Misali na tambaya don tantance vector da aka samu ta amfani da vectors na sassan

2 Misalan tambayoyi kan tantance vector mai sakamakon ta amfani da vectors masu haɗin kai

1. F₁ = 6 N, F₂ = 10 N. Sakamakon vectors guda biyu shine…

Tattaunawa
F_1x = F₁ kowa 60^o = (6)(0,5) = 3 N (tabbatacce saboda yana kan alkiblar x mai kyau)
F_2x = F₂ kowa 30^o = (10)(0,5√3) = 5√3 = (5)(1,372) = -8,66 N (mara kyau saboda yana kan hanyar x mara kyau)
F_1y = F₁ ba 60^o = (6)(0,5√3) = 3√3 = (3)(1,372) = 4,116 N (tabbatacce saboda yana kan alkiblar y mai kyau)
F_2y = F₂ ba 30^o = (10)(0,5) = -5 N (mara kyau saboda yana kan hanyar y mara kyau)

F_x = F_1x - F_2x = 3 – 8,66 = -5,66 N
F_y = F_1y - F_2y  = 4,116 – 5 = -0,884 N

Sakamakon vector shine 5,7 N.

2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Sakamakon vectors uku masu ƙarfi shine…

Tattaunawa
F_1x = F₁ kowa 60^o = (4)(0,5) = 2 N (tabbatacce saboda yana kan alkiblar x mai kyau)
F_2x = -4 N (mara kyau saboda yana cikin alkiblar x mara kyau)
F_3x = F₃ kowa 60^o = (8)(0,5) = 4 N (tabbatacce saboda yana kan alkiblar x mai kyau)
F_1y = F₁ ba 60^o = (4)(0,5√3) = 2√3 N (mai kyau saboda yana kan alkiblar y mai kyau)
F_2y = 0
F_3y = F₃ ba 60^o = (8)(0,5√3) = -4√3 N (mara kyau saboda yana kan hanyar y mara kyau)

F_x = F_1x - F_2x +F_3x = 2 – 4 + 4 = 2 N
F_y = F_1y +F_2y  - F_3y = 2√3 + 0 – 4√3 = -2√3 N

Sakamakon vector shine 4 N.

Tambayoyi kan tantance vector da aka samu ta amfani da vectors na sassa

1. F₁ = 6 N, F₂ = 12 N. Sakamakon vectors guda biyu shine…
2. F₁ = 10 N, F₂ = 10 N, F₃ = 15 N. Sakamakon vectors uku masu ƙarfi shine…

[Turanci: Magance matsalolin vector - tantance sakamakon vector guda biyu ta amfani da abubuwan da ke cikin vector]