1. Qaar ka mid ah gaasaska ugu habboon waxay marka hore leeyihiin cadaadis P iyo mugga V. Haddii gaasku maro habka isothermal-ka si cadaadiska kama dambaysta ahi uu u noqdo 4 jeer cadaadiska bilowga ah, markaa mugga ugu dambeeya ee gaaska waa…
La yaqaan:
Cadaadiska bilowga ah (P 1 ) = P
Cadaadiska kama dambaysta ah (P 2 ) = 4P
Mugga bilowga ah (V1 ) = V
La Doonayo: Mugga Ugu Dambeeya (V 2 )
Xalka:
Qaacidada sharciga Boyle :
PV = joogto ah
P 1 V 1 = P 2 V 2
(P)(V) = (4P)( V2 )
V = 4 V 2
V 2 = V / 4 = ¼ V
Mugga ugu dambeeya ee gaasaska waa ¼ jeer mugga bilowga ah.
2. Weel xiran, gaasku wuu ballaaraa si mugga ugu dambeeya uu u noqdo 2 jeer mugga bilowga ah (V = mugga bilowga ah, P = cadaadiska bilowga ah). Cadaadiska ugu dambeeya ee gaasaska waa…
La yaqaan:
Cadaadiska bilowga ah (P 1 ) = P
Mugga bilowga ah (V1 ) = V
Mugga kama dambaysta ah (V2 ) = 2V
La Rabay : Cadaadis kama dambays ah (P 2 )
Xalka:
P 1 V 1 = P 2 V 2
PV = P 2 (2V)
P = P 2 (2)
P 2 = B / 2 = ½ B
Cadaadiska gaastu wuxuu noqdaa ½ jeer cadaadiska bilowga ah.
3. Weel xiran, gaasas leh cadaadis dhan 2 atm iyo mug dhan 1 litir. Haddii cadaadiska gaasku noqdo 4 atm markaas mugga gaasku wuxuu noqdaa...
La yaqaan:
Cadaadiska bilowga ah (P1 ) = 2 atm = 2 x 10 5 Pa
Cadaadiska kama dambaysta ah (P2 ) = 4 atm = 4 x 10 5 Pa
Mugga bilowga ah (V1 ) = 1 litir = 1 dm 3 = 1 x 10 -3 m 3
La Doonayo : Mugga kama dambaysta ah ( V2 )
Xalka:
P 1 V 1 = P 2 V 2
( 2 x 10 5 )(1 x 10 -3 ) = (4 x 10 5 ) V 2
( 1)(1 x 10 -3 ) = (2) V 2
1 x 10 -3 = (2) V 2
V 2 = ½ x 10 -3
V 2 = 0.5 x 10 -3 m 3 = 0.5 dm 3 = 0.5 litir s
