Su'aalo tusaale ah oo ku saabsan go'aaminta qaybaha vector-ka

2 Tusaalooyin su'aalo ah oo ku saabsan go'aaminta qaybaha vector-ka

1. Feetarka xoogga F = 20 Newton wuxuu sameeyaa xagal 30 ^o ah oo u jeeda dhidibka x ee togan. Go'aami qaybaha feetarka F ee ku yaal dhidibka x (F _x ) iyo dhidibka y (F _y ).

Dood
F_x = F cos 30^o = (20)(koos 30)^o) = (20)(0,5√3) = 10√3 Newtons
F_y = F sin 30^o = (20)(dembi 30^o) = (20)(0,5) = 10 Newton

2. Vektor F ₁ = 20 Newton waxay samaysaa xagal 30 ^o ah oo leh dhidibka y-ga ee togan iyo F ₂ = 30 Newton waxay samaysaa xagal 60 ^o ah oo leh dhidibka x-ga ee taban. Go'aami qaybaha vektorrada F ₁ iyo F ₂ ee ku yaal dhidibka x iyo dhidibka y-ga.

Dood
F_1x =F₁ cs 60^o = (20)(koos 60)^o) = (20)(0,5) = -10 Newton (taban sababtoo ah waxay ku jirtaa jihada x taban)
F_2x =F₂ cs 60^o = (30)(koos 60)^o) = (30)(0,5) = -15 Newton (taban sababtoo ah waxay ku jirtaa jihada x taban)
F_1y =F₁ aan lahayn 60^o = (20)(dembi 60^o) = (20)(0,5√3) = 10√3 Newton (togan sababtoo ah waxay ku jirtaa jihada y ee togan)
F_2y =F₂ aan lahayn 60^o = (30)(dembi 60^o) = (30)(0,5√3) = -15√3 Newton (taban sababtoo ah waxay ku socotaa jihada y taban)

3. F ₁ = 2 N, F ₂ = 4 N, F ₃ = 6 N. Go'aami qaybaha fallaadhaha F ₁ , F ₂ iyo F ₃ ee dhidibyada x iyo y!

Dood
F_1x =F₁ cs 60^o = (2)(koos 60)^o) = (2)(0,5) = 1 Newton (togan sababtoo ah waxay ku jirtaa jihada x ee togan)
F_2x =F₂ cs 30^o = (4)(koos 30)^o) = (4)(0,5√3) = -2√3 Newton (taban sababtoo ah waxay ku jirtaa jihada x taban)
F_3x =F₃ cs 60^o = (6)(koos 60)^o) = (6)(0,5) = 3 Newton (togan sababtoo ah waxay ku jirtaa jihada x ee togan)
F_1y =F₁ aan lahayn 60^o = (2)(dembi 60^o) = (2)(0,5√3) = √3 Newton (togan sababtoo ah waxay ku jirtaa jihada y ee togan)
F_2y =F₂ aan lahayn 30^o = (4)(dembi 30^o) = (4)(0,5) = 2 Newton (togan sababtoo ah waxay ku jirtaa jihada y ee togan)
F_3y =F₃ aan lahayn 60^o = (6)(dembi 60^o) = (6)(0,5√3) = -3√3 Newton (taban sababtoo ah waxay ku socotaa jihada y taban)

Su'aalo ku saabsan go'aaminta qaybaha vector-ka

1. Vektorka xoogga F = 8 Newton wuxuu sameeyaa xagal 60 ah^o dhidibka x-ga ee togan. Go'aami qaybaha fallaarta F ee ku taal dhidibka x (F)_x) iyo dhidibka y (F)_y).
2. Vektor F₁ = 8 Newtons waxay sameeyaan xagal 45 ah^o dhidibka y-togan iyo F-ga₂ = 10 Newtons waxay sameeyaan xagal 30 ah^o dhidibka x ee taban. Go'aami qaybaha vektorka F₁ iyo F₂ dhidibka x iyo dhidibka y.
3. F₁ = 4 N, F₂ = 8 N, F₃ = 12 N. Go'aami qaybaha vektorka F₁, F₂ iyo F₃ dhidibka x iyo dhidibka y!

[Ingiriis: Xalinta dhibaatooyinka vectors - go'aaminta qaybaha vector ]