Adeegsiga sharciga koowaad ee thermodynamics-ka qaar ka mid ah hababka thermodynamic-ka (Isobaric Isothermal Isochoric)

30 Adeegsiga sharciga koowaad ee thermodynamics-ka ee qaar ka mid ah hababka thermodynamics-ka (Isobaric Isothermal Isochoric) 1. Jaantuska hoose wuxuu muujinayaa wareegga thermodynamic-ka ee uu gaas la kulmo. Shaqada uu gaasku ka qabto habka ABCD waa … La yaqaan: Cadaadiska 1 (P1) = 2 x 105 Pa Cadaadiska 2 (P2) = 4 x 105 … Akhri wax dheeraad ah

Sharciga ugu horreeya ee thermodynamics - dhibaatooyinka iyo xalalka

30 Sharciga ugu horreeya ee thermodynamics - dhibaatooyinka iyo xalalka 1. 3000 J oo kuleyl ah ayaa lagu daraa nidaam, 2500 J oo shaqo ahna waxaa sameeya nidaamku. Waa maxay isbeddelka tamarta gudaha ee nidaamka? La yaqaan: Kulaylka (Q) = +3000 Joules Shaqada (W) = +2500 Joules La Rabay: isbeddelka ... Akhri wax dheeraad ah

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka

1. Igaasaska ku beddel a weel xiran marka hore waxay leeyihiin mugga V iyo cadaadiska P. Haddii cadaadiska kama dambaysta ahi yahay 4P oo mugga la ilaaliyo, waa maxay ra-gu?tio tamarta dhaqdhaqaaqa bilowga ah ee leh kama dambaysta tamar kuleylka.

La yaqaan:

Cadaadiska bilowga ah (P1) = P

Cadaadiska kama dambaysta ah (P2) = 4P

Mugga bilowga ah (V1) = V

Mugga kama dambaysta ah (V2) = V

SE buska: Saamiga tamarta dhaqdhaqaaqa bilowga ah iyo tamarta dhaqdhaqaaqa ugu dambeysa (KE1 :KE2)

Xalka:

Xiriirka ka dhexeeya cadaadiska (P), mugga (V) iyo tamarta dhaqdhaqaaqa (KE) ee gaasaska ku habboon :

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 18

Saamiga tamarta dhaqdhaqaaqa bilowga ah iyo tamarta dhaqdhaqaaqa ugu dambeysa:

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 19

2. Waa maxay celceliska tamarta dhaqdhaqaaqa tarjumaadda ee molecules ee gaaska ku habboon 57oC.

La yaqaan:

Heerkulka gaaska (T) = 57oC + 273 = 330 Kelvin

BoltzmannJoogto ah (k) = 1.38 x 10-23 Joule/Kelvin

SE buska: Celceliska tamarta dhaqdhaqaaqa tarjumaadda

Xalka:

Xiriirka ka dhexeeya tamarta dhaqdhaqaaqa (KE) iyo heerkulka gaaska (T):

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 3

Tamarta dhaqdhaqaaqa tarjumaadda celceliska:

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 4

3. Gaas ku yaal 27oC weel xidhan. Haddii tamarta dhaqdhaqaaqa gaaska ay kordho 2 jeer tamarta dhaqdhaqaaqa bilowga ah, sidaas darteed heerkulka ugu dambeeya ee gaaska waa…

La yaqaan:

Heerkulka bilowga ah (T1= 27oC + 273 = 300 K

Tamarta dhaqdhaqaaqa bilowga ah =KE

Tamarta dhaqdhaqaaqa kama dambaysta ah = 4 KE

SE buska: Heerkulka kama dambaysta ah (T2)

Xalka:

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 5

4. Gaaska ku habboon wuxuu ku jiraa weel xiran, waa la kululeeyaa si uu u noqdo mid kama dambays ah xawaaraha celceliska Xawaaraha celceliska bilowga ah ee walxaha gaaska ayaa kordha 3 jeer. Haddii heerkulka gaaska ee bilowga ah uu yahay 27oC, markaas heerkulka ugu dambeeya ee gaaska ku habboon waa…

La yaqaan:

Heerkulka bilowga ah = 27oC + 273 = 300 Kelvin

Xawaaraha bilowga ah =v

Xawaaraha kama dambaysta ah = 2v

rabay :Theerkulka ugu dambeeya ee gaaska ku habboon

Xalka:

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 20

Xawaaraha celceliska ugu dambeeya = 2x xawaaraha celceliska bilowga ah

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 7

5. Saddex moles oo gaas ah ayaa ku jira meel muggeedu yahay 36 litir. Molekul kasta oo gaas ah wuxuu leeyahay tamar dhaqdhaqaaq oo ah 5 x 10-21 Joule. Joogtada gaaska guud = 8.315 J/mole.K iyo Joogtada Boltzmann = 1.38 x 10-23 J/K. Waa maxay cadaadiska gaaska ee ku jira weelka.

La yaqaan:

Tirada boollada (n) = 3 boollada

Mugga = 36 litir = 36 dm3 = 36x10-3 m3

Joogtada Boltzmann (k) = 1.38 x 10-23 J/K

Tamarta dhaqdhaqaaqa (KE) = 5 x 10-21 Joule

Joogtada gaaska guud (R) = 8.315 J/mole.K

rabay Cadaadiska gaaska (P)

Xalka:

Xisaabi heerkulka adoo isticmaalaya isle'egta tamarta dhaqdhaqaaqa ee gaaska.

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 8

Xisaabi cadaadiska gaaska adoo isticmaalaya isla'egta th ee sharciga gaaska ee ku habboon (tirada moles, n):

PV = n RT

B (36 x 10-3) = (3)(8.315)(241.5)

B (36 x 10-3= 6024.22

Aragtida kinetic ee gaasaska - dhibaatooyinka iyo xalalka 9

Cadaadiska gaaska waa 1.67 x 105 Jawiga Pascal ama 1.67.

Akhri wax dheeraad ah

Sharciga gaaska ee ugu habboon - dhibaatooyinka iyo xalalka

1. Anigagaasaska ku beddel a weel xiran marka hore waxay leeyihiin mugga V iyo heerkulka S. Heerkulka kama dambaysta ah waa 5/4T iyo kan kama dambaysta ah waa 5/4T cadaadiska waa 2P. Waa maxay mugga ugu dambeeya ee gaaska?

La yaqaan:

Mugga bilowga ah (V)1) = V

Heerkulka bilowga ah (T)1) = T

Heerkulka kama dambaysta ah (T)2) = 5/4 T

Cadaadiska bilowga ah (P)1) = P

Cadaadiska kama dambaysta ah (P)2) = 2P

SE buska: Mugga kama dambaysta ah (V)2)

Xalka:

Sharciga gaaska ee ku habboon - dhibaatooyinka iyo xalalka 1

2. Go'aami mugga 2.00 moles gaasaska (gaaska ku habboon) ee STP. STP = Heerkulka iyo Cadaadiska Caadiga ah.

La yaqaan:

Moles-ka gaaska (n) = 2 moles

Heerkulka caadiga ah (T) = 0 oC = 0 + 273 = 273 Kelvin

Cadaadiska caadiga ah (P) = 1 atm = 1.013 x 105 Pa

Joogtada gaaska guud (R) = 8.315 Joules/mole.Kelvin

rabay Mugga gaasaska (V)

Xalka:

Isle'egta Sharciga gaaska ee ku habboon (tirada burooyinka, n)

Sharciga gaaska ee ku habboon - dhibaatooyinka iyo xalalka 2

Mugga 2 moles oo gaas ah waa 44.8 litir.

Mugga 1 mole oo gaas ah waa 45.4 litir / 2 = 22.4 litir.

Mugga 1 mole ee gaas kasta waa 22.4 litir.

3. 4 litir oo gaas ogsijiin ah waxay leedahay heerkul ah 27°C iyo cadaadis ah 2 atm (1 atm = 10)5 Pa) weel xiran. Joogtada gaaska guud (R) = 8.314 J.mole-1.K-1 iyo lambarka Avogadro (NA= 6.02 x 1023 Molekulada/moleWaa maxay molecules-ka gaasaska oksijiinta ee ku jira weelka?

La yaqaan:

Mugga gaasaska (V) = 4 litir = 4 dm3 = 4x10-3 m3

Heerkulka gaasaska (T) = 27oC = 27 + 273 = 300 Kelvin

Cadaadiska gaasaska (P) = 2 atm = 2 x 105 Pa

Joogtada gaaska guud (R) = 8.314 J.mole-1.K-1

Lambarka Avogadro (N)A) = 6.02 x 1023

rabay Waa maxay molecules-ka gaasaska oksijiinta ee ku jira weelka (N)

Xalka:

Sharciga gaaska ee ku habboon - dhibaatooyinka iyo xalalka 3

1 mole oo gaas ogsijiin ah, waxaa ku jira 1.93 x 1023 Moleekulada oksijiinta.

4. Weel ka kooban gaas neon ah (Ne, cufnaanta atomka = 20 u) heerkulka iyo cadaadiska caadiga ah (STP)) waxay leedahay dherer dhan 2 mitir3Go'aami cufka gaaska neon!

La yaqaan:

Cufnaanta atamka ee neon = 20 garaam/mole = 0,02 kg/mole

Heerkulka caadiga ah (T) = 0oC = 273 Kelvin

Cadaadiska caadiga ah (P) = 1 atm = 1.013 x 105 Pascal

Mugga (V) = 2 m3

rabay : mass (M) gaaska neon ee gaaska neon

Xalka:

Heerkulka iyo cadaadiska caadiga ah (STP), 1 mole gaas kasta, ku dar gaaska neon, mug leh 22.4 litirs = 22.4 dm3 = 0.0448 m3.

Sharciga gaaska ee ku habboon - dhibaatooyinka iyo xalalka 4

Mugga 2 m3, waxaa jira 44.6 moles oo gaas neon ah.

Cufka atomiga ee gaaska neon waa 20 garaam/mole.

Taas macnaheedu waa in 1 mole uu ku jiro 20 garaam ama 0.02 kg oo gaas neon ah. Sababtoo ah 1 mole waxaa ku jira 0.02 kg oo gaas neon ah marka 44.6 mole waxaa ku jira 44.6 mole x 0.02 kg/mole = 0.892 kg = 892 garaam oo gaas neon ah.

Akhri wax dheeraad ah

Sharciga Gay-Lussac (mugga joogtada ah) - dhibaatooyinka iyo xalalka

1. Igaasaska heshiisku waxay markii hore leeyihiin cadaadiska P iyo heerkulka T. Gaasku wuxuu maraa habka isochoric si cadaadiska ugu dambeeya uu u noqdo 4 jeer cadaadiska bilowga ah. Waa maxay heerkulka ugu dambeeya ee gaaska?

La yaqaan:

Cadaadiska bilowga ah (P)1) = P

Cadaadiska kama dambaysta ah (P)2) = 4P

Heerkulka bilowga ah (T)1) = T

SE buska: Heerkulka kama dambaysta ah (T)2)

Xalka:

Qaaciddada Sharciga Gay-Lussac :

Sharciga Gay-Lussac (mugga joogtada ah) - dhibaatooyinka iyo xalalka 1

Heerkulka kama dambaysta ah wuxuu noqonayaa 4 jeer heerkulka bilowga ah.

2. Weel xiran, gaasaska ugu habboon waxay marka hore leeyihiin heerkul ah 27oC. Haddii Cadaadiska ugu dambeeya wuxuu noqonayaa 2 jeer cadaadiska bilowga ah, waa maxay heerkulka ugu dambeeya?

La yaqaan:

Cadaadiska bilowga ah (P)1) = P

Cadaadiska kama dambaysta ah (P)2) = 2P

Heerkulka bilowga ah (T)1= 27oC + 273 = 300 K

SE buska: Heerkulka kama dambaysta ah (T)2)

Xalka:

Sharciga Gay-Lussac (mugga joogtada ah) - dhibaatooyinka iyo xalalka 2

3. Taayir waxaa lagu shubaa cadaadis cabbirkiisu yahay 2 atm oo ah 27°C. Ka dib marka la wado, heerkulka taayirku wuxuu gaaraa 47°C. Waa maxay cadaadiska taayirku hadda ku jiro?

La yaqaan:

Cadaadiska jawiga = 1 atm = 1 x 105 Pa

Cadaadiska cabbirka bilowga ah = 2 atm = 2 x 105 Pa

Cadaadiska ugu horreeya ee dhammaystiran (P)1) = 1 atm + 2 atm = 3 atm = 3 x 105 Pa

Heerkulka bilowga ah (T)1= 27oC + 273 = 300 K

Heerkulka kama dambaysta ah (T)1= 47oC + 273 = 320 K

La doonayo: Heerkulka cabbirka kama dambaysta ah

Xalka:

Sharciga Gay-Lussac (mugga joogtada ah) - dhibaatooyinka iyo xalalka 3

Cadaadiska cabbirka kama dambaysta ah = cadaadiska kama dambaysta ah ee kama dambaysta ah - cadaadiska jawiga

Cadaadiska cabbirka kama dambaysta ah = 3.2 atm – 1 atm

Cadaadiska cabbirka kama dambaysta ah = 2.2 atm

Akhri wax dheeraad ah

Sharciga Charles (cadaadis joogto ah) - dhibaatooyinka iyo xalalka

1. Weel xiran, gaasku wuu ballaartaa si mugga ugu dambeeya uu u noqdo 3 jeer mugga bilowga ah (V = mugga bilowga, T = bilowga heerkulka) Waa maxay heerkulka ugu dambeeya?

La yaqaan:

Mugga bilowga ah (V)1) = V

Mugga kama dambaysta ah (V)2) = 3V

Heerkulka bilowga ah (T)1) = T

SE buska: Heerkulka kama dambaysta ah (T)2)

Xalka:

Qaaciddada Sharciga Charles :

Sharciga Charles (cadaadis joogto ah) - dhibaatooyinka iyo xalalka 1

Heerkulka ugu dambeeya ee gaasaska wuxuu noqdaa 3 jeer heerkulka bilowga ah.

2. AnigaGaasaska heshiisku waxay marka hore leeyihiin mugga V iyo heerkulka T. Haddii gaasku uu maro habka isobaric si heerkulku u noqdo 2 jibaar heerkulka bilowga ah markaa mugga ugu dambeeya ee gaasaska waa…

La yaqaan:

Mugga bilowga ah (V)1) = V

Heerkulka bilowga ah (T)1) = T

Heerkulka kama dambaysta ah (T)2) = 2T

SE buska: mugga kama dambaysta ah (V)2)

Xalka:

Sharciga Charles (cadaadis joogto ah) - dhibaatooyinka iyo xalalka 2

Mugga ugu dambeeya ee gaasaska wuxuu noqonayaa 2 jeer mugga bilowga ah.

3. Weel xiran, gaasaska ugu habboon waxay marka hore leeyihiin mug dhan 2 litir iyo heerkul dhan 27.oC. Haddii mugga ugu dambeeya ee gaasaska uu noqdo 3 litir markaas heerkulka kama dambaysta ah waa…

La yaqaan:

Mugga bilowga ah (V)1) = 2 litir = 2 dm3 = 2x10-3 m3

Mugga kama dambaysta ah (V)2) = 3 litir = 3 dm3 = 3x10-3 m3

Heerkulka bilowga ah (T)1= 27oC + 273 = 300 K

La doonayo: Heerkulka kama dambaysta ah (T)2)

Xalka:

Sharciga Charles (cadaadis joogto ah) - dhibaatooyinka iyo xalalka 3

Heerkulka kama dambaysta ah waa 177oC ama 177 + 273 = 450 Kelvin.

Akhri wax dheeraad ah

Sharciga Boyle (heerkulka joogtada ah) - dhibaatooyinka iyo xalalka

1. Qaar ka mid ah gaasaska ugu habboon ayaa marka hore leh cadaadiska P iyo mugga V. Haddii gaaska uu galo Habka isothermal-ka si cadaadiska kama dambaysta ahi uu u noqdo 4 jeer cadaadiska bilowga ah, ka dibna mugga ugu dambeeya ee gaaska waa…

La yaqaan:

Cadaadiska bilowga ah (P1) = P

Cadaadiska kama dambaysta ah (P2) = 4P

Mugga bilowga ah (V1) = V

SE buska: Mugga kama dambaysta ah (V2)

Xalka:

Qaaciddada Sharciga Boyle :

PV = joogto ah

P1 V1 =P2 V2

(P)(V) = (4P)(V)2)

V = 4 V2

V2 = V / 4 = ¼ V

Mugga ugu dambeeya ee gaasaska waa ¼ jeer mugga bilowga ah.

2. Weel xiran, gaasku wuu fidaa si uu final mugga noqotaa 2 jeer mugga bilowga ah (V = mugga bilowga ah, P = cadaadiska bilowga ah). Cadaadiska ugu dambeeya ee gaasaska waa…

La yaqaan:

Cadaadiska bilowga ah (P1) = P

Mugga bilowga ah (V1) = V

Mugga kama dambaysta ah (V2) = 2V

rabay : Cadaadiska kama dambaysta ah (P2)

Xalka:

P1 V1 =P2 V2

PV = P2 (2V)

P= P2 (2)

P2 = B / 2 = ½ B

Cadaadiska gaastu wuxuu noqdaa ½ jeer cadaadiska bilowga ah.

3. Weel xiran, gaasaska leh cadaadis dhan 2 atm iyo mugga 1 litir. Haddii cadaadiska gaasku noqdo 4 atm markaas mugga gaasku wuxuu noqdaa...

La yaqaan:

Cadaadiska bilowga ah (P1) = 2 atm = 2 x 105 Pa

Cadaadiska kama dambaysta ah (P2) = 4 atm = 4 x 105 Pa

Mugga bilowga ah (V1) = 1 litir = 1 dm3 = 1x10-3 m3

rabay : Mugga kama dambaysta ah (V2)

Xalka:

P1 V1 =P2 V2

(2 x 105)(1 x 10-3) = (4 x 105) V2

(1)(1 x 10)-3) = (2) V2

1 x 10-3 = (2) V2

V2 = ½ x 10-3

V2 = 0.5x10-3 m3 = 0.5 dm3 = 0.5 litirs

Akhri wax dheeraad ah

Kondenser-yada taxanaha ah iyo kuwa is barbar socda - dhibaatooyinka iyo xalalka

1. Saddex kaabayaal, C1 = 2 μF, C2 = 4 μF, C3 = 4 μF, waa ku xiran taxane iyo is barbar socdaGo'aami awoodda hal kaabsal oo yeelan doonta saameyn la mid ah isku-darka.

Kondenser-yada taxanaha ah iyo kuwa is barbar socda - dhibaatooyinka iyo xalalka 1La yaqaan:

Capacitor C1 = 2 μF

Kondenser C2 = 4 μF

Kondenser C3 = 4 μF

La doonayo: Awoodda u dhiganta (C)

Xalka:

Capacitor C2 iyo C3 isku xiran oo is barbar socda. Awoodda u dhiganta:

CP = C2 +C3 = 4 + 4 = 8 μF

Capacitor C1 iyo Cp Ku xiran taxane. Awoodda u dhiganta:

1/C = 1/C1 + 1/CP = 1/2 + 1/= 8 4/8 + 1/8 = 5/8

C = 8/5 μF

2. Shan kapacitors-ka, C1 = 2 μF, C2 = 4 μF, C3 = 6 μF, C4 = 5 μF, C5 = 10 μF, waxay ku xiran yihiin taxane iyo is barbar socda. Go'aami awoodda kaabsoodh keliya oo yeelan doonta saameyn la mid ah isku-darka.

La yaqaan:

Kondenser-yada taxanaha ah iyo kuwa is barbar socda - dhibaatooyinka iyo xalalka 2Kondenser C1 = 2 μF

Kondenser C2 = 4 μF

Kondenser C3 = 6 μF

Kondenser C4 = 5 μF

Kondenser C5 = 10 μF

La doonayo: Awoodda u dhiganta (C)

Xalka:

Capacitor C2 iyo C3 waxay ku xiran yihiin is barbar socda. Awoodda u dhiganta:

CP = C2 +C3

CP = 4 + 6

CP = 10 μF

Capacitor C1, CP, C4 iyo C5 waxay ku xiran yihiin taxane. Awoodda u dhiganta:

1/C = 1/C1 + 1/CP + 1/C4 + 1/C5

1/C = 1/2 + 1/10 + 1/5 + 1/10

1/C = 5/10 + 1/10 + 2/10 + 1/10

1/C = 9/10

C = 10/9 μF

3 C1 = 3 μF, C2 = 4 μF iyo C3 = 3 μF, waxay ku xiran yihiin taxane iyo is barbar socda. Go'aami tamarta korantada ku saabsan wareegyada.

La yaqaan:

Kondenser C1 = 3 μFKondenser-yada taxanaha ah iyo kuwa is barbar socda - dhibaatooyinka iyo xalalka 3

Kondenser C2 = 4 μF

Kondenser C3 = 3 μF

La doonayo: Awoodda u dhiganta (C)

Xalka:

Capacitor C2 iyo C3 waxay ku xiran yihiin is barbar socda. Awoodda u dhiganta:

CP = C2 +C3

CP = 4 + 3

CP = 7 μF

Capacitor C1 iyo CP waxay ku xiran yihiin taxane. Awoodda u dhiganta:

1/C = 1/C1 + 1/CP

1/C = 1/3 + 1/7

1/C = 7/21 + 3/21

1/C = 10/21

C = 21/10

C = 2.1 μF

C = 2.1 x 10-6 F

Tamarta korontada ee wareegyada:

E = ½ CV2

E = ½ (2.1 x 10-6(12)2)

E = ½ (2.1 x 10)-6) (144)

E = (2.1 x 10-6) (72)

E = 151.2 x 10-6 Joule

E = 1.5 x 10-4 Joule

Akhri wax dheeraad ah

Kondenser-yada taxanaha ah - dhibaatooyinka iyo xalalka

1. Afar kaabayaal, C1 = 2 μF, C2 = 1 μF, C3 = 3 μF, C4 = 4 μF, ayaa ku xiran taxanahaGo'aami awoodda hal kondhayaha taasi waxay yeelan doontaa saameyn la mid ah isku-darka.

La yaqaan:

Kondenser C1 = 2 μF

Kondenser C2 = 1 μF

Kondenser C3 = 3 μF

Kondenser C3 = 4 μF

La doonayo: Awoodda u dhiganta

Xalka:

Awoodda u dhiganta:

1/C = 1/C1 + 1/C2 + 1/C3 + 1/C4

1 / C = 1/2 + 1/1 + 1/3 + 1/4

1 / C = 6/12 + 12/12 + 4/12 + 3/12

1 / C = 25 / 12

C = 12 / 25

C = 0.48

Awoodda u dhiganta ee isku-darka oo dhan is 0.48 μF.

2. Go'aami kharashka ku jira capacitor C1 haddii farqiga suurtagalka ah inta u dhaxaysa P iyo Q is 12 Volt…

Kondenser-yada taxanaha ah - dhibaatooyinka iyo xalalka 1La yaqaan:

Kondenser C1 = 10 μF = 10 x 10-6 F

Kondenser C2 = 20 μF = 20 x 10-6 F

Farqiga suurtagalka ah (V) = 12 Waat

La doonayo: kharashka ku jira capacitor C1 (Q1)

Xalka:

Awoodda u dhiganta:

1/C = 1/C1 + 1/C2

1/C = 1/10 + 1/20 = 2/20 + 1/20 = 3/20

C = 20/3 μF = (20/3) x 10-6 F

Kharashka korontada ku saabsan capacitor-ka u dhigma:

Q = (C)(V) = (20/3)(12)(10)-6) = 80 x 10-6 C

Q = 80 μC

Kondenser-yadu waxay ku xiran yihiin taxane sidaas darteed dallacaadda korontada ee ku jirta capacitors-ka u dhigma = dallacaadda korontada ee capacitors-ka C1 = dallac koronto oo ku yaal capacitor-ka C2.

Dakhli koronto oo ku jira kalkulator-ka C1 waa 80 μC.

3. Laba kapacitor, C1 = 2 μF iyo C2 = 4 μF, waxay ku xiran yihiin taxane. Kaabsadeyaashu waa la dallacayaa. Farqiga suurtagalka ah ee ku saabsan kaabsade C1 waa 2 Volts. Dakhli koronto oo ku jira capacitor C2 waa ...

La yaqaan:

Capaccitor C1 = 2 μF = 2 x 10-6 F

Capaccitor C2 = 4 μF = 4 x 10-6 F

Farqiga u dhexeeya capacitors-ka C1 (V1) = 2 Volt

rabay : Lacag koronto oo ku jirta capacitor-ka C2.

Xalka:

Lacag koronto oo ku jirta capacitor-ka C1 :

Q1 = C1 V1 = (2 x 10-6)(2) = 4 x 10-6 C

Q1 = 4 μC

Capacitors waxaa lagu xiraa taxane si koronto loogu dallaco capacitor-ka C1 = dallac koronto oo ku yaal capacitor-ka C2.

Kharashkii ku jiray capacitor-ka C2 is 4 μC.

Akhri wax dheeraad ah

Kondenser-yada is barbar socda - dhibaatooyinka iyo xalalka

1. Afar capacitors, C1 = 2 μF, C2 = 1 μF, C3 = 3 μF, C4 = 4 μF, waxay ku xiran yihiin is barbar socda. Go'aami awoodda kaabsoodh keliya oo yeelan doonta saameyn la mid ah isku-darka.

La yaqaan:

Capacitor C1 = 2 μF

Capacitor C2 = 1 μF

Capacitor C3 = 3 μF

Capacitor C3 = 4 μF

La doonayo: Awoodda u dhiganta

Xalka:

Awoodda u dhiganta:

C = C1 +C2 +C3

C = 4 μF+2 μF+3 μF=9 μF

Awoodda u dhiganta ee isku-darka oo dhan waa 9 μF.

2. Go'aaminta waa lacag ku shaqeeya kondensarka C2 haddii farqiga suurtagalka ah inta u dhaxaysa barta A iyo B waa 9 Volts…

Kondenser-yada is barbar socda - dhibaatooyinka iyo xalalka 1

La yaqaan:

Capaccitor C1 = 20 μF = 20 x 10-6 F

Capaccitor C2 = 30 μF = 30 x 10-6 F

Farqiga suurtagalka ah ee u dhexeeya dhibcaha A iyo B (V)AB) = 9 Volt

rabay : kharashka ku jira capacitor-ka C2 (Q2)

Xalka:

Farqiga suurtagalka ah:

Kondenser-yadu waxay ku xiran yihiin is barbar socda si loo ogaado farqiga u dhexeeya A iyo B (V)AB) = farqiga suurtagalka ah ee capacitor C1 (V1) = farqiga suurtagalka ah ee capacitor C2 (V2) = 9 Volts.

Lacag koronto oo ku jirta capacitor-ka C2 :

Q2 = C2 V2 = (30 x 10-6)(9) = 270 x 10-6 C

Q2 = 270 μC

Dakhli koronto oo ku jira kalkulator-ka C2 is 270 μC.

3. Saddex kapacitors-ka, C1 = 4 μF, C2 = 2 μF, C3 = 3 μF, waxay ku xiran yihiin is barbar socda. Kaabsadeyaashu waa la dallacayaa. Farqiga suurtagalka ah ee kaabsadeyaashu way ku kala duwan yihiin C2 waa 4 Volts. Go'aami

(a) Kharash koronto oo ku jira capacitor C1, C2 iyo C3

(b) Kharash koronto oo ku jira kalkuletar u dhigma isku-darka oo dhan

La yaqaan:

Capaccitor C1 = 4 μF = 4 x 10-6 F

Ccapacitor C2 = 2 μF = 2 x 10-6 F

Ccapacitor C3 = 3 μF = 3 x 10-6 F

Farqiga suurtagalka ah ee capacitor-ka C2 (V2) = 4 Volt

rabay : Lacag koronto oo ku jirta capacitor-ka C3 (Q3)

Xalka:

(A) Lacag koronto oo ku jirta capacitor-ka C3

Farqiga u dhexeeya capacitors-ka C3 :

Kondenser-ku waxay ku xiran yihiin is barbar socda si farqiga u dhexeeya capacitor-ka uu u dhexeeyo C3 (V3) = farqiga u dhexeeya capacitor ee capacitor C2 (V2) = farqiga u dhexeeya capacitor ee capacitor C1 (V1) = farqiga u dhexeeya capacitor-ka u dhigma (V) = 4 Volt

Lacag koronto oo ku jirta capacitor-ka C1 :

Q1 = C1 V1 = (4 x 10-6)(4) = 16 x 10-6 C

Q1 = 16 μC

Lacag koronto oo ku jirta capacitor-ka C2 :

Q2 = C2 V2 = (2 x 10-6)(4) = 8 x 10-6 C

Q2 = 8 μC

Lacag koronto oo ku jirta capacitor-ka C3 :

Q3 = C3 V3 = (3 x 10-6)(4) = 12 x 10-6 C

Q3 = 12 μC

(B) Kharash koronto oo ku jira kondensator u dhigma

Q = Q1 +Q2 +Q3

Q = 16 μC+8 μC+12 μC = 36 μC

Xal kale:

Awoodda u dhiganta:

C = C1 +C2 +C3

C = 4 μF+2 μF+3 μF=9 μF

C = 9 x 10-6 F

Farqiga suurtagalka ah ee ku yimaada capacitor-ka u dhigma:

V1 =V2 =V3 = V = 4 Volt

Kharash koronto oo ku jira kalkulatorka u dhigma:

Q = CV = (9 x 10-6)(4) = 36 x 10-6 C

Q = 36 μC

Akhri wax dheeraad ah