## Impuls formula

Article with questions and answer about Impuls formula Impulse, in physics, is a fundamental concept that provides a bridge between force and motion, specifically, the change in an object’s momentum. In scenarios like a bat striking a ball, a car collision, or even the soft landing of a spacecraft, impulse is a crucial aspect that … Read more

## Static and kinetic friction force formula

Article with questions and answer about Static and kinetic friction force formula Friction is an omnipresent force, acting between surfaces in contact, opposing relative motion. This force plays a pivotal role in our daily lives, from walking on the ground to driving cars. Broadly categorized, friction can be classified into two main types: static and … Read more

## Normal force formula

Article with questions and answers about Normal force formula The physical world we interact with daily is rife with forces that act on objects, determining their motion and interactions. Among these forces, the “normal force” stands out as an essential component, especially when objects are in contact with surfaces. This article aims to elucidate the … Read more

## Rope tension formula

Article with questions and answer about Rope tension formula From the simple act of pulling a sled to the complex mechanisms of elevators and cranes, rope tension is a fundamental concept that dictates the efficiency and safety of these operations. Understanding the forces acting within ropes, cables, and strings is crucial in physics and engineering. … Read more

## Moment of inertia formula

Article with questions and answers about Moment of inertia formula In the realms of rotational dynamics, just as mass plays a pivotal role in linear motion, the concept of “moment of inertia” emerges as its rotational counterpart. It essentially dictates how an object resists changes to its rotational motion. This article endeavors to elucidate the … Read more

## Momentum formula

Article with questions and answers about about Momentum formula When we witness a moving object, whether it’s a sprinting athlete or a speeding train, it’s not just the speed or mass alone that determines its impact; it’s the combination of the two. This combination is described by a crucial concept in physics known as “momentum.” … Read more

## Speed formula

Article with questions and answers about Speed formula Imagine watching a race car zipping through a track or a swift stream flowing down a mountain – the commonality is speed. Speed is an intuitive yet pivotal concept in understanding motion in our universe. This article introduces the formula for speed, elaborates on its various facets, … Read more

## Gravity equation

1. Three particles each with a mass of 1 kg are at the vertices of an equilateral triangle whose sides are 1 m long. How large is the gravitational force experienced by each point particle (in G)?

Solution The magnitude of the gravitational force experienced by one of the particles.

F12 = G (m1)(m2) / r2 = G (1)(1) / 12 = G/1 = G

F13 = G (m1)(m3) / r2 = G (1)(1) / 12 = G/1 = G

Resultant gravitational force at point 1:

## Electric field equation

3 questions about Electric field equation

1. A conducting ball with a radius of 10 cm has an electric charge of 500 μC. Points A, B, and C lie in line with the center of the ball at a distance of 12 cm, 10 cm and 8 cm respectively from the center of the ball. Calculate the electric field strength at points A, B, and C!

Known: The radius of the conducting ball (R) = 10 cm = 0.1 m

Electric charge (q) = 500 μC = 500 x 10-6 C

rA = 12 cm = 0,12 m

rB = 10 cm = 0,1 m

rC = 8 cm = 0,08 m

Coulomb constant (k) = 9 x 109

Wanted: The electric field strength at point A (EA), at point B (EB) and at point C (EC)

Solution:

## Spring constant equation

3 questions about Spring constant equation

1. A spring in free suspension has a length of 10 cm. At the free end, a 200 gram weight is suspended so that the length of the spring is 11 cm. If g = 10 m/s2, what is the spring force constant?

Known:

The initial length of the spring (y1) = 10 cm = 0.10 m

The final length of the spring (y2) = 11 cm = 0.11 m

Spring length change (Δy) = 0.11 – 0.10 = 0.01 meter

The mass of the load (m) = 200 grams = 0.2 kg

Load weight (w) = m g = (0,2)(10) = 2 Newtons

Wanted: Spring constant (k)

Solution: