Isimiso se-Pascals - izinkinga nezixazululo

Isimiso se-Pascals - izinkinga nezixazululo

1. Okwaziwayo:

Indawo ye-A 1 = 10 cm 2

Indawo ye-A 2 = 100 cm 2

Amandla 2 (F 2 ) = 100 Newton

Kufunwa: Amandla 1 (F 1 )

Isixazululo:

P = F / A

P = ingcindezi , F = amandla , A = indawo

P1 =F1 / TO1
P
2 =F2 / TO2

P1 =P2
F
1 / TO1 =F2 / TO2

F 1 / 10 cm 2 = 100 N / 100 cm 2

F 1/10 = 1 N​

F 1 = (10)(1 N)

F 1 = 10 Newton

2. Uma indawo ka-A 1 = 0.001 m2 kanye nendawo ka-A 2 = 0.1 m2 , amandla okufaka angaphandle F 1 = 100 N, khona-ke amandla okukhipha angaphandle F 2?

Kwaziwa:Isimiso sikaPascal - izinkinga nezixazululo 2

Indawo ye-A 1 = 0.001 m 2

Indawo ye-A 2 = 0.1 m 2

Amandla okufaka angaphandle F 1 = 100 Newtons

Okufunwayo : Amandla okukhipha angaphandle (F 2 )

Isixazululo:

P1 =P2
F
1 / TO1 =F2 / TO2

100 N / 0.001 m 2 = F 2 / 0.1 m 2

100 N / 0.001 = F 2 / 0.1

100,000 N = F 2 / 0.1

F 2 = (0.1)(100,000 N)

F 2 = 10,000 N

3. Isisindo semoto = 16,000 N. Iyini amandla okufaka angaphandle F…

Kwaziwa:Isimiso sikaPascal - izinkinga nezixazululo 3

Isisindo semoto (w) = 16,000 N

Indawo ye-B (A B ) = 4000 cm 2 = 4000 / 10,000 m 2 = 4 / 10 m 2 = 0.4 m 2

Indawo ye-A (A A ) = 50 cm 2 = 50 / 10,000 m 2 = 0.005 m 2

Kufunwa: I-Force F

Isixazululo:

F / A A = w / A B

F / 0.005 m 2 = 16,000 N / 0.4 m 2

F / 0.005 = 16,000 N / 0.4

F / 0.005 = 40,000 N

F = (40,000 N)(0.005)

F = 200 Newton

4.

Indawo ka-A ingu-60 cm 2 kanti indawo ka-B ingu-4,200 cm 2 , nquma amandla okufaka angaphandle ka-F.

Kwaziwa:Isimiso sikaPascal - izinkinga nezixazululo 3

Indawo ye-A (A A ) = 60 cm 2

Indawo ye-B (A B ) = 4200 cm 2

Isisindo w (w) = 3500 Newton

Kufunwa: F 1

Isixazululo:

Amandla ka-F abalwe kusetshenziswa i-equation yesimiso sikaPascal :

F 1 / A 1 = F 2 / A 2

F 1 / 60 cm 2 = 3500 N / 4200 cm 2

F 1 / 60 = 35 N / 42

F 1 = (60)(35) / 42

F 1 = 2100 / 42

F 1 = 50 Newton

5. I-hydraulic lift ine-cross section enkulu kanye ne-cross section encane. Indawo enkulu ye-cross section iphindwe izikhathi ezingu-20 kune-cross section encane. Uma engxenyeni encane ye-cross power inikezwa amandla okufaka angu-25 N, khona-ke nquma amandla okukhipha.

Kwaziwa:

Indawo encane enqamula ingxenye (A 1 ) = A

Indawo enkulu enqamulayo (A 2 ) = 20A

Amandla okufaka (F 1 ) = 25 N

Okufunwayo: Amandla okukhipha (F 2 )

Isixazululo:

Isimiso sikaPascal - izinkinga nezixazululo 7

  1. Iyini isimiso sikaPascal?
    • Impendulo: Isimiso sikaPascal sithi noma yiluphi ushintsho ekucindezelweni okusetshenziswayo kunoma yisiphi isikhathi oketshezini ludluliselwa ngaphandle kokuncipha kulo lonke uketshezi kuzo zonke izinhlangothi.
  2. Isebenza kanjani i-hydraulic lift ngokusekelwe ku-Pascal's Principle?
    • Impendulo: Ku-hydraulic lift, amandla amancane asetshenziswa ku-piston yendawo encane adala ingcindezi edluliselwa inganciphisiwe ku-piston yendawo enkulu. Lokhu kuphumela emandleni amakhulu ku-piston enkulu, okwenza ikwazi ukuphakamisa izinto ezisindayo.
  3. Kungani ushintsho lwengcindezi lungancishisiwe ku-Pascal's Principle?
    • ImpenduloNgenxa yokuthi uketshezi alucindezelwa, uma ingcindezi ifakwa engxenyeni eyodwa yoketshezi, ayikwazi ukucindezela, ngakho-ke idlulisela ushintsho lokucindezela ngokulinganayo kuzo zonke ezinye izingxenye zoketshezi.
  4. Ukwanda kokujula kuthinta kanjani ukucindezeleka koketshezi, uma ucabangela isimiso sikaPascal?
    • Impendulo: Njengoba ukujula kukhuphuka oketshezini, ingcindezi nayo iyanda ngenxa yesisindo soketshezi olungenhla. Lokhu kuhambisana nesimiso sikaPascal njengoba ukwanda kwengcindezi kwenzeka ngokulinganayo ekujuleni okuthile.
  5. Kungani izindlebe zethu ziqhuma uma senyuka noma sehla ngokushesha endizeni noma sicwila phansi emanzini?
    • Impendulo: Ukuphakama okusheshayo noma izinguquko zokujula kuholela ekushintsheni okusheshayo kwengcindezi endaweni ezungezile (umoya noma amanzi). Izindlebe zethu ziyaqhuma njengendlela yokulinganisa ingcindezi yangaphakathi nengcindezi yangaphandle, ngokuvumelana neSimiso sikaPascal.
  6. Uma isirinji evaliwe engenamabhamuza omoya icindezelwe, kungani kunzima ukucindezela uketshezi olungaphakathi?
    • Impendulo: Uketshezi alunakucindezelwa nhlobo. Uma uzama ukunciphisa umthamo woketshezi olungaphakathi kwesirinji, ingcindezi iyanda, imelane nokucindezelwa, ngokusho kwePascal's Principle.
  7. I-Pascal's Principle iyichaza kanjani isenzakalo sokuqhuma kwedamu uma kudaleka umgodi omncane phansi kwalo?
    • Impendulo: Ngenxa yesisindo samanzi, ingcindezi esezansi kwedamu iphakeme. Ngisho nomgodi omncane uvumela ukuthi le ngcindezi ephezulu ifakwe ezakhiweni ezizungezile, okungaholela ekwehlulekeni okukhulu kwedamu.
  8. Kungani kulula ukukhafula uketshezi oluvela ebhodleleni elicishe ligcwale kunolucishe lungenalutho?
    • Impendulo: Ibhodlela eligcwele linoketshezi oluningi, lapho licindezelwa, lidlulisela ingcindezi esetshenziswayo ngempumelelo enkulu kulo lonke uketshezi ngenxa yeSisekelo sikaPascal. Ibhodlela elicishe lingenalutho linomoya omningi, okungacindezelwa, ngakho-ke ingcindezi efanayo ayikhiqizi uketshezi olunamandla.
  9. Ezinhlelweni ze-hydraulic, ingabe amandla okukhipha ahlala emakhulu kunamandla okufaka?
    • Impendulo: Akunjalo ngempela. Isilinganiso samandla okukhipha amandla okufaka sinqunywa yisilinganiso sezindawo zama-piston okukhipha kanye nama-piston okufaka. Uhlelo luklanyelwe ukukhulisa amandla ngokuba nendawo enkulu ye-piston yokukhipha kunokufaka, kodwa yisilinganiso sendawo esinquma ukukhulisa amandla.
  10. Uma sicabangela isimiso sikaPascal, kungani izidalwa zasolwandle ezijulile zinemizimba eqinile neqinile?
  • Impendulo: Izidalwa zasolwandle ezijulile zithola ukucindezeleka okukhulu ngenxa yesisindo sekholomu yamanzi ephezu kwayo. Ukuze ziphile, lezi zidalwa ziye zashintsha zaba nemizimba eqinile neqinile engamelana nalezi zingcindezi eziphakeme.