Misalan Tambayoyi game da Zagayen Wutar Lantarki na Yanzu

Misalan Tambayoyi 6 na Canjin Da'irar Wutar Lantarki ta Yanzu

1. Kalli hoton da'irar RLC mai zuwa! Idan da'irar impedance 250 Ω ce, to juriyar resistor (R) ita ce…..

A. 50 Ω

B. 200 Ω

C. 400 Ω

D. 600 Ω

E. 800 Ω

Tattaunawa

An san cewa:

Z = 250 Ω

C = 8 m F = 8 x 10 ^-6 F

L = 0,8 H

V = Volt 200

ω = 500 rad/s

Tambaya: Juriyar juriyar resistor (R)

Amsa:

Tsarin juriya na jimillar da'irar:

Amsar da ta dace ita ce B.

2. Kalli jerin RLC masu zuwa! Bambancin da ke tsakanin ƙarshen inductor shine….

A. Volt 100

B. 200 Volt

C. 300 Volt

D. 350 Volt

E. 400 Volt

Tattaunawa

An san cewa:

R = W 40

X _L = 150 W

X _C = 120 W

V = Volt 100

Tambaya: Bambancin da zai iya faruwa a ƙarshen inductor

Amsa:

Tsarin juriya na jimillar da'irar:

Amsar da ta dace ita ce C.

3. Kalli zane mai kama da RLC!
Matsakaicin wutar lantarki na da'irar shine.. (1 µF = 10^-6 F)

A. 1,3 A
B. 1,5 A
C. 2,0 A
D. 2,4 A
E. 2√2 A

Tattaunawa

An sani :
Resistor (R) = 12 Ohm
Inductor (L) = 0,075 H
Capacitor (C) = 500 µF = 500 x 10^-6 F = 5 x 10^-4 Farad
Wutar lantarki (V) = V_o zunubi ωt = V_o sin 2πft = 26 sin 200t
An tambaya : Matsakaicin wutar lantarki na da'irar
Jawab :

Maganin amsawar inductive (X)_L) = ωL = (200)(0,075) = 15 Ohm
Maganin amsawar ƙarfin (X)_C= 1 / ωC = 1 / (200) (5 x 10^-4) = 1 / (1000 x 10^-4= 1 / 10^-1 = 10¹ = 10 Ohms   
Resistor (R) = 12 Ohm
Rashin daidaituwa (Z) :
Ƙarfin halin yanzu (I) :
I = V / Z = Volts 26 / Ohms 13
I = 2 Volts/Ohm
I = 2 Amperes
Amsar da ta dace ita ce C.

4. An shirya da'irar RLC kamar yadda aka nuna a hoton da ke ƙasa. Jadawalin raƙuman sine da ya fito idan_L > X_C shine…

Tattaunawa

Bayani:
X_L = amsawar inductive ko impedance na inductor
X_C = amsawar capacitive ko impedance capacitor

A cikin inductor, ƙarfin lantarki (v) yana gaba da wutar lantarki (i) da ¼ juyawa ko 90°.^o.
A cikin capacitor, wutar lantarki (i) tana gaba da wutar lantarki (v) da ¼ juyawa ko 90°.^o.

Idan X _L > X _C to da'irar tana da inductive, don haka jadawalin raƙuman sine da aka samu yana kama da amsar C inda ƙarfin lantarki (v) ke jagorantar halin yanzu (i) ta hanyar ¼ juyawa ko 90 ^o.

Amsar da ta dace ita ce C.

5. Kalli hoton da ke ƙasa!

An shirya da'irar RLC kamar yadda aka nuna a sama. Jadawalin raƙuman sine da aka samar idan X _L > X _C shine...

Tattaunawa

Bayani:

X _L = amsawar inductive ko impedance na inductor, X _C = amsawar capacitive ko impedance na capacitor.

A cikin inductor, ƙarfin lantarki (V) yana gaba da wutar lantarki (I) da ¼ juyi ko 90 ^o.

A cikin capacitor, wutar lantarki (I) tana gaba da wutar lantarki (v) da ¼ juyawa ko 90 ^o.

Idan X _L > X _C to da'irar tana da inductive, don haka jadawalin raƙuman sine da aka samu yana kama da amsar C inda ƙarfin lantarki (v) ke jagorantar halin yanzu (i) ta hanyar ¼ juyawa ko 90 ^o.

Amsar da ta dace ita ce C.

6. An shirya da'irar RLC kamar yadda aka nuna a hoton da ke ƙasa. Jadawalin raƙuman sine da aka samar idan X _L > X _C shine ...

Tattaunawa

Bayani:

X _L = amsawar inductive ko impedance na inductor, X _C = amsawar capacitive ko impedance na capacitor

A cikin inductor, ƙarfin lantarki (V) yana gaba da wutar lantarki (I) da ¼ juyi ko 90 ^o.

A cikin capacitor, wutar lantarki (I) tana gaba da wutar lantarki (v) da ¼ juyawa ko 90 ^o.

Idan X _L > X _C to da'irar tana da inductive, don haka jadawalin raƙuman sine da aka samu yana kama da amsar C inda ƙarfin lantarki (v) ke jagorantar halin yanzu (i) ta hanyar ¼ juyawa ko 90 ^o.

Amsar da ta dace ita ce C.

Tushen tambaya:

Tambayoyin Jarrabawar Ƙasa ta Fizik ta SMA/MA U-ZC-2013/2014