3 Izinkinga nezixazululo mayelana ne-Moment of inertia equation
1. Isilinda esiqinile sinobubanzi obungu-8 cm kanye nesisindo esingu-2 kg. Okwamanje, ibhola eliqinile linobubanzi obungu-5 cm kanye nesisindo esingu-4 kg. Uma izinto ezimbili zijikeleza nge-axis phakathi nendawo yazo, nquma isilinganiso sesikhathi sokungapheleli kwesilinda kanye nebhola.
Kwaziwa:
Irediyasi yesilinda eqinile (r) = 8 cm = 0.08 m
Isisindo sesilinda esiqinile (m) = 2 kg
Irediyasi yebhola eqinile (r) = 5 cm = 0.05 m
Isisindo sebhola eliqinile (m) = 4 kg
Okufunwayo: Ukuqhathaniswa kwesikhathi sokungahlali kahle kwesilinda nebhola
Isixazululo :
Ifomula yesikhathi sokungabi namandla kwesilinda esiqinile:
I = ½ MR 2 = ½ (2) (0,08) 2 = 0,0064
Ifomula yesikhathi sokungabi namandla kwebhola eliqinile:
I = 2/5 MR 2 = 1/5 (4) (0,05) 2 = (0,8) (0,0025) = 0,002
Ukuqhathaniswa kwesikhathi sokungabi namandla kwesilinda nebhola:
0,0064: 0,002
3,2: 1
2. Ithini lapho kwafakwa khona amabhisikidi lasetshenziswa njengethoyizi. Isisindo sethini singamagremu angu-200 kanti ububanzi bungamasentimitha angu-15. Ithini ligoqwa phansi elivundlile. Uma isivalo kanye nephansi lethini kunganakwa, nquma isikhathi sokungabi namandla kwethini.
Kwaziwa:
Ithini lifana nesilinda esingenalutho.
Isisindo (m) = 200 amagremu = 0.2 kg
Irediyasi (r) = 15 cm = 0.15 m
Okufunayo:
Isixazululo:
Ifomula yesikhathi sokungabi namandla kwesilinda esingenalutho nge-axis:
I = MR 2 = (0,2)(0,15) 2 = (0,2)(0,0225) = 0,0045 kg m 2
3. Idiski ekhululekile ukuzungeza cishe nge-axis eqondile iyakwazi ukujikeleza ngesivinini sama-revolution angu-80 ngomzuzu. Uma into encane enesisindo esingu-4 x 10-2 kg inamathele kwidiski eqhele ngo-5 cm ukusuka ku-axis, kuvela ukuthi ukujikeleza kuyi-revolutions engu-60 ngomzuzu, bese unquma isikhathi sokungabi namandla kwediski.
Kwaziwa:
Ijubane lokuqala le-angular (ω o ) = ama-put angu-80 / 60 s = ama-put angu-4/3/s
Isikhathi sokuqala sokungakhathali (I o ) = I
Ijubane lokugcina le-angular (ω t ) = 60 put / 60 s = 1 put/s
Isikhathi sokugcina sokungakhathali ( It ) = I + mr 2 = I + (0.04)(0.05) 2 = I + (0.04)(0.0025) = I + 0.0425
Kufunwa: umzuzu wokungabi namandla kweDiski
Isixazululo:
Umthetho wokulondolozwa komfutho we-angular
Mina ω o = Mina ω t
Mina (4/3) = Mina + (0,0425 (1))
4 I / 3 = I + 0,0425
4 I = 3 I + 0,1275
4 I – 3 I = 0,1275
I = 0,1275 kg m 2
