Misalai 7 na canza motsi na zagaye daidai gwargwado
1. Motar da ke da ƙarfin juyawa da farko tana juyawa da sauri sau 2 a kowane lokaci.2. Kayyade saurin kusurwa da kuma saurin kusurwar propeller bayan daƙiƙa 2. Ka bayyana su a cikin radians da daƙiƙa.
Tattaunawa
An sani :
An tambaya : hanzarin kusurwa da saurin kusurwa bayan daƙiƙa 2
Jawab :
(A) Haɓaka kusurwa bayan daƙiƙa 2
Haɓakar kusurwar tana dawwama saboda haka bayan daƙiƙa 2, haɓakar kusurwar ta kasance 2 rad/s2.
(B) Saurin kusurwa bayan daƙiƙa 2
Hanzarin kusurwa 2 rad/s2 = Radians 2/daki a kowace dakika yana nufin saurin kusurwa yana ƙaruwa da radians 2/daki a kowace dakika 1. Bayan dakika 1, saurin kusurwa yana zama radians 2/dakika. Bayan dakika 2, saurin kusurwa yana zama radians 4/dakika.
2. Tayar da ta fara hutawa tana sauri daidai gwargwado. Bayan daƙiƙa 10, tayar tana juyawa a gudun kusurwa na 60 rpm. Ka ƙayyade saurin kusurwa na tayar!
Tattaunawa
Jawab :
Tsarin motsi mai sauri daidai gwargwado (GMBB) yayi kama da tsarin motsi mai sauri daidai gwargwado (GLBB).
Hanzarta kusurwar dabaran shine 0,628 rad/s 2
3. Saurin kusurwar silinda yana canzawa daidai gwargwado daga 20 rad/s zuwa 10 rad/s cikin daƙiƙa 4. Kayyade saurin kusurwar silinda!
Tattaunawa
Jawab :
Haɓakar kusurwar silinda shine -2,5 rad/s2. Alamar korau = hanzari mara kyau ko raguwa. Idan a cikin hanzari, saurin kusurwa yana ƙaruwa, to a cikin raguwa, saurin kusurwa yana raguwa.
4. Abu da ke juyawa da farko a gudun kusurwa na 10 rad/s yana fuskantar saurin kusurwa na 2 rad/s.2. Kayyade kusurwar da ke kewaye da abin bayan daƙiƙa 2!
Tattaunawa
5. Tayar mota da farko ke juyawa da saurin kusurwa na 20 rad/s, tana tsayawa tana juyawa bayan ta yi tafiya da kusurwar radian 20. Hanzarta kusurwar tayar ita ce…
Tattaunawa
Jawab :
Ana warware wannan tambayar ta amfani da dabara ta 3.
6. Tambayoyin Jarrabawar Ƙasa na 1999/2000 P4 No. 26
Ana juya sandar PQ mai tsawon santimita 60 tare da tip Q a matsayin axis da PQ a matsayin radius na juyawa. Sandar PQ tana juyawa daga hutawa tare da hanzarin kusurwa na 0,3 rad s -2 . Idan matsayin kusurwar farko = 0, to saurin layi (v) na tip P a t = daƙiƙa 10 shine...
A. 1,8 ms -1
B. 3 ms -1
C. 5 ms -1
D. 30 ms -1
E. 180 ms -1
Tattaunawa
An san cewa:
Tsawon sandar PQ = radius na da'ira (r) = 60 cm = 60/100 m = mita 0,60
Saurin kusurwa na farko (ωo ) = 0 rad/s
Haɓaka kusurwa (α) = 0,3 rad s -2
Matsayin kusurwa na farko (θ o ) = 0
Tambaya: Saurin layi (v) na ƙarshen P a lokacin t = daƙiƙa 10
Amsa:
Da farko, ƙididdige saurin kusurwar sandar a lokacin t daƙiƙa 10.
Tsarin Motsin Zagaye Mai Sauri Daidai:
ω t = ω o + α t = 0 rad/s + (0,3 rad s -2 )(10 sec) = 3 rad s -1
Saurin kusurwa a t = daƙiƙa 10 shine radians 3/daƙiƙa.
Ana ƙididdige saurin layi a t = daƙiƙa 10 ta amfani da dabarar da ke nuna alaƙar da ke tsakanin saurin layi (v), saurin kusurwa (ω) da radius (r).
v = r ω = (mita 0,6)(radian 3/daƙiƙa) = mita 1,8/daƙiƙa.
Amsar da ta dace ita ce A.
7. Tambayoyin Jarrabawar Ƙasa na 2002/2003
Wani abu yana motsawa a cikin da'ira mai saurin farko na 4 rad/s kuma yana fuskantar saurin kusurwa na 0,5 rad/s 2 , sannan saurin abu a cikin daƙiƙa ta huɗu shine...
A. 4,0 rad/s
B. 4,5 rad/s
C. 5,0 rad/s
D. 6,0 rad/s
E. 8,0 rad/s
Tattaunawa
An san cewa:
Saurin kusurwa na farko (ω o ) = 4 radians/daƙiƙa
Hanzarin kusurwa (α) = 0,5 rad/s 2
Tazarar lokaci (t) = daƙiƙa 4
Tambaya: Saurin abu a cikin daƙiƙa ta huɗu (ω t )
Amsa:
Tsarin canza motsi na zagaye daidai gwargwado:
ω t = ω o + α t
ω t = 4 + (0,5)(4)
ω t = 4 + 2
ω t = 6 radians/daƙiƙa
Amsar da ta dace ita ce D.
