1.
Based on the above table, find R and P.
Solution
Transformer’s equation :
Vs Np = Ns Vp and Vp Ip = Vs Is
Vs = secondary voltage, Vp = primary voltage, Ns = secondary loops, Np = primary loops, Ip = primary current, Is = secondary current
Primary voltage (Vp)
Vp Ip = Vs Is
Vp (4) = (10)(80)
Vp = 800 / 4
Vp = R = 200 Volt
Secondary loops (Ns)
Vs Np = Ns Vp
(10)(600) = Ns (200)
6000 = 200 Ns
Ns = 6000 / 200
Ns = P = 30 loops
2.
Based on the above table, find K and L.
Solution :
Secondary current (Is) of transformer 1 :
Vp Ip = Vs Is
(200)(3) = (300)(Is)
Is = 600 / 300
Is = K = 2 A
Secondary voltage (Vs) of transformer 2 :
Vp Ip = Vs Is
(40)(0,75) = Vs (1)
Vs = L = 30 Volt
3.
Based on the table above, find P and Q.
Solution :
Primary voltage (Vp)
Vs Np = Ns Vp
(220)(300) = (600) Vp
(220)(3) = (6) Vp
660 = 6 Vp
Vp = 660 / 6
Vp = P = 110 Volt
Primary current (Ip)
Vp Ip = Vs Is
(110)(Ip) = (220)(2)
(110)(Ip) = 440
Ip = 440 / 110
Ip = Q = 4 A