Mibvunzo mitatu nezve Potential difference equation
1. Chaja yemagetsi inofambiswa mumunda wemagetsi wakafanana une simba re2√3 N chinhambwe che20 cm. Kana divi resimba riri pakona ye30 o kusvika pakubviswa kwechaja yemagetsi, musiyano uripi pakati pesimba remagetsi panzvimbo dzekutanga nedzekupedzisira dzechaja yemagetsi.
Anozivikanwa:
Simba (F) = 2√3 N
Nhambwe (s) = 20 cm = 0.2 m
Angle (θ) = 30 o
Zvinodiwa: Musiyano wemagetsi
Solution:
Basa rekutumira chaji +q kubva kuna a kuenda kuna b rakaenzana nemusiyano wesimba remagetsi papoindi a na b.
ΔEP = ΔW
Kana divi resimba F maererano nedivi rekutumira chaji +q rakatenderedzwa ne θ, saka basa rekutumira chaji +q kubva kuna a kuenda kuna b nderekuti:
ΔW = F Δs cos θ = ( 2 √ 3 )(0,2)(cos 30) = (0,4 √ 3 )(0,5 √ 3 ) = (0,2)(3) = 0,6 Joule
2. Kana chaji uye kugona kwema capacitor zvichizivikanwa kuti 5 µC uye 20 µF, zvichiteerana, sarudza musiyano unogona kuitika wema capacitor.
Anozivikanwa:
Chaja yemagetsi (q) = 5 µC = 5 x 10 -6 C
Kugona kwe capacitor (C) = 20 µF = 20 x 10 -6 F
Zvinodiwa: Musiyano we capacitor (V)
Solution:
Fomura yekusiyana kwe capacitor potential, capacitor capacitor uye chaji:
V = q / C = (5 x 10 -6 ) / 20 x 10 -6 = 5/20 = 0,25 Volts
3. Mapoinzi maviri emagetsi QA = -4 µC uye QB = 8 µC ari kure ne16 cm. Sarudza simba remagetsi pakati pemapoinzi maviri aya.
Anozivikanwa:
Chaja yemagetsi 1 (Q A ) = 4 x 10 -6 C
Chaja yemagetsi 2 (Q B ) = 8 x 10 -6 C
Kureba (r) = 8 cm = 0,08 m
Chimiro cheCoulomb (k) = 9 × 10 9 Nm 2 /C 2
Zvinodiwa: Simba remagetsi paC (V C )
Solution:
V A = k Q / r = (9 × 10 9 )(4 x 10 -6 ) / 0,08 = (36 × 10 3 ) / 0,08 = -450 Volts
V B = k Q / r = (9 × 10 9 )(8 x 10 -6 ) / 0,08 = (72 × 10 3 ) / 0,08 = 900 Volts
Simba remagetsi paC (V C ) = 900 – 450 = 450 Volts
