Cov Teeb Meem Tau Daws Hauv Kev Kawm Txog Physics Yooj Yim

1. Lub zog P raug siv rau ib kawg ntawm ib lub beam uas ntev li 2 m. Qhov loj ntawm lub zog ntawd yog dab tsi? lub zogLub axis ntawm kev tig ntawm qhov chaw A.

Paub:

Lub zog (F) = 10 N

Qhov ntev ntawm AB (r_AB) = 2 m

Lub zog F yog perpendicular rau lub beam.

Lub zog ntawm lub lever (l)) =r_AB kev txhaum 90^o = (2 m)(1) = 2 m

SE pob: Lub torque nyob ib ncig ntawm lub axis ntawm kev sib hloov

Tshuaj:

Lub zog torque:

τ = Fl = (10 N)(2 m) = 20 N m

Lub cim ntxiv vim yog lub teeb tig tig counterclockwise.

2. Qhov ntev ntawm ib lub beam AB yog 2 m thiab qhov loj ntawm lub zog F yog 10 N. Qhov loj ntawm lub zog torque yog dab tsi? Lub axis ntawm kev tig ntawm qhov chaw A.

Paub:

Lub zog (F) = 10 N

Qhov ntev ntawm AB (r_AB) = 2 m

Lub zog ntawm lub lever (l)) =r_AB kev txhaum 60^o = (2 m)(0.53) = 3 m

SE pob: Lub torque nyob ib ncig ntawm lub axis ntawm kev sib hloov

Tshuaj:

Lub zog torque:

τ = Fl = (10 N)(3 m) = 103 N m

Lub cim ntxiv vim tias lub zog F ua rau lub beam tig tig counterclockwise.

3. Qhov ntev ntawm ib lub beam yog 2 m. Qhov loj ntawm F₁ yog 10 N thiab qhov loj ntawm F₂ yog 15 N. Txheeb xyuas qhov net torque nyob ib ncig ntawm qhov chaw ntawm lub beam.

Lub axis ntawm kev sib hloov ntawm qhov chaw ntawm lub beam.

Paub:

Lub zog 1 (F₁) = 10 N

cov deb nruab nrab ntawm F₁ thiab qhov chaw nruab nrab ntawm lub beam (r₁) = 1 m

Lub tes tuav 1 (l₁) =r₁ kev txhaum 90^o = (1 m)(1) = 1 m

Lub zog F₁ yog perpendicular rau lub beam.

Lub zog 2 (F₂) = 15 N

Qhov nrug ntawm F₂ thiab qhov chaw nruab nrab ntawm lub beam (r₂) = 1 m

Lub zog F₂ yog perpendicular rau lub beam.

Lub tes tuav 2 (l₂) =r₁ kev txhaum 90^o = (1 m)(1) = 1 m

Xav tau: Tlub net torque txog lub axis ntawm kev sib hloov

Tshuaj:

Lub zog torque 1:

τ₁ =F₁ l₁ = (10 N)(1 m) = 10 N m

Lub cim ntxiv vim yog lub zog ntawm F₁ ua rau lub teeb tig tig counterclockwise.

Lub zog torque 2:

τ₂ =F₂ l₂ = (15 N)(1 m) = -15 N

Lub cim rho tawm vim tias lub zog F₂ ua rau lub beam tig mus rau sab xis.

Lub zog net:

Στ = τ₁ – τ₂ = 10 – 15 = – 5 N m

Lub cim minus vim tias lub beam rau tig mus rau sab xis.

4. Qhov ntev ntawm lub beam AB yog 2 m, Qhov loj ntawm F₁ yog 10 N thiab qhov loj ntawm F₂ is 10 N. Txheeb xyuas qhov net torque nyob ib ncig ntawm qhov chaw nruab nrab ntawm lub beam.

Lub axis ntawm kev sib hloov ntawm qhov chaw ntawm lub beam.

Paub:

Lub zog 1 (F₁) = 10 Nn

Qhov nrug ntawm F₁ thiab qhov chaw nruab nrab ntawm lub beam (r₁) = 1 m

Lub tes tuav 1 (l₁) =r₁ kev txhaum 60^o = (1 m)(0.53= 0.5 TZS3 m

Lub zog 2 (F₂) = 10 N

Qhov nrug ntawm F₂ thiab qhov chaw nruab nrab ntawm lub beam (r₂) = 1 m

Lub zog F₂ yog perpendicular rau lub beam.

Lub tes tuav 2 (l₂) = r₂ kev txhaum 90^o = (1 m)(1) = 1 m

Xav tau: Lub net torque nyob ib ncig ntawm lub axis ntawm kev sib hloov

Tshuaj:

Lub zog torque 1:

τ₁ =F₁ l₁ = (10 N)(0.53 m) = 5√3 = 8.7 Nm

Lub cim ntxiv vim tias lub zog F₁ ua rau lub beam tig mus rau sab xis.

Lub zog torque 2:

τ₂ =F₂ l₂ = (10 N)(1 m) = -10 N m

Lub cim rho tawm vim tias lub zog F₂ ua rau lub beam tig mus rau sab xis.

Lub zog net:

Στ = τ₁ – τ₂ = 8.7 – 10 = – 1.3 N m

Lub cim rho tawm vim tias lub zog net ua rau lub beam tig mus rau sab xis.

5. Qhov ntev ntawm ib lub beam yog 10 m, qhov loj ntawm F₁ yog 10 N, qhov loj ntawm F₂ yog 10 N thiab qhov loj ntawm F₃ yog 15 N. Qhov deb ntawm qhov chaw A thiab qhov chaw C yog 7.5 m. Lub zog F₂ nyob rau hauv nruab nrab ntawm lub beam. Txheeb xyuas lub net torque txog qhov point C nyob ntawm 2.5 m ntawm qhov point B.

Lub axis ntawm kev sib hloov yog nyob ntawm qhov chaw C

Paub:

Lub zog 1 (F₁) = 10 N

Qhov nrug ntawm F₁ thiab taw tes C (r₁) = 2.5 m

Lub zog F₁ yog perpendicular rau lub beam.

Lub tes tuav 1 (l₁) =r₁ kev txhaum 90^o = (2.5 m)(1) = 2.5 m

Lub zog 2 (F₂) = 10 N

Qhov nrug ntawm F₂ thiab taw tes C (r₂) = 2.5 m

Lub zog F₂ yog perpendicular rau lub beam.

Lub tes tuav 2 (l₂) = r₂ kev txhaum 90^o = (2.5 m)(1) = 2.5 m

Lub zog 3 (F₃) = 15 N

Qhov nrug ntawm F₃ thiab taw tes C (r₃) = 7.5 m

Lub zog F₃ yog perpendicular rau lub beam.

Lub tes tuav 3 (l₃) = r₃ kev txhaum 90^o = (7.5 m)(1) = 7.5 m

Xav tau: Lub net torque nyob ib ncig ntawm lub axis ntawm kev sib hloov

Tshuaj:

Lub zog torque 1:

τ₁ =F₁ l₁ = (10 N)(2.5 m) = 25 N m

Lub cim ntxiv vim tias lub zog F₁ ua rau lub beam tig mus rau sab xis.

Lub zog torque 2:

τ₂ =F₂ l₂ = (10 N)(2.5 m) = 25n mav

Tnws lub cim ntxiv vim tias lub zog F₂ ua rau lub beam tig mus rau sab xis.

Lub zog torque 3:

τ₃ =F₃ l₃ = (15 N)(7.5 m) = -112..5 N m

Lub cim rho tawm vim tias lub zog F₃ ua rau lub beam tig mus rau sab xis.

Lub zog net:

Στ = τ₁ + τ₂ – τ₃ = 25 + 25 - 112.5 = – 62.5 N m

Lub cim rho tawm vim tias lub zog net ua rau lub beam tig mus rau sab xis.

6. Qhov ntev ntawm ib lub beam yog 10 m, qhov loj ntawm F₁ yog 10 N, qhov loj ntawm F₂ yog 10 N thiab qhov loj ntawm F₃ yog 10 N. Txheeb xyuas lub zog net torque txog qhov chaw A, nyob 5 m ntawm qhov chawnt ntawm kev siv lub zog F₁.

Lub axis ntawm kev tig ntawm qhov chaw A.

Paub:

Lub zog 1 (F₁) = 10 N

Qhov nrug ntawm F₁ thiab taw tes A (r₁) = 5 m

Lub tes tuav 1 (l₁) =r₁ kev txhaum 60^o = (5 m)(0.53= 2.5 TZS3 m

Force 2 (F)₂) = 10 N

Qhov nrug ntawm F₂ thiab taw tes A (r₂= 0 TZS

Lub zog F₂ yog perpendicular rau lub beam.

Lub tes tuav 2 (l₂) = r₂ kev txhaum 90^o = (0)(1) = 0

Lub zog 3 (F₃) = 10 N

Qhov nrug ntawm F₃ thiab taw tes A (r₃) = 10 m

Lub tes tuav 3 (l₃) = r₃ kev txhaum 30^o = (10 m)(0.5) = 5 m

Xav tau: lub net torque txog lub axis ntawm kev tig

Tshuaj:

Lub zog torque 1:

τ₁ =F₁ l₁ = (10 N)(2.5√3 m) = 25√3 = 43.3 N m

Lub cim ntxiv vim tias lub zog F₁ ua rau lub beam tig mus rau sab xis.

Lub zog torque 2:

τ₂ =F₂ l₂ = (10 N)(0) = 0

Lub zog torque 3:

τ₃ =F₃ l₃ = (10 N)(5 m) = -50 N m

Lub cim rho tawm vim tias lub zog F₃ ua rau lub beam tig mus rau sab xis.

Lub zog net:

Στ = τ₁ + τ₂ – τ₃ = 43.3 + 0 - 50 = – 6.7 N m

Lub cim rho tawm vim tias lub zog net ua rau lub beam tig mus rau sab xis.

nyeem ntxiv

1. A 500-grkuv yog ib yam khoom, A, txav mus rau ntawm 10 m / s thiab khoom 200-gram, B, txav mus rau 12 m/s. Cov khoom txav mus ze rau ib leeg thiab sib tsoo. Yog tias qhov ceev ntawm khoom A tom qab kev sib tsoo yog 6 m/s, qhov ceev ntawm yam khoom B tom qab sib tsoo yog dab tsi?

Paub:

Pawg ntawm yam khoom 1 (m₁) = 500 grams = 0.5 kg

Pawg ntawm yam khoom 2 (m)₂) = 200 grams = 0.2 kg

Initial tshaj tawm ntawm yam khoom 1 (v₁) = -10 m/s

Qhov ceev pib ntawm yam khoom 2 (v₂) = 12 m/s

Qhov ceev kawg ntawm yam khoom 1 (v₁') = 6 m/s

Cov cim ntxiv thiab cov cim tsis qhia qhia tias cov khoom txav mus rau qhov sib txawv.

xav : qhov ceev kawg ntawm yam khoom 2 (v₂')

Tshuaj:

m₁ v₁ +m₂ v₂ = kuv₁ v₁' + m₂ v₂'

(0.5)(-10)+(0.2)(12) = (0.5)(6)+(0.2)(v₂')

-5 + 2.4 = 3 + 0.2 v₂'

-2.6 = 3 + 0.2 v₂'

-2.6 – 3 = 0.2 v₂'

-5.6 = 0.2 v₂'

v₂' = -5.6 / 0.2

v₂' = -28 m/s

Qhov ceev ntawm yam khoom 2 tom qab sib tsoo yog 28 m/s.

Cov cim ntxiv thiab rho tawm qhia tias cov khoom txav mus rau sab nraud.

2. Ob yam khoom sib npaug zos los ze rau ib leeg thiab sib tsoo. Qhov ceev ntawm yam khoom 1 yog 6 m/s thiab qhov ceev ntawm yam khoom 2 yog 8 m/s. Tom qab sib tsoo, yam khoom 2 txav mus rau sab laug nrog qhov ceev ntawm 5 m/s. Qhov loj thiab qhov kev coj ntawm qhov ceev ntawm yam khoom 1 yog dab tsi tom qab kev sib tsoo?

Paub:

Pawg ntawm yam khoom 1 (m)₁) = m

Pawg ntawm yam khoom 2 (m₂) = m

Qhov ceev pib ntawm yam khoom 1 (v₁) = -6 m/s

qhov ceev pib ntawm yam khoom 2 (v₂) = 8 m/s

Qhov ceev kawg ntawm yam khoom 2 (v₂') = -5 m/s

xav : qhov loj thiab kev coj ntawm yam khoom 1 tom qab kev sib tsoo

Tshuaj:

Cov qauv ntawm kev txuag ntawm linear momentum :

m₁ v₁ +m₂ v₂ = kuv₁ v₁' + m₂ v₂'

mv₁ +m v₂ = kuv v₁' + m v₂'

m (v)₁ +v₂) = m(v)₁' + v₂')

v₁ +v₂ = v₁' + v₂'

-6 + 8 = v₁' – 5

2 = v₁' – 5

2 + 5 = v₁'

v₁' = 7 m/s

Qhov ceev ntawm yam khoom 1 tom qab sib tsoo (v₁') is 3 XNUMXm/s.

Cov cim ntxiv thiab rho tawm qhia tias cov khoom txav mus rau sab nraud.

3. Lub pob 1-kg 1 thiab lub pob 2 2-kg muaj tib qho kev taw qhia thiab sib tsoo tsis sib luag. Ua ntej sib tsoo, lub pob 1 txav nrog qhov ceev ntawm 10 m/s thiab lub pob 2 txav nrog qhov ceev ntawm 5 m/s. Qhov ceev ntawm lub pob 2 tom qab sib tsoo yog 4 m/s. Txheeb xyuas qhov ceev ntawm lub pob 1 tom qab sib tsoo.

Paub:

Pawg Pob 1 (m)₁) = 1 kg

Pawg Pob 2 (m)₂) = 2 kg

Qhov ceev ntawm lub pob 1 (hauv₁) = 10 m/s

Qhov ceev ntawm lub pob 2 (v₂) = 5 m/s

Qhov ceev kawg ntawm lub pob 2 (v₂') = 4 m/s

Lub cim ntxiv ntawm qhov ceev qhia tias cov pob muaj tib qho kev taw qhia.

xav : qhov ceev kawg ntawm lub pob 1 (v₁')

Tshuaj:

m₁ v₁ +m₂ v₂ = kuv₁ v₁' + m₂ v₂'

(1)(10) + (2)(5) = (1)(v)₁') + (2)(4)

10 + 10 = v₁' + 8

20 – 8 = v₁'

v₁' = 12 m/s

Qhov ceev ntawm lub pob 1 tom qab sib tsoo yog 12 XNUMXm/s.

[wpdm_package id='1190′]

1. Cov teeb meem thiab kev daws teeb meem ntawm linear momentum
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog thiab lub zog txav mus los
3. Kev sib tsoo zoo kawg nkaus hauv ib qho teeb meem thiab kev daws teeb meem
4. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
5. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem

nyeem ntxiv

1. Ib lub mos txwv hnyav 30-gram uas txav mus los ntawm 30 m/s sib tsoo nrog ib lub thaiv hnyav 1-kg thaum so. Txheeb xyuas qhov ceev ntawm lub thaiv yog tias lub mos txwv thiab lub thaiv xauv ua ke vim yog qhov kev sib tsoo.

Paub:

Pawg ntawm lub mos txwv (m₁) = 30 grams = 0.03 kg

Pawg ntawm thaiv (m₂) = 1 kg

Qhov ceev pib ntawm lub mos txwv (v₁) = 30 m/s

qhov ceev pib ntawm lub thaiv (v₂) = 0 (thaiv thaum so)

xav : qhov ceev ntawm lub mos txwv thiab thaiv tom qab sib tsoo (v')

Tshuaj:

m₁ v₁ +m₂ v₂ = (m₁ +m₂) v'

(0.03)(30) + (1)(0) = (0.03 + 1) v'

0.9 + 0 = 1.03 v'

0.9 = 1,03 v'

v' = 0.9 / 1,03

v' = 0.87 m/s

2. Lub pob Billiard A uas hnyav 2 kg txav mus nrog qhov ceev v_A = 6 ms^-1 sib tsoo taub hau nrog lub pob B uas muaj qhov hnyav sib npaug. Yog tias qhov kev sib tsoo tsis sib luag, qhov ceev ntawm ob lub pob tom qab kev sib tsoo yog dab tsi.

Paub:

Qhov hnyav A (m_A) = 2 kg

Qhov hnyav B (m_B) = 2 kg

Qhov ceev pib ntawm lub pob A (v_A) = -6 m/s

Qhov ceev pib ntawm lub pob B (v_B) = 4 m/s

Cov cim ntxiv thiab cov cim tsis qhia qhia tias cov khoom txav mus rau qhov sib txawv.

xav: qhov ceev ntawm ob lub pob tom qab kev sib tsoo. (v')

Tshuaj:

m_A v_A +m_B v_B = (m_A' + m_B) v'

(2)(-6) + (2)(4) = (2 + 2) v'

-12 + 8 = 4 v'

-4 = 4 v'

v' = -4 / 4

v' = -1 m/s

3. m₁ = 3 kg thiab m₂ = 4 kg mus txog ib leeg rau ib leeg hauv kev taw qhia sib txawv nrog kev nrawm ntawm v₁ = 10 m/s thiab v₂ = 12 m/s. Yog tias qhov kev sib tsoo tsis muaj zog kiag li, qhov ceev ntawm ob lub pob tom qab kev sib tsoo yog dab tsi.

Paub:

Pawg yam khoom 1 (m)₁) = 3 kg

Pawg yam khoom 2 (m)₂) = 4 kg

Qhov ceev ntawm yam khoom 1 (v₁) = -10 m/s

Qhov ceev ntawm yam khoom 2 (v₂) = 12 m/s

xav : qhov ceev tom qab sib tsoo (v')

Tshuaj:

m₁ v₁ +m₂ v₂ = (m₁' + m₂) v'

(3)(-10) + (4)(12) = (3 + 4) v'

-30 + 48 = 7 v'

18 = 7 v'

v' = 18 / 7

v' = 2.6 m/s

[wpdm_package id='1157′]

1. Cov teeb meem thiab kev daws teeb meem ntawm linear momentum
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog thiab lub zog txav mus los
3. Kev sib tsoo zoo kawg nkaus hauv ib qho teeb meem thiab kev daws teeb meem
4. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
5. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem

nyeem ntxiv

1. Ib lub pob A hnyav 200-gram, txav mus los ntawm qhov ceev 10 m/s, ntaus lub pob B hnyav 200-gram, thaum so. Qhov ceev ntawm lub pob A thiab lub pob B yog dab tsi tom qab kev sib tsoo?

Paub:

Pawg ntawm lub pob A (m_A) = 200 grams = 0.2 kg

Qhov hnyav ntawm lub pob B (m_B) = 200 grams = 0.2 kg

Qhov ceev ntawm lub pob A ua ntej sib tsoo (v_A) = 10 m/s

Qhov ceev ntawm lub pob B ua ntej sib tsoo (v)_B= 0 TZS

SE pob: qhov ceev ntawm lub pob A (v_A') thiab qhov ceev ntawm lub pob B (v_B') tom qab muaj kev sib tsoo

Tshuaj:

v_A' = v_B = 0

v_B' = v_A = 10 m/s

2. Ob yam khoom uas muaj qhov hnyav sib npaug zos los ze rau ib leeg, sib tsoo thiab tom qab ntawd dhia tawm. Qhov ceev ntawm qhov hnyav A ua ntej sib tsoo yog 8 m/s thiab qhov ceev ntawm qhov hnyav B ua ntej sib tsoo yog 12 m/s. Qhov loj thiab qhov kev taw qhia ntawm qhov no yog dab tsi? tshaj tawm ntawm pawg A thiab pawg B tom qab kev sib tsoo!

Paub:

Qhov hnyav A (m_A) = m

Qhov hnyav B (m_B) = m

Qhov ceev ntawm pawg A ua ntej kev sib tsoo (v_A) = -8 m/s

Qhov ceev ntawm pawg B ua ntej sib tsoo (v_B) = 12 m/s

Cov cim ntxiv thiab rho tawm qhia tias cov khoom txav mus rau sab nraud.

SE pob: qhov loj thiab kev coj ntawm qhov ceev ntawm pawg A (v)_A') thiab pawg B (v_B') tom qab muaj kev sib tsoo

Tshuaj:

Hauv kev sib tsoo uas ywj pheej zoo kawg nkaus, yog tias cov khoom muaj qhov hnyav sib npaug ces qhov ceev ntawm A tom qab kev sib tsoo (v_A') = qhov ceev ntawm B ua ntej sib tsoo (v)_B) thiab qhov ceev ntawm B tom qab kev sib tsoo (v_B') = qhov ceev ntawm A ua ntej sib tsoo (v_A).

Yog tias ua ntej sib tsoo, A txav mus rau sab xis thiab B txav mus rau sab laug, ces, tom qab sib tsoo, A txav mus rau sab laug thiab B txav mus rau sab xis.

Cov khoom muaj qhov hnyav sib npaug thiab kev sib tsoo yog elastic zoo kawg nkaus yog li ob qho khoom sib pauv qhov ceev.

v_A' = -v_B = -12 m/s

v_B' = v_A = 8 m/s

Cov cim ntxiv thiab rho tawm qhia tias cov khoom txav mus rau sab nraud.

3. Ib yam khoom hnyav 2-kg, A, txav mus nrog qhov ceev 10 m/s, ntaus ib lub pob hnyav 4-kg, B, txav mus nrog qhov ceev 20 m/s. Yog tias qhov kev sib tsoo yog elastic zoo kawg nkaus, qhov ceev ntawm yam khoom A thiab yam khoom B yog dab tsi tom qab kev sib tsoo?

Paub:

Qhov hnyav A (m_A) = 2 kg

Qhov hnyav B (m_B) = 4 kg

Qhov ceev ntawm yam khoom A ua ntej sib tsoo (v_A) = 10 m/s

Qhov ceev ntawm yam khoom B ua ntej sib tsoo (v_B) = 20 m/s

xav : qhov ceev ntawm yam khoom A (v_A') thiab qhov ceev ntawm yam khoom B (v_B') tom qab kev sib tsoo

tshuaj :

In kev sib tsoo zoo kawg nkaus elastic, yog tias cov khoom muaj qhov hnyav sib npaug thiab los ze rau ib leeg, qhov ceev ntawm cov khoom tom qab sib tsoo raug suav los ntawm kev siv cov mis no:

Qhov ceev ntawm yam khoom A tom qab kev sib tsoo:

4. Ib yam khoom hnyav 100-gram txav mus los ntawm 20 m/s tsoo ib phab ntsa uas sib tsoo tau zoo heev. Qhov loj thiab qhov kev coj ntawm qhov ceev ntawm yam khoom tom qab sib tsoo yog dab tsi.

Paub:

Qhov hnyav (m_A) = 100 grams = 0.1 kg

Qhov hnyav ntawm phab ntsa (m_B) = tsis muaj qhov kawg

Qhov ceev ntawm lub cev ua ntej sib tsoo (v)_A) = 20 m/s

Qhov ceev ntawm pawg tom qab sib tsoo (v)_B= 0 TZS

xav : qhov loj thiab kev coj ntawm qhov ceev tom qab kev sib tsoo

Tshuaj:

Yog tias v_B = 0, m_A me me heev thiab m₂ loj heev ces v_A' = -v_A thiab v₂' = 0.

Cov cim ntxiv thiab rho tawm qhia tias cov khoom txav mus rau sab nraud.

5. Ob lub pob, A nrog ib pawg ntawm 2 kg thiab pob B nrog qhov hnyav ntawm 5-kg, ua ntej thiab tom qab kev sib tsoo tau qhia nyob rau hauv daim duab hauv qab no. Yog tias kev sib tsoo yog elastic zoo kawg nkaus, qhov ceev ntawm lub pob A ua ntej kev sib tsoo yog dab tsi?

Paub:

Qhov hnyav ntawm lub pob Ib (m_A) = 2 kg

Qhov hnyav ntawm lub pob B (m_B) = 5 kg

Qhov ceev ntawm lub pob B ua ntej sib tsoo (v_B) = 2 m/s

Qhov ceev ntawm lub pob A tom qab kev sib tsoo (v_A') = 5 m/s

Kev ceev ntawm lub pob B tom qab kev sib tsoo (v_B') = 4 m/s

Ob lub pob txav mus rau sab xis yog li lawv qhov ceev kos npe zoo.

Xav tau: Qhov ceev ntawm lub pob A ua ntej kev sib tsoo (v_A)

Tshuaj:

m_A v_A +m_B v_B = kuv_A v_A' + m_B v_B'

2(v)_A) + (5)(2) = (2)(5) + (5)(4)

2(v)_A) + 10 = 10 + 20

2(v)_A) + 10 = 30

2(v)_A) = 30 – 10

2(v)_A= 20 TZS

v_A = 20 / 2

v_A = 10 m/s

6. Cov khoom A thiab B mus ncig raws kab rov tav, raws li pom hauv daim duab hauv qab no. Yog tias qhov kev sib tsoo yog elastic zoo kawg nkaus thiab qhov ceev ntawm cov khoom B tom qab kev sib tsoo yog 15 m / s¹, qhov ceev ntawm yam khoom A tom qab sib tsoo yog dab tsi.

Paub:

Qhov hnyav ntawm yam khoom Ib (m_A) = 5 kg

Qhov hnyav ntawm yam khoom B (m_B) = 2 kg

Qhov ceev ntawm yam khoom A ua ntej sib tsoo (v_A) = 12 m/s

Qhov ceev ntawm yam khoom B ua ntej sib tsoo (v_B) = 10 m/s

Qhov ceev ntawm yam khoom B tom qab sib tsoo (v_B') = 15 m/s

Ob qho khoom, ua ntej thiab tom qab sib tsoo, txav mus rau sab xis kom lawv qhov ceev kos npe zoo.

Xav tau: Qhov ceev ntawm yam khoom A tom qab sib tsoo (v_A')

Tshuaj:

m_A v_A +m_B v_B = kuv_A v_A' + m_B v_B'

(5)(12) + (2)(10) = (5)v_A' + (2)(15)

60 + 20 = (5)v_A' + 30

80 = (5)v_A' + 30

80 – 30 = (5)v_A'

50 = (5)v_A'

v_A' = 50/5

v_A' = 10 m/s

[wpdm_package id='1156′]

1. Cov teeb meem thiab kev daws teeb meem ntawm linear momentum
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog thiab lub zog txav mus los
3. Kev sib tsoo zoo kawg nkaus hauv ib qho teeb meem thiab kev daws teeb meem
4. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
5. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem

nyeem ntxiv

1. Muaj ib lub pob me me pov rau ntawm ib sab nrog qhov ceev tas li ntawm 10 m/s. Lub pob ntaus rau ntawm phab ntsa thiab cuam tshuam nrog tib qhov ceev. Qhov kev hloov pauv yog dab tsi? lub zog linear ntawm lub pob?

Paub:

Pawg (m) = 0.2 kg

Qhov ceev pib (v_o) = -10 m/s

Qhov ceev kawg (v_t) = 10 m/s

Cov cim ntxiv thiab cov cim tsis qhia qhia tias cov khoom txav mus rau qhov sib txawv.

xav : kev hloov pauv ntawm lub zog linear (Δp)

Tshuaj:

Cov qauv ntawm kev hloov pauv ntawm linear momentum :

Δp = mv_t – mv_o = m (v)_t -v_o)

Kev hloov pauv ntawm lub zog linear:

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

Δ p = 4 kg m/s

2. Ib lub pob 10-gram poob dawb paug los ntawm qhov siab, ntaus hauv pem teb ntawm 15 m/s, tom qab ntawd cuam tshuam rau saum ntuj ntawm 10 m/s. Txheeb xyuas lub zog!

Paub:

Qhov hnyav (m) = 10 grams = 0.01 kg

Qhov ceev pib (v_o) = -15 m/s

Qhov ceev kawg (v_t) = 10 m/s

Xav tau: Impulse (I)

Tshuaj:

Lub zog (I) sib npaug rau qhov kev hloov pauv ntawm lub zog (Δp)

Kuv = mv_t – mv_o = m (v)_t -v_o)

Lub zog ua ntej:

Kuv = 0.01 (10 – (-15)) = 0.01 (10 + 15)

Kuv = 0.01 (25)

Kuv = 0.25 kg m/s

3. Muab pov ib lub pob 200-gram kab rov tav nrog qhov ceev ntawm 4 m/s, ces muab lub pob ntaus rau tib qho kev taw qhia. Lub sijhawm ntawm lub pob kov nrog lub ntaus pob yog 2 milli vib nas this thiab lub pob ceev tom qab tawm hauv lub ntaus pob yog 12 m/s. Lub qhov loj ntawm quab yuam ua haujlwm los ntawm tus neeg ntaus pob ntawm lub pob yog ...

Paub:

Qhov hnyav (m) = 200 grams = 0.2 kg

Qhov ceev pib (v_o) = 4 m/s

Qhov ceev kawg (v_t) = 12 m/s

Lub sijhawm luv (t) = 2 milliseconds = (2/1000) vib nas this = 0.002 vib nas this

xav Qhov loj ntawm lub zog (F)

Tshuaj:

Cov qauv ntawm lub zog:

Kuv = Ft

Tus qauv ntawm kev hloov pauv ntawm momentum:

mv_t – mv_o = m (v)_t -v_o)

Lub zog (I) sib npaug rau qhov kev hloov pauv ntawm lub zog (Δp)

Kuv = Δp

Ft = m (v)_t -v_o)

F (0.002) = (0.2)(12 – 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Newtons

[wpdm_package id='1155′]

1. Cov teeb meem thiab kev daws teeb meem ntawm linear momentum
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog thiab lub zog txav mus los
3. Kev sib tsoo zoo kawg nkaus hauv ib qho teeb meem thiab kev daws teeb meem
4. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
5. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem

nyeem ntxiv

1. Ib yam khoom mus ncig nrog qhov ceev tas li 10 m/s. Xam qhov lub zog linear ntawm tus khoom.

Paub Tias :

Pawg (m) = 1 kg

Tshaj tawm (v) = 10 m/s

Xav tau: lub zog linear (p)

Tshuaj:

Cov qauv ntawm lub zog linear:

p = mv

p = linear momentum, m = mass, v = velocity

Lub zog linear:

p = mv = (1)(10) = 10 kg m/s²

2. Ib lub thaiv 2-kg thiab ib lub thaiv 4-kg txav mus los ntawm qhov ceev tas li 20 m/s. Lub zog ntawm cov thaiv yog dab tsi?

Paub:

Pawg ntawm thaiv Ib (m_A) = 2 kg

Pawg ntawm thaiv B (m_B) = 4 kg

Qhov ceev ntawm thaiv A (v_A) = 20 m/s

Qhov ceev ntawm thaiv B (v_B) = 20 m/s

Xav tau: Lub zog ntawm lub block A (p)_A) thiab linear momentum ntawm block B (p_B)

Tshuaj:

Lub zog ntawm lub block A :

p_A = kuv_A v_A = (2)(20) = 40 kg m/s

Lub zog ntawm lub block B :

p_B = kuv_B v_B = (4)(20) = 80 kg m/s

3. Ib lub thaiv 2-kg txav ntawm qhov ceev tas li 2 m/s thiab ib lub thaiv 2-kg txav ntawm qhov ceev tas li 4 m/s. Txheeb xyuas qhov momentum linear ntawm cov thaiv.

Paub:

Pawg ntawm thaiv Ib (m_A) = 2 kg

Qhov hnyav ntawm lub block B (m_B) = 2 kg

Qhov ceev ntawm lub thaiv A (v)_A) = 2 m/s

Qhov ceev ntawm thaiv B (v_B) = 4 m/s

Xav tau: lub zog linear ntawm cov blocks

Tshuaj:

Kab ncaj momentum ntawm thaiv A :

p_A = kuv_A v_A = (2)(2) = 4 kg m/s

Lub zog linear ntawm thaiv B:

p_B = kuv_B v_B = (2)(4) = 8 kg m/s

4. Ib yam khoom hnyav 5-kg uas so. Lub zog ntawm lub zog ntawd yog dab tsi?

Paub:

Qhov hnyav (m) = 5 kg

Qhov ceev ntawm cov khoom (v) = 0

xav : lub zog linear (p.) v

Tshuaj:

p = mv = (5)(0) = 0

[wpdm_package id='1155′]

1. Cov teeb meem thiab kev daws teeb meem ntawm linear momentum
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog thiab lub zog txav mus los
3. Kev sib tsoo zoo kawg nkaus hauv ib qho teeb meem thiab kev daws teeb meem
4. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
5. Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem

nyeem ntxiv

Lub zog yog qhov nrawm uas ua haujlwm tiav hauv ib lub sijhawm. Hauv kev suav lej, lub zog yog qhov sib piv ntawm kev ua haujlwm/lub sijhawm.

P = W/t

Kev piav qhia: P = lub zog (Joule/ob = Watt), W = ua haujlwm (Joule), t = lub sijhawm luv (ob)

Raws li qhov sib npaug no, nws tuaj yeem xaus lus tias qhov ua haujlwm ntau dua, lub zog ntau dua. Ntawm qhov tod tes, qhov ua haujlwm me dua, lub zog me dua. Kev ua haujlwm txhais tau tias qhov ua haujlwm tiav.

Lub zog yog ib qho scalar. Chav SI ntawm lub zog yog Joule/ob. Joule/ob = Watt (luv ua W), hu ua li ntawd los ua kev hwm rau James Watt. Chav imperial Askiv rau lub zog yog foot-pounds ib ob.

Lub tshuab no me dhau rau kev siv tau, yog li ntawd, siv lub zog loj dua (hu ua hp). Ib lub zog = 550 foot-pounds ib ob = 764 Watts = ¾ kilowatt.

Tus nqi ntawm txoj haujlwm kuj tseem tuaj yeem qhia ua lub zog x lub sijhawm, piv txwv li, kilowatt-teev lossis kWh. Ib kWh txhais tau tias txoj haujlwm ua tiav ntawm tus nqi tas li ntawm 1 kiloWatt rau ib teev.

1. Ib qho 50-kg tus neeg khiav nce ntaiv 10 meters siab in 2 feeb. Akev ua kom nrawm vim lub ntiajteb txawj nqus (g) yog 10 m/s². Txiav txim lub hwj chim.

Paub:

Pawg (m) = 50 kg

Qhov siab (h) = 10 meters

Acceleration vim lub ntiajteb txawj nqus (g) = 10 m/s²

Lub sijhawm luv (t) = 2 feeb = 2 (60) = 120 thib obs

xav : hwj chim (P)

Tshuaj:

Tus qauv ntawm lub zog:

P = W / t

P = hwj chim, W = ua hauj lwm, t = lub sij hawm

Tus qauv ua haujlwm:

W = F s = wh = mgh

W = ua hauj lwm, F = quab yuam, wb = hnyav, d = xaav, h = qhov siab, m = pawg, g = acceleration vim lub ntiajteb txawj nqus

W = mgh = (50)(10)(10) = 5000 Joules.

P = W / t = 5000 / 120 = 41.7 Joules / second.

2. Xam lub zog uas ib tug neeg hnyav 60-kg xav tau thaum nce ntoo siab 5 meters hauv 10 vib nas this. Kev nrawm vim lub ntiajteb txawj nqus yog 10 m/s.².

Paub:

Qhov hnyav (m) = 60 kg

Qhov siab (h) = 5 meterss

Acceleration vim lub ntiajteb txawj nqus (g) = 10 m/s²

Lub sijhawm luv (t) = 10 vib nas this

xav : hwj chim

Tshuaj:

Ua Haujlwm:

W = mgh = (60)(10)(5) = 3000 Joules

Lub hwj chim:

P = W / t = 3000 / 10 = 300 Joules / second.

3. Ib lub tshuab ua yeeb yam rotary uas muaj zog 300 watts thiab lub sijhawm tig 5 feeb. Lub zog uas nws siv yog….

A. 15 kJ

B. 75 kJ

C. 90 kJ

D. 450 kJ

Paub:

Lub zog (P) = 300 Watts = 300 Joules/ob

Lub Sijhawm (T) = 5 feeb = 5 (60 vib nas this) = 300 vib nas this

Tus naj npawb ntawm kev tig = 5

SE pob: Lub zog siv los ntawm kev ua yeeb yam rotary

Tshuaj:

Cov lus teb yog D.

[wpdm_package id='1190′]

1. Ua haujlwm tau ua tiav los ntawm kev siv zog teeb meem thiab kev daws teeb meem
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm-kinetic
3. Cov teeb meem thiab kev daws teeb meem ntawm lub hauv paus ntsiab lus ntawm lub zog ua haujlwm-mechanical
4. Cov teeb meem thiab kev daws teeb meem ntawm lub zog gravitational
5. Lub zog muaj peev xwm ntawm cov teeb meem caij nplooj ntoos hlav elastic thiab kev daws teeb meem
6. Teeb meem fais fab thiab kev daws teeb meem
7. Kev siv ntawm kev txuag lub zog mechanical rau kev txav mus los dawb
8. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus rau saum thiab nqis hauv kev txav mus los dawb
9. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm qhov chaw nkhaus
10. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm lub dav hlau inclined
11. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm projectile

nyeem ntxiv

1. Ib lub thaiv swb rau ntawm qhov du lub dav hlau inclined tsis muaj kev sib txhuam. Dab tsi yog thaiv tshaj tawm thaum ntaus hauv av. Kev nrawm vim lub ntiajteb txawj nqus yog 10 m/s²

Paub:

Qhov siab (h) = 8 m

Acceleration vim lub ntiajteb txawj nqus (g) = 10 m/s²

xav : qhov ceev (v)

tshuaj :

Lub zog kho tshuab pib (ME_o) = lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus (PE)

ME_o PE = mgh = m (10)(8) = 80 m

Lub zog kho tshuab kawg (ME_t) = kev tig tau lub zog (TAU)

ME_t = KE = ½ mv²

Lub hauv paus ntsiab lus ntawm kev txuag lub zog tshuab hais tias thawj zaug txhua yam zog = lub zog kho tshuab kawg:

ME_o = KUV_t

80 m = ½ mv²

80 = ½ v²

160 = v²

v = √160 = √(16)(10) = 4√10 m/s

2. Ib yam khoom hnyav 1-kg swb nqes mus raws 8 meters. Txheeb xyuas lub zog kinetic tom qab yam khoom txav mus raws 5 meters… Kev nrawm vim lub ntiajteb txawj nqus g = 10 m/s²

Paub:

Qhov hnyav (m) = 0.2 kg

d = 5 meters

Kev nrawm vim lub ntiajteb txawj nqus (g) = 10 m/s²

xav lub zog kinetic (KE)

Tshuaj:

kev txhaum 30^o = h / hnub

0.5 = h / 5

h = (0.5)(5) = 2.5 meters

Qhov kev hloov pauv ntawm qhov siab ntawm cov khoom yog 2.5 meters.

Lub zog kho tshuab pib (ME)_o) = lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus (PE)

ME_o = PE = mgh = (1)(10)(2.5) = 25 Joules

Lub zog kho tshuab kawg (ME)_t) = lub zog kinetic (KE)

ME_t = RAU

Lub hauv paus ntsiab lus ntawm kev txuag hluav taws xob hais tias lub zog kho tshuab pib = lub zog kho tshuab kawg:

ME_o = KUV_t

25 = KE

Lub zog Kinetic = 25 Joule.

[wpdm_package id='1170′]

1. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm-kinetic
3. Cov teeb meem thiab kev daws teeb meem ntawm lub hauv paus ntsiab lus ntawm lub zog ua haujlwm-mechanical
4. Cov teeb meem thiab kev daws teeb meem ntawm lub zog gravitational
5. Lub zog muaj peev xwm ntawm cov teeb meem caij nplooj ntoos hlav elastic thiab kev daws teeb meem
6. Teeb meem fais fab thiab kev daws teeb meem
7. Kev siv ntawm kev txuag lub zog mechanical rau kev txav mus los dawb
8. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus rau saum thiab nqis hauv kev txav mus los dawb
9. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm qhov chaw nkhaus
10. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm lub dav hlau inclined
11. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm projectile

nyeem ntxiv

1. Ib lub thaiv 1-kg swb rau ntawm qhov chaw du thiab nkhaus. Txheeb xyuas qhov kev tig tau lub zog thiab qhov ceev ntawm lub thaiv ntawm qhov chaw qis tshaj plaws. Acceleration vim lub ntiajteb txawj nqus yog 10 m/s².

Paub:

Pawg (m) = 1 kg

Qhov kev hloov pauv ntawm qhov siab (h) = 5 m

Kev nrawm vim lub ntiajteb txawj nqus (g) = 10 m/s²

SE pob: Lub zog Kinetic (KE) thiab tshaj tawm ntawm lub thaiv.

Tshuaj:

(a) Lub zog Kinetic

thawj zaug txhua yam zog = lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus

ME_o = PE = mgh = (1)(10)(5) = 50 Joules

Lub zog tshuab kawg = lub zog kinetic

ME_t = KE = ½ mv_t²

Ntsiab Cai ntawm kev txuag hluav taws xob hais tias lub zog kho tshuab pib = lub zog kho tshuab kawg:

ME_o = KUV_t

PE = KE

50 = KE

Lub zog Kinetic (KE) = 50 Joules.

(b) Qhov ceev ntawm lub thaiv

Lub hauv paus ntsiab lus ntawm kev txuag lub zog tshuab:

Lub zog kho tshuab pib (ME)_o) = lub zog kho tshuab kawg (ME_t)

Lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus (PE) = lub zog kinetic (KE)

50 = ½ mv²

2(50) / m = v²

100 / 1 = v²

100 = v²

v = √100

v = 10 m/s

2. Ib yam khoom hnyav 2-kg swb nqes los yam tsis muaj kev sib txhuam. Lub zog kinetic thiab qhov ceev ntawm yam khoom ntawm 2 meters saum av yog dab tsi? Kev nrawm vim lub ntiajteb txawj nqus yog 10 m/s²

Paub:

Qhov hnyav (m) = 2 kg

Qhov kev hloov ntawm qhov siab (h) = 10 – 2 = 8 m

Kev nrawm vim lub ntiajteb txawj nqus (g) = 10 m/s²

xav : lub zog kinetic (KE) thiab qhov ceev (v) ntawm 2 meters saum av.

Tshuaj:

(a) Lub zog Kinetic ntawm 2 meters saum av

Lub zog pib ntawm lub tshuab = lub zog gravitational

ME_o = PE = mgh = (2)(10)(8) = 160 Joules

Lub zog tshuab kawg = lub zog kinetic

ME_t = KE = ½ mv_t²

Lub hauv paus ntsiab lus ntawm kev txuag lub zog tshuab hais tias lub zog tshuab pib = lub zog tshuab kawg:

ME_o = KUV_t

PE = KE

160 = KE

Lub zog Kinetic (KE) ntawm 2 meters saum av yog 160 Joules.

(b) Qhov ceev ntawm yam khoom ntawm qhov chaw qis tshaj plaws

Lub hauv paus ntsiab lus ntawm kev txuag lub zog kho tshuab:

Lub zog kho tshuab pib (ME)_o) = lub zog kho tshuab kawg (EM_t)

Lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus (PE) = lub zog kinetic (KE)

160 = ½ mv²

160 = ½ (2) v²

160 = v²

v = √160 = √(16)(10) = 4√10 m/s

[wpdm_package id='1167′]

1. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm-kinetic
3. Cov teeb meem thiab kev daws teeb meem ntawm lub hauv paus ntsiab lus ntawm lub zog ua haujlwm-mechanical
4. Cov teeb meem thiab kev daws teeb meem ntawm lub zog gravitational
5. Lub zog muaj peev xwm ntawm cov teeb meem caij nplooj ntoos hlav elastic thiab kev daws teeb meem
6. Teeb meem fais fab thiab kev daws teeb meem
7. Kev siv ntawm kev txuag lub zog mechanical rau kev txav mus los dawb
8. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus rau saum thiab nqis hauv kev txav mus los dawb
9. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm qhov chaw nkhaus
10. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm lub dav hlau inclined
11. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm projectile

nyeem ntxiv

1. Ib lub pob ncaws pob uas raug ncaws tawm hauv av ntawm lub kaum sab xis θ = 30^o nrog rau qhov ceev pib ntawm 10 m/s. Pob loj = 0.1kg. Acceleration vim lub ntiajteb txawj nqus yog 10 m / s². Txheeb xyuas (a) Qhov lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus ntawm qhov chaw siab tshaj plaws (b) Qhov chaw siab tshaj plaws lossis qhov siab tshaj plaws

Paub:

Qhov hnyav (m) = 0.1 kg

Qhov ceev pib (v_o) = 10 m/s

Lub kaum sab xis = 30^o

Kev nrawm vim lub ntiajteb txawj nqus (g) = 10 m/s²

Tshuaj:

(a) Lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus

Xam cov khoom kab rov tav (v_ox) thiab qhov feem ntsug (v_oy) ntawm qhov ceev pib.

v_ox = v_o cos θ = (10)(cos 30^o) = (10)(0.5√3) = 5√3 m/s

v_oy = v_o kev txhaum θ = (10)(kev txhaum 30^o) = (10)(0.5) = 5 m/s

Lub zog pib ntawm lub tshuab

thawj zaug txhua yam zog (Kuv_o) = kev tig tau lub zog (TAU)

ME_o = KE = ½ mv_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 Joules

Lub zog kho tshuab kawg

Lub zog Kinetic ntawm qhov siab tshaj plaws:

KE = ½ mv_ox² = ½ (0.1)(5√3)² = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Joules

Lub hauv paus ntsiab lus ntawm kev txuag lub zog tshuab

Lub zog kho tshuab pib (ME)_o) = lub zog kho tshuab kawg (ME_t)

KE = PE + KE

5 = EP + 3.75

PE = 5 – 3.75 = 1.25 Joule

Lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus ntawm qhov chaw siab tshaj plaws yog 1.25 Joules.

(b) Qhov siab tshaj plaws lossis qhov siab tshaj plaws

PE = mg/h

1.25 = (0.1)(10) teev

1.25 = teev

Qhov siab tshaj plaws yog 1.25 meters.

2. Ib lub pob 0.1-kg raug tso tawm kab rov tav nrog qhov ceev pib v_o = 10 m/s ntawm lub tsev siab 10 meters. Kev nrawm vim yog lub ntiajteb txawj nqus yog 10 m/s²Txheeb xyuas lub zog kinetic ntawm lub pob thaum nws ntaus hauv av.

Paub:

Qhov hnyav (m) = 0.1 kg

Qhov ceev pib (v_o) = 10 m/s

Kev nrawm vim lub ntiajteb txawj nqus (g) = 10 m/s²

Qhov kev hloov ntawm qhov siab (h) = 10 – 2 = 8 m

SE pob: lub zog kinetic ntawm 2 meters saum av

Tshuaj:

Lub zog muaj peev xwm ntawm lub ntiajteb txawj nqus (PE) = mgh = (0.1)(10)(10) = 10 Joules

Lub zog pib kinetic (KE) = ½ mv_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 Joules

Lub zog kinetic kawg = lub zog gravitational thawj zaug + lub zog kinetic thawj zaug = 10 + 5 = 15 Joules

[wpdm_package id='1173′]

1. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm
2. Cov teeb meem thiab kev daws teeb meem ntawm lub zog ua haujlwm-kinetic
3. Cov teeb meem thiab kev daws teeb meem ntawm lub hauv paus ntsiab lus ntawm lub zog ua haujlwm-mechanical
4. Cov teeb meem thiab kev daws teeb meem ntawm lub zog gravitational
5. Lub zog muaj peev xwm ntawm cov teeb meem caij nplooj ntoos hlav elastic thiab kev daws teeb meem
6. Teeb meem fais fab thiab kev daws teeb meem
7. Kev siv ntawm kev txuag lub zog mechanical rau kev txav mus los dawb
8. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus rau saum thiab nqis hauv kev txav mus los dawb
9. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm qhov chaw nkhaus
10. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm lub dav hlau inclined
11. Kev siv ntawm kev txuag lub zog kho tshuab rau kev txav mus los ntawm projectile

nyeem ntxiv