Harorat shkalasini konvertatsiya qilish (Selsiy shkalasi Farengeyt shkalasi Kelvin shkalasi)

9 Harorat shkalasini konvertatsiya qilish (Selsiy shkalasi Farengeyt shkalasi Kelvin shkalasi)

1. 50 ^oC = ….. ^oF ?

qaror

Standart atmosferada bosim, suvning muzlash nuqtasi 0 ga teng ^oC ustida Selsiy shkalasi va 32 ^oFarengeyt shkalasi bo'yicha F. Standart atmosfera bosimida suvning qaynash harorati 100 ga teng. ^oSelsiy shkalasi bo'yicha C va 212 ^oFarengeyt shkalasi bo'yicha F.

0 ^oC = 32 ^oF va 100 ^oC = 212 ^oF. 5 C ning o'zgarishi^o = 9 F o'zgarishi^o.

Selsiy shkalasi uchun, orasidagi masofa 0 ^oC va 100 ^oC 100 ta teng oraliqqa bo'lingan. Farengeyt shkalasi uchun 0 orasidagi masofa ^oC va 100 ^oC 180 ta teng oraliqlarga bo'lingan.

T^oF = (180/100) T^oC + 32

T^oF = (9/5) T^oC + 32

T^oF = (9/5) 50 + 32

T^oF = (9) 10 + 32

T^oF = 90 yil + 32

T^oF = 122 yil

50 ^oC = 122 ^oF

2. 86 ^oF = ….. ^oC ?

qaror

T^oC = (100/180)(T)^oF – 32)

T^oC = (5/9)(T)^oF – 32)

T^oC = (5/9)(86 – 32)

T^oC = (5/9)(54)

T^oC = (5)(6)

T^oC = 30

86 ^oF = 30 yil ^oC

3. 50^oC = ….. K ?

qaror

T = T ^oC + 273

T = 50 + 273

T = 323

50 ^oC= 323 K

4. 212^oF = ….. K ?

qaror

T^oC = (100/180)(T)^oF – 32)

T^oC = (5/9)(T)^oF – 32)

T^oC = (5/9)(212 – 32)

T^oC = (5/9)(180)

T^oC = (5)(20)

T^oC = 100

212 ^oF = 100 yil ^oC + 273

212 ^oF = 373 yil K

 

5. x ^oC = x ^oF

x = ….. ?

qaror

1: Selsiy shkalasini Farengeyt shkalasiga o'tkazish

2: Farengeyt shkalasini Selsiy shkalasiga o'tkazish

6. 122°F = ….. Selsiy

qaror

Ikki harorat shkalasi orasidagi konversiya quyidagicha yozilishi mumkin:

T_C = 5/9 (T_F - 32)

T_C = harorat Selsiy bo'yicha, T_F = Farengeyt bo'yicha harorat

Selsiy bo'yicha harorat:

T_C = 5/9 (122 – 32) = T_C = 5/9 (90) = 5 (10)

T_C = 50 ^oC

7. Quyidagi rasmda ko'rsatilgan haroratni o'lchash a Farengeyt shkalasi termometri bilan suyuqlik! Agar suyuqlikning harorati Selsiy shkalasi termometri yordamida o'lchansa, unda nima bu suyuqlik haroratie.

Ma'lum:

Farengeyt Miqyosi (T_F) = 95^oF

Qidirilgan: Selsiy shkalasi

yechim:

1 atm bosimda, suvning muzlash nuqtasi is 0 °C, Farengeyt shkalasi esa 32 ga teng ^oF. Aksincha, tsuvning qaynash nuqtasi C uchunElsius shkala 100 ga teng ^oC Farengeyt shkalasi bilan is 212 ^oF.

Selsiy shkalasi bo'yicha 0 °C va 100 °C oralig'ida 100 °C, Farengeyt shkalasida esa 32 °F dan 212 °F gacha bo'lgan haroratda esa 180 °C mavjud.

T_C = 100/180 (T_F - 32)

T_C = 5/9 (T_F - 32)

T_C = 5/9 (95 - 32)

T_C = 5/9 (63)

T_C = 315 / 9

T_C = 35^oC

8. Quyidagi rasmga asoslanib, t ni aniqlang.Selsiy termometrida P harorati.

qaror

T_C = 100/180 (T_F - 32)

T_C = 5/9 (T_F - 32)

T_C = 5/9 (104 – 32)

T_C = 5/9 (72)

T_C = 360 / 9

T_C = 40 ^oC

9. Agar quyidagi rasmda ko'rsatilgandek Selsiy shkalasi harorati bo'lsa, quyidagi rasmda ko'rsatilgandek Farengeyt shkalasining haroratini aniqlang.

yechim:

T^oF = (180/100) T^oC + 32

T^oF = (9/5) T^oC + 32

T^oF = (9/5) 60 + 32

T^oF = (9) 12 + 32

T^oF = 108 yil + 32

T^oF = 140 yil

1. Harorat shkalalarini konvertatsiya qilish
2. Chiziqli kengayish
3. Hududni kengaytirish
4. Hajmni kengaytirish
5. issiqlik
6. Issiqlikning mexanik ekvivalenti
7. Maxsus issiqlik va issiqlik sig'imi
8. Yashirin issiqlik, erish issiqligi, bug'lanish issiqligi
9. Issiqlik uzatish uchun energiya tejash