Kimiyya

Fahimta
Ana ɗaukar jiki mai tauri a matsayin wanda ya ƙunshi ƙwayoyin cuta da yawa, kuma nauyin abu shine jimlar nauyin kowanne ƙwayar cuta da ta ƙunshi abu. Tsakiyar taro wuri ne da ke kan abu inda ake ɗaukar nauyin dukkan ƙwayoyin cuta da suka ƙunshi abu a matsayin mai tarawa a wannan lokacin.

Tsarin dabara
Ana ɗauka cewa kowace jiki mai tauri ta ƙunshi ƙwayoyin cuta da yawa, kowannensu yana da nisan da ya yi daidai da ɗayan. Duk da haka, don sauƙaƙa samowar dabarar tantance tsakiyar taro, ana yin sauƙaƙawa ta hanyar ɗauka cewa jiki mai tauri ya ƙunshi ƙwayoyin cuta biyu kawai. Ana iya kiran waɗannan ƙwayoyin cuta guda biyu tsarin jiki mai tauri.

Karin bayani

Haka kuma yi nazarin Misalan Tambayoyi na Cibiyar Nauyi

Fahimtar Cibiyar Nauyi
Ana ɗaukar abu mai tauri a matsayin wanda ya ƙunshi ƙwayoyin cuta da yawa saboda wannan ƙarfin nauyi yana aiki akan kowanne daga cikin waɗannan ƙwayoyin. A wata ma'anar, kowane ƙwayar cuta yana da nasa nauyin. Cibiyar nauyi ta abu ita ce wuri a kan ko kusa da abin inda aka tattara nauyin dukkan sassan abin.

Idan abu ya yi kama da juna (yawan wasu abubuwa iri ɗaya ne ko kuma abin ya ƙunshi kayan iri ɗaya) kuma siffar abin ta yi daidai (misali murabba'i, murabba'i mai kusurwa huɗu, da'ira) to cibiyar nauyi ta abu ta yi daidai da tsakiyar nauyin abin da ke tsakiyar abin. Ga alwatika, tsakiyar nauyi yana nan a 1/3 h, inda h = tsayin alwatika.

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Ba duk abubuwan da muke fuskanta a rayuwar yau da kullum ba ne suke hutawa koyaushe. Abu yana iya hutawa da farko, amma idan an motsa shi, zai iya motsawa. Tambayar ita ce ko ya koma matsayinsa na asali bayan ya motsa ko a'a. Wannan ya dogara ne da motsin. nau'ikan ma'aunin abu tersebut
Idan wani abu da ke hutawa ya fuskanci matsala (akwai ƙarfin da ya haifar ko kuma lokacin ƙarfin da ya haifar da ke aiki akan abu) to abin zai motsa. Bayan motsi, akwai yiwuwar abubuwa uku, wato: (1) abin ya koma matsayinsa na asali, (2) abin ya motsa daga matsayinsa na asali, (3) abin ya ci gaba da kasancewa a sabon matsayinsa. Idan bayan motsi, abin ya koma matsayinsa na asali to abin yana cikin daidaito mai karkoIdan bayan motsi, abin ya ƙara matsawa daga matsayinsa na asali, to abin yana cikin Daidaito mara tabbasA gefe guda kuma, idan bayan motsa abin ya ci gaba da kasancewa a sabon matsayinsa, to abin yana cikin daidaito tsaka-tsaki.

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Misalai 2 na tambayoyin daidaiton barbashi

1. An rataye wani abu mai nauyin kilogiram 10 a kan igiya. A tantance matsin lamba a cikin igiyar (T)! g = 10 m/s²
Tattaunawa

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Misalan 5 na tambayoyin aikin makamashin motsi da kimiyyar lissafi

1. Motar da nauyinta ya kai kilogiram 5000 da farko tana tsayawa a tsaye, sannan ta yi tafiya da gudun mita 20/s. Ka tantance jimlar aikin da aka yi a motar...
Tattaunawa
An sani :
Mass (m) = 5000 kg
Saurin farko (v)_o) = 0 m/s (da farko motar ba ta tsayawa)
Saurin ƙarshe (v)_t) = 20 m/s
An tambaya : Jimillar ƙoƙari

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Misalai 15 na Tambayoyin Ka'idojin Baƙar fata

1. Kankara mai nauyin kilogiram 0,2 ana gauraya ta da shayi mai dumi mai nauyin kilogiram 0,2. Zafin kankara = - 10 ^oC , zafin shayi mai dumi = 40 ^oC . Zafin kankara na musamman = 2100 J/kg C ^o , zafin ruwa na musamman = 4200 J/kg C ^o , zafin haɗuwar ruwa = 334.000 J/kg. Idan kankara da shayi mai dumi an gauraya su a cikin tsarin rufewa, a tantance zafin ƙarshe na cakuda.

Tattaunawa
An sani :
Nauyin kankara (m es) = 0,2 kg
Nauyin ruwan shayi mai dumi (m shayi) = 0,2 kg
Takamaiman zafin ruwa (c ruwa) = 4180 J/kg C^o
Takamaiman zafin kankara (c es) = 2100 J/kg C^o
Zafin haɗakar ruwa (L)_f ruwa) = 334.000 J/kg

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Misalai 5 na ƙaura mai kusurwa da ƙaura mai layi a cikin motsi mai zagaye

1. Tayar da ke da radius na santimita 30 tana juyawa tazarar radius 10. Har yaushe wani wuri a gefen tayar yake tafiya?
Tattaunawa
Nisa tsakanin gefen dabaran da tsakiyar dabaran = radius na dabaran.
An san cewa:
Radius (r) = 30 cm = mita 0,3
Kusurwa (inna) = radian 10
An tambaya: nisan da aka yi tafiya (s)
Amsa:

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2 Misalan tambayoyi kan tantance vector mai sakamakon ta amfani da vectors masu haɗin kai

1. F ₁ = 6 N, F ₂ = 10 N. Sakamakon vectors guda biyu shine…

Tattaunawa
F_1x = F₁ kowa 60^o = (6)(0,5) = 3 N (tabbatacce saboda yana kan alkiblar x mai kyau)
F_2x = F₂ kowa 30^o = (10)(0,5√3) = 5√3 = (5)(1,372) = -8,66 N (mara kyau saboda yana kan hanyar x mara kyau)
F_1y = F₁ ba 60^o = (6)(0,5√3) = 3√3 = (3)(1,372) = 4,116 N (tabbatacce saboda yana kan alkiblar y mai kyau)
F_2y = F₂ ba 30^o = (10)(0,5) = -5 N (mara kyau saboda yana kan hanyar y mara kyau)

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2 Misalan tambayoyi kan tantance sassan vector

1. Ƙarfin vector F = 20 Newton yana samar da kusurwar 30 ^o zuwa ga axis ɗin x mai kyau. Ƙayyade abubuwan da ke cikin vector F akan axis ɗin x (F _x ) da axis ɗin y (F _y ).

Tattaunawa
F_x = F cos 30^o = (20)(kwas 30)^o) = (20)(0,5√3) = 10√3 Newtons

Karin bayani

Yi nazarin misalan matsalolin tsangwama da rarrabuwar haske - tsaga ɗaya , sannan ka yi aiki a kan matsalolin tsangwama da rarrabuwar haske.

1. Hasken da ke da tsawon nisan nm 700 yana ratsawa ta cikin wani tsagi mai faɗin mm 0,2. Tsarin rarrabawa akan allon yana da nisan santimita 50 daga tsagin. A tantance tazarar da ke tsakanin layin duhu na biyu da babban layin haske.
Tattaunawa

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