1.
AL-aċċelerazzjoni minħabba l-gravità hija ta' 10 N/kg. L-erja tal-wiċċ tal-ħuta ppressata mill-ilma 'l fuq minnha hija ta' 6 ċm2Iddetermina l-forza tal-ilma 'l fuq mill-ħut li taġixxi fuq il-ħut.
Magħruf:
Aċċelerazzjoni minħabba l-gravità (g) = 10 N/kg
Surface area of fish (A) = 6 cm2 = 6x10-4 m2
Densità of water = 1 gram/cm3 = 1 (10-3 kg) / 10-6 m3 = 103 kg / m3 = 1000 kg/m3
Height of water = 100 cm – 15 cm = 85 cm = 85 x 10-2 metri
Meħtieġ: Force of the water above fish that acts on fish
Soluzzjoni:
Ekwazzjoni ta' pressjoni:
P = F / A
F = P A
F = ρ g h A
F = (1000)(10)(85 x 10-2)(6 x 10-4 m2)
F = (104)(510 x 10-6)
F = 510 x 10-2
F = 5.1 Newton
2. The normal pressure of blood is 80 mm hg to 120 mm hg. This value is equal to…
A. 80 Pascal to 120 Pascal
B. 800 Pascal to 1200 Pascal
C. 10256 Pascal to 17589 Pascal
D. 10526 Pascal to 15789 Pascal
Magħruf:
The normal pressure of blood = 80 mm Hg – 120 mm Hg
Mfittxija: This value is equal to… Pascal
Soluzzjoni:
The height of mercury in a barometer (above the surface of the sea) = 760 mm Hg
Pressure of air (above the surface of sea) = 1 atm = 1.0 x 105 Pascal
1 mm Hg = ……. Pascal?
80 mm Hg = 80 x 131.58 Pascal = 10,526 Pascal
120 mm Hg = 120 x 131.58 Pascal = 15,789 Pascal
It-tweġiba t-tajba hija D.
3. Above the surface of the sea, the height of mercury in a barometer is 760 mm. If at a place, the height of mercury in a barometer is 700 mm. Determine the pressure of air at that place.
Magħruf:
The height of mercury in a barometer (above the surface of the sea) = 760 mm Hg
Pressure of air (above the surface of sea) = 1 atm = 1,013 x 105 Pascal
Mfittxija: Determine the pressure of air if the height of mercury is 700 mm
Soluzzjoni:
760 mm Hg = 1.013 x 105 Pascal
700 mm Hg = ……… Pascal?
