Misali na da'irar resistor

Misalai 3 na tambayoyin da'irar resistor

1. Jerin resistor da ke ƙasa waɗanda ke da mafi girman juriya iri ɗaya shine...

Tattaunawa game da da'irorin resistor

Tattaunawa

Amsa A

R 1 = 2 Ω, R 2 = 2 Ω, R 3 = 6 Ω, R 4 = 6 Ω

R3 da kuma R4 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R 34 = 1/R 3 + 1/R 4 = 1/6 + 1/6 = 2/6

R 34 = 6/2 = 3 Ω

R1, R2 da kuma R34 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R = R 1 + R 2 + R 34 = 2 Ω + 2 Ω + 3 Ω

R = 7Ω

Amsa B

R 1 = 2 Ω, R 2 = 4 Ω, R 3 = 4 Ω, R 4 = 8 Ω

R2 da kuma R3 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R 23 = R 2 + R 3 = 4 Ω + 4 Ω = 8 Ω

R23 da kuma R4 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R 234 = 1/R 23 + 1/R 4 = 1/8 + 1/8 = 2/8

R 234 = 8/2 = 4 Ω

R1 da kuma R234 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R = R 1 + R 234 = 2 Ω + 4 Ω

R = 6 Ω

Amsa C

R 1 = 9 Ω, R 2 = 9 Ω, R 3 = 9 Ω, R 4 = 2 Ω

R1, R2 da kuma R3 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R 123 = 1/ R 1 + 1/ R 2 + 1/R 3 = 1/9 + 1/9 + 1/9 = 3/9

R 123 = 9/3 = 3 Ω

R123 da kuma R4 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R = R 123 + R 4 = 3 Ω + 2 Ω

R = 5 Ω

Amsa D

R 1 = 5 Ω, R 2 = 10 Ω, R 3 = 2 Ω, R 4 = 2 Ω

R1 da kuma R2 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R 12 = 1/R 1 + 1/R 2 = 1/5 + 1/10 = 2/10 + 1/10

1/R 12 = 3/10

R 12 = 10/3 Ω

R3 da kuma R4 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1/R 34 = 1/R 3 + 1/R 4 = 1/2 + 1/2 = 2/2

R 34 = 1 Ω

R12 da kuma R34 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R = R 12 + R 34 = 10/3 + 3/3 = 13/3

R = 4,3 Ω

Amsar da ta dace ita ce A.

2. Daidaiton juriya a cikin hoton da ke ƙasa shine…

A. 26 OhmTattaunawa kan tambayoyin da'irar resistor 1

B. 16 Ohm

C. 15 Ohm

D. 11 Ohm

Tattaunawa

An haɗa masu juriya 6 Ω, 3 Ω da 2 Ω a layi ɗaya. Masu juriyar maye gurbin sune:

1/R P = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6

R P = 6/6 = 1 Ω

An haɗa masu juriya 7 Ω, 8 Ω, da 1 Ω a jere. Masu juriyar maye gurbin sune:

R = 7 + 8 + 1 = 16 Ω

Amsar da ta dace ita ce B.

3. Nawa ne Rp a cikin da'irar gauraye da ke ƙasa?

A. 8 ohmsTattaunawa kan tambayoyin da'irar resistor 2

B. 1/8 ohm

C. 1 ohm

D. 7 ohms

Tattaunawa

An san cewa:

Resistor 1 (R 1 ) = 2 Ohm

Resistor 2 (R 2 ) = 2 Ohm

Resistor 3 (R 3 ) = 2 Ohm

Resistor 4 (R 4 ) = 2 Ohm

An tambaya: Resistor na maye gurbin

Amsa:

An haɗa masu juriya R 2 da R 3 a layi ɗaya. Masu tsayayyar maye gurbin:

1/R 23 = 1/R 2 + 1/R 3

1/R 23 = 1/2 + 1/2 = 2/2

R 23 = 1 Ohm

An haɗa Resistor R 1 , Resistor R 23 da Resistor R 3 a jere. Resistor masu maye gurbin:

R = R 1 + R 2 + R 3 = 2 + 1 + 2

R = 5 Ohm

Amsar da ta dace ita ce 5 Ohms.

Tushen tambaya:

Tambayoyin Jarrabawar Ƙasa ta Kimiyya ta Makarantar Sakandare/Makarantar Sakandare ta Musulunci

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