1. Ƙayyade ƙarfin wutar lantarki a wani wuri da ke da nisan 1 cm daga caji 5.0 μ C. Madaidaitan Coulomb (k) = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C.
An sani:
Nisa daga caji (r) = 1 cm = 1/100 m = 0.01 m = 10 -2 m
Cajin (q) = 5.0 μ C = 5.0 x 10 -6 C
Madaidaitan Coulomb (k) = 9 x 10 9 Nm 2 C −2
Ana nema: Ƙarfin wutar lantarki (V)
Magani:
Ƙarfin wutar lantarki:

Ƙarfin wutar lantarki shine 4.5 x 10 6 Volts
[irp]
2. cajin Q1 = 5.0 μC da caji Q2 = 6.0 μC. Coulomb na yau da kullun (k) = 9 x 109 Nm2C-2, 1 μC = 10-6 C. Maki na A yana tsakanin cajin. Ƙayyade ƙarfin wutar lantarki a wurin A.

An sani:
Cajin Q 1 = -5.0 μ C = -5.0 x 10 -6 C
Nisa daga maki A daga Q 1 = 10 cm = 0.1 m = 10 -1 m
Cajin Q 2 = 6.0 μ C = 6.0 x 10 -6 C
Nisa daga maki a daga Q 2 = 10 cm = 0.1 m = 10 -1 m
Madaidaitan Coulomb (k) = 9 x 10 9 Nm 2 C −2
Ana so: Ƙarfin wutar lantarki a wuri na A
Magani:
Ƙarfin wutar lantarki 1 :

Ƙarfin wutar lantarki 2 :

Ƙarfin wutar lantarki a wuri na A :
V = V 2 – V 1
V = (54 – 45) x 10 4
V = 9 x 10 4
[irp]
3. cajin q1 = 5.0 μC da caji q2 = 6.0 μC. Coulomb na yau da kullun (k) = 9 x 109 Nm2C-2, 1 μC = 10-6 C. Ƙayyade ƙarfin wutar lantarki a wurin A.
An sani:
Cajin Q 1 = -5.0 μ C = -5.0 x 10 -6 C
Nisa daga maki A daga Q 1 = 40 cm = 0.4 m = 4 x 10 -1 m
Cajin Q 2 = 6.0 μ C = 6.0 x 10 -6 C
Nisa daga maki A daga Q 2 = 50 cm = 0.5 m = 5 x 10 -1 m
Madaidaitan Coulomb (k) = 9 x 10 9 Nm 2 C −2
Ana so: Ƙarfin wutar lantarki a wuri na A
Magani:
Ƙarfin wutar lantarki 1 :

Ƙarfin wutar lantarki 2 :

Ƙarfin wutar lantarki a wuri na A :
V = V 1 + V 2
V = (-11.25 + 10.8) x 10 4
V = -0.45 x 10 4
V = -4.5 x 10 3
Ƙarfin wutar lantarki a wurin A shine -4.5 x 10 3 Volts