Misalan Tambayoyi game da Zagayen Wutar Lantarki na Yanzu

Misalan Tambayoyi 6 na Canjin Da'irar Wutar Lantarki ta Yanzu

1. Kalli hoton da'irar RLC mai zuwa! Idan da'irar hanawar ita ce 250 Ω, to juriyar ɗan adawa (R) shine…..

A. 50 Ω

B. 200 Ω

C. 400 Ω

D. 600 Ω

E. 800 Ω

Tattaunawa

An san cewa:

Z = 250 Ω

C=8 m F = 8 x 10^-6 F

L = 0,8 H

V = Volt 200

ω = 500 rad/s

An tambaya: Juriyar juriya (R)

Amsa:

Tsarin juriya na jimillar da'irar:

Amsar da ta dace ita ce B.

2. Yi la'akari da jerin RLC masu zuwa! Bambancin da zai iya faruwa a ƙarshen inductor shine….

A. Volt 100

B. 200 Volt

C. 300 Volt

D. 350 Volt

E. 400 Volt

Tattaunawa

An san cewa:

R = 40 W

X_L = 150 W

X_C= 120 W

V = Volt 100

An tambaya: Bambancin da zai iya faruwa tsakanin ƙarshen inductor

Amsa:

Tsarin juriya na jimillar da'irar:

Amsar da ta dace ita ce C.

3. Kalli zane mai kama da RLC!
Matsakaicin wutar lantarki na da'irar shine.. (1 µF = 10^-6 F)

A. 1,3 A
B. 1,5 A
C. 2,0 A
D. 2,4 A
E. 2√2 A

Tattaunawa

An sani :
Resistor (R) = 12 Ohm
Inductor (L) = 0,075 H
Capacitor (C) = 500 µF = 500 x 10^-6 F = 5 x 10^-4 Farad
Wutar lantarki (V) = V_o zunubi ωt = V_o sin 2πft = 26 sin 200t
An tambaya : Matsakaicin wutar lantarki na da'irar
Jawab :

Maganin amsawar inductive (X)_L) = ωL = (200)(0,075) = 15 Ohm
Maganin amsawar ƙarfin (X)_C= 1 / ωC = 1 / (200) (5 x 10^-4) = 1 / (1000 x 10^-4= 1 / 10^-1 = 10¹ = 10 Ohms   
Resistor (R) = 12 Ohm
Rashin daidaituwa (Z) :
Ƙarfin halin yanzu (I) :
I = V / Z = Volts 26 / Ohms 13
I = 2 Volts/Ohm
I = 2 Amperes
Amsar da ta dace ita ce C.

4. An shirya da'irar RLC kamar yadda aka nuna a hoton da ke ƙasa. Jadawalin raƙuman sine da ya fito idan_L > X_C shine…

Tattaunawa

Bayani:
X_L = amsawar inductive ko impedance na inductor
X_C = amsawar capacitive ko impedance capacitor

A cikin inductor, ƙarfin lantarki (v) yana gaba da wutar lantarki (i) da ¼ juyawa ko 90°.^o.
A cikin capacitor, wutar lantarki (i) tana gaba da wutar lantarki (v) da ¼ juyawa ko 90°.^o.

Idan X_L > X_C to da'irar tana da inductive, don haka jadawalin raƙuman sine da aka samu yana kama da amsar C inda ƙarfin lantarki (v) yake gaba da na yanzu (i) ta hanyar juyawar ¼ ko 90°^o.

Amsar da ta dace ita ce C.

5. Kalli hoton da ke ƙasa!

An shirya da'irar RLC kamar yadda aka nuna a sama. Jadawalin raƙuman sine da ya fito idan_L > X_C shine…

Tattaunawa

Bayani:

X_L = amsawar inductive ko impedance na inductor, X_C = amsawar capacitive ko impedance na capacitor.

A cikin inductor, ƙarfin lantarki (V) yana gaba da wutar lantarki (I) da ¼ juyawa ko 90°.^o.

A cikin capacitor, wutar lantarki (I) tana gaba da wutar lantarki (v) da ¼ juyawa ko 90°.^o.

Idan X_L > X_C to da'irar tana da inductive, don haka jadawalin raƙuman sine da aka samu yana kama da amsar C inda ƙarfin lantarki (v) yake gaba da na yanzu (i) ta hanyar juyawar ¼ ko 90°^o.

Amsar da ta dace ita ce C.

6. An shirya da'irar RLC kamar yadda aka nuna a hoton da ke ƙasa. Jadawalin raƙuman sine da ya fito idan_L > X_C shine...

Tattaunawa

Bayani:

X_L = amsawar inductive ko impedance na inductor, X_C = amsawar capacitive ko impedance capacitor

A cikin inductor, ƙarfin lantarki (V) yana gaba da wutar lantarki (I) da ¼ juyawa ko 90°.^o.

A cikin capacitor, wutar lantarki (I) tana gaba da wutar lantarki (v) da ¼ juyawa ko 90°.^o.

Idan X_L > X_C to da'irar tana da inductive, don haka jadawalin raƙuman sine da ya fito yayi kama da amsar C inda ƙarfin lantarki (v) kafin aure (i) har zuwa ¼ juyawa ko 90^o.

Amsar da ta dace ita ce C.

Tushen tambaya:

Tambayoyin Jarrabawar Ƙasa ta Fizik ta SMA/MA U-ZC-2013/2014