Tamarta Kinetic - dhibaatooyinka iyo xalalka
1. Laba baabuur waxay leeyihiin cuf isku mid ah , iyagoo ku socda tamar kala duwan oo dhaqdhaqaaqa. Tamarta dhaqdhaqaaqa ee gaariga koowaad waa 9 jibaar tamarta dhaqdhaqaaqa ee gaariga labaad. Isbarbardhigga xawaaraha gaariga ee ugu horreeya iyo kan labaad waa…..
La yaqaan:
Cufka gaariga A (m A ) = m
Cufka gaariga B (m B ) = m
Tamarta dhaqdhaqaaqa ee gaariga B (K E B ) = K E
Tamarta dhaqdhaqaaqa ee gaariga A (K E A ) = 9 K E
La Doonayo: Isbarbardhigga xawaaraha gaariga ee ugu horreeya iyo kan labaad
Xalka:
Isle'egta tamarta dhaqdhaqaaqa:
KE = 1/2 mv 2
2 K E = mv 2
v 2 = 2 K E / m
Xawaaraha gaariga A:
v 2 = 2 K E A / m A = 2 (9 K E ) / m = 18 K E / m
Xawaaraha gaariga B :
v 2 = 2 K E B / m B = 2 K E / m = 2 K E / m
Isbarbardhigga xawaaraha gaariga A iyo gaariga B:
18 K E / m: 2 K E / m
18: 2
9: 1 = 3 2 : 1 2
2. Tamarta dhaqdhaqaaqa shayga ee barta B = 100 J. Haddii cufka shaygu yahay 2.5 kg , markaa go'aami tamarta dhaqdhaqaaqa shayga marka uu dhulka ku dhufto barta C. Dardargelinta cufisjiidadka awgeed waa 10 m/s 2.
Solution
Tamarta dhaqdhaqaaqa shayga marka uu gaaro barta B:
PE = mgh = (2.5)(10)(4) = 100 Joules
Tamarta dhaqdhaqaaqa shayga marka uu gaaro barta C:
PE = mgh
PE = (2.5)(10)(4 + 6)
PE = (2.5)(10)(10)
PE = 250 Joule
