Makamashin wutar lantarki - matsaloli da mafita

1. Ana hanzarta na'urar lantarki daga hutawa ta hanyar bambancin V na 12. Menene canjin da ke cikin makamashin wutar lantarki na electron?

An sani:

The cajin akan na'urar lantarki (e) = -1.60 x 10^-19 Coulomb

Ƙarfin wutar lantarki = irin ƙarfin lantarki (V) = Volt 12

SE busca: Canjin makamashin lantarki na lantarki (ΔPE)

Magani:

ΔPE = q V = (-1.60 x 10^-19 C)(12 V) = -19.2 x 10^-19 Joule

Alamar ragewa tana nuna cewa ƙarfin kuzarin da ake da shi yana raguwa.

2. Ana cajin faranti biyu masu layi daya. Raba tsakanin faranti shine 2 cm kuma girman faranti filin lantarki Tsakanin faranti shine Volt 500/mita. Menene canjin kuzarin da ake samu a cikin proton idan aka hanzarta shi daga farantin da aka caji mai kyau zuwa farantin da aka caji mai korau.

An sani:

Girman filin lantarki tsakanin faranti (E) = Volt 500/mita

The distance tsakanin faranti (s) = 2 cm = 0,02 m

Cajin da ke kan proton = +1.60 x 10^-19 Coulomb

Ana so: Canjin makamashin lantarki (ΔPE)

Magani:

Ƙarfin wutar lantarki:

V = Es

V = (Volt 500/m)(0.02 m)

V = Volt 10

Canjin makamashin lantarki:

ΔPE = qV

ΔPE = (1,60 x 10^-19 C)(V 10)

ΔPE = 16 x 10^-19 Joule

ΔPE = 1.6 x 10^-18 Joule

3. An raba caji maki biyu da nisan santimita 10. Caji a kan maki A =+9 μC kuma caji akan batu B = -4 μC. k = 9 x 10⁹ Nm²C^-2, 1 μC = 10^-6 C. Menene canjin makamashin wutar lantarki na caji a wurin B idan aka hanzarta zuwa wurin A?

An sani:

Cajin A (q)₁) = +9 μC = +9 x 10^-6 C

cajin B (q₁) = -4 μC = -4 x 10^-6 C

ku = 9 x 10⁹ Nm²C^-2

Nisa tsakanin caji A da B (r) = 10 cm = 0.1 m = 10^-1 m

Ana so: Canjin makamashin lantarki (ΔEP)

Magani: