Isibalo sejubane le-angular

Imibuzo emi-3 mayelana ne-Angular velocity equation

1. Into ehamba endleleni eyindilinga inobubanzi obungu-0.5 m. Le nhlayiya iyakwazi ukumboza i-engeli engu-60π rad ngemizuzwana eyi-15. Thola ijubane le-engeli lento.

Kwaziwa:

Irediyasi (r) = amamitha angu-0.5

I-engeli (θ) = 60π rad

Isikhawu sesikhathi (t) = imizuzwana eyi-15

Okufunwayo: Ijubane le-angular (ω)

Isixazululo:

θ = ω t

60π = ω (15)

ω = 60π / 15 = 4π rad/s

2. Isondo lebhayisikili elinobubanzi obungamasentimitha angu-30 lijikeleza ngesivinini esingaguquki. Ivalvu yesondo ingajikeleza nge-engeli engu-120π rad imizuzwana eyi-10. Thola isivinini se-angular.

Kwaziwa:

Irediyasi (r) = 30 cm

I-engeli (θ) = 120π rad

Isikhawu sesikhathi (t) = 10 s

Okufunwayo: Ijubane le-angular (ω)

Isixazululo:

θ = ω t

120π = ω (10)

ω = 120π / 10 = 12π rad/s

3. Intambo igoqwe isondo elinerediyasi R = 25 cm njengoba kuboniswe. Uma iphuzu entanjeni (iphuzu A) linesivinini esingu-5 m/s khona-ke ijubane lokujikeleza kwesondo…

Kwaziwa:Isibalo sejubane le-angular 1

Irediyasi (r) = 25 cm = 0.25 amamitha

Isivinini (v) = 5 m/s

Okufunwayo: Ijubane le-angular (ω)

Isixazululo:

Ifomula yobudlelwano phakathi kwejubane le-angular, ijubane eliqondile kanye ne-radius:

v = r ω

5 = (0,25) ω

ω = 5 / 0,25 = 20 rad/s