fisiks

Mathata a Rarollotsoeng Motsamaong o Mola – Lintho tse oelang ka bolokolohi

1. Ntho e oeleng ho tloha holimo lefikeng. E bonahala e thula mobu o ka tlase kamora metsotsoana e 3. Fumana lebelo la yona pele e thula mobu. Ho potlaka ha matla a khoheli ke 10 m/s ² . Hlokomoloha ho hanyetsa metsi.

Tse tsejoang:

Lebelo la pele (vo _o ) = 0 (ntho e theohile)

Nako ea ho arohana (t) = metsotsoana e 3

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa: Lebelo la ho qetela (v _t )

Tharollo:

Ho potlaka ka lebaka la matla a khoheli holim'a lefatše, boholo ba lona ke 9.8 m/s ^2. Ho etsa hore lipalo li be bonolo, re sebelisa 10 m/s ².

10 m/s ² kapa 10 m/s / motsotsoana o le mong, ho bolela hore lebelo le eketseha ka tatellano ka 10 m/s nakong ea motsotsoana o mong le o mong.

Kamora motsotsoana o le mong, lebelo la ntho = 10 m/s

Kamora metsotsoana e 2, lebelo la ntho = 20 m/s

Kamora metsotsoana e 3, lebelo la ntho = 30 m/s.

Re ka boela ra sebelisa li-equation tsa kinematic bakeng sa motsamao ka ho potlaka ho sa khaotseng , joalo ka ha ho bontšitsoe ka tlase.

v _t = v _o + ho

s = vo _ot + ½ ho ²

v _t ² = v _o ² + 2 jwalo ka

Ho oa ho lokolohileng ha ho na lebelo la pele (v _o = 0), kahoo equation e kaholimo e ka fetoloa joalo ka ha ho bontšitsoe ka tlase:

Tekanyo ea motsamao o oang ka bolokolohi :

v _t = gt ………… 1

h = ½ gt ² ………… 2

v _t ² = 2 gh ………….. 3

v _t = gt

v _t = (10)(3)

v _t = 30 m/s

Lebelo la ho qetela ke 30 m/s

[irp]

2. Setopo se oa ka bolokolohi phomolong, ho tloha bophahamong ba limithara tse 25. Fumana (a) Lebelo leo se otlang fatše ka lona. (b) Nako eo se e nkang ho fihla fatše.

Ho potlaka ka lebaka la matla a khoheli holim'a Lefatše ke 10 m/s ².

Tse tsejoang:

Bophahamo (h) = limithara tse 5

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa:

(a) Lebelo la ho qetela (v _t )

(b) Nako e sa fellang (t)

Tharollo:

Tekanyo ea hoetla e sa lefelloeng:

v _t = gt

h = ½ gt ²

v _t ² = 2 gh

(a) Lebelo la ho qetela (v _t )

v _t ² = 2 gh = 2(10)(5) = 100

v _t = 10 m/s

(b) Nako e sa fellang (t)

h = ½ gt ²

5 = ½ (10) t ²

5 = 5 t ²

t ² = 5/5 = 1

t = motsotsoana o le mong

[irp]

3. Bolo e oele ho tloha bophahamong. Fumana (a) Ho potlaka (b) Sebaka kamora metsotsoana e 3 (c) Nako moeeng haeba lebelo la ho qetela e le 20 m/s. Ho potlaka ka lebaka la matla a khoheli = 10 m/s ²

Tse tsejoang :

Ho potlaka ha matla a khoheli (g) = 10 m/s ²

Ho batloa:

(a) Ho potlaka (a)

(b) Sebaka kapa bophahamo (h) haeba nako e fetile (t) = metsotsoana e 3

(c) Nako e sa fellang (t) haeba v _t = 20 m/s

Tharollo:

Tekanyo ea hoetla e sa lefelloeng:

v _t = gt

h = ½ gt ²

v _t ² = 2 gh

(a) Ho potlaka (a)

Ho potlaka = ho potlaka ka lebaka la matla a khoheli = 10 m/s ² . Ho bolela keketseho ea lebelo ka 10 m/s ka motsotsoana.

(b) Sebaka kapa bophahamo (h) kamora t = metsotsoana e 3

h = ½ gt ² = ½ (10)(3) ² = (5)(9) = limithara tse 45

(c) Nako e fetile (t) haeba v _t = 20 m/s

v _t = gt

20 = (10) t

t = 20 / 10 = metsotsoana e 2

[irp]

[ID ea sephutheloana sa wpdm='511′]

[ID ea sephutheloana sa wpdm='517′]

1. Sebaka le ho falla
2. Lebelo le tloaelehileng le lebelo le tloaelehileng
3. Lebelo le sa fetoheng
4. Ho potlaka kamehla
5. Motsamao oa hoetla o lokolohileng
6. Motsamao oa ho theoha ha ho oa ka bolokolohi
7. Motsamao o yang hodimo le tlase nakong ya ho wa ha mahala

Bala haholoanyane

Mathata a Rarollotsoeng Motsamaong o Mola - Ho potlaka ho sa khaotseng

1. Koloi e potlakisa ho tloha phomolong ho ea ho 20 m/s ka metsotsoana e 10. Fumana lebelo la koloi!

tharollo

Tse tsejoang:

Lebelo la pele (vo _o ) = 0 (phomolo)

Nako ea ho arohana (t) = metsotsoana e 10

Lebelo la ho qetela (v _t ) = 20 m/s

Ho batloa : Ho potlaka (a)

Tharollo:

v _t = v _o + ho

20 = 0 + (a)(10)

20 = 10 a

a = 20/10

a = 2 m/s ²

[irp]

2. Koloi e theoha lebelo ho tloha ho 30 m/s ho ea phomola ka metsotsoana e 10. Fumana lebelo la koloi.

tharollo

Tse tsejoang:

Lebelo la pele (vo _o ) = 30 m/s

Lebelo la ho qetela (v _t ) = 0

Nako ea ho arohana (t) = metsotsoana e 10

Ho batloa: ho potlakisa (a)

Tharollo:

v _t = v _o + ho

0 = 30 + (a)(10)

– 30 = 10 a

a = – 30 / 10

a = -3 m/s ²

Letšoao le fosahetseng le hlaha hobane lebelo la ho qetela le ka tlase ho lebelo la pele.

[irp]

3. Koloi e qala le ho potlakisa ka lebelo le sa fetoheng la 4 m/s ka motsotsoana o ^le mong. Fumana lebelo le sebaka kamora metsotsoana e 10.

tharollo

(a) Lebelo

Ho potlaka ha 4 m/s ² ho bolela keketseho ea lebelo ka 4 m/s motsotsoana o mong le o mong o le mong. Kamora metsotsoana e 2, lebelo la koloi ke 8 m/s. Kamora metsotsoana e 10, lebelo la koloi ke 40 m/s.

(b) Sebaka

Tse tsejoang:

Lebelo la pele (v _o ) = 0

Lebelo la ho qetela (v _t ) = 40 m/s

Ho potlaka (a) = 4 m/s ²

Ho batloa: Sebaka

Tharollo:

s = vo _o t + ½ ho ² = 0 + ½ (4)(10 ² ) = (2)(100) = limithara tse 200

[irp]

4. Koloi e tsamaea ka lebelo le sa fetoheng la 10 m/s, ebe e theoha butle butle ka lebelo le sa fetoheng la 2 m/s ^{2 ho fihlela e phomola. Fumana nako e fetileng le} sebaka sa koloi pele e phomola.

Tse tsejoang:

Lebelo la pele (vo _o ) = 10 m/s

Ho potlaka (a) = -2 m/s ² (Letšoao le fosahetseng le hlaha hobane lebelo la ho qetela le ka tlase ho lebelo la pele)

Lebelo la ho qetela (v _t ) = 0 (phomolo)

Ho batloa: Nako le sebaka

Tharollo:

(a) Nako e sa fellang (t)

v _t = v _o + ho

0 = 10 + (-2)(t)

0 = 10 – 2 t

10 = 2 t

t = 10 / 2 = metsotsoana e 5

(b) Sebaka

v _t ² = v _o ² + 2 jwalo ka

0 = 10 ² + 2(-2) s

0 = 100 – 4 metsotsoana

100 = metsotsoana e 4

s = 100 / 4 = limithara tse 25

[irp]

5. Koloi e tsamaea ka lebelo la 40 m/s, e theoha butle ka lebelo le sa fetoheng la 4 m/s ² ho fihlela e phomola. Fumana lebelo le sebaka ka mor'a ho theoha butle ka metsotsoana e 10!

tharollo

Tse tsejoang:

Lebelo la pele (vo _o ) = 40 m/s

Ho potlaka (a) = -4 m/s ²

Nako ea ho arohana (t) = metsotsoana e 10

Ho batloa: lebelo la ho qetela (v _t ) le sebaka (s)

Tharollo:

(a) Lebelo la ho qetela

v _t = vo _o + ho = 40 + (-4)(10) = 40 – 40 = 0 m/s

0 m/s e bolela phomolo ea koloi.

(b) Sebaka

s = vo _o t + ½ ho ² = (40)(10) + ½ (-4)(10 ² ) = 400 + (-2)(100) = 400 – 200 = limithara tse 200

[irp]

6. Fumana sebaka ka mora metsotsoana e 10!

tharollo

Sebaka: s = vt = (10-0)(5-0) = (10)(5) = limithara tse 50

7. Fumana sebaka ka mora metsotsoana e 4!

tharollo

Sebaka = sebaka se sekwere + sebaka se kgutlotharo

Sebaka = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = 96 metres

8. Fumana sebaka sa koloi ka mor'a metsotsoana e 4!

tharollo

Sebaka = sebaka sa khutlotharo = ½ (4-0)(8-0) = ½ (4)(8) = limithara tse 16

9. Koloi e tsamaya ka lebelo la 90 km/h ho feta koloi ya mapolesa e emang pela tsela. Motsotso o le mong hamorao, koloi ya mapolesa e a lelekisa ka lebelo la 0.8 m/s . ^2. Koloi ya mapolesa e fihla koloing hole hakae?

Tse tsejoang:

Lebelo la koloi (v) = 90 km/hora = 90,000 metres / metsotsoana e 3600 = 25 metres/motsotsoana

Nako e sa fellang (t) = motsotso o le 1 = metsotsoana e 60

Ho potlaka ha koloi ea mapolesa (a) = 0.8 m/s ²

Lebelo la pele la koloi ea mapolesa (vo _o ) = 0 m/s

Ho batloa: Sebaka se tsamauoang ka koloi ea mapolesa

Tharollo:

Koloi e tsamaea ka lebelo le sa fetoheng. Sebaka se tsamauoang ka koloi:

Sebaka sa pele:

s = vt = (25)(60) = limithara tse 1500

Sebaka sa ho qetela:

s = vt = (25)(t)

Kakaretso ea sebaka = 1500 + 25 t

Koloi ea mapolesa e tsamaea ka lebelo le sa khaotseng. Sebaka se tsamauoang ke koloi ea mapolesa:

s = vo _o t + ½ ho ² = (0)(t) + ½ (0.8)(t ² ) = 0 + 0.4 t ² = 0.4 t ²

Ha koloi ea mapolesa e fihla koloing, sebaka se tsamauoang ke koloi ea mapolesa se tšoana le sebaka se tsamauoang ke koloi.

Sebaka se tsamauoang ka koloi = sebaka se tsamauoang ka koloi ea mapolesa

1500 + 25 t = 0.4 t ²

0.4 t ² – 25 t – 1500 = 0

Sebelisa foromo ea quadratic:

Sebaka se tsamauoang ka koloi ea mapolesa:

s = 0.4 t ² = (0.4)(100 ² ) = (0.4)(10,000) = 4000 limithara s = 4 km

10. Koloi e tsamaya ka brake e sa fetoheng ya 24 m/s hoo e ka bang le phokotso e sa fetoheng ya 0.952 m/s . ^2. Fumana lebelo la koloi kamora sebaka sa dimithara tse 250.

Tse tsejoang:

Lebelo la pele (vo _o ) = 24 m/s

Ho potlaka (a) = – 0.952 m/s ² ( e saennweng ka nepo hobane ho fokotseha ha lebelo )

Sebaka ( d ) = limithara tse 250 s

Ho batloa: Lebelo la koloi ka mor'a limithara tse 250 s

Tharollo:

Tse tsejoang: lebelo la pele (v_o), ho potlaka (a), distanta (d), e batloang: lebelo la ho qetela (v_t) kahoo sebelisa equation ea v_t² = v_o² + 2 a d

v _t = lebelo la ho qetela , v _o = lebelo la pele , a = ho potlakisa , d = sebaka

v _t ² = (24) ² + (2)(-0.952)(250)

v _t ² = 576 – 476

v _t ² = 100

v _t = √100

v _t = 10 m/s

[irp]

[ID ea sephutheloana sa wpdm='507′]

[ID ea sephutheloana sa wpdm='517′]

1. Sebaka le ho falla
2. Lebelo le tloaelehileng le lebelo le tloaelehileng
3. Lebelo le sa fetoheng
4. Ho potlaka kamehla
5. Motsamao oa hoetla o lokolohileng
6. Motsamao oa ho theoha ha ho oa ka bolokolohi
7. Motsamao o yang hodimo le tlase nakong ya ho wa ha mahala

Bala haholoanyane

Mathata a Rarollotsoeng Motsamaong o Mola - Lebelo le sa Feleng

1. Koloi e tsamaea ka lebelo le sa fetoheng la 10 m/s. Fumana sebaka kamora metsotsoana e 10 le metsotsoana e 60.

tharollo

Lebelo le sa fetoheng la limithara tse 10 ka motsotsoana le bolela hore koloi e tsamaea limithara tse 10 motsotsoana o mong le o mong.

Kamora metsotsoana e 2, koloi e tsamaea limithara tse 20,

Kamora metsotsoana e 5, koloi e tsamaea limithara tse 50,

Kamora metsotsoana e 10, koloi e tsamaea limithara tse 100 ,

Kamora metsotsoana e 60, koloi e tsamaea limithara tse 600.

[irp]

2. Koloi e tsamaea tseleng e otlolohileng ka lebelo le sa fetoheng la 72 km/h. Fumana sebaka sa koloi kamora metsotso e 2 le metsotso e 5.

tharollo

72 km/h = (72)(limithara tse 1000) / metsotsoana e 3600 = metsotsoana e 72,000 / metsotsoana e 3600 = limithara tse 20/motsotsoana.

Lebelo le sa fetoheng la limithara tse 20 ka motsotsoana le bolela hore koloi e tsamaea limithara tse 20 motsotsoana o mong le o mong.

Kamora metsotsoana e 120 kapa metsotso e 2, koloi e tsamaea limithara tse 20 x 120 = limithara tse 2400 ,

Kamora metsotsoana e 300 kapa metsotso e 5, koloi e tsamaea limithara tse 20 x 300 = limithara tse 6000.

[irp]

3. 'Mele o tsamaea tseleng e otlolohileng ka limithara tse 100 ka metsotsoana e 50. Fumana lebelo la 'mele.

tharollo

Limithara tse 100 / metsotsoana e 50 = limithara tse 10 / metsotsoana e 5 = limithara tse 2 ka motsotsoana.

4. Fumana lebelo ho latela setshwantsho se ka tlase….

tharollo

Lebelo = Sebaka / nako e fetile

Lebelo = limithara tse 2 / motsotsoana o le mong = limithara tse 4 / metsotsoana e 2 = limithara tse 6 / metsotsoana e 3 = limithara tse 8 / metsotsoana e 4 = limithara tse 2 ka motsotsoana.

5. Likoloi A le B lia atamelana litseleng tse bapileng. Ha sebaka se pakeng tsa likoloi tse peli e le limithara tse 100, koloi A e tsamaea ka lebelo le sa fetoheng la 10 m/s, koloi B e tsamaea ka lebelo le sa fetoheng la 40 m/s. Fumana (a) sebaka sa koloi A pele u feta koloi B (b) nako e sa fellang pele koloi B e feta koloi A.

tharollo

Koloi A e tsamaya ka lebelo le sa fetoheng la limithara tse 10 ka motsotsoana, ho bolelang hore koloi A e tsamaya ho fihlela limithara tse 10 motsotsoana o mong le o mong. Kamora metsotsoana e 2, koloi e tsamaya ho fihlela limithara tse 20.

Koloi ea B e tsamaea ka lebelo le sa fetoheng la limithara tse 40 ka motsotsoana, ho bolelang hore koloi ea B e tsamaea ho fihlela limithara tse 40 motsotsoana o mong le o mong. Kamora metsotsoana e 2, koloi ea B e tsamaea ho fihlela limithara tse 80.

Limithara tse 20 + limithara tse 80 = limithara tse 100.

(a) Sebaka sa koloi A pele koloi B e feta ke limithara tse 20. Sebaka sa koloi B pele koloi A e feta ke limithara tse 80.

(b) Nako e pakeng tsa koloi B pele e feta koloi A ke metsotsoana e 2. Nako e pakeng tsa koloi A pele e feta koloi B ke metsotsoana e 2

5. Haeba sesupa-tsela sa lebelo sa koloi se bontša 108 km/h, fumana sebaka seo koloi e se tsamaileng ka motsotso o le mong.

Tharollo:

Speedometer ke sesebelisoa sa ho lekanya lebelo. Lebelo la koloi ke 108 km/hora.
108 km / h = (108) (limithara tse 1000) / metsotsoana e 3600 = limithara tse 30 ka motsotsoana.

Motsotso o le 1 = metsotsoana e 60

Lebelo la koloi la limithara tse 30 ka motsotsoana le bolela hore koloi e tsamaea ho fihlela ho limithara tse 30 ka motsotsoana o le mong.

Kamora motsotsoana o le mong, koloi e tsamaya ho fihlela ho 1 x 30 metres = 30 metres.

Kamora metsotsoana e 2, koloi e tsamaya ho fihlela ho 2 x 30 metres = 60 metres.

Kamora metsotsoana e 60, koloi e tsamaya ho fihlela ho 60 x 30 metres = 1800 metres.

6. Tom o lahlela bolo ka ho toba ho Andrew . Tom le Andrew ba arohane ho fihlela ho dimithara tse 10.08 . Bolo e lahlelwa ka ho rapama mme e tsamaya ka lebelo la 20 m/ s (ho hlokomoloha matla a khoheli). Andrew o otla bolo metsotsoana e 4.00 x 10 ^-3 kamora hore bolo e lahlelwe. Haeba motho ya otlang a tsamaya ka lebelo le sa fetoheng la 5.00 m/s, bolo e otlwa ke motho ya otlang ka mora hore motho ya otlang a tsamaye ho fihlela...

Tse tsejoang:

Sebaka se pakeng tsa Tom le Andrew = limithara tse 10.08

Lebelo la bolo (v) = 20 m/s

Nako e sa fellang (t) = 4 x 10 ^-3 metsotsoana = 0.004 metsotsoana

Lebelo la moqhobi (v) = 5 m / s

Oa Batla: Bolo e otloa ke motho ea otlang ka mor'a hore bolo e tsamaee ho fihlela…

Tharollo:

Sebaka sa bolo:

s ₁ = vt = (20) (0.004) = 0.08 limithara

Sebaka sa sebapali:

s ₂ = vt = 5 t

Sebaka sa bolo + sebaka sa motho ea otlang = sebaka se pakeng tsa Tom le Andrew.

0.08 + 5 t = 10.08

5 t = 10.08 – 0.08

5 t = 10

t = 10/5

t = metsotsoana e 2

Sebaka sa sebapali:

s ₂ = vt = 5 t = (5) (2) = limithara tse 10

7. Setsomi se nang le koloi ea sona se lelekisa khama. Koloi e tsamaea ka lebelo la 72 km/h 'me khama e matha ka lebelo la 64.8 km/h. Ha sebaka se pakeng tsa koloi le khama e le limithara tse 2012, setsomi se ile sa thunya sethunya sa sona. Lithunya li tsoa ka sethunya ka lebelo la 200 m/s. Fumana nako eo khama e thunngoang ka eona.

A. 0.5 s

B. 1 s

C. 1.25 s

D. 1.5 s

Tse tsejoang:

Lebelo la koloi (v _b ) = 72 km/h = (72)(1000 m) / 3600 s = 20 m/s

Lebelo la khama (v _r ) = 64.8 km/h = (64.8)(1000 m) / 3600 s = 64800 m / 3600 s = 18 m/s

Ha kulo e thunngoa, sebaka se pakeng tsa koloi le khama = limithara tse 202

Lebelo la mollo (v _p ) = 20 m/s + 200 m/s = 220 m/s

Libetsa li tšoaroa ke litsomi tse ka koloing e tsamaeang ka lebelo la 20 m/s e le hore lebelo la koloi le lona le eketsoe lebelong la kulo.

Ho batloa: Fumana nako eo khama e thunngoang ka eona

Tharollo:

Nahana ka likoloi le likhama tse tsamaeang ka lebelo le sa fetoheng.

Tekanyo: v = s / t kapa s = vt

v = lebelo, s = sebaka, t = nako e sa fellang

Sebaka = 202 + X _r = 202 + v _r t = 202 + 18 t

Sebaka = Y _p = v _p t = 220 t

Sebaka se tsamauoang ke khama = sebaka se tsamauoang ke kulo

202 + 18 t = 220 t

202 = 220 t – 18 t

202 = 202 t

t = 202/202

t = motsotsoana o le mong

Karabo e nepahetseng ke B.

[irp]

[ID ea sephutheloana sa wpdm='507′]

[ID ea sephutheloana sa wpdm='517′]

1. Sebaka le ho falla
2. Lebelo le tloaelehileng le lebelo le tloaelehileng
3. Lebelo le sa fetoheng
4. Ho potlaka kamehla
5. Motsamao oa hoetla o lokolohileng
6. Motsamao oa ho theoha ha ho oa ka bolokolohi
7. Motsamao o yang hodimo le tlase nakong ya ho wa ha mahala

Bala haholoanyane

Mathata a Rarollotsoeng Motsamaong o Mola - Lebelo le tloaelehileng le lebelo le tloaelehileng

1. Koloi e tsamaea tseleng e otlolohileng e lebang bochabela ka limithara tse 100 ka metsotsoana e 4, ebe e leba bophirima ka limithara tse 50 ka motsotsoana o le mong. Fumana lebelo le tloaelehileng le lebelo le tloaelehileng.

tharollo

Sebaka = limithara tse 100 + limithara tse 50 = limithara tse 150

Ho falla = limithara tse 100 - limithara tse 50 = limithara tse 50, ho ea ka bochabela.

Nako e fetile = metsotsoana e 4 + motsotsoana o le 1 = metsotsoana e 5.

Lebelo le tloaelehileng = Sebaka / nako e fetileng = limithara tse 150 / metsotsoana e 5 = limithara tse 30 ka motsotsoana.

Lebelo le tloaelehileng = Ho falla / nako e fetileng = limithara tse 50 / metsotsoana e 5 = limithara tse 10/motsotsoana.

[irp]

2. Motho o tsamaea limithara tse 4 ka bochabela ka motsotsoana o le mong, ebe o tsamaea limithara tse 3 ka leboea ka motsotsoana o le mong. Fumana lebelo le tloaelehileng le lebelo le tloaelehileng.

tharollo

Sebaka = limithara tse 4 + limithara tse 3 = limithara tse 7

Ho falla = = limithara, ho ea ka leboea-bochabela.

Nako e fetile = motsotsoana o le 1 + motsotsoana o le 1 = metsotsoana e 2.

Lebelo le tloaelehileng = sebaka / nako e fetileng = limithara tse 7 / metsotsoana e 2 = limithara tse 3.5/motsotsoana

Lebelo le tloaelehileng = ho falla / nako e fetileng = limithara tse 5 / metsotsoana e 2 = limithara tse 2.5/motsotsoana

[irp]

3. Semathi se potoloha tsela e khutlonnetsepa ka bolelele = limithara tse 50 le bophara = limithara tse 20. Kamora ho potoloha tsela e khutlonnetsepa habeli, semathi se khutlela moo se qalang teng. Haeba nako e feta = metsotsoana e 100, fumana lebelo le tloaelehileng le lebelo le tloaelehileng.

tharollo

Selikalikoe sa khutlonnetsepa = 2 (limithara tse 50) + 2 (limithara tse 20) = limithara tse 100 + limithara tse 40 = limithara tse 140.

O tsamaea ho potoloha khutlonnetsepa ka makhetlo a 2 = 2 (limithara tse 140) = limithara tse 280.

Sebaka = limithara tse 280.

Sebaka se secha = 0 limithara . ( momathi o kgutlela moo ho qalwang teng)

Lebelo le tloaelehileng = sebaka / nako e fetileng = limithara tse 280 / metsotsoana e 100 = limithara tse 2.8 ka motsotsoana.

Lebelo le tloaelehileng = ho falla / nako e fetileng = 0 / metsotsoana e 100 = 0.

[irp]

[ID ea sephutheloana sa wpdm='505′]

[ID ea sephutheloana sa wpdm='517′]

1. Sebaka le ho falla
2. Lebelo le tloaelehileng le lebelo le tloaelehileng
3. Lebelo le sa fetoheng
4. Ho potlaka kamehla
5. Motsamao oa hoetla o lokolohileng
6. Motsamao oa ho theoha ha ho oa ka bolokolohi
7. Motsamao o yang hodimo le tlase nakong ya ho wa ha mahala

Bala haholoanyane

Mathata a rarollotsoeng ka har'a li-vector - fumana sephetho sa li-vector tse peli u sebelisa likarolo tsa vector

1. F ₁ = 6 N, F ₂ = 10 N. Fumana vekthara e hlahang.

tharollo

F _1x = F ₁ cos 60 ^o = (6)(0.5) = 3 N ( e ntle hobane e na le tataiso e tšoanang le x axis )

F _2x = F ₂ cos 30 ^o = (10)(0.5 √ 3) = 5 √ 3 = (5)(1.372) = -8.66 N (e mpe hobane e na le tataiso e tšoanang le -x axis)

F _1y = F ₁ sin 60 ^o = (6)(0.5 √ 3) = 3 √ 3 ​​​​= (3)(1.372) = 4.116 N ( e ntle hobane e na le tataiso e tšoanang le ea y axis )

F _2y = F ₂ sin 30 ^o = (10)(0.5 ) = -5 N (e mpe hobane e na le tataiso e tšoanang le -y axis)

F _x = F _1x – F _2x = 3 – 8.66 = -5.66 N

F _y = F _1y – F _2y = 4.116 – 5 = -0.884 N

 

Sephetho sa matla ana a mabeli ke 5.7 N.

[irp]

2. F ₁ = 4 N, F ₂ = 4 N, F ₃ = 8 N. Fumana vekthara e hlahang.

tharollo

F_1x =F₁ Cos 60^o = (4)(0.5) = 2 N (e ntle hobane e na le tsela e tšoanang le ea axis ea x)

F _2x = -4 N (e mpe hobane e na le tataiso e tšoanang le -x axis)

F _3x = F ₃ cos 60 ^o = (8)(0.5) = 4 N ( e ntle hobane e na le tataiso e tšoanang le x axis )

F_1y =F₁ sebe 60^o = (4)(0.5√3) = 2√3 N (e ntle hobane e na le tsela e tšoanang le ea axis ea y)

F _2y = 0

F_3y =F₃ sebe 60^o = (8)(0.5√3) = -4√3 N (e mpe) hobane e na le tataiso e tšoanang le -y axis)

F _x = F _1x – F _2x + F _3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 – 4√3 = -2√3 N

Sephetho sa matla ana a mararo ke 5.7 N.

[irp]

[ID ea sephutheloana sa wpdm='542′]

[ID ea sephutheloana sa wpdm='554′]

1. Fumana sephetho sa vekthareng ea mola
2. Fumana likarolo tsa vector
3. Fumana sephetho sa li-vector tse peli u sebelisa theorem ea Pythagorean
4. Fumana sephetho sa li-vector tse peli u sebelisa equation ea cosines
5. Fumana sephetho sa li-vector tse peli u sebelisa likarolo tsa li-vector

Bala haholoanyane

Mathata a rarollotsoeng ka har'a li-vector - fumana sephetho sa li-vector tse peli u sebelisa equation ea cosine

1. F ₁ = 10 N le F ₂ = 20 N. Fumana vekthara e hlahang.

[irp]

2. A ₁ = 15 le A ₂ = 9. Sekhutlo pakeng tsa divekthara tse pedi ke 60 ^o . Fumana vekthara e hlahang.

tharollo

[irp]

3. v ₁ = 5 le v ₂ = 12. Sekhutlo pakeng tsa divekthara tse pedi ke 90 ^o . Fumana vekthara e hlahang.

tharollo

[irp]

[ID ea sephutheloana sa wpdm='542′]

[ID ea sephutheloana sa wpdm='554′]

1. Fumana sephetho sa vekthareng ea mola
2. Fumana likarolo tsa vector
3. Fumana sephetho sa li-vector tse peli u sebelisa theorem ea Pythagorean
4. Fumana sephetho sa li-vector tse peli u sebelisa equation ea cosines
5. Fumana sephetho sa li-vector tse peli u sebelisa likarolo tsa li-vector

Bala haholoanyane

Mathata a rarollotsoeng ka har'a li-vector - fumana sephetho sa li-vector tse peli u sebelisa khopolo-taba ea Pythagorean

1. Fumana sephetho sa livekthara tse peli tsa ho falla joalo ka ha ho bontšitsoe setšoantšong se ka tlase.

[irp]

2. Fumana sephetho sa matla a mabeli , 12 N le 5 N.

[irp]

3. Moithuti o tsamaea limithara tse 4 ho ea bophirima, ebe limithara tse 6 ho ea leboea le limithara tse 4 ho ea bophirima. Fumana sebaka seo moithuti a fallang ho sona.

tharollo

Sebaka sa ho falla ke limithara tse 10 , ho ea leboea-bophirima.

[irp]

[ID ea sephutheloana sa wpdm='542′]

[ID ea sephutheloana sa wpdm='554′]

1. Fumana sephetho sa vekthareng ea mola
2. Fumana likarolo tsa vector
3. Fumana sephetho sa li-vector tse peli u sebelisa theorem ea Pythagorean
4. Fumana sephetho sa li-vector tse peli u sebelisa equation ea cosines
5. Fumana sephetho sa li-vector tse peli u sebelisa likarolo tsa li-vector

Bala haholoanyane

Mathata a rarollotsoeng ho li-vector - fumana likarolo tsa vector

1. Matla a 20 Newton o etsa sekhutlo sa 30 ^o ka x-axis. Fumana dikarolo tsa x le y tsa matla.

tharollo

F _x = F cos 30 ^o = (20)(cos 30 ^o ) = (20)(0.5 √ 3 ) = 10 √ 3 Li-Newton

F _y = F sebe 30 ^o = (20)(sebe 30 ^o ) = (20)(0.5) = 10 Newtons

[irp]

2. F ₁ = 20 Newton o etsa sekhutlo sa 30 ^o ka mothapo wa y mme F ₂ = 30 Newton o etsa sekhutlo sa 60 ^o ka mothapo wa -x. Fumana dikarolo tsa x le y tsa F ₁ le F ₂.

tharollo

F _1x = F ₁ cos 60 ^o = (20)(cos 60 ^o ) = (20)(0.5) = -10 Newtons (e mpe hobane e na le tataiso e tšoanang le -x axis)

F _2x = F ₂ cos 60 ^o = (30)(cos 60 ^o ) = (30)(0.5) = -15 Newtons (e mpe hobane e na le tataiso e tšoanang le -x axis)

F_1y =F₁ ntle 60^o = (20)(sebe sa 60^o) = (20)(0.5√3= 10√3 Newton (e ntle hobane e na le tataiso e tšoanang le ea axis ea y)

F_2y =F₂ ntle 60^o = (30)(sebe sa 60^o) = (30)(0.5√3) = -15√3 Newton (e mpe hobane e na le tataiso e tšoanang le -y axis)

[irp]

3. F ₁ = 2 N, F ₂ = 4 N, F ₃ = 6 N. Fumana dikarolo tsa x le y tsa F ₁ , F ₂ le F ₃!

tharollo

F _1x = F ₁ cos 60 ^o = (2)(cos 60 ^o ) = (2)(0.5) = 1 Newtons (e ntle hobane e na le tataiso e tšoanang le x axis)

F_2x =F₂ cos 30^o = (4)(cos 30^o) = (4)(0.5√3) = -2√3 Newton (e mpe hobane e na le tsela e tšoanang le -x axis)

F _3x = F ₃ cos 60 ^o = (6)(cos 60 ^o ) = (6)(0.5) = 3 Newtons (e ntle hobane e na le tataiso e tšoanang le x axis)

F_1y =F₁ ntle 60^o = (2)(sebe sa 60^o) = (2)(0.5√3) = √3 Newton (e ntle hobane e na le tataiso e tšoanang le ea axis ea y)

F _{2 y} = F ₂ sin 3 0 ^o = (4)(sin 30 ^o ) = (4)(0.5) = 2 Newtons (e ntle hobane e na le tataiso e tšoanang le mothapo oa y)

F_3y =F₃ ntle 60^o = (6)(sebe sa 60^o) = (6)(0.5√3) = -3√3 Newton (e mpe hobane e na le tsela e tšoanang le -y axis)

[irp]

[ID ea sephutheloana sa wpdm='542′]

[ID ea sephutheloana sa wpdm='554′]

1. Fumana sephetho sa vekthareng ea mola
2. Fumana likarolo tsa vector
3. Fumana sephetho sa li-vector tse peli u sebelisa theorem ea Pythagorean
4. Fumana sephetho sa li-vector tse peli u sebelisa equation ea cosines
5. Fumana sephetho sa li-vector tse peli u sebelisa likarolo tsa li-vector

Bala haholoanyane

Mathata a rarollotsoeng ho li-vector - fumana sephetho sa ho vector ea mola

1. Moithuti o tsamaya ka maoto ho ya leboya ho fihlela dimithareng tse 10 ebe o ya borwa ho fihlela dimithareng tse 4. Ho falla ha moithuti ho…

tharollo

R = 10 m – 4 m = 6 limithara

Boholo ba ho falla ke limithara tse 6, tsela eo ho falla ho leng ka eona e ka leboea.

2. F ₁ = 10 N, F ₂ = 15 N. Fumana vekthara e hlahang…

tharollo

R = 10 N + 15 N = 25 Newton

Boholo ba vektara e hlahang ke di-Newton tse 25, tataiso ya vektara e hlahang e lebile botjhabela kapa ka ho le letona.

[irp]

3. F ₁ = 4 N, F ₂ = 8 N. Fumana vekthara e hlahang…

tharollo

R = 8 N – 4 N = 4 Newton

Boholo ba vektara e hlahang ke di-Newton tse 4, tataiso ya vektara e hlahang e lebile botjhabela kapa ka ho le letona.

4. F ₁ = 10, F ₂ = 15 N, F ₃ = 5 N. Fumana vekthara e hlahang…

tharollo

R = 10 N + 5 N – 15 N = 0

Boholo ba vekthara e hlahang ke 0.

[irp]

[ID ea sephutheloana sa wpdm='542′]

[ID ea sephutheloana sa wpdm='554′]

1. Fumana sephetho sa vekthareng ea mola
2. Fumana likarolo tsa vector
3. Fumana sephetho sa li-vector tse peli u sebelisa theorem ea Pythagorean
4. Fumana sephetho sa li-vector tse peli u sebelisa equation ea cosines
5. Fumana sephetho sa li-vector tse peli u sebelisa likarolo tsa li-vector

Bala haholoanyane