Misalai 3 na tambayoyin da'irar resistor
1. Jerin resistor da ke ƙasa waɗanda ke da mafi girman juriya iri ɗaya shine...

Tattaunawa
Amsa A
R 1 = 2 Ω, R 2 = 2 Ω, R 3 = 6 Ω, R 4 = 6 Ω
R3 da kuma R4 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R 34 = 1/R 3 + 1/R 4 = 1/6 + 1/6 = 2/6
R 34 = 6/2 = 3 Ω
R1, R2 da kuma R34 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R = R 1 + R 2 + R 34 = 2 Ω + 2 Ω + 3 Ω
R = 7Ω
Amsa B
R 1 = 2 Ω, R 2 = 4 Ω, R 3 = 4 Ω, R 4 = 8 Ω
R2 da kuma R3 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R 23 = R 2 + R 3 = 4 Ω + 4 Ω = 8 Ω
R23 da kuma R4 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R 234 = 1/R 23 + 1/R 4 = 1/8 + 1/8 = 2/8
R 234 = 8/2 = 4 Ω
R1 da kuma R234 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R = R 1 + R 234 = 2 Ω + 4 Ω
R = 6 Ω
Amsa C
R 1 = 9 Ω, R 2 = 9 Ω, R 3 = 9 Ω, R 4 = 2 Ω
R1, R2 da kuma R3 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R 123 = 1/ R 1 + 1/ R 2 + 1/R 3 = 1/9 + 1/9 + 1/9 = 3/9
R 123 = 9/3 = 3 Ω
R123 da kuma R4 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R = R 123 + R 4 = 3 Ω + 2 Ω
R = 5 Ω
Amsa D
R 1 = 5 Ω, R 2 = 10 Ω, R 3 = 2 Ω, R 4 = 2 Ω
R1 da kuma R2 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R 12 = 1/R 1 + 1/R 2 = 1/5 + 1/10 = 2/10 + 1/10
1/R 12 = 3/10
R 12 = 10/3 Ω
R3 da kuma R4 an haɗa shi a layi ɗaya. Resistor ɗin maye gurbin shine:
1/R 34 = 1/R 3 + 1/R 4 = 1/2 + 1/2 = 2/2
R 34 = 1 Ω
R12 da kuma R34 An haɗa shi cikin jerin. Resistor ɗin maye gurbin shine:
R = R 12 + R 34 = 10/3 + 3/3 = 13/3
R = 4,3 Ω
Amsar da ta dace ita ce A.
2. Daidaiton juriya a cikin hoton da ke ƙasa shine…
A. 26 Ohm
B. 16 Ohm
C. 15 Ohm
D. 11 Ohm
An haɗa masu juriya 6 Ω, 3 Ω da 2 Ω a layi ɗaya. Masu juriyar maye gurbin sune:
1/R P = 1/6 + 1/3 + 1/2 = 1/6 + 2/6 + 3/6 = 6/6
R P = 6/6 = 1 Ω
An haɗa masu juriya 7 Ω, 8 Ω, da 1 Ω a jere. Masu juriyar maye gurbin sune:
R = 7 + 8 + 1 = 16 Ω
Amsar da ta dace ita ce B.
3. Nawa ne Rp a cikin da'irar gauraye da ke ƙasa?
A. 8 ohms
B. 1/8 ohm
C. 1 ohm
D. 7 ohms
Tattaunawa
An san cewa:
Resistor 1 (R 1 ) = 2 Ohm
Resistor 2 (R 2 ) = 2 Ohm
Resistor 3 (R 3 ) = 2 Ohm
Resistor 4 (R 4 ) = 2 Ohm
An tambaya: Resistor na maye gurbin
Amsa:
An haɗa masu juriya R 2 da R 3 a layi ɗaya. Masu tsayayyar maye gurbin:
1/R 23 = 1/R 2 + 1/R 3
1/R 23 = 1/2 + 1/2 = 2/2
R 23 = 1 Ohm
An haɗa Resistor R 1 , Resistor R 23 da Resistor R 3 a jere. Resistor masu maye gurbin:
R = R 1 + R 2 + R 3 = 2 + 1 + 2
R = 5 Ohm
Amsar da ta dace ita ce 5 Ohms.
Tushen tambaya:
Tambayoyin Jarrabawar Ƙasa ta Kimiyya ta Makarantar Sakandare/Makarantar Sakandare ta Musulunci