Misalan tambayoyi da dabarun raƙuman ruwa masu wucewa, raƙuman ruwa masu tsayi, raƙuman ruwa masu tsayawa
Raƙuman ruwa masu wucewa
1. Nisa tsakanin magudanan ruwa guda biyu da ke kusa da raƙuman ruwa na saman ruwa mita 20 ne. Wani abu yana shawagi a saman ruwa kuma yana jin motsin girgiza. Idan lokacin girgiza ɗaya ya kai daƙiƙa 4, to saurin raƙuman ruwa shine…. m/s
- 20
- 15
- 10
- 5
Tattaunawa
An san cewa:
Tsawon Raƙuman Ruwa (λ) = mita 20
Lokaci (T) = daƙiƙa 4
An tambaya: Gudun igiyar ruwa (v)
Amsa:
Tsarin saurin raƙuman ruwa:
v = λ / T = mita 20 / daƙiƙa 4 = mita 5 / daƙiƙa
Amsar da ta dace ita ce D.
2. Maki biyu na A da B suna kan igiya kuma suna da nisan santimita 90 tsakanin juna. A kan igiyar, raƙuman ruwa masu ratsawa, don haka wannan batu na A yana kan kololuwar raƙuman ruwa, batu na B yana ƙasan raƙuman ruwa, kuma tsakanin su biyun akwai kololuwa biyu da ƙasan raƙuman ruwa biyu. Idan lokacin raƙuman ruwa ya kasance daƙiƙa 0,3, to Gudun yaɗuwar raƙuman ruwa Yana da….
- 10,8 cm / s
- 18,0 cm / s
- 120,0 cm / s
- 200,0 cm / s
Tattaunawa
An san cewa:
Nisa AB (l) = 90 cm
Lokacin raƙuman ruwa (T) = daƙiƙa 0,3
Mitar raƙuman ruwa (f) = 1/0,3 daƙiƙa
Ma'ana A tana kan kololuwar raƙuman ruwa, ma'ana B tana ƙasan raƙuman ruwa
Tsakanin maki A da B akwai kololuwa biyu da ƙasa biyu na raƙuman ruwa
An tambaya: Gudun yaɗuwar raƙuman ruwa (v = f λ)
Amsa:
Dangane da hoton, an kammala da cewa akwai raƙuman ruwa 2,5. Nisa na raƙuman ruwa ɗaya (λ) = 90 cm / 2,5 = 36 cm
Saurin yaɗuwar raƙuman ruwa:
v = f λ = (1/0,3) (36) = 36/0,3 = 120 cm/s.
Amsar da ta dace ita ce C.
3. Jadawalin da ke ƙasa yana nuna matsar da wani wuri a cikin matsakaici a matsayin aikin lokaci yayin da raƙuman ruwa ke ratsawa ta cikin matsakaici.
Idan tsawon tsayin igiyar mita 6 ne, to saurin yaɗuwar igiyar...
- 3 m / s
- 6 m / s
- 8 m / s
- 12 m / s
Tattaunawa
An san cewa:
Akwai raƙuman ruwa guda biyu bisa ga jadawalin da ke sama.
Nisa tsakanin raƙuman ruwa guda 1 (λ) = mita 6 / 2 = mita 3.
Lokaci (T) = daƙiƙa 0,5
An tambaya: Gudun igiyar ruwa (v)
Amsa:
v = f λ = λ / T = mita 3 / daƙiƙa 0,5 = mita 6 / daƙiƙa
Amsar da ta dace ita ce B.
Raƙuman ruwa masu tsayi
4. Ana yin sautin sautuka guda biyu a lokaci guda a cikin matsakaici ɗaya da zafin jiki iri ɗaya. Tushen sauti na farko yana da mita na 640 Hz kuma tushen sauti na biyu shine 1280 Hz. Bayanin da ya dace shine….
- Saurin sautin farko ya fi saurin sautin na biyu girma
- Saurin sautin farko ya fi na sautin na biyu ƙanƙanta
- Sautin sauti na farko da na biyu iri ɗaya ne
- Doguwa raƙuman sauti dukkansu girmansu iri ɗaya ne
Tattaunawa
Saurin sauti ya dogara da matsakaici, don haka idan matsakaici ɗaya ne, saurin sautunan biyu zai kasance iri ɗaya. Akasin haka, idan mitar ta yi yawa, tsawon zai yi ƙanƙanta, haka nan, idan mitar ta yi ƙasa, tsawon zai yi girma. Mitar sautunan biyu ta bambanta, don haka tsawon sautunan biyu suma za su bambanta.
Amsar da ta dace ita ce C.
Raƙuman ruwa masu tsayawa (tsaye raƙuman ruwa)
5. Zaren da aka manne shi da ƙarshensa biyu yana samar da sautin asali mai mita 420 Hz. Mitar sautunan da ke kan maɓallan uku sune….
- 840 Hz
- 1260 Hz
- 1680 Hz
- 2940 Hz
Tattaunawa
An san cewa:
Mita ta asali (f)1) = 420 Hz
An ɗaure ƙarshen waya biyu
An tambaya: Mitar sautuka uku
Amsa:
Mitar sautin na biyu (f)2) = 2 f1 = 2 (420 Hz) = 840 Hz
Mitar sautin na uku (f)3) = 3 f1 = 3 (420 Hz) = 1260 Hz
Amsar da ta dace ita ce B.
Sautin raƙuman sauti
6.
Hoton da ke ƙasa yana nuna kararrawa mai amfani da wutar lantarki a cikin wani rufaffen gida. Daga nan sai aka yi ƙararrawa, tana fitar da iska daga cikin gidan. Bayan an saki iska daga cikin gidan, ba a sake jin sautin kararrawa ba. Dangane da wannan lamari, za a iya yanke hukuncin cewa sautin...
- ba ya faruwa a cikin rufaffiyar sarari
- ɗauke da iskar da ke fitowa daga murfin
- ba zai iya yaduwa a cikin sarari ba
- ba zai iya yaduwa ta hanyar daskararru ba
Tattaunawa
Sauti wani irin rawa ne da ke ratsa ta cikin daskararru, ruwaye, da iskar gas. Idan kararrawa tana cikin wani wuri mai duhu, raƙuman sauti ba za su iya tafiya daga kararrawa zuwa kunnen mai sauraro ba.
Amsar da ta dace ita ce C.
Tushen tambaya:
Tambayoyin OSN na Makarantar Sakandare ta Junior Physics