1. The Earth’s distance from the Sun is 149.6 x 106 km and period of Earth’s revolution is 1 year. Calculate T2 / r3
Known :
T = 1 year, r = 149.6 x 106 km
Wanted : T2 / r3 = … ?
Solution :
k = T2 / r3 = 12 / (149.6 x 106)3 = 1 / (3348071.9 x 1018) = 2.98 x 10-25 year2/km3
[irp]
2. Universal constant (G) = 6.67 x 10-11 N.m2/kg2 and Sun’s 1.99 x 1030 kg.
[irp]
3. The mean distance of Earth from the Sun is 149.6 x 106 km and the mean distance of Mercury from the Sun is 57.9 x 106 km. The period of Earth’s revolutions is 1 year, what is the period of Mercury’s revolution?
Known :
r of Earth = 149.6 x 106 km
r of mercury = 57.9 x 106 km
T of Earth = 1 year
Wanted: T of mercury?
Solution :
[wpdm_package id=’953′]
- Newton’s law of universal gravitation problems and solutions
- Gravitational force, weight problems, and solutions
- Acceleration due to gravity problems and solutions
- Geosynchronous satellite problems and solutions
- Kepler’s law problems and solutions problems and solutions
