Misalai 3 na dokar Boyle (zafin jiki mai dorewa na isothermal)
1. Wani adadin iskar gas mai kyau da farko yana da matsin lamba na P da kuma girman V. Idan iskar gas ta fuskanci tsarin isothermal ta yadda matsin lambar ya ninka matsin lamba na asali sau 4, girman iskar gas ɗin zai canza zuwa...
Tattaunawa
An sani :
Matsi na farko (P)1) = P
Matsi na ƙarshe (P)2) = 4P
Ƙaramin farko (V)1) = V
An tambaya : ƙarar ƙarshe ta iskar gas (V)2)
Jawab :
Dokar Boyle (tsarin yanayin zafi mai ɗorewa ko na isothermal) :
PV = mai dorewa
P1 V1 =P2 V2
(P)(V) = (4P)(V)2)
V = V 42
V2 = V / 4 = ¼ V
Yawan iskar gas yana canzawa zuwa ¼ na girman farko.
2. A cikin akwati mai rufewa, iskar gas tana faɗaɗa ta yadda girmanta zai canza zuwa sau biyu na girman farko (V = girman farko, P = matsin lamba na farko). Matsin iskar gas yana canzawa zuwa…
Tattaunawa
An sani :
Matsi na farko (P)1) = P
Ƙaramin farko (V)1) = V
Ƙarar ƙarshe (V)2) = 2V
An tambaya : matsin lamba na ƙarshe (P)2)
Jawab :
P1 V1 =P2 V2
PV = P2 (2V)
P=P2 (2)
P2 = P / 2 = ½ P
Matsin iskar gas yana canzawa zuwa sau ½ na matsin lamba na farko.
3. A cikin jirgin ruwa mai rufewa akwai iskar gas wacce ke da matsin lamba na atm 2 da kuma girman lita 1. Idan matsin iskar gas ya zama atm 4 to girman iskar gas din zai kasance...
Tattaunawa
An sani :
Matsi na farko (P)1) = 2 atm = 2 x 105 Pascal
Matsi na ƙarshe (P)2) = 4 atm = 4 x 105 Pascal
Ƙaramin farko (V)1) = lita 1 = 1 dm3 = 1 x10-3 m3
An tambaya : Juzu'i na ƙarshe (V)2)
Jawab :
P1 V1 =P2 V2
(2x105)(1 x 10-3) = (4 x 105) V2
(1)(1 x 10-3) = (2) V2
1 x 10-3 = (2) V2
V2 = ½ x 10-3
V2 = 0,5 x10-3 m3 = Dubu dm3 = 0,5 lita
