# Eyeglass Farsightedness Nearsightedness

### Article about Eyeglass Farsightedness Nearsightedness

Nearsightedness can be normalized using eyeglass lenses and contact lenses. Eyeglass lenses are affixed to the eyeglass, while contact lenses are attached to the eyeball. Eyeglass has a certain distance from the eye while the contact lenses stick to the eye so that the distance between the contact lens and the eye can be ignored.

In this paper, we explain examples of problems experienced by sufferers of nearsightedness and farsightedness, the type of lens used to normalize the eye, and the focal length and the power of the lens. This focuses on the use of glasses to normalize nearsightedness and farsightedness.

### Farsightedness and eyeglass

The farthest distance that can be seen clearly by a person with nearsightedness is 102 cm. Determine (a) the type of lens used, (b) the focal length of the lens, (c) the power of the lens so that the nearsighted eyes can see infinite objects.

Eyeglass lenses are generally 2 cm from the eye.

Solution

(a) The type of lens used

Regarding nearsightedness, it has been explained that the lens used to normalize nearsighted eyes is a concave lens or divergent lens or negative lens.

(b) The focal length of the lens

The object that is observed in nearsighted eyes through the eyeglass are at infinite, so the lens must form an image at a distance of 102 cm in front of the eye. The eyeglass lens is 2 cm from the eye, so the image is 100 cm in front of the lens. The image is in front of the lens, so the image is virtual and upright (compare the explanation regarding the image formation of the concave lens)

Known:

The object distance (do) = infinite

The image distance (di) = -100 cm (negative means image is virtual)

Wanted: the focal length (f)

Solution:

1/f = 1/do + 1/di

1/f = 1/~ + (- 1/100)

1/f = 0 – 1/100

1/f = – 1/100

f = – 100/1 cm = -100 cm = -1 meter.

The focal length is negative, means that the lens used is a concave lens or a diverging lens.

(c) Power of lens

P = 1/f = 1/-1 m = -1 Diopter

The power of the lens is -1 D. Negative sign means the lens used is a concave lens or divergent lens.

### Nearsightedness and eyeglass

The closest distance that can be seen clearly by a sufferer of nearsightedness is 102 cm. For the person to be able to read at a distance of 25 cm in front of the eyes, determine (a) the type of lens used, (b) the focal length of the lens, (c) the power of the lens. Eyeglass lenses are generally 2 cm from the eye.

Solution

(a) The type of lens used

The lens used to normalize nearsighted eyes is a convex lens or convergent lens or positive lens.

(b) The focal length of the lens

The object observed is 25 cm in front of the eye, so the lens must form an image at a distance of 102 cm in the front of the eye. The eyeglass lens is 2 cm in the front of the eye, so the image is 100 cm in the front of the eyeglass lens and the object is 23 cm in the front of the eyeglass lens. The image is in the front of the lens, so the image is upright and virtual.

Known:

The object distance (do) = 23 cm

The image distance (di) = -100 cm (negative means the image is virtual)

Wanted: the focal length (f)

Solution:

1/f = 1/do + 1/di

1/f = 1/23 + 1/-100

1/f = 1/23 – 1/100

1/f = 100/2300 – 23/2300

1/f = 77/2300

f = 2300/77 = 30 cm = 0.3 meters

The focal length signed positive means that the lens used is a convex lens or convergent lens or positive lens.

(c) Power of lens

P = 1/f = 1/0.3 = +3 Diopters

The power of the lens is +3 D. Positive sign means that the lens used is a convex lens or convergent lens.

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