1. Ib yam khoom khiav nrawm li ntawm 10 m/s tas li. Xam lub zog ntawm yam khoom ntawd.
Paub :
Qhov hnyav (m) = 1 kg
Qhov ceev (v) = 10 m/s
Xav tau: lub zog linear (p)
Tshuaj:
Cov qauv ntawm lub zog linear:
p = mv
p = linear momentum, m = mass, v = velocity
Lub zog linear:
p = mv = (1)(10) = 10 kg m/s 2
[irp]
2. Ib lub thaiv 2-kg thiab ib lub thaiv 4-kg txav mus los ntawm qhov ceev tas li 20 m/s. Lub zog ntawm cov thaiv yog dab tsi?
Paub:
Qhov hnyav ntawm thaiv A (m A ) = 2 kg
Qhov hnyav ntawm thaiv B (mB ) = 4 kg
Qhov ceev ntawm thaiv A (v A ) = 20 m/s
Qhov ceev ntawm thaiv B (v B ) = 20 m/s
Xav tau: Lub zog linear ntawm block A (p A ) thiab lub zog linear ntawm block B (p B )
Tshuaj:
Lub zog linear ntawm thaiv A :
p A = m A v A = (2)(20) = 40 kg m/s
Lub zog ntawm lub block B :
p B = m B v B = (4)(20) = 80 kg m/s
[irp]
3. Ib lub thaiv 2-kg txav ntawm qhov ceev tas li 2 m/s thiab ib lub thaiv 2-kg txav ntawm qhov ceev tas li 4 m/s. Txheeb xyuas lub zog linear ntawm cov thaiv.
Paub:
Qhov hnyav ntawm thaiv A (m A ) = 2 kg
Qhov hnyav ntawm thaiv B (mB ) = 2 kg
Qhov ceev ntawm thaiv A (v A ) = 2 m/s
Qhov ceev ntawm thaiv B (v B ) = 4 m/s
Xav tau: lub zog linear ntawm cov blocks
Tshuaj:
Lub zog linear ntawm thaiv A :
p A = m A v A = (2)(2) = 4 kg m/s
Lub zog linear ntawm thaiv B:
p B = m B v B = (2)(4) = 8 kg m/s
[irp]
4. Ib yam khoom hnyav 5-kg uas so. Lub zog ntawm lub zog ntawd yog dab tsi?
Paub:
Qhov hnyav (m) = 5 kg
Qhov ceev ntawm yam khoom (v) = 0
Xav tau : lub zog linear (p)
Tshuaj:
p = mv = (5)(0) = 0
[wpdm_package id='1155′]
- Cov teeb meem thiab kev daws teeb meem ntawm linear momentum
- Cov teeb meem thiab kev daws teeb meem ntawm lub zog thiab lub zog txav mus los
- Kev sib tsoo zoo kawg nkaus hauv ib qho teeb meem thiab kev daws teeb meem
- Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
- Kev sib tsoo tsis sib xws hauv ib qho teeb meem thiab kev daws teeb meem
