fisiks

Botebo le ho phaphamala ka tekano - mathata le litharollo

1. Boloko bo behilweng ka hara diedi tse pedi tse nang le mefuta e fapaneng. Metsing A, karolo ya 0.6 ya ntho e ka hara mokelikeli. Metsing B, karolo ya 0.5 ya ntho e ka hara mokelikeli. Fumana karolelano ya bongata ba mokelikeli A ho mokelikeli B.

Tse tsejoang:

Botenya ba boloko = x

Karolo ea ntho e ka har'a mokelikeli A = 0.6

Boima ba mokelikeli A = y

Karolo ea ntho e ka har'a mokelikeli B = 0.5

Bala haholoanyane

Paballo ea matla a mechini holim'a libaka tse kobehileng - mathata le litharollo

1. Haeba lebelo la bolo ntlheng ea A e le 6 m/s, lebelo la bolo ntlheng ea B ke √92 m/s, 'me ho potlaka ka lebaka la matla a khoheli ke g = 10 m/s ^2. Bophahamo ba ntlha ea B (h) ke bofe?

Tse tsejoang:

Lebelo la bolo ntlheng ea A (v)_A) = 6 m/s

Lebelo la bolo ntlheng ea B (v _B ) = √92 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Bophahamo ba A (h _A ) = limithara tse 5.6

Bala haholoanyane

Setsi sa matla a khoheli - mathata le litharollo

1. Fumana likhokahano tsa setsi sa matla a khoheli sa ntho joalo ka ha ho bontšitsoe setšoantšong se ka tlase.

Tharollo:

Arola ntho ka likarolo tse tharo.

Sebaka sa karolo ea 1 (A ₁ ) = (2)(6) = 12 cm ²

Ntlha e bohareng e lutse hodima mothapo wa x (x ₁ ) = 1/2 (2) = 1 cm

Ntlha e bohareng e lutse hodima mothapo wa y (y ₁ ) = 1/2 (6) = 3 cm

Bala haholoanyane

Khopolo-taba ea Torricelli - mathata le litharollo

1. Phaephe e nang le bophahamo ba 100 cm e tletseng metsi. Lesoba la Q le fumaneha ho 10 cm ka holimo ho mobu. Sebaka se bataletseng (x) ke sefe?

Tse tsejoang:

Sebaka se pakeng tsa lesoba le bokaholimo ba metsi (h) = 100 cm – 10 cm = 90 cm = 0.9 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Bala haholoanyane

Vekthara - mathata le litharollo

Vekthara le Scalar

1. Har'a likhetho tse latelang, e leng lipara tsa scalar-vector…

A. Matla – ho potlaka

B. Kgatelelo – matla

C. Ho falla – ​​lebelo

D. Motlakase wa motlakase – kgatello

Bala haholoanyane

Maekroskoupo e kopaneng - mathata le litharollo

1.

Ho latela setšoantšo se kaholimo, keketseho ka kakaretso ke efe? Nka hore leihlo le tloaelehileng kahoo ntlha e haufi (N) = 25 cm.

Tse tsejoang:

Bala haholoanyane

Bongata ba 'Mele Diyuniti Litekanyo - Mathata le Litharollo

1.

Ho ipapisitsoe le tafole e ka holimo, ke bongata bofe bo nang le diyuniti le litekanyo tsa nnete.

Bala haholoanyane

Ho potlakisa mahlaseli a kotsi - mathata le litharollo

1. Ke kerafo efe e ka tlase e bonts'ang kamano pakeng tsa ho potlaka ha centripetal kapa ho potlaka ha radial (a _R ) le lebelo le otlolohileng (v) motsamaong o chitja o ts'oanang.

Tharollo:

Bala haholoanyane

Matla a ka bang teng – mathata le ditharollo

Matla a khoheli a ka bang teng

1. Matla a 4900 Joules a sebediswa ho phahamisa ntho e boima ba 50 kg ho isa bophahamong ba h. Bophahamo ba h ke bofe? Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 ms ^-2.

Tse tsejoang:

Phetoho ea matla a ka bang teng (ΔPE) = 4900 Joules

Boima ba ntho (m) = 50 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 9.8 m/s ²

Bala haholoanyane

Nako ea ho se tsitse ha likaroloana - mathata le litharollo

1. Libolo tse peli tse hokahaneng ka thupa, joalo ka ha ho bontšitsoe setšoantšong se ka tlase. Hlokomoloha boima ba thupa . Boima ba bolo P ke ligrama tse 600 'me boima ba bolo Q ke ligrama tse 400. Nako ea ho se sebetse hantle ha sistimi ke efe mabapi le AB?

Tse tsejoang:

Mothapo oa potoloho ke AB.

m _p = dikgerama tse 600 = 0.6 kg, m _q = dikgerama tse 400 = 0.4 kg

r _p = 20 cm = 0.2 m, r _q = 50 cm = 0.5 m

Ho batloa: Motsotso oa ho hloka botsitso ha tsamaiso

Bala haholoanyane