Misalan 10 na Tambayoyin Shigar da Electromagnetic a cikin EMF
1. Janareta yana da na'ura mai juyi da dama N da kuma yanki mai giciye-sashe A. Na'urar tana cikin filin maganadisu B, sannan a juya ta a saurin kusurwa ω don a samar da matsakaicin EMF da aka haifar na volts 50. Idan filin maganadisu ya canza zuwa kashi 1/2 na ƙimarsa ta asali kuma saurin kusurwarsa ya canza zuwa sau 4 na ƙimarsa ta asali, to matsakaicin EMF da aka haifar zai kasance...
A. 25 volt
B. volts 50
C. volts 100
D. volts 200
Wutar lantarki ta E. 250 volts
Tattaunawa
An san cewa:
Adadin juyawa 1 (N 1 ) = N
Yankin giciye 1 (A 1 ) = A
Filin maganadisu 1 (B1 ) = B
Gudun kusurwa 1 (ω 1 ) = ω
Matsakaicin ƙarfin lantarki mai ƙarfin lantarki EMF 1 (ε 1 ) = Volts 50
Filin maganadisu 2 (B 2 ) = 0,5B = 0,5(1) = 0,5
Gudun Angular 2 (ω 2 ) = 4ω = 4(1) = 4
Tambaya: Matsakaicin EMF da aka haifar shine 2 (ε 2 )
Amsa:
Matsakaicin lissafin EMF da aka haifar:
ε max = NBA ω
Bayani:
ε max = matsakaicin emf da aka haifar, N = adadin juyawa, B = filin maganadisu, A = yankin giciye, ω = saurin kusurwa
Matsakaicin EMF 1 (ε 1 ):
ε max = NBA ω
Idan ω = 1 da B = 1 to
50 = N (1) A (1)
50 = NA
Matsakaicin EMF 2 (ε 2 ):
ε max = NBA ω
NA = 50, B = 0,5, ω = 4
ε matsakaicin = (50)(0,5)(4)
ε matsakaicin = 100
Amsar da ta dace ita ce C.
2. Domin matsakaicin EMF da janareta ya samar ya zama 1/2 na asali, adadin da dole ne a canza bisa ga bayanin da ke ƙasa shine...
A. Saurin kusurwa da adadin juyawa sun ninka sau biyu
B. An ninka ƙarfin maganadisu da mitarsa sau biyu.
C. An ninka yankin giciye kuma an ninka lokacin sau biyu
D. Adadin juyawa da lokacin an yi su sau 4 na asali.
E. An ninka mita da lokacin sau biyu.
Tattaunawa
Matsakaicin lissafin EMF da aka haifar:
ε max = NBA ω
Bayani:
ε max = matsakaicin emf da aka haifar, N = adadin juyawa, B = filin maganadisu, A = yankin giciye, ω = saurin kusurwa
Idan N = 1, B = 1, A = 1, ω = 1 to ε max = NBA ω = (1) (1) (1) (1) = 1
A. Saurin kusurwa (ω) da adadin juyawa (N) sun ninka sau biyu
ε max = NBA ω
ε matsakaicin = (2)(1)(1)(2)
ε matsakaicin = 4
B. An ninka ƙarfin maganadisu (B) da mitarsa (f).
Tsarin saurin kusurwa (ω) = 2πf. Mita yana daidai gwargwado kai tsaye don haka idan mitar (f) ta ninka sau biyu, saurin kusurwa (ω) ya ninka sau biyu.
ε max = NBA ω
ε matsakaicin = (1)(2)(1)(2)
ε matsakaicin = 4
C. An ninka yankin giciye (A) sau biyu kuma tsawon ya ninka na asali sau 4
Tsarin saurin kusurwa (ω) = 2πf = 2π/T. Lokacin yana da daidaiton juzu'i don haka idan lokacin ya zama sau 4 na asali to saurin kusurwa ya zama sau 1/4 na asali.
ε max = NBA ω
ε matsakaicin = (1)(1)(2)(1/4) = 2/4
ε mafi girma = 1/2
D. An ƙara adadin juyawa (N) da lokaci (T) zuwa sau 4
Tsarin saurin kusurwa (ω) = 2πf = 2π/T. Lokacin yana da daidaiton juzu'i don haka idan lokacin ya zama sau 4 na asali to saurin kusurwa ya zama sau 1/4 na asali.
ε max = NBA ω
ε matsakaicin = (4)(1)(1)(1/4) = 4/4
ε matsakaicin = 1
E. An ninka mitar (f) da period (T).
Mitar tana daidai gwargwado kai tsaye ta yadda idan aka ninka mitar (f) sau biyu to saurin kusurwa (ω) zai ninka. Lokacin yana daidai gwargwado ta yadda idan aka ninka lokacin sau biyu to saurin kusurwa zai zama 1/2 na asali. Sakamakon ƙarshe, saurin kusurwa yana daidai gwargwado.
ε max = NBA ω
ε matsakaicin = (1)(1)(1)(1)
ε matsakaicin = 1
Amsar da ta dace ita ce C.
3. Ruwan maganadisu a cikin na'ura mai juyawa 1.000 yana ƙaruwa daga 0,03 Wb zuwa 0,04 Wb a cikin daƙiƙa 0,2 don haka ƙimar EMF da aka samu ita ce E1 . Idan na'urar iri ɗaya ta sami canji a cikin ruwan maganadisu daga 0,02 Wb zuwa 0,04 Wb a cikin daƙiƙa 0,1, ƙimar EMF da aka haifar ita ce E2 . Rabon E1 da E2 shine …
A. 1: 1
B. 1: 2
C. 1: 4
D. 2: 1
E. 4: 1
Tattaunawa
An san cewa:
Adadin juyawa (N) = 1000
Canjin juyi 1 ( Δφ 1 ) = 0,04 Wb – 0,03 Wb = 0,01 Wb
Tazarar lokaci 1 (Δt 1 ) = daƙiƙa 0,2
EMF 1 da aka jawo = E 1
Canjin juyi 2 ( Δφ 1 ) = 0,04 Wb – 0,02 Wb = 0,02 Wb
Tazarar lokaci 2 (Δt 2 ) = daƙiƙa 0,1
EMF 2 da aka jawo = E 2
An tambaya: E 1 : E 2
Amsa:
Kwatanta E 1 da E 2 :
E 1 : E 2
50: 200
1: 4
Amsar da ta dace ita ce C.
4. Na'ura tana ratsa wani filin maganadisu iri ɗaya a tsaye, wanda ke haifar da EMF da aka haifar. Idan aka maye gurbin na'urar da wani na'ura mai ninka adadin juyawa na na'urar asali kuma saurin canjin kwararar ruwa ya kasance iri ɗaya, to rabon EMF da aka haifar na farko da na ƙarshe shine...
A. 1: 1
B. 1: 2
C. 2: 1
D. 3: 1
E. 3: 2
Tattaunawa
An sani :
Adadin farko na juyawa (N) = 1
Adadin juyawa na ƙarshe (N) = 2
Saurin canjin kwararar ruwa na farko (ΔØ)B / Δt) = ƙimar canjin kwararar ƙarshe (ΔØB /Δt)
An tambaya Kwatanta EMF da aka haifar da farko da na ƙarshe
Jawab :
Tsarin dokar Faraday na shigar da abubuwa :
E = -N (ΔØB /Δt)
Bayani: E = emf da aka haifar, N = adadin juyawa, ΔØB / Δt = ƙimar canjin kwararar ruwa
Kwatanta EMF da aka haifar da farko da na ƙarshe :
Farawar E: Ƙarshen E
-N (ΔØB / Δt): -N (ΔØB /Δt)
1: 2
Amsar da ta dace ita ce B.
5. A yanayin farko (1), kwararar maganadisu tana canzawa da 5 Wb cikin daƙiƙa 2 a cikin na'ura mai juyawa 20. A yanayin (2), canjin kwarara iri ɗaya yana ɗaukar daƙiƙa 8. Rabon EMF da aka haifar a cikin yanayi (1) da (2) shine…
A. 1: 1
B. 2: 1
C. 3: 1
D. 4: 1
E. 4: 3
Tattaunawa
An sani :
Yawan canjin ruwa (ΔØ)B / Δt) farko = 5/2
Yawan canjin ruwa (ΔØ)B / Δt) ƙarshe = 5/8
Adadin juyawa (N) = 20
An tambaya Kwatanta EMF da aka haifar da farko da na ƙarshe
Jawab :
Farawar E: Ƙarshen E
-N (ΔØB / Δt): -N (ΔØB /Δt)
20 (5/2): 20 (5/8)
5/2: 5/8
1/1: 4/1
4: 1
Amsar da ta dace ita ce D.
6. Ruwan maganadisu na na'urar farko yana da juyawa 200 kuma yana canzawa da 0,06 Wb a cikin 0,4 s. A cikin na'urar ta biyu, ruwan maganadisu yana canzawa da 0,08 Wb a cikin 0,2 s. Idan adadin juyawa a cikin na'urar ta biyu an maye gurbinsa da rabin adadin juyawa a cikin na'urar ta farko, to rabon emf da aka haifar a cikin na'urar ta farko da ta biyu shine...
A. 2: 3
B. 3: 1
C. 3: 4
D. 3: 5
E. 3: 8
Tattaunawa
An sani :
Yawan canjin ruwa (ΔØ)B / Δt) farko = 0,06/0,4
Adadin farko na juyawa (N) = 200
Yawan canjin ruwa (ΔØ)B / Δt) ƙarshe = 0,08/0,2
Adadin juyawa na ƙarshe (N) = 100
An tambaya Kwatanta EMF da aka haifar da farko da na ƙarshe
Jawab :
Farawar E: Ƙarshen E
-N (ΔØB / Δt): -N (ΔØB /Δt)
200 (0,06/0,4): 100 (0,08/0,2)
2 (0,15): 1 (0,4)
0,3: 0,4
3: 4
7. Daga cikin waɗannan abubuwan:
(1) Adadin juyawar na'ura
(2) Yawan canjin kwararar maganadisu
(3) Alkiblar filin maganadisu
Abin da ke ƙara yawan EMF da aka haifar shine…
A. (1), (2), da (3)
B. (1) da (2) kawai
C. (1) da (3) kawai
D. (1) kawai
E. (2) kawai
Tattaunawa
EMF tana nufin Ƙarfin Wutar Lantarki. A wata ma'anar, EMF tushen wutar lantarki ne, kamar batir, da sauransu. Dangane da gwaje-gwajen da Faraday ya gudanar, an gano cewa kodayake filin maganadisu mai ɗorewa ba zai iya samar da wutar lantarki ba, filin maganadisu mai canzawa zai iya samar da wutar lantarki. Wannan wutar lantarki da ta samo asali ana kiranta da wutar lantarki da aka haifar.
Ana iya tantance abubuwan da ke tasiri ga EMF da aka haifar ta amfani da dokar Faraday ta induction, wanda aka bayyana ta hanyar lissafi ta hanyar dabarar:
Alamar da ba ta dace ba a cikin dabarar da ke sama ta bayyana cewa alkiblar filin maganadisu da wutar lantarki ta haifar koyaushe tana akasin alkiblar filin maganadisu wanda ke samar da wutar lantarki da aka haifar.
Bayani:
N = adadin juyawar na'urar, B = filin maganadisu, A = yankin saman madauki, θ = kusurwa tsakanin filin maganadisu (B) da layin da ke daidai da saman na'urar (A).
Idan B yana tsaye a saman na'urar to θ = 0 o don haka Φ B = BA cos 0 o = BA (1) = B A.
Idan B yana daidai da saman na'urar, to θ = 90 o don haka Φ B = BA cos 9 0 o = BA (0) = 0.
Dangane da dabarar da ke sama, an kammala da cewa abin da ke ƙara EMF da aka haifar shine adadin juyawar na'ura (N), saurin canjin kwararar maganadisu da kuma alkiblar filin maganadisu (θ ).
Amsar da ta dace ita ce A.
8. Daga cikin waɗannan abubuwan:
(1) adadin juyawar na'ura
(2) saurin canjin kwararar maganadisu
(3) cikas na waje
Abin da ke haifar da EMF da ke cikin na'urar shine…
A. (1) da (3)
B. (1) da (2)
C. (2) kawai
D. (2) da (3)
E. (3) kawai
Tattaunawa
Amsar da ta dace ita ce B.
9. Kalli hoton da ke ƙasa! Idan wutar lantarki ta I tana gudana ta cikin waya AB, to alkiblar ƙarfin maganadisu da waya AB ke fuskanta shine...
A. Zuwa ga B
B. Zuwa hagu
C. Zuwa dama
D. Daidai da saman takardar
E. Daidai da saman takardar
Tattaunawa
An sani :
Alkiblar wutar lantarki = A zuwa B (ƙasa)
Alkiblar filin maganadisu = sandar arewa zuwa sandar kudu na maganadisu (a dama)
An tambaya : Alkiblar ƙarfin maganadisu
Jawab :
Dokar hannun dama
Miƙa hannun dama, miƙe babban yatsanka, sannan ka rufe sauran yatsunka huɗu. Shirya yatsunka huɗu don su nuna alkiblar filin maganadisu (B). dan Babban yatsa yana nuna alkiblar motsin caji (v). Idan cajin lantarki yana da kyau, tafin hannun dama yana fuskantar alkiblar ƙarfin maganadisu (F). Idan cajin yana da kyau, bayan hannun dama yana fuskantar alkiblar ƙarfin maganadisu (F).
Alkiblar wutar lantarki ta al'ada, kamar yadda yake a cikin matsalar da ke sama, iri ɗaya ce da alkiblar cajin lantarki mai kyau. Idan aka yi amfani da ƙa'idar hannun dama, alkiblar ƙarfin maganadisu tana daidai da matakin takardar, ko kuma zuwa ga idon mai karatu.
Amsar da ta dace ita ce E.
10. An sanya waya madaidaiciya mai ɗauke da wutar lantarki ta I tsakanin sandunan maganadisu guda biyu kamar yadda aka nuna a cikin hoton. Alkiblar ƙarfin maganadisu akan wayar tana cikin alkibla ɗaya da...
A. Axis mai kyau na z
B. Axis-z mara kyau
C. Axis mai kyau na y
D. Axis-y mara kyau
E. Axis mai kyau na x
Tattaunawa
An sani :
Alkiblar wutar lantarki = zuwa hagu
Alkiblar filin maganadisu = arewa zuwa kudu (sama)
An tambaya : Alkiblar ƙarfin maganadisu
Jawab :
Idan aka yi amfani da ƙa'idar hannun dama, alkiblar ƙarfin maganadisu tana daidai da saman takardar ko kuma nesa da idon mai karatu ko kuma a cikin alkiblar z mara kyau.
Amsar da ta dace ita ce B.
Tushen tambaya:
Tambayoyin Nazarin Fizik na Ƙasa ga Makarantar Sakandare ta Babbar Sakandare/Makarantar Sakandare ta Sana'a
