Misali na da'irar resistor

Misalai 3 na tambayoyin da'irar resistor

1. Jerin resistor da ke ƙasa waɗanda ke da mafi girman juriya iri ɗaya shine...

Tattaunawa

Amsa A

R₁ = 2 Ω, R₂ = 2 Ω, R₃ = 6 Ω, R₄ = 6 Ω

R₃ da kuma R₄ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1 / R₃₄ = 1/R₃ +1/R₄ = 1/6 + 1/6 = 2/6

R₃₄ = 6/2 = 3 Ω

R_1, R₂ da kuma R₃₄ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R = ba R₁ + R₂ + R₃₄ = 2 Ω + 2 Ω + 3 Ω

R = 7Ω

Amsa B

R₁ = 2 Ω, R₂ = 4 Ω, R₃ = 4 Ω, R₄ = 8 Ω

R₂ da kuma R₃ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R₂₃ = R₂ + R₃ = 4 Ω + 4 Ω = 8 Ω

R₂₃ da kuma R₄ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1 / R₂₃₄ = 1/R₂₃ +1/R₄ = 1/8 + 1/8 = 2/8

R₂₃₄ = 8/2 = 4 Ω

R₁ da kuma R₂₃₄ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R=R₁ + R₂₃₄ = 2 Ω + 4 Ω

R = 6 Ω

Amsa C

R₁ = 9 Ω, R₂ = 9 Ω, R₃ = 9 Ω, R₄ = 2 Ω

R_1, R₂ da kuma R₃ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1 / R₁₂₃ = 1 /R₁ + 1/R₂ +1/R₃ = 1/9 + 1/9 + 1/9 = 3/9

R₁₂₃ = 9/3 3 Ω

R₁₂₃ da kuma R₄ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R=R₁₂₃ + R₄ = 3 Ω + 2 Ω

R = 5 Ω

Amsa D

R₁ = 5 Ω, R₂ = 10 Ω, R₃ = 2 Ω, R₄ = 2 Ω

R₁ da kuma R₂ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1 / R₁₂ = 1/R₁ +1/R₂ = 1/5 + 1/10 = 2/10 + 1/10

1 / R₁₂ = 3 / 10

R₁₂ = 10 / 3 Ω

R₃ da kuma R₄ an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:

1 / R₃₄ = 1/R₃ +1/R₄ = 1/2 + 1/2 = 2/2

R₃₄ = 1 Ω

R₁₂ da kuma R₃₄ An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:

R=R₁₂ + R₃₄ = 10/3 + 3/3 = 13/3

R = 4,3 Ω

Amsar da ta dace ita ce A.

2. Daidaiton juriya a cikin hoton da ke ƙasa shine…

A. 26 Ohm

B. 16 Ohm

C. 15 Ohm

D. 11 Ohm

Tattaunawa

An haɗa masu juriya 6 Ω, 3 Ω da 2 Ω a layi ɗaya. Masu juriyar maye gurbin sune:

1 / R_P = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6

R_P = 6/6 = 1 Ω

An haɗa masu juriya 7 Ω, 8 Ω, da 1 Ω a jere. Masu juriyar maye gurbin sune:

R = 7 + 8 + 1 = 16 Ω

Amsar da ta dace ita ce B.

3. Nawa ne Rp a cikin da'irar gauraye da ke ƙasa?

A. 8 ohms

B. 1/8 ohm

C. 1 ohm

D. 7 ohms

Tattaunawa

An san cewa:

Resistor 1 (R)₁) = 2 Ohms

Resistor 2 (R)₂) = 2 Ohms

Resistor 3 (R)₃) = 2 Ohms

Resistor 4 (R)₄) = 2 Ohms

An tambaya: Resistor mai maye gurbin

Amsa:

Resistor R₂ da kuma juriya R₃ an haɗa shi a layi ɗaya. Resistor na maye gurbin:

1 / R₂₃ = 1/R₂ +1/R₃

1 / R₂₃ = 1/2 + 1/2 = 2/2

R₂₃ = 1 Ohms

Resistor R₁, resistor R₂₃ da kuma juriya R₃ an haɗa shi cikin jerin. Resistor na maye gurbin:

R=R₁ + R₂ + R₃ = 2 + 1 + 2

R = 5 Ohm

Amsar da ta dace ita ce 5 Ohms.

Tushen tambaya:

Tambayoyin Jarrabawar Ƙasa ta Kimiyya ta Makarantar Sakandare/Makarantar Sakandare ta Musulunci