 # Centripetal acceleration – problems and solutions

1. A ball, attached to the end of a horizontal cord, is revolved in a circle of radius 20 cm. The ball around 360o each second. Determine the magnitude of the centripetal acceleration!

Known :

Angular speed (ω) = 360o/second = 1 revolution/second = 6.28 radians/second

Radius (r) = 20 cm = 0.2 m

Wanted : Centripetal acceleration (ar)

Solution :

ar = v2 / r —> v = r ω

ar = (r ω)2 / r = r2 ω2 / r

ar = r ω2

as = centripetal acceleration, v = linear velocity, r = radius, ω = angular velocity

The magnitude of the centripetal acceleration :

ar = r ω2 ar = (0,2 m)(6.28 rad/s)

ar = 1.256 m/s2

2. A wheel 30 cm in radius rotate at a rate of 180 rpm. Determine the centripetal acceleration of a point on the edge of wheel!

Known :

Radius (r) = 30 cm = 0.3 m

Angular speed (ω) = 180 revolutions / 60 seconds = 3 revolutions / second = (3)(6.28 radians) / second = 18.84 radians/second

Wanted : centripetal acceleration (ar) of r = 0.3 m

Solution :

The magnitude of the centripetal acceleration :

ar = r ω2

ar = 5.65 m/s2

3. A race car moving on a circular track of radius 50 meters. If car’s speed is 72 km/h, determine the magnitude of the centripetal acceleration!

Known :

Speed (v) = 72 km/h = (72)(1000 meters) / 3600 seconds = 20 meters/second

Wanted : the magnitude of the centripetal acceleration (ar)

Solution :

ar = v2 / r = 202 / 50 = 400 / 50 = 8 m/s2

4. A car has the maximum centripetal acceleration 10 m/s2, so the car can turn without skidding out of a curved path. If the car is moving at a constant 108 km/h, what is the radius of unbanked curve ?

Known :

Centripetal acceleration (ar) = 10 m/s2

Car’s speed (v) = 108 km/h = (108)(1000) / 3600 = 30 meters/second