Mathata a Rarollotsoeng Fisiks ea Motheo

Matla a likaroloana - mathata le litharollo

1. Ntho A e nang le boima ba 6-kg le ntho B e nang le boima ea 4-kg e hokahantsoe ka thapo 'me e huloa ka matla a F = 60 N, joalo ka ha ho bontšitsoe setšoantšong se ka tlase. khohlano ea kinetic Pakeng tsa mokatong le dintho ka bobedi ke 0.5 (tan θ = ¾). Ho potlakisa ka baka la matla a khoheli ke 10 m/s². Boholo ba matla a tsitsipano ke bofe?

Tse tsejoang:

Boima ba ntho A (m_A) = 6 kg

Boima ba ntho B (m_B) = 4 kg

Matla (F) = 60 Newton

Bala haholoanyane

Botebo le ho phaphamala ka tekano - mathata le litharollo

1. Boloko bo behilweng ka hara diedi tse pedi tse nang le mefuta e fapaneng. Metsing A, karolo ya 0.6 ya ntho e ka hara mokelikeli. Metsing B, karolo ya 0.5 ya ntho e ka hara mokelikeli. Fumana karolelano ya bongata ba tsona ea mokelikeli A ho ea ho mokelikeli B.

Tse tsejoang:

Botenya ba boloko = x

Karolo ea ntho e ka har'a mokelikeli A = 0.6

Boima ba mokelikeli A = y

Karolo ea ntho e ka har'a mokelikeli B = 0.5

Bala haholoanyane

Paballo ea matla a mechini holim'a libaka tse kobehileng - mathata le litharollo

1. Haeba lebelo la bolo ntlheng ea A e le 6 m/s, lebelo la bolo ntlheng ea B ke √92 m/s, 'me ho potlaka ka lebaka la matla a khoheli ke g = 10 m/s²Bophahamo ba ntlha B (h) ke bokae?

Tse tsejoang:

Lebelo la bolo ntlheng ea A (v)_A) = 6 m/s

Lebelo la bolo ntlheng ea B (v)_B) = √92 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Bophahamo ba A (h_A) = limithara tse 5.6

Bala haholoanyane

Setsi sa matla a khoheli - mathata le litharollo

1. Fumana likhokahano tsa setsi sa matla a khoheli ea ntho eo joalokaha ho bontšitsoe setšoantšong se ka tlase.

Tharollo:

Arola ntho ka likarolo tse tharo.

Sebaka sa karolo ea 1 (A)₁) = (2)(6) = 12 cm²

Ntlha e bohareng e lutse hodima mothapo wa x (x₁) = 1/2 (2) = 1 cm

Ntlha e bohareng e lutse hodima mothapo wa y (y₁) = 1/2 (6) = 3 cm

Bala haholoanyane

Khopolo-taba ea Torricelli - mathata le litharollo

1. Phaephe e nang le bophahamo ba 100 cm e tletseng metsi. Lesoba la Q le fumaneha ho 10 cm ka holimo ho mobu. Sebaka se bataletseng (x) ke sefe?

Tse tsejoang:

Sebaka se pakeng tsa lesoba le bokaholimo ba metsi (h) = 100 cm – 10 cm = 90 cm = 0.9 m

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s²

Bala haholoanyane

Vekthara - mathata le litharollo

Vekthara le Scalar

1. Har'a likhetho tse latelang, e leng lipara tsa scalar-vector…

A. Matla – ho potlaka

B. tsotellehe khatello – matla

C. Ho tlosoa – lebelo

D. Motlakase wa motlakase – kgatello

Bala haholoanyane

Maekroskoupo e kopaneng - mathata le litharollo

1.

Ho latela setšoantšo se kaholimo, keketseho ka kakaretso ke efe? Nka hore leihlo le tloaelehileng kahoo ntlha e haufi (N) = 25 cm.

Tse tsejoang:

Bala haholoanyane

Bongata ba 'Mele Diyuniti Litekanyo - Mathata le Litharollo

1.

Ho ipapisitsoe le tafole e ka holimo, ke bongata bofe bo nang le diyuniti le litekanyo tsa nnete.

Bala haholoanyane

Ho potlakisa mahlaseli a kotsi - mathata le litharollo

1. Ke kerafo efe e ka tlase e bonts'ang kamano pakeng tsa ho potlaka ha centripetal kapa ho potlaka ha radial (a_R) le lebelo le otlolohileng (v) ho motsamao o chitja o tšoanang.

Tharollo:

Bala haholoanyane

Matla a ka bang teng – mathata le ditharollo

Matla a khoheli a ka bang teng

1. Matla a 4900 Joules a sebediswa ho phahamisa ntho e boima ba 50 kg ho isa bophahamong ba h. Bolelele ba h ke bofe? Ho potlakisa ka baka la matla a khoheli (g) = 9.8 ms^-2.

Tse tsejoang:

Phetoho ea matla a ka bang teng (ΔPE) = 4900 Joule

Boholo ea ntho (m) = 50 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s²

Bala haholoanyane