Harorat shkalasini konvertatsiya qilish (Selsiy shkalasi Farengeyt shkalasi Kelvin shkalasi)

9 Harorat shkalasini konvertatsiya qilish (Selsiy shkalasi Farengeyt shkalasi Kelvin shkalasi)

1. 50 ^° C = ….. ^o F ?

qaror

Standart atmosfera bosimida suvning muzlash nuqtasi Selsiy shkalasi bo'yicha 0 ^o C va Farengeyt shkalasida 32 ^o F ni tashkil qiladi. Standart atmosfera bosimida suvning qaynash nuqtasi Selsiy shkalasida 100 ^o C va Farengeyt shkalasida 212 ^{o F ni tashkil qiladi.}

0 ^o C = 32 ^o F va 1 00 ^o C = 212 ^{o F. 5 C} ning o'zgarishi = 9 ^F ning o'zgarishi.

Selsiy shkalasi uchun 0 ^° C va 100 ^° C orasidagi masofa 100 ta teng oraliqqa bo'lingan. Farengeyt shkalasi uchun 0 ^° C va 100 ^° C orasidagi masofa 180 ta teng oraliqqa bo'lingan.

^{F dan} F gacha = (180/100) C ^dan + 32 gacha

^{F dan} F gacha = (9/5) C ^dan C gacha + 32 gacha

^{F dan} F gacha = (9/5) 50 + 32 gacha

^{F ga} = (9) 10 + 32 gacha

^{F dan} F gacha = 90 + 32 gacha

^{F dan} F gacha = 122 gacha

50 ^° C = 122 ^° F

2. 86 ^o F = ….. ^o C ?

qaror

^{C gacha} = (100/180)( F ^gacha – 32)

^{C gacha} = (5/9)( F ^gacha – 32)

^{C ga} = (5/9)(86 – 32)

^{C ga} = (5/9)(54)

^{C ga} = (5)(6)

^C ga = 30 gacha

86 ^° F = 30 ^° C

3. 50 ^o C = ….. K ?

qaror

T = T ^dan C gacha + 273 gacha

T = 50 + 273

T = 323

50 ^° C = 323 K

4. 212 ^o F = ….. K ?

qaror

^{C gacha} = (100/180)( F ^gacha – 32)

^{C gacha} = (5/9)( F ^gacha – 32)

^{C ga} = (5/9)(212 – 32)

^{C ga} = (5/9)(180)

^{C ga} = (5)(20)

^C ga = 100 gacha

212 ^o F = 100 ^o C + 273

212 ^o F = 373 K

 

5. x ^o C = x ^o F

x = ….. ?

qaror

1: Selsiy shkalasini Farengeyt shkalasiga o'tkazish

2: Farengeyt shkalasini Selsiy shkalasiga o'tkazish

6. 122°F = ….. Selsiy

qaror

Ikki harorat shkalasi orasidagi konversiya quyidagicha yozilishi mumkin:

T _C = 5/9 (T _F – 32)

T _C = Selsiy bo'yicha harorat _{, T F} = Farengeyt bo'yicha harorat

Selsiy bo'yicha harorat:

T _C = 5/9 (122 – 32) = T _C = 5/9 (90) = 5 (10)

T _C = 50 ^° C

7. Quyidagi rasmda Farengeyt shkalasi termometri bilan suyuqlikning haroratini o'lchash ko'rsatilgan ! Agar suyuqlikning harorati Selsiy shkalasi termometri yordamida o'lchansa, u holda suyuqlikning harorati qanday bo'ladi e.

Ma'lum:

Farengeyt shkalasi (TF ₎ = 95 ^o F

Kerakli: Selsiy shkalasi

yechim:

1 atm bosimda suvning muzlash nuqtasi 0 °C, Farengeyt shkalasi esa 32 ^o F. Aksincha, Selsiy shkalasi uchun suvning qaynash nuqtasi 100 o ^C , Farengeyt shkalasi esa 212 ^o F.

Selsiy shkalasi bo'yicha 0 °C va 100 °C oralig'ida 100 °C, Farengeyt shkalasida esa 32 °F dan 212 °F gacha bo'lgan haroratda esa 180 °C mavjud.

T _C = 100/180 (T _F – 32)

T _C = 5/9 (T _F – 32)

T _C = 5/9 ( 95 – 32)

T _C = 5/9 ( 63 )

T _C = 315/9

T _C = 35 ^° C

8. Quyidagi rasmga asoslanib, Selsiy termometrida P haroratni aniqlang.

qaror

T_C = 100/180 (T_F - 32)

T _C = 5/9 (T _F – 32)

T _C = 5/9 (104 – 32)

T _C = 5/9 (72)

T _C = 360/9

T _C = 40 ^° C

9. Agar harorat Selsiy shkalasi bo'yicha quyidagi rasmda ko'rsatilgandek bo'lsa, Farengeyt shkalasining haroratini quyidagi rasmda ko'rsatilgandek aniqlang.

yechim:

T^oF = (180/100) T^oC + 32

^{F dan} F gacha = (9/5) C ^dan C gacha + 32 gacha

^{F dan} F gacha = (9/5) 60 + 32 gacha

^{F ga} = (9) 12 + 32 gacha

^{F dan} F gacha = 108 + 32 gacha

^{F dan} F gacha = 140 gacha

1. Harorat shkalalarini konvertatsiya qilish
2. Chiziqli kengayish
3. Hududni kengaytirish
4. Hajmni kengaytirish
5. issiqlik
6. Issiqlikning mexanik ekvivalenti
7. Maxsus issiqlik va issiqlik sig'imi
8. Yashirin issiqlik, erish issiqligi, bug'lanish issiqligi
9. Issiqlik uzatish uchun energiya tejash