1. A small ball is thrown horizontally with a constant speed of 10 m/s. The ball hits the wall and reflected with the same speed. What is the change in chiziqli momentum to'pningmi?
Ma'lum:
Mass (m) = 0.2 kg
Boshlang'ich tezlik (v)o) = -10 m/s
Yakuniy tezlik (v)t) = 10 m/s
Plyus va minus belgilari jismlarning qarama-qarshi yo'nalishda harakatlanishini ko'rsatadi.
Wanted : the change in linear momentum (Δp)
yechim:
Formula of the change in linear momentum :
Δp = mvt – mvo = m (v)t - vo)
The change in linear momentum :
Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)
Δp = 0.2 (20)
dp = 4 kg m/s
2. A 10-gram ball falls freely from a height, hits the floor at 15 m/s, then reflected upward at 10 m/s. Determine the impulse!
Ma'lum:
Mass (m) = 10 gram = 0.01 kg
Boshlang'ich tezlik (v)o) = -15 m/s
Yakuniy tezlik (v)t) = 10 m/s
Qidirilgan: Impuls (I)
yechim:
The impulse (I) equals the change in momentum (Δp)
I = m vt – mvo = m (v)t - vo)
Impulse :
I = 0.01 (10 – (-15)) = 0.01 (10 + 15)
I = 0.01 (25)
I = 0.25 kg m/s
3. A 200-gram ball thrown horizontally with a speed of 4 m/s, then the ball was hit in the same direction. The duration of the ball in contact with the bat is 2 milliseconds and the ball speed after leaving the bat is 12 m/s. The magnitude of kuch harakat qilgan by the batter on the ball is …
Ma'lum:
Mass (m) = 200 gram = 0.2 kg
Boshlang'ich tezlik (v)o) = 4 m/s
Yakuniy tezlik (v)t) = 12 m/s
Time interval (t) = 2 milliseconds = (2/1000) seconds = 0.002 seconds
Wanted : The magnitude of the force (F)
yechim:
Formula of impulse :
I = F t
Formula of the change in momentum :
mvt – mvo = m (v)t - vo)
The impulse (I) equals the change in momentum (Δp)
I = Δp
F t = m (vt - vo)
F (0.002) = (0.2)(12 – 4)
F (0.002) = (0.2)(8)
F (0.002) = 1.6
F = 1.6 / 0.002
F = 800 Nyuton
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