Momentum va impuls – muammolar va yechimlar

1. A small ball is thrown horizontally with a constant speed of 10 m/s. The ball hits the wall and reflected with the same speed. What is the change in chiziqli momentum to'pningmi?

Ma'lum:

Mass (m) = 0.2 kg

Boshlang'ich tezlik (v)o) = -10 m/s

Yakuniy tezlik (v)t) = 10 m/s

Plyus va minus belgilari jismlarning qarama-qarshi yo'nalishda harakatlanishini ko'rsatadi.

Wanted : the change in linear momentum (Δp)

yechim:

Formula of the change in linear momentum :

Δp = mvt – mvo = m (v)t - vo)

The change in linear momentum :

Δp = 0.2 (10 – (-10)) = 0.2 (10 + 10)

Δp = 0.2 (20)

dp = 4 kg m/s

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2. A 10-gram ball falls freely from a height, hits the floor at 15 m/s, then reflected upward at 10 m/s. Determine the impulse!

Ma'lum:

Mass (m) = 10 gram = 0.01 kg

Boshlang'ich tezlik (v)o) = -15 m/s

Yakuniy tezlik (v)t) = 10 m/s

Qidirilgan: Impuls (I)

yechim:

The impulse (I) equals the change in momentum (Δp)

I = m vt – mvo = m (v)t - vo)

Impulse :

I = 0.01 (10 – (-15)) = 0.01 (10 + 15)

I = 0.01 (25)

I = 0.25 kg m/s

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3. A 200-gram ball thrown horizontally with a speed of 4 m/s, then the ball was hit in the same direction. The duration of the ball in contact with the bat is 2 milliseconds and the ball speed after leaving the bat is 12 m/s. The magnitude of kuch harakat qilgan by the batter on the ball is …

Ma'lum:

Mass (m) = 200 gram = 0.2 kg

Boshlang'ich tezlik (v)o) = 4 m/s

Yakuniy tezlik (v)t) = 12 m/s

Time interval (t) = 2 milliseconds = (2/1000) seconds = 0.002 seconds

Wanted : The magnitude of the force (F)

yechim:

Formula of impulse :

I = F t

Formula of the change in momentum :

mvt – mvo = m (v)t - vo)

The impulse (I) equals the change in momentum (Δp)

I = Δp

F t = m (vt - vo)

F (0.002) = (0.2)(12 – 4)

F (0.002) = (0.2)(8)

F (0.002) = 1.6

F = 1.6 / 0.002

F = 800 Nyuton

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