Nquma ukuphakama okuphezulu kokunyakaza okubonakalayo

Izinkinga ezixazululiwe ekuhambeni kwe-projectile - thola ukuphakama okuphezulu

1. Ibhola elikhahlelwayo lishiya umhlabathi nge-engeli engu-θ = 60 ^o kanti elivundlile linesivinini sokuqala esingu-10 m/s. Bala ukuphakama okuphezulu! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s ².

Kwaziwa:

I-engeli (θ) = 60 ^o

Isivinini sokuqala (v _o ) = 10 m/s

Okufunwayo: Ukuphakama okuphezulu (h)

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

isono 60 ^o = v _oy / v _o

v _oy = v _o isono 60 ^o = (10)(isono 60 ^o ) = (10)(0.5 √ 3 ) = 5 √ 3 m/s

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s ² (ukwehla okungekuhle)

Ingxenye eqondile yejubane lokuqala (v _oy ) = + 5 √ 3 m/s (ephezulu phezulu)

Ijubane lokugcina ekuphakameni okuphezulu (v _ty ) = 0

Okufunwayo: Ukuphakama okuphezulu (h)

Isixazululo:

v _t ² = v _o ² + 2 gh

0 ² = ( 5 √ 3) ² + 2 (-10) h

0 = 2 5 ( 3 ) – amahora angu-20

0 = 75 – 20 amahora

75 = amahora angu-20

h = 75/20

h = amamitha angu-3.75

Ukuphakama okuphezulu kungamamitha angu-3.75.

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2. Umzimba uphakanyiswa ubheke phezulu nge-engeli engu-30 ^o kanti ukuphakama kwawo kungama-20 metres ukusuka esakhiweni. Isivinini sawo sokuqala singama-4 m/s. Bala ukuphakama okuphezulu! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s ².

Kwaziwa:

I-engeli (θ) = 30 ^o

Ukuphakama kokuqala (h) = amamitha angu-20

Ijubane lokuqala (v _o ) = 4 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Ukuphakama okuphezulu (h)

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

isono 30 ^o = v _oy / v _o

v _oy = v _o isono 30 ^o = (4)(isono 30 ^o ) = (4)(0.5) = 2 m/s

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s ² (ukwehla okungekuhle)

Ingxenye eqondile yejubane lokuqala (v _oy ) = +2 m/s (ephezulu phezulu)

Ijubane lokugcina ekuphakameni okuphezulu (v _ty ) = 0

Okufunwayo: Ukuphakama okuphezulu

Isixazululo:

Ukuphakama okuphezulu:

v _t ² = v _o ² + 2 gh

0 ² = 2 ² + 2 (-10) amahora

0 = 4 – 20 amahora

4 = amahora angu-20

h = 4/20

h = amamitha angu-0.2

Ukuphakama okuphezulu kakhulu kungamamitha angu-0.2 + amamitha angu-20 = amamitha angu-20.2.

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1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yezinto
6. Nquma ijubane lokugcina