Tusaale su'aal ah si loo go'aamiyo vektor-ka natiijada leh iyadoo la adeegsanayo vektors-ka qaybaha

2 Tusaalooyin su'aalo ah oo ku saabsan go'aaminta vektor-ka natiijada leh iyadoo la adeegsanayo vektor-yada qaybaha

1. F₁ = 6 N, F₂ = 10 N. Natiijada labada fallaadhaha xoogga waa…

Dood
F_1x =F₁ cs 60^o = (6)(0,5) = 3 N (togan sababtoo ah waxay ku jirtaa jihada x ee togan)
F_2x =F₂ cs 30^o = (10)(0,5√3) = 5√3 = (5)(1,372) = -8,66 N (taban sababtoo ah waxay ku jirtaa jihada x ee taban)
F_1y =F₁ aan lahayn 60^o = (6)(0,5√3) = 3√3 = (3)(1,372) = 4,116 N (togan sababtoo ah waxay ku socotaa jihada y ee togan)
F_2y =F₂ aan lahayn 30^o = (10)(0,5) = -5 N (taban sababtoo ah waxay ku socotaa jihada y ee taban)

F_x =F_1x - F_2x = 3 – 8,66 = -5,66 N
F_y =F_1y - F_2y  = 4,116 – 5 = -0,884 N

Vektor-ka natiijada ka soo baxda waa 5,7 N.

2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Natiijada saddexda fallaadhaha xoogga waa…

Dood
F_1x =F₁ cs 60^o = (4)(0,5) = 2 N (togan sababtoo ah waxay ku jirtaa jihada x ee togan)
F_2x = -4 N (taban sababtoo ah waxay ku jirtaa jihada x ee taban)
F_3x =F₃ cs 60^o = (8)(0,5) = 4 N (togan sababtoo ah waxay ku jirtaa jihada x ee togan)
F_1y =F₁ aan lahayn 60^o = (4)(0,5√3) = 2√3 N (togan sababtoo ah waxay ku socotaa jihada y ee togan)
F_2y = 0
F_3y =F₃ aan lahayn 60^o = (8)(0,5√3) = -4√3 N (taban sababtoo ah waxay ku socotaa jihada y ee taban)

F_x =F_1x - F_2x +F_3x = 2 – 4 + 4 = 2 N
F_y =F_1y +F_2y  - F_3y = 2√3 + 0 – 4√3 = -2√3 N

Vektor-ka natiijada ka soo baxda waa 4 N.

Su'aalo ku saabsan go'aaminta vektor-ka natiijada leh iyadoo la adeegsanayo vektor-yada qaybaha

1. F₁ = 6 N, F₂ = 12 N. Natiijada labada fallaadhaha xoogga waa…
2. F₁ = 10 N, F₂ = 10 N, F₃ = 15 N. Natiijada saddexda fallaadhaha xoogga waa…

[Ingiriis: Xalinta dhibaatooyinka vector-ka - go'aaminta natiijooyinka laba vector iyadoo la adeegsanayo qaybaha vector-ka]