Pinnu awọn paati fekito

Ti a yanju awọn iṣoro ninu awọn vektọ - pinnu awọn paati vektọ

1. Agbára 20 Newton ṣe igun 30 ^o pẹlu ipo-x. Wa awọn ẹya x ati y ti agbara naa.

ojutu

F _x = F cos 30 ^o = (20)(cos 30 ^o ) = (20)(0.5 √ 3 ) = 10 √ 3 Newtons

F _y = F ẹṣẹ 30 ^o = (20) (ese 30 ^o ) = (20) (0.5) = 10 Newtons

2. F ₁ = 20 Newton ṣe igun 30 ^o pẹlu axis y ati F ₂ = 30 Newton ṣe igun 60 ^o pẹlu axis -x. Wa awọn paati x ati y ti F ₁ ati F _{2 mejeeji}.

ojutu

F _1x = F ₁ cos 60 ^o = (20)(cos 60 ^o ) = (20)(0.5) = -10 Newtons (odi nitori pe o ni itọsọna kanna bi ipo -x)

F _2x = F ₂ cos 60 ^o = (30)(cos 60 ^o ) = (30)(0.5) = -15 Newtons (odi nitori pe o ni itọsọna kanna bi ipo -x)

F_1y =F₁ lai 60^o = (20)(ẹ̀ṣẹ̀ 60^o) = (20)(0.5)√3) = 10√3 Newton (rere nitori pe o ni itọsọna kanna bi ipo y)

F_2y =F₂ lai 60^o = (30)(ẹ̀ṣẹ̀ 60^o) = (30)(0.5)√3) = -15√3 Newton (odi nitori pe o ni itọsọna kanna bi ipo -y)

3. F ₁ = 2 N, F ₂ = 4 N, F ₃ = 6 N. Wa awọn eroja x ati y ti F ₁ , F ₂ ati F ₃!

ojutu

F _1x = F ₁ cos 60 ^o = (2)(cos 60 ^o ) = (2)(0.5) = 1 Newtons (rere nitori pe o ni itọsọna kanna pẹlu ipo x)

F_2x =F₂ nitori 30^o = (4)(coms 30)^o) = (4)(0.5)√3) = -2√3 Newton (odi nitori pe o ni itọsọna kanna pẹlu ipo -x)

F _3x = F ₃ cos 60 ^o = (6)(cos 60 ^o ) = (6)(0.5) = 3 Newtons (rere nitori pe o ni itọsọna kanna pẹlu ipo x)

F_1y =F₁ lai 60^o = (2)(ẹ̀ṣẹ̀ 60^o) = (2)(0.5)√3) = √3 Newton (rere nitori pe o ni itọsọna kanna bi ipo y)

F _{2 y} = F ₂ sin 3 0 ^o = (4)(sin 30 ^o ) = (4)(0.5) = 2 Newtons (rere nitori pe o ni itọsọna kanna pẹlu ipo y)

F_3y =F₃ lai 60^o = (6)(ẹ̀ṣẹ̀ 60^o) = (6)(0.5)√3) = -3√3 Newton (odi nitori pe o ni itọsọna kanna pẹlu ipo -y)

[wpdm_package id='542']

[wpdm_package id='554']

1. Pinnu abajade ninu fekito laini kan
2. Pinnu awọn paati fekito
3. Pinnu abajade awọn vektọ meji nipa lilo ilana Pythagorean
4. Pinnu abajade awọn vektọ meji nipa lilo idogba cosines
5. Pinnu abajade awọn vektọ meji nipa lilo awọn paati ti awọn vektọ