Nā kaʻina hana thermodynamics Isochoric - nā pilikia a me nā hoʻonā

30 mau kaʻina hana thermodynamics Isochoric - nā pilikia a me nā hoʻonā

1. Hōʻike ka kiʻikuhi PV ma lalo nei i kahi kinoea kūpono e hele ana i kahi kaʻina hana isochoric . E helu i ka hana a ke kinoea i hana ai ma ke kaʻina hana AB.

Nā kaʻina hana thermodynamics Isochoric - nā pilikia a me nā hoʻonā 1Lōlā:

He kaʻina hana isochoric (ka nui mau) ke kaʻina hana AB. He mau ka nui no laila ʻaʻohe hana e hana ʻia e ke kinoea.

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2. ʻEkolu mole o ke kinoea monoatomic ma 47 o C a ma ke kaomi 2 x 10 5 Pa, ke hana nei i ke kaʻina hana isochoric i piʻi ai ke kaomi 3 x 10 5 Pa. ʻO ka loli o ka ikehu kūloko o ke kinoea… Universal gas constant (R) = 8.315 J/mol.K

ʻIke ʻia:

Ka mahana mua (T 1 ) = 47 o C + 273 = 320 K

Kaomi mua (P 1 ) = 2 x 10 5 Pa

Kaomi hope loa (P 2 ) = 3 x 10 5 Pa

ʻO ke kūpaʻa kinoea honua (R) = 8.315 J/mol.K

Helu o nā mole (n) = 3

Makemake ʻia: Ka loli o ka ikehu kūloko o ke kinoea.

Lōlā:

I ke kaʻina hana isochoric, mālama ʻia ka nui i ʻole e hana ʻia kekahi hana e ke kinoea (W = 0).

ʻO ke kānāwai mua o ka thermodynamics :

ΔU = QW

ΔU = Q-0

ʻΔU = Q

ΔU = ikehu kūloko, Q = wela

Ikehu kūloko o ke kinoea:

ΔU = 3/2 n R ΔT = 3/2 n R (T 2 – T 1 )

Ke kānāwai o Gay-Lussac ( ka leo mau ) :

Nā kaʻina hana thermodynamics Isochoric - nā pilikia a me nā hoʻonā 2

Ka loli o ka ikehu kūloko o ke kinoea:

ΔU = 3/2 n R (T 2 – T 1 ) = 3/2 (3)(8.315)(480-320)

ΔU = 3/2 (24.945)(160) = 3/2 (3991.2)

ʻO ΔU = 5986.8 Joule

3. Aia nā mole 0.2 o nā kinoea monatomic ma 27 o C i loko o kahi pahu pani. Hoʻohui ʻia ka wela i ke kinoea i lilo ai ka mahana o ke kinoea i 400 K… Universal gas constant (R) = 8.315 J/mol.K

ʻIke ʻia:

Helu o nā mole (n) = 0.2 mol

Ka mahana mua (T 1 ) = 27 o C + 273 = 300 K

Mahana hope loa (T 2 ) = 400 K

Kinoea mau loa (R) = 8.315 J/mol.K

Makemake ʻia : Hoʻohui ʻia ka wela (Q)

Lōlā:

I ke kaʻina hana isochoric, mālama ʻia ka nui i ʻole e hana ʻia kekahi hana e ke kinoea (W = 0).

ʻO ke kānāwai mua o ka thermodynamics:

ΔU = QW

ΔU = Q-0

ʻΔU = Q

ΔU = ikehu kūloko, Q = wela

Ka ikehu kūloko o ke kinoea:

ΔU = 3/2 n R ΔT = 3/2 n R (T 2 – T 1 )

ΔU = 3/2 (0.2)(8.315)(400-300)

ΔU = 3/2 (0.2)(8.315)(100)

ʻO ΔU = 249.45 Joule

4. E helu i ka hoʻoili wela no kahi kinoea kūpono e hana ana i kahi kaʻina hana isochoric mai ka mahana mua o 300 K a i ka mahana hope loa o 400 K. Manaʻo ʻia he 2 mol o ke kinoea, a ʻo ka mana wela molar ma ka leo mau (Cᵥ) he 20 J/(mol K).
Hoʻonā: ΔQ = n × Cᵥ × ΔT = 2 mol × 20 J/(mol K) × (400 K – 300 K) = 4000 J

5. E huli i ka loli o ka ikehu kūloko no ka pilikia i luna.
Hoʻonā: ΔU = ΔQ = 4000 J

6. E hoʻoholo i ka hana i hana ʻia ma kahi ʻōnaehana i ka wā o ke kaʻina hana isochoric no nā kūlana i luna.
Hoʻonā: W = 0 J (ʻoiai ʻaʻole loli ka leo, ʻaʻohe hana i hana ʻia)

7. No ke kinoea maikaʻi monatomic e hana ana i kahi kaʻina hana isochoric, inā he 2 atm ke kaomi mua a he 3 atm ke kaomi hope loa, he aha ka lakio o nā mahana hope loa i nā mahana mua?
Hoʻonā: ʻOiai ʻo P₁/T₁ = P₂/T₂, ʻo T₂/T₁ = 3/2

8. He aha ka loli entropy no kahi kinoea kūpono i loko o kahi kaʻina hana isochoric ke loli ka mahana mai 300 K a i 600 K, a ʻo n = 2 mol, Cᵥ = 20 J/(mol·K)?
Hoʻonā: ΔS = n × Cᵥ × ln(T₂/T₁) = 2 × 20 × ln(600/300) ≈ 27.73 J/K

9. Inā ua wehewehe ʻia ke kūlana mua o kahi kinoea diatomic ideal e V = 2 L, P = 1 atm, a me T = 300 K, e ʻimi i ke kaomi hope loa inā pāpālua ʻia ka mahana i loko o kahi kaʻina hana isochoric.
Hoʻonā: P₂ = 2 × P₁ = 2 atm

10. E huli i ka loli o ka ikehu manuahi o Gibbs no kahi kaʻina hana isochoric.
Hoʻonā: ΔG = 0 (No ke kaʻina hana isochoric i loko o kahi ʻōnaehana pani, ΔG = 0)

11. E helu i ka mahana hope loa o kahi kinoea kūpono e hana ana i kahi kaʻina hana isochoric inā he 200 K ka mahana mua, a ʻo nā kaomi mua a me ka hope he 2 atm a me 4 atm.
Hoʻonā: T₂ = 2 × T₁ = 400 K

12. No ke kinoea kūpono, inā ʻo ka mana wela ma ka leo mau (Cᵥ) he 30 J/(mol·K), e ʻimi i ka hoʻoili wela ke loli ka mahana mai 300 K a i 450 K, me 3 mol o ke kinoea.
Hoʻonā: ΔQ = n × Cᵥ × ΔT = 3 × 30 × 150 = 13500 J

13. No ke kaʻina hana like me luna, e helu i ka loli o ka ikehu kūloko.
Hoʻonā: ΔU = ΔQ = 13500 J

14. E hoʻoholo i ka loli entropy no kahi kaʻina hana isochoric me n = 1 mol, Cᵥ = 25 J/(mol·K), T₁ = 200 K, a me T₂ = 400 K.
Hoʻonā: ΔS = n × Cᵥ × ln(T₂/T₁) = 25 × ln(2) ≈ 17.33 J/K

15. E huli i ka hana i hana ʻia e ka ʻōnaehana i ka wā o ke kaʻina hana isochoric o 3 mol o ke kinoea, a loli ka mahana mai 200 K a i 300 K.
Hoʻonā: W = 0 J (ʻoiai ʻaʻole loli ka leo, ʻaʻohe hana i hana ʻia)

16. E helu i ka hoʻoili wela no kahi kinoea kūpono e hana ana i kahi kaʻina hana isochoric me ka mahana mua o 150 K, ka mahana hope loa o 300 K, a me Cᵥ = 15 J/(mol·K) no 4 mol o ke kinoea.
Hoʻonā: ΔQ = n × Cᵥ × ΔT = 4 × 15 × 150 = 9000 J

17. He aha ka loli entropy no kahi kinoea kūpono i loko o kahi kaʻina hana isochoric me n = 1 mol, Cᵥ = 30 J/(mol·K), T₁ = 100 K, a me T₂ = 200 K?
Hoʻonā: ΔS = n × Cᵥ × ln(T₂/T₁) = 30 × ln(2) ≈ 20.79 J/K

18. E hoʻoholo i ke kaomi hope loa o kahi kinoea e hana ana i kahi kaʻina hana isochoric, i hāʻawi ʻia ʻo P₁ = 5 atm, T₁ = 250 K, a me T₂ = 500 K.
Hoʻonā: P₂ = (T₂/T₁) × P₁ = 2 × 5 atm = 10 atm

19. E huli i ka hoʻoili wela no 5 mol o kahi kinoea maikaʻi monatomic e hana ana i kahi kaʻina hana isochoric mai 300 K a i 600 K. Manaʻo ʻia ʻo Cᵥ = 15 J/(mol K).
Hoʻonā: ΔQ = n × Cᵥ × ΔT = 5 × 15 × 300 = 22500 J

20. He aha ka loli o ka ikehu kūloko no ka pilikia ma luna?
Hoʻonā: ΔU = ΔQ = 22500 J

21. E hoʻoholo i ka loli entropy no kahi kaʻina hana isochoric kahi n = 2 mol, Cᵥ = 25 J/(mol K), T₁ = 300 K, a me T₂ = 600 K.
Hoʻonā: ΔS = n × Cᵥ × ln(T₂/T₁) = 2 × 25 × ln(2) ≈ 34.66 J/K

22. E helu i ka mahana hope loa o 1 mol o kahi kinoea maikaʻi monatomic e hana ana i kahi kaʻina hana isochoric inā ʻo ka mahana mua he 400 K, a ʻo nā kaomi mua a me ka hope he 3 atm a me 6 atm.
Hoʻonā: T₂ = 2 × T₁ = 800 K

23. No ke kinoea diatomic ideal e hana ana i kahi kaʻina hana isochoric, e helu i ka loli o ka ikehu kūloko ke loli ka mahana mai 300 K a i 600 K, me 2 mol o ke kinoea, a ʻo Cᵥ = 30 J/(mol·K).
Hoʻonā: ΔU = n × Cᵥ × ΔT = 2 × 30 × 300 = 18000 J

24. E helu i ka hoʻoili wela no kahi kinoea kūpono e hana ana i kahi kaʻina hana isochoric me ka mahana mua o 100 K, ka mahana hope loa o 300 K, a me Cᵥ = 20 J/(mol·K) no 2 mol o ke kinoea.
Hoʻonā: ΔQ = n × Cᵥ × ΔT = 2 × 20 × 200 = 8000 J

25. E huli i ka hana i hana ʻia ma ka ʻōnaehana i ka wā o ke kaʻina hana isochoric no nā kūlana i luna.
Hoʻonā: W = 0 J (ʻoiai ʻaʻole loli ka leo, ʻaʻohe hana i hana ʻia)

26. He aha ka loli entropy no kahi kinoea kūpono i loko o kahi kaʻina hana isochoric ke loli ka mahana mai 400 K a i 800 K, a ʻo n = 3 mol, Cᵥ = 20 J/(mol·K)?
Hoʻonā: ΔS = n × Cᵥ × ln(T₂/T₁) = 3 × 20 × ln(2) ≈ 41.58 J/K

27. E huli i ka loli o ka ikehu manuahi o Gibbs no kahi kaʻina hana isochoric.
Hoʻonā: ΔG = 0 (No ke kaʻina hana isochoric i loko o kahi ʻōnaehana pani, ΔG = 0)

28. E hoʻoholo i ke kaomi hope loa o kahi kinoea e hana ana i kahi kaʻina hana isochoric, i hāʻawi ʻia ʻo P₁ = 3 atm, T₁ = 300 K, a me T₂ = 450 K.
Hoʻonā: P₂ = (T₂/T₁) × P₁ = 1.5 × 3 atm = 4.5 atm

29. E helu i ka loli o ka ikehu kūloko no kahi ʻōnaehana e hana ana i kahi kaʻina hana isochoric me 3 mol o ke kinoea, Cᵥ = 20 J/(mol K), a loli ka mahana mai 200 K a i 400 K.
Hoʻonā: ΔU = n × Cᵥ × ΔT = 3 × 20 × 200 = 12000 J

30. E hoʻoholo i ka loli entropy no kahi kaʻina hana isochoric kahi n = 4 mol, Cᵥ = 30 J/(mol K), T₁ = 150 K, a me T₂ = 300 K.
Hoʻonā: ΔS = n × Cᵥ × ln(T₂/T₁) = 4 × 30 × ln(2) ≈ 55.86 J/K

Uhi kēia mau pilikia i nā manaʻo like ʻole e pili ana i nā kaʻina hana isochoric, e like me ka hoʻoili wela, ka loli ikehu kūloko, ka hana i hana ʻia, ka loli entropy, a me nā mea hou aku.