Izinkinga nezixazululo ezi-3 mayelana ne-Speed equation
1. Imoto iya eningizimu ibanga elingamamitha ayi-100 ngomzuzu owodwa bese ijika iye empumalanga ibanga elingamamitha ayi-120 ngemizuzu engu-0.5. Nquma isivinini esimaphakathi semoto.
Kwaziwa:
Ibanga eliphelele = amamitha ayi-100 + amamitha ayi-120 = amamitha angama-220
Isikhathi esiphelele = umzuzu o-1 + imizuzu engu-0.5 = imizuzu engu-1.5 = imizuzwana engu-90
Okufunayo: Ijubane elimaphakathi
Isixazululo:
Ifomula yesivinini
Isivinini esimaphakathi = ibanga eliphelele: isikhathi esiphelele = amamitha angu-220: imizuzwana engu-90 = amamitha angu-2.4/umzuzwana
2. Isikebhe esihamba emgqeni oqondile ibanga elingamamitha ayi-100 ngemva kwemizuzwana eyi-10. Singakanani isivinini esimaphakathi sesikebhe?
Kwaziwa:
Ibanga = amamitha ayi-100
Isikhathi = imizuzwana eyi-10
wayefuna: Ijubane elimaphakathi
Isixazululo:
Ifomula yesivinini
Isivinini esimaphakathi = amamitha ayi-100: imizuzwana eyi-10 = amamitha ayi-10 ngomzuzwana
3. Inhlayiya isuka endaweni ethi O iye endaweni ethi B ngemizuzwana emi-4 kanye nesuka ku-B iye ku-A ngemizuzwana engama-20. Nquma isivinini esimaphakathi sezinhlayiya.
Kuyaziwa:
Ibanga le-OB = amamitha angu-5
Ibanga le-BA = amamitha angu-8
Isikhathi se-OB = imizuzwana emi-4
Isikhathi se-BA = imizuzwana engama-20
Okufunayo: Isivinini esimaphakathi sezinhlayiya
Isixazululo:
Ifomula yesivinini
Isivinini esimaphakathi sezinhlayiya = ibanga eliphelele: isikhathi esiphelele = (5 + 8): (4 + 20) = 13: 24 = 0.54 amamitha/umzuzwana
