepayipi lika-Y ivalwa ngomunwe bese idonswa phezulu, ukuze imilenze emibili yepayipi lika-Y igcwaliswe ngekholomu yoketshezi oluhlukahlukene olunobukhulu obuphezulu. Uma ubukhulu boketshezi lokuqala bungu-0.80 gram.cm-3 kanye nobuningi besibili is 0.75 amagremu/cm-3, futhi ikholomu engezansi yoketshezi ingu-8 cm, bese kuba inqume umehluko wokuphakama phakathi kwamakholomu amabili e-liquid ku-U pipe.
A. 1.0666 cm
B. 0.9375 cm
C. 0.3533 cm
D. 0.5333 cm
Kwaziwa:
Ubuningi boketshezi lokuqala (ρ1) = 0,80 amagremu.cm-3
Ubuningi boketshezi lwesibili (ρ2) = 0,75 amagremu.cm-3
Ukuphakama koketshezi oluphansi (h1= 8cm
Kufunwa: Tumehluko wokuphakama phakathi kwamakholomu amabili oketshezi ku-U pipe
Isixazululo:
Tukuphakama kwe uketshezi oluphezulu (h2):
ρ1 h1 = ρ2 h2
(0.80)(8) = (0.75)(h)2)
6.4 = 0.75 (ihora2)
h2 = 6.4/0.75
h2 = 8.5cm
Umehluko wokuphakama koketshezi = h2 - h1 = 8.5333 cm - 8 cm = 0.5333 cm
Impendulo efanele ngu-D.
7. Itshe elinomthamo ongu-0.5 m3 ibekwe oketshezini olunobukhulu obungu-1.5 gr cm-3. Ukusheshisa ngenxa yamandla adonsela phansi kungu-10 ms-2. Iyini amandla anamandla?
Kwaziwa:
Umthamo wetshe (V) = 0.5 m3
Ubuningi bamanzi (ρ) = 1.5 gr cm-3 = 1500 kg m-3
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 ms-2
Okufunayo: amandla okuphapha (F)A)
Isixazululo:
Isibalo samandla agelezayo:
FA = ρ g V = (1500 kg m-3)(10 ms-2)(0.5 m3) = 7500 kg m/s2 = 7500 uNewton
I-Float
8. Ibhulokhi leqhwa liyantanta olwandle njengoba kuboniswe esithombeni esingezansi. Ubuningi bolwandle buyi-1.2 gr cm-3 futhi ubuningi beqhwa bungu-0.9 gr c-3. Umthamo weqhwa emanzini olwandle = ……. x umthamo weqhwa emoyeni.
Kwaziwa:
Ubuningi bolwandle (ρ)Ulwandle) = 1.2 gr cm-3
Ubuningi beqhwa (ρ)Ice) = 0.9 gr c-3
Okufunayo: Umthamo weqhwa emanzini olwandle = ……. x umthamo weqhwa emoyeni.
Isixazululo:
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Umthamo weqhwa olwandle = 0.75
Umthamo weqhwa emoyeni = 0.25
Umthamo weqhwa emanzini olwandle = 3 x umthamo weqhwa emoyeni (3 x 0.25 = 0.75).
9. Into intanta oketshezini lapho u-2/3 wento useketshezini. Uma ubukhulu bento bungu-0.6 gr cm3, pho kuyini ukuminyana kwamanzi.
Kwaziwa:
Ingxenye yento ewuketshezi = 2/3
Ubuningi bento = 0.6 g cm3 = 600 kg m3
Okufunayo: ubuningi boketshezi (x)
Isixazululo:

Ubuningi boketshezi buyi-900 kg m3
10. Izinkuni zintanta emanzini, lapho ingxenye engu-3/5 yezinkuni isemanzini. Uma ubuningi bamanzi bungu-1 × 103 kg / m3, buyini ubukhulu bokhuni?
Kwaziwa:
Ingxenye yento emanzini = 3/5
Ubuningi bamanzi = 1×103 kg / m3 = 1000 kg / m3
Kufunwa: Ubuningi bokhuni (x)
Isixazululo:

Ubuningi bokhuni bungu-600 kg/m23 = 6 x102 kg / m3
- Kuyini uketshezi oluqhubekayo?
- Impendulo: I-fluid statics, eyaziwa nangokuthi i-hydrostatics, iyigatsha le-fluid mechanics elifunda uketshezi oluphumuzayo kanye namandla asetshenziswa uketshezi olunganyakazi ezintweni ezicwilisiwe kanye nezindonga zesitsha.
- Ingcindezi kuketshezi ihluka kanjani ngokujula?
- Impendulo: Kuketshezi olunganyakazi, ingcindezi iyanda ngokulandelana ngokujula ngenxa yesisindo sekholomu yoketshezi ngaphezu kwanoma yikuphi ukujula okunikeziwe. Ushintsho ekucindezelweni ngokujula lunikezwa yi , lapho ukuminyana koketshezi, ukusheshisa kwamandla adonsela phansi, futhi ℎ ukujula.
- Iyini isimiso sikaPascal?
- Impendulo: Isimiso sikaPascal sithi ushintsho ekucindezelweni okusetshenziswa kuketshezi oluvalekile ludluliselwa lungapheli kuzo zonke izingxenye zoketshezi nasezindongeni zesitsha salo.
- Isebenza kanjani i-hydraulic lift ngokusekelwe ezimisweni ze-fluid statics?
- Impendulo: I-hydraulic lift isebenzisa isimiso sikaPascal. Uma amandla amancane esetshenziswa episton encane, idala ingcindezi kuketshezi. Lokhu kucindezela kudluliselwa kunganciphi kulo lonke uketshezi, kusebenzisa amandla amakhulu kakhulu episton enkulu, okwenza i-lift ikwazi ukuphakamisa izinto ezisindayo ngomzamo omncane kakhulu.
- Iyini amandla okuphapha futhi ahlobene kanjani ne-fluid statics?
- Impendulo: Amandla okuphapha ngamandla aphezulu asetshenziswa uketshezi kunoma iyiphi into ecwilisiwe. Ngokomthetho ka-Archimedes, amandla okuphapha entweni alingana nesisindo soketshezi olususwe yinto.
- Kungani izinto zintanta noma zicwila oketshezini?
- Impendulo: Ukuthi into iyantanta noma iyacwila kuncike ebuhlotsheni obuphakathi kwamandla okuntanta kanye nesisindo sento. Uma amandla okuntanta (ngenxa yoketshezi olususiwe) makhulu kunesisindo sento, izontanta. Uma isisindo sento sikhulu, izocwila.
- Uyini umqondo wokucindezela kwe-hydrostatic?
- Impendulo: Ukucindezela kwe-hydrostatic yingcindezi ekhishwa uketshezi oluphumulile ngenxa yamandla adonsela phansi. Iyanda ngokulandelana ngokujula koketshezi, futhi ibalwa ngokuthi , lapho ukucindezela okungaphezulu, ukuminyana koketshezi, ukusheshisa kwamandla adonsela phansi, futhi ℎ ukujula.
- Ingcindezi yomoya ihlobene kanjani ne-fluid statics?
- Impendulo: Umkhathi ungacatshangwa njengoketshezi. Umfutho womoya umfutho okhishwa yisisindo somoya ngaphezu kwephuzu elithile. Uyancipha ngokuphakama, ngendlela efanayo nendlela umfutho oketshezini oncipha ngayo njengoba umuntu ekhuphukela phezulu kukholamu yoketshezi.
- Iyiphi indima edlalwa ukuma kwesitsha ekusatshalalisweni kwengcindezi yoketshezi olungaguquki ngaphakathi kwaso?
- Impendulo: Ku-fluid statics, ingcindezi ekujuleni okunikeziwe incike kuphela ekuphakameni kwekholomu yoketshezi ngaphezu kwalokho kujula, hhayi ekumeni kwesitsha. Ngakho-ke, ingcindezi ekujuleni okuthile iyafana kungakhathaliseki ukuma kwesitsha.
- Iyini ukubaluleka kwe-hydrostatic paradox?
- Impendulo: I-hydrostatic paradox iqokomisa ukuthi kuma-static e-fluid, amandla asetshenziswa uketshezi oluqhubekayo phansi kwesitsha ancike kuphela ekuphakameni kwekholomu ye-fluid, hhayi kumthamo wayo noma ukuma kwesitsha. Ngakho-ke, izitsha ezihlukene kakhulu ezinokuphakama okufanayo koketshezi zinomfutho ofanayo esisekelweni sazo, noma ngabe ziphethe amanani ahlukene oketshezi.