Daws cov teeb meem hauv Newton txoj cai ntawm kev txav mus los - Lub zog ntawm qhov static thiab kinetic friction
1. Ib yam khoom nyob rau hauv pem teb kab rov tav. Tus coefficient ntawm static friction yog 0.4 thiab acceleration ntawm gravity yog 9.8 m/s 2. Txheeb xyuas (a) Lub zog siab tshaj plaws ntawm static friction (b) Lub zog tsawg kawg nkaus ntawm F

tshuaj

Paub:
Qhov hnyav (m) = 1 kg
Tus coefficient ntawm kev sib txhuam zoo li qub (μs ) = 0.4
Qhov kev nrawm ntawm lub ntiajteb txawj nqus (g) = 9.8 m/s 2
Qhov hnyav (w) = mg = (1 kg) (10 m/s 2 ) = 10 kg m/s 2 = 10 Newtons
Lub zog ib txwm (N) = w = 10 Newtons
Xav tau:
(a) Lub zog siab tshaj plaws ntawm kev sib txhuam static (b) Lub zog tsawg kawg nkaus ntawm F
Tshuaj:
(a) Lub zog siab tshaj plaws ntawm kev sib txhuam zoo li qub
f s = μ s N
fs = (0.4)(9.8 N) = 3.92 Newtons
(b) Lub zog tsawg kawg nkaus ntawm F
Yog tias lub zog F siv rau ntawm yam khoom tab sis yam khoom tsis txav mus, yog li ntawd yuav tsum muaj lub zog ntawm kev sib txhuam zoo li qub uas hauv pem teb siv rau ntawm yam khoom. Yog tias yam khoom yuav pib txav mus, lub zog ntawm kev sib txhuam zoo li qub dhau lawm, yuav tsum muaj lub zog ntawm kev sib txhuam kinetic. Yam khoom pib txav mus yog tias F loj dua lub zog siab tshaj plaws ntawm kev sib txhuam zoo li qub.
Yog li ntawd, lub zog tsawg kawg nkaus ntawm F = lub zog siab tshaj plaws ntawm kev sib txhuam zoo li qub = 3.92 Newtons.
[irp]
2. Lub thawv 1 kg raug rub raws ntug kab rov tav los ntawm lub zog F, yog li lub thawv txav mus los ntawm qhov ceev tas li. Yog tias qhov sib txhuam kinetic yog 0.1, txiav txim siab qhov loj ntawm lub zog F! (g = 9.8 m/ s2 )

Paub:
Tus coefficient ntawm kev sib txhuam kinetic ( μk ) = 0.1
Lub thawv qhov hnyav (m) = 1 kg
Kev nrawm ntawm lub ntiajteb txawj nqus (g) = 9.8 m/s 2
Qhov hnyav (w) = mg = (1 kg) (9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons
Lub zog ib txwm (N) = w = 9.8 Newtons
Xav tau : F
Tshuaj:
Txoj cai lij choj thawj zaug ntawm Newton hais tias yog tsis muaj lub zog ua haujlwm rau ib yam khoom, txhua yam khoom yuav txuas ntxiv mus rau hauv nws lub xeev so, lossis qhov ceev tas li hauv ib txoj kab ncaj.
Yog li ntawd, yog tias qhov khoom txav mus rau qhov ceev tas li , yuav tsum tsis muaj lub zog net ( Σ F = 0) . Lub zog F raug siv rau ntawm qhov khoom hauv qhov kev taw qhia kom lub zog ntawm kev sib txhuam kinetic raug siv rau ntawm qhov khoom mus rau sab laug.
∑ F = 0
F – fk = 0
F = fk
Lub zog ntawm kev sib txhuam kinetic:
f k = μ k N = (0.1)(9.8 N) = 0.98 Newtons
khoom txav nrog qhov ceev tas li, F = f k = 0.98 Newtons
[irp]
3. Ib yam khoom swb mus rau hauv ib lub dav hlau inclined nrog qhov ceev tas li. Txheeb xyuas qhov sib txhuam kinetic ( μk ) . g = 9.8 m/s 2

tshuaj

w = qhov hnyav, w x = feem kab rov tav ntawm qhov hnyav, cov ntsiab lus raws qhov nqes, w y = feem ntsug ntawm qhov hnyav, perpendicular rau lub dav hlau nqes, N = lub zog ib txwm muaj, f k = lub zog ntawm kev sib txhuam kinetic.
Paub:
Qhov hnyav (m) = 1 kg
Kev nrawm ntawm lub ntiajteb txawj nqus (g) = 9.8 m/s 2
qhov hnyav (w) = mg = (1 kg)(9.8 m/s2 ) = 9.8 kg m/s2 = 9.8 Newtons
w x = w sin 30 o = (9.8 N)(0.5) = 4.9 Newtons
w y = w cos 30 o = (9.8 N)(0.5) √ 3 = 4.9 √ 3 Newtons
Lub zog ib txwm (N) = wy = 4.9 √ 3 Newtons
Xav tau : kinetic friction coefficient ( μk )
Tshuaj:
Khoom txav mus rau hauv ib lub dav hlau inclined nrog qhov ceev tas li kom lub zog net = 0.
∑ F = 0
w x – f k = 0
w x = f k
w x = μ k N
5 = μ k ( 5 √ 3 )
μ k = 5 / 5 √ 3
μ k = 1 / √ 3
μk = 0.58
[irp]
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- Qhov hnyav thiab qhov hnyav
- ib txwm muaj zog
- Newton txoj cai thib ob ntawm kev txav mus los
- Lub zog sib txhuam
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