Motsi kai tsaye

Kayan Motsi Madaidaiciya

Motsi wani abu ne da muke lura da shi a kullum a rayuwar yau da kullum. Reshen kimiyyar lissafi da ke nazarin motsi ana kiransa makanikai. Reshen makanikai da ke tattauna yadda abu ke motsawa, ba tare da la'akari da dalilin motsi ba, ana kiransa kinematics . Akasin haka, reshen makanikai da ke tattauna dalilan motsi kuma ya bayyana dalilin da yasa abubuwa ke motsawa kamar yadda suke yi ana kiransa da kuzari. A cikin wannan batu, ana ɗaukar kowane abu mai motsi kamar barbashi ne ko kuma maki (.). Ana ɗaukar abubuwa masu motsi a matsayin maki kawai don sauƙaƙe nazarinmu. Ka yi tunanin idan batu ya motsa a layi madaidaiciya, to hanyarsa za ta samar da layi madaidaiciya.

Ana cewa abu yana motsi a kwance idan hanyarsa madaidaiciya ce. Idan hanyarsa ta lankwasa, abu ba ya motsi a kwance. Motsin abu, wanda ake ɗauka a matsayin barbashi, yana da girma ɗaya. Motsin girma ɗaya na iya faruwa a kwance (daidai da axis na x) ko a tsaye (daidai da axis na y).

Misalin matsalolin

1. Tambayoyin Jarrabawar Ƙasa ta 2017

Kalli hoton!

Mafi girman nisan da abu ya yi a cikin tazara tsakanin lokaci…

A. 0 s zuwa 10 sTattaunawa kan Jarrabawar Ƙasa ta 2017 don Ilimin Lissafi na Makarantun Sakandare - 5

B. Daƙiƙa 10 zuwa daƙiƙa 20

C. 20 daƙiƙa zuwa 30 daƙiƙa

D. Daƙiƙa 30 zuwa daƙiƙa 50

E. 50 s zuwa 70 s

Tattaunawa

Tsarin nisa:

s = vt

Nisa = yanki mai inuwa.

Mafi girman nisa = mafi girman yanki.

A. ½ (10-0)(20-0) = ½ (10)(20) = (5)(20) = 100

B. (20-10)(10-0) + (½)(20-10)(20-10) = (10)(10) + ½ (10)(10) = 100 + (5)(10) = 100 + 50 = 150

C. (30-20)(10-0) = (10)(10) = 100

D. (50-30)(10-0) = (20)(10) = 200

E (70-50) (10-0) + ½ (70-50) (30-10) = (20) (10) + ½ (20) (20) = 200 + (10) (20) = 200 + 200 = 400

Amsar da ta dace ita ce E.

2. Tambayoyin Jarrabawar Ƙasa ta 2017

Ƙwayar da ke motsawa sama tana bin lissafin y = 8t – t 2 , tare da y da t a cikin mita da daƙiƙa, bi da bi. Gudun abu a t = daƙiƙa 2 shine…

A. 2 ms -1

B. 4 ms -1

C. 8 ms -1

D. 12 ms -1

E. 16 ms -1

Tattaunawa

y = 8t – t 2

v = 8 – 2t

Saurin abu a t = daƙiƙa 2:

v = 8 – 2t = 8 – 2(2) = 8 – 4 = 4 m/s.

Amsar da ta dace ita ce B.

3. Tambayoyin Jarrabawar Ƙasa ta SMA/MA ta 2017

Duba jadawalin bayanai na sauri don abubuwa uku masu zuwa!

Tattaunawa kan Jarrabawar Ƙasa ta 2017 don Ilimin Lissafi na Makarantun Sakandare - 15

Dangane da tebur, za a iya kammala da cewa abin da ke da mafi girman hanzari shine...

A. Abu A don t 1 – t 2

B. Abu A don t 2 – t 3

C. Abu B don t 1 – t 2

D. Abu C don t 1 – t 2

E. Abu C don t 2 – t 3

Tattaunawa

Abu na A: saurin abu yana ƙaruwa da m4/s a kowace daƙiƙa 2 ko m2/s a kowace daƙiƙa 1 = m2/s 2.

Abu na B: saurin abu yana ƙaruwa da m5/s a kowace daƙiƙa 2 ko m2,5/s a kowace daƙiƙa 1 = m2,5/s 2.

Abu na C: saurin abu yana raguwa da m2/s a kowace daƙiƙa 2 ko m1/s a kowace daƙiƙa 1 = -1 m/s 2.

Amsar da ta dace ita ce C.

Ku bar sharhi