1. Metsi a 1 kg ho 100 o C a kopantsoe le metsi a 1 kg ho 10 o C tsamaisong e arohaneng. Mocheso o itseng wa metsi ke 4200 J/kg o C. Fumana mocheso wa ho qetela wa motswako!
Tse tsejoang:
Boima ba metsi a chesang (m 1 ) = 1 kg
Mocheso oa metsi a chesang (T 1 ) = 100 o C
Boima ba metsi a batang (m2 ) = 1 kg
Mocheso oa metsi a batang (T 2 ) = 10 o C
Ho batloa: Thempereichara ea ho qetela (T)
Tharollo:
Ho lahleheloa ke mocheso = Mocheso o fumanoeng (tsamaiso e arohaneng)
m c Δ T = m c Δ T
m Δ T = m Δ T
m 1 (T 1 – T) = m 2 (T – T 2 )
(1)(100 – T) = (1)(T – 10)
100 – T = T – 10
100 + 10 = T + T
110 = 2T
T = 110 / 2
T = 55
Mocheso oa ho qetela ke 55 o C.
[irp]
2. Boloko ba loto ea 3 kg ho 80o e beoa ka metsing a 10 kg. Mocheso o itseng oa loto ke 1400 J.kg-1C-1 'me mocheso o itseng oa metsi ke 4200 J.kg-1C-1Mocheso oa ho qetela oa tekano ea mocheso ke 20oC. Fumana mocheso oa pele oa metsi!
Tse tsejoang:
Boima ( m1 ) = 3 kg
Mocheso o itseng oa loto (c 1 ) = 1400 J.kg -1 C -1
Mocheso oa loto (T 1 ) = 80 o C
Boima ba metsi (m2 ) = 10 kg
Mocheso o itseng oa metsi (c 2 ) = 4200 J.kg -1 C -1
Mocheso oa tekano ea mocheso (T) = 20 o C
Ho batloa: Thempereichara ea pele ea metsi (T 2 )
Tharollo:
Mocheso o lahlehileng = Mocheso o fumanoeng
Q lead = Q metsi
m 1 c 1 ΔT = m 2 c 2 ΔT
(3)(1400)(80-20) = (10)(4200)(20-T)
(4200)(60) = (42,000)(20-T)
252,000 = 840,000 – 42,000 T
42,000 T = 840,000 – 252,000
42,000 T = 588,000
T = 588,000 / 42,000
T = 14
Mocheso oa pele oa metsi ke 14 ° C.
[irp]
3. Boloko ba koporo ho 100oC e beoa ka har'a ligrama tse 128 tsa metsi 30 oC. Mocheso o itseng oa metsi ke 1 cal.g-1oC-1 'me mocheso o itseng oa koporo ke 0.1 cal.g-1oC-1. Haeba mocheso oa tekano ea mocheso o 36 oC, fumana boima ba koporo!
Tse tsejoang:
Thempereichara ea koporo (T 1 ) = 100 o C
Mocheso o itseng oa koporo (c 1 ) = 0.1 c al.g -1o C -1
Boima ba metsi (m2 ) = digrama tse 128
Mocheso oa metsi (T 2 ) = 30 o C
Mocheso o itseng oa metsi (c 2 ) = 1 kcal al.g -1o C -1
Mocheso oa tekano ea mocheso (T) = 36 o C
Ho batloa: Boima ba koporo (m 1 )
Tharollo:
Mocheso o lahlehileng = Mocheso o fumanoeng
Koporo ea Q = Metsi a Q
m 1 c 1 ΔT = m 2 c 2 ΔT
(m 1 )(0.1)(100-36) = (128)(1)(36-30)
(m 1 )(0.1)(64) = (128)(1)(6)
(m 1 )(6.4) = 768
m 1 = 768 / 6.4
m 1 = 120
Boima ba koporo ke digrama tse 120.
[irp]
4. Leqhoa la M-kg ho 0oC e beoa ka har'a ligrama tse 340 tsa metsi ho 20oC ka har'a vase. Haeba mocheso oa ho kopanya bakeng sa metsi = 80 cal g-1, mocheso o itseng oa metsi ke 1 khalori g-1 oC-1. Leqhoa lohle lea qhibiliha le mocheso oa tekatekano ea mocheso is 5oC, fumana boima ba leqhoa!
Tse tsejoang:
Boima ba metsi (m) = digrama tse 340
Thempereichara ea leqhoa ( leqhoa la T ) = 0 o C
Thempereichara ea metsi ( metsi a T ) = 20 o C
Mocheso oa tekano ea mocheso (T) = 5 o C
Mocheso oa ho kopanya metsi ( L ) = 80 cal g -1
Mocheso o itseng oa metsi (c metsi ) = 1 cal g -1 o C -1
Ho batloa: Boima ba leqhoa (M)
Tharollo:
Mocheso o lahlehileng = Mocheso o fumanoeng
Q metsi = Q leqhoa
m c ( ΔT) = m es L es + m c ( Δ T)
(340)(1)(20-5) = M (80) + M (1)(5-0)
(340)(15) = 80M + 5M
5100 = 85M
M = 5100/85
M = digrama tse 60
[ID ea sephutheloana sa wpdm='714′]
- Ho fetola sekala sa mocheso
- Katoloso ya mola
- Katoloso ea sebaka
- Ho atolosoa ha molumo
- Heat
- E lekanang le mocheso ka mechine
- Mocheso le bokgoni ba mocheso bo ikgethang
- Mocheso o patehileng, mocheso oa ho kopana, mocheso oa mouoane
- Paballo ea matla bakeng sa phetisetso ea mocheso
